PHP - I Want To Check A Table

Say you have three tables like this...   STUDENTS (studentid, name)   CLASSES (studentid, classname)   GRADES  (studentid, grade)   And not all students have grades yet.  If you're doing a mysql query like below, is there anything you can add to the statement to check if a grade exists for each student?   So that if while lopping through the results of the main query, I can easily do something with the students who don't yet have a grade yet (like maybe mark their names in red).   I can do this by putting a whole separate mysql query inside the looping of the main query, but that seems terribly inefficient to call the database again for EVERY student.

$sql = "SELECT * FROM students, classes, grades
	WHERE students.studentid = classes.studentid
        ORDER BY students.lastname";
	$info= mysqli_query($connection, $sql);
	if (!$info) {
	die("Database query failed: " . mysqli_error());
	} else {
           //code
        }

Thanks! Greg

I have displayed check box values(ugroup field) from ugroups table.now what i want to do is,when user select multiple check boxes and submit it should be insert into relavent feild in table.now it's insert check boxes values.but not in relevant field.this is my code.Please help me.

//select ugroup's from group table.
<?php
$result = "SELECT id,ugroup FROM group";
$res_result = db::getInstance()->query($result);
?>

<form action="db_sql/db_add_page.php" method="get">
Tittle :<input type="text" size="100" name="tittle" />
Description :<textarea cols="80" id="editor1" name="description" rows="10"></textarea>

//Display ugroups in textboxes and checkboxes
       <?php 
while( $line=$res_result->fetch(PDO::FETCH_ASSOC)) {
echo '<input type="checkbox" name="group[]" value=" '. $line['ugroup'] .'" />';
echo'<input type="text" name="ugroup" disabled="disabled" value=" '. $line['ugroup'] .'" size="7" "/>';
echo ' ';
}
?><input type="submit" value="Submit">
</form>

db_add_page.php

if(isset($_POST))
{


$tittle = $_POST['tittle'];
$description = $_POST['description'];
$ugroup = $_POST['group'];
$acc_status = "INSERT INTO add_services (id,tittle,description,g1,g2,g3,g4,g5,g6,g7,g8)
 VALUES(NULL,'".$tittle."','".$description."','".$ugroup[0]."','".$ugroup[1]."','".$ugroup[2]."','
".$ugroup[3]."','".$ugroup[4]."','".$ugroup[5]."','".$ugroup[6]."','".$ugroup[7]."')";
$rate = db::getInstance()->exec($acc_status); 
if(!$rate){
echo '<script type="text/javascript">alert("Update Error !");</script>';
}else{
header('Location:../add_page.php');
echo '<script type="text/javascript">alert("Successfuly Updated User Group !");</script>'; 



}

}

Attached Files  group.jpg   22.14KB   0 downloads  add_services.jpg   21.36KB   0 downloads

hi,

Hi All, I want to copy into a table values from another table that partially match a given value, case-insensitively. So far I do as follows but I wonder whether there is a quicker way.

$input_table=array('1'=>'toto','2'=>'tota','3'=>'hello','4'=>'TOTO','5'=>'toto');
$input_table_2 = array_map('strtolower', $input_table);
$value_to_look_for='Tot';
$value_to_look_for_2=strtolower($value_to_look_for);
$output_table=array();
foreach ($input_table_2 as $k=>$v)
  {
  if(false !== strpos($v, $value_to_look_for_2))
    {
    $output_table[]=$input_table[$k];
    }
}

One drawback is that $input_table_2 is 'foreached' whereas there might be no occurrences, which would lead to a loss of time/resources for big arrays.   Thanks.

Hello,

I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints?



Thanks in advance,
Vero

Hello everyone.

I need help with the following PHP APP. I am running on (Version PHP 7.2.10) I am trying to have a page table form on table.php pass the input variable of “5-Numbers” to another page called table_results.php

I want that variable string of “5-Numbers” to be compared against 4 arrays and output any duplicates found within each of those 4 lists. If nothing is found, I still want some visual output that reads “None found”.

 

Lets pretend I have the following example ..

On table.php, I typed inside my table form the 5-Numbers ..

INPUT:  2,15,37,13,28

On table_results.php, the 4 arrays to be compared against my input numbers “ 2,15,37,13,28” are ..

 

$array_A = array(2,6,8,11,14,18,24); 

$array_B = array(1,2,9,10,13,14,25,28,);  

$array_C = array(1,3,7,9,13,15,20,21,24); 

$array_D = array(4,5,12,22,23,27,28,29); 

 

So my output should read as follows below ..

OUTPUT: 

 

TABLE

COLUMN 1   COLUMN 2

ROW 1 Matches Found Results ..

ROW 2 GROUP A:            2 

ROW 3 GROUP B:             2,13,28

ROW 4 GROUP ?            13,15

ROW 5 GROUP ?            28

ROW 6 5#s Input:              2,15,37,13,28

 

Please let me know if anyone has any suggestions on how to go about it. 

Thanks.

Edited January 1, 2019 by Jayfromsandiego
Wanted to include image example

hi...

i have a table ...

i add and remove data in the table...when i add new record , information add to center of the table ! whats problem?   i want add data in first of table.   please guide me.thanks

 

 

Hi All ,   I have a small table with 4 fields namely Day_ID, Dues, Last_Visit, Points. where Day_ID is an auto-increment field. The table would be as follows:   Day_ID -- Dues ---  Last_Visit ---  Points. 1  --------- 900 -------- 1/12  --------   6      2  --------- 700 -------- 4/12  --------   7 3  --------- 600 -------- 7/12  --------   5 4  --------- 600 -------- 9/12  --------   6 5  --------- 600 -------- 10/12 -------   6 6  --------- 600 -------- 14/12 -------   6   So this is the record of a person's visit to say a club. The last row indicates the last date of his visit to the club. His points on this date are 6. Based on this point value of 6 in the last row I want to retrieve all the previous BUT adjoining all records that have the same Points i.e. 6.    So my query should retrieve for me, based on the column value of Points of the last row (i.e. Day_ID - 6 ), as follows:   4  --------- 600 -------- 9/12  --------   6 5  --------- 600 -------- 10/12 -------   6 6  --------- 600 -------- 14/12 -------   6   This problem stated above had been completely resolved, thanks to a lot of help from Guru Barand by this following query :-

$query = "SELECT cv.day_id, cv.dues, cv.last_visit, cv.points
FROM clubvisit cv
WHERE last_visit >=
(
SELECT MAX(last_visit) FROM clubvisit
WHERE points <>
(
SELECT points as lastpoints
FROM clubvisit
JOIN
(
SELECT MAX(last_visit) as last_visit
FROM clubvisit
) as latest USING (last_visit)
)
)";

I am using this and it works perfectly except that now there is a slight change in the table because the criteria for points is now dependent on more than one column cv.points and is more like cv.points1, cv.points2, cv.points3 etc. So now I need to make a selection based on each of these cv.points columns.   As of now I can still get the results by running the query multiple times for each of the cv.points columns ( seperately for cv.points1, cv.points2, cv.points3) and it works correctly. However I am wondering if there is a better way to do this in just one go. This not only makes the code repetitive but also since the queries are interconnected, involves the use of transactions which I wish to avoid if possible.    The values that I require for each of the cv.point columns is  1. day_id of the previous / old day on which the cv.points value changed from the current day value, and  2. cv.points on that old/ previous day.    So for  example if the table is as below:   Day_ID -- Dues ---  Last_Visit ---  Points1 --- Points2. 1  --------- 900 -------- 1/12  -----------   9  ------------ 5    2  --------- 600 -------- 4/12  -----------   6  ------------ 6 3  --------- 400 -------- 7/12  -----------   4  ------------ 7 4  --------- 500 -------- 9/12  -----------   5  ------------ 8 5  --------- 600 -------- 10/12 ----------   6  ------------ 8 6  --------- 600 -------- 11/12 ----------   6  ------------ 8 7  --------- 600 -------- 13/12 ----------   6  ------------ 7 8  --------- 500 -------- 15/12 ----------   5  ------------ 7 9  --------- 500 -------- 19/12 ----------   5  ------------ 7   Then I need the following set of values : 1. day_id1 -- Day 7,      points1 ---- 6,          days_diff1 -- (9-7 = 2)  . // Difference between the latest day and day_id1 2. day_id2 -- Day 6,      points2 ---- 8,          days_diff2  -- (9-6 = 3) 3. day_id3 -- ....   and so on for other points.    Thanks all !

Hi I am very new to PHP & Mysql. I am trying to insert values into two tables at the same time. One table will insert a single row and the other table will insert multiple records based on user insertion. Everything is working well, but in my second table, 1st Table ID simply insert one time and rest of the values are inserting from 2nd table itself. Now I want to insert the first table's ID Field value (auto-incrementing) to a specific column in the second table (only all last inserted rows).   Ripon.   Below is my Code:

<?php



$con = mysql_connect("localhost","root","aaa");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }


mysql_select_db("ccc", $con);


$PI_No = $_POST['PI_No'];
$PO_No = $_POST['PO_No'];


$qry = "INSERT INTO wm_order_entry (
Order_No,
PI_No,
PO_No) 


VALUES(
NULL,
  '$PI_No',
 '$PO_No')";
$result = @mysql_query($qry);




$val1=$_POST['Size'];
$val2=$_POST['Style'];
$val3=$_POST['Colour'];
$val4=$_POST['Season_Code'];
$val5=$_POST['Dept'];
$val6=$_POST['Sub_Item'];
$val7=$_POST['Item_Desc'];
$val8=$_POST['UPC'];
$val9=$_POST['Qty'];
$N = count($val1);
for($i=0; $i < $N; $i++)
{


$profile_query = "INSERT INTO order_entry(Size,
Style,
Colour,
Season_Code,
Dept,
Sub_Item,
Item_Desc,
UPC,
Qty,
Order_No
) VALUES( '$val1[$i]','$val2[$i]','$val3[$i]','$val4[$i]','$val5[$i]','$val6[$i]','$val7[$i]','$val8[$i]','$val9[$i]',LAST_INSERT_ID())";
$t_query=mysql_query($profile_query);
}
header("location: WMView.php");
mysql_close($con);
?>

Output is attached.

Hello their,

I'm wanting to use PHP to check to see if a username and password match a remote RDP server. The reason I ask is because I want to verify that the information the user is giving is correct.

I'm looking though LDAP but I have no idea what I'm looking for.

To recap, I would like to login to a RDP server and return a result based on if it completed.

Thank-you for reading
Paul
P.S Sorry for the bad English, I seemed to forgot how to spell some words and have had to replace them with longer sentences

ok so i can get this to work

so i want to check if there is a video on inside my db if there is no video and nothing happens but if there is i want it to echo video

Code: [Select]

<?php

if($video == ""){

}else{

echo "VIDEO";

}

?>

Suppose i have a table with around 10 entries in which one column contains the id and the second column contains a checkbox...

If a checkbox a selected and the button (below the table) is pressed then i want to delete the columns corresponding the checked checkboxes....

I am not getting how sgould i pass the get variable on the link of the button???

-Pranshu Agrawal
pranshu.a.11@gmail.com

I am unable to execute mysql_num_rows properly in this program.
Code: [Select]
<?php
$link=mysql_connect("localhost","root","");
$db = mysql_select_db("myDB",$link);
$result = mysql_query("SELECT * FROM jobs WHERE jobType=abc"); 
$num = mysql_num_rows($result);
echo "Found $num records";
?>
error is mysql_num_rows() expects parameter 1 to be resource

Hello,

I have created a little voting script for my site. The insertion code into the MySQL databse when they vote is very simple:

$ipaddress = addslashes($_POST['ipaddress']);
$theid = addslashes($_POST['theid']);
$gamert = addslashes($_POST['gamert']);
$serveron = addslashes($_POST['serveron']);

$db = mysql_connect("localhost", "username", "password");

mysql_select_db("thedb",$db);

mysql_query ("INSERT INTO voting (theid,ipaddress,gamert,serveron2) 
                VALUES
('$theid','$ipaddress','$gamert','$serveron')
");

Obviously I only want them to be able to vote once. What is the best way to do a check of the IPs already in the database and check against theirs before submitting?

Thanks.

Not sure how to do this at all... I'm creating a page with a form to edit existing info in two tables in the database. I need to pre-check some checkboxes and I don't know how. The first query query_selectguest below puts data into the form just fine. query_checked looks in the second table for any rows that match the discount id. Then further down in the form, I have a php snippet that pulls all the classes from a third database. As I'm echoing these out to the page, I want them to be pre-checked if they match a result found in $result_checked

here's what I have right now...

Code: [Select]
$query_selectguest = 'SELECT * FROM tbl_discount WHERE discount_id='.$passedID;
$result_guest = mysql_query($query_selectguest);
$g_row = mysql_fetch_array($result_guest);

$query_checked = 'SELECT * FROM active_discounts WHERE disc_id='.$passedID;
$result_checked = mysql_query($query_checked);
$h_row = mysql_fetch_array($result_checked);

?>

<form name="form1" method="post" action="update_discount.php" onSubmit="return validate_form()">

<input name="discount_name" type="text" class="input" id="subject" size="50" maxlength="100" value="<? print $g_row['discount_name'] ?>">
<input name="discount_amount" type="text" class="input" id="subject" size="5" maxlength="3" value="<? print $g_row['discount_amount'] ?>">

<!-- here's what I'm concerned with -->

This discount applies to these classes:<br>
         
           <?php
$quer4=mysql_query("SELECT workshop_id, workshop_title FROM tbl_workshops order by workshop_title");

while($row4 = mysql_fetch_array($quer4)) {
echo "<input type='checkbox' name='workshop_link_1[]' value='".$row4[workshop_id]."'>".$row4[workshop_title]."<BR>";
}

 ?>