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PHP - Coding Style
Hi,
I use the following style for building my websites, I understand this is a fairly common style and was wondering if there is a name for it? Code: [Select] <?php include ('application.php'); include ('cms_config.php'); include ('templates/header.php'); switch ($_GET['action']) { case "home" : display_home(); break; case "services" : display_services(); break; case "testimonials" : display_testimonials(); break; case "contact" : display_contact(); break; default : display_home(); break; } include ('templates/footer.php'); // Function list // Display home page function display_home(){ $qid = mysql_query('SELECT * FROM testimonials ORDER BY RAND() LIMIT 0,1;'); include('templates/home.php'); } // Display services page function display_services(){ include('templates/services.php'); } // Display testimonials page function display_testimonials(){ $qid = mysql_query('SELECT * FROM Testimonials'); include('templates/testimonials.php'); } // Display home page function display_contact(){ include('templates/contact.php'); } ?> Similar TutorialsI am making a simple shopping cart. To add a product, I use this code: Code: [Select] <?php if (isset ($_GET['action']) && $_GET ['action'] == 'add' ) { $id = intval($_GET['id']); $_SESSION['cart'][] = $id; } $cart = $_SESSION['cart']; if (!$cart) { echo "No product in cart."; } elseif ($cart) { foreach ($_SESSION['cart'] as $id) { echo $id; } } ?> <A href="index.html?action=add&id=1">Add to cart</A> I am going to be selling t-shirts, I'm going to need a size along with the product ID, so now I need to add a 'size' value. I've tried simply doubling up on the code above with this code, but it isn't working. I was wondering if I am going the right way about it? Code: [Select] <?php if (isset ($_GET['action']) && $_GET ['action'] == 'add , size') { $id = intval($_GET['id']); $_SESSION['cart'][] = $id; $size = intval($_GET['size']); $_SESSION['cart'][] = $size; } $cart = $_SESSION['cart']; if (!$cart) { echo "No product in cart."; } elseif ($cart) { foreach ($_SESSION['cart'] as $id) { echo $id; } foreach ($_SESSION['cart'] as $size) { echo $size; } } ?> <A href="index.html?action=add&id=1&size=sizel">Add to cart</A> Hello guys, I am a beginner in PHP, so please be gentle. I am building this website for a friend of mine. This website is made up by HTML/CSS. i.e., I have a page made with HTML & CSS. there are a few menus on the page. say Home, About Us, Contact Us, etc., Now I want to separate the page elements (like header/footer) from the page so as its easy to work on. the source is something like this Code: [Select] <HTML> <HEAD> <TITLE> My Page </TITLE> <LINK REL="STYLESHEET" HREF="./mystyle.css" TYPE="text/css" /> </HEAD> <BODY> <DIV ID="wrapper"> <DIV ID="header"> <DIV ID="logo"> <UL ID="menu"> <LI> <A HREF="./index.php"><SPAN>Home</SPAN></A> </LI> <LI> <A HREF="./login.php"><SPAN>Login</SPAN></A> </LI> <LI> <A HREF="./contactus.php"><SPAN>Contact Us</SPAN></A> </LI> </UL> <DIV ID="date"> <?php echo Date("d M Y");?> </DIV> </DIV> </DIV> <DIV ID="bodywrapper"> <DIV ID="main"> <DIV ID="content"> THIS IS A TEST! </DIV> </DIV> </DIV> <DIV ID ="clearfooter"></DIV> </DIV> <DIV ID="footer"> © <?php echo date("Y");?> </DIV> </BODY> </HTML> now I will have my content in the DIV called 'content'. now I have separated this one page into three different pages. like this: header.php Code: [Select] <HTML> <HEAD> <TITLE> My Page </TITLE> <LINK REL="STYLESHEET" HREF="./mystyle.css" TYPE="text/css" /> </HEAD> <BODY> <DIV ID="wrapper"> <DIV ID="header"> <DIV ID="logo"> <UL ID="menu"> <LI> <A HREF="./index.php"><SPAN>Home</SPAN></A> </LI> <LI> <A HREF="./login.php"><SPAN>Login</SPAN></A> </LI> <LI> <A HREF="./contactus.php"><SPAN>Contact Us</SPAN></A> </LI> </UL> <DIV ID="date"> <?php echo Date("d M Y");?> </DIV> </DIV> </DIV> footer.php Code: [Select] <DIV ID ="clearfooter"></DIV> </DIV> <DIV ID="footer"> © <?php echo date("Y");?> </DIV> </BODY> </HTML> and index.php Code: [Select] <?php include_once('header.php');?> <DIV ID="bodywrapper"> <DIV ID="main"> <DIV ID="content"> THIS IS A TEST </DIV> </DIV> </DIV> <?php include_once('footer.php');?> Is this the right way to code? I am worried because I have to keep in mind the safety of the website as I have to include a basic login module to this. is there any other style to write this? please do let me know.. thanks Hello.
I'm in need of help when it comes to page rendering, is it good practice to have own html file for each controller and controller->method OR 1 view file for each controller and then dynamically change content depending on the method?
My structure is like so:
controllers methods
-------------
services-> repair, car glass.....
info-> contact, about me.....
What is the best or good practice to handle the content in the view? The content is always the same.
Thanks in advance.
<?
// Bank Version 1.0.0 21-05-2014 Desmond O'Toole.
include ("secure/SecureFunctions.php");
include ("secure/SecureFunctionsLibAdmin.php");
session_start();
Session_Init();
$page = "Bank_EE Doc";
define ('hostname16', 'xxx'); // Des-otoole.co.uk
define ('username16', 'xxx');
define ('password16', 'xxx');
define ('database16', 'xxx');
function myErrorHandler($errno, $errstr, $errfile, $errline)
{
switch ($errno) {
case E_USER_ERROR:
$_SESSION['MyError'] = "Gotcha: <br>$errstr<br>$errfile<br>$errline";
mailtoX('Error', $errstr,$_SESSION['MyError']);
$redirect = "Location: myerror.php";
header($redirect);
exit(0);
break;
case E_USER_WARNING:
echo "This is your last warning";
break;
case E_USER_NOTICE:
echo "This is your final warning";
break;
default:
echo "Just go away";
break;
}
/* Don't execute PHP internal error handler */
return true;
}
$old_error_handler = set_error_handler("myErrorHandler");
function connectDB($db)
{
$host = hostname16;
$user = username16;
$pass = password16;
$data = database16;
if(!$link = @mysql_connect($host, $user, $pass))
trigger_error('Can\'t connect to server: ('. $db . ')', E_USER_ERROR);
if(!$database = @mysql_select_db($data, $link))
trigger_error('Can\'t select database on: (' . $db . ')', E_USER_ERROR);
}
connectDB(CURRENT_DB);
echo "Hi there";
?>
Hi this coding works on another website although I have reduced it down here for clarity. I have had my website moved to another server and I can't connect now.If there is a better way? I was given this coding from someone on this website about 4 years ago. I didn't want to use a strait connect because when there was difficulty connecting to the database I received an error giving me and any hacker all the details of the database server. This was to be a more controlled access. Edited by ignace, 09 June 2014 - 01:34 PM. onkeydown="this.style.fontStyle='normal';"How can I add color: #000; to this? Thanks,
Background:
Question:
My experience: Code Examples:
function getInfo(ProductNumber){
$.ajax({
url:'Ajax-PHP-Page.php?ProductNumber='+ProductNumber,
success: function(html) {
document.getElementById("my_div").value = '';
document.getElementById("my_div").value = html;
}
});
}
function getInfo(ProductNumber) {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("my_div").value = this.responseText;
}
};
xmlhttp.open("GET","Ajax-PHP-Page.php?ProductNumber="+ProductNumber,true);
xmlhttp.send();
}
Thank you!! Edited May 5, 2020 by StevenOliverHello, My wife wants to set up a PHP Powered Demerit System at her school. I have basic PHP and MySQL skills. Basically she wants a web interface where a student logs in with Student Number and Password. Demerits and merits accrue to the students as below: Coming late to school, 1 Demerit Handing an assignment late, 2 Demerits No Demerits in 3 months equals 1 Merit assigned Student suspended after 6 / more Demerits Parent / Gaurdian emailed The student will see the table below once logged in: Student Name Student ID Date Action Demerit Merit Total A123 2012/02/26 Late Sign In 1 0 1 2012/02/28 Late Assignment 1 0 2 2012/05/29 3 month Merit earned 0 1 1 2012/06/08 Late Assignment 2 0 3 2012/06/10 Late Assignment 2 0 5 2012/06/12 Late Assignment 2 0 7 Student suspended Send email to parent/gaurdian I would really appreciate any help you can offer in terms of what PHP code to include in the HTML doc as well as how many MySQL Tables to setup as well as where to store which data? Thanks, Ishvir Hi guys,
I am needing some help of how to place the coding as I can not get it to work.
--
Basically I am building a website for the local motorclub and want some code that will "add up" each persons results.
Here is what I have come up with but it does not work;
<?php $total = mysql_fetch_array("SELECT cat1 + cat2 + cat3 + cat4 + cat5 + cat6 AS total FROM results") ?>
<?php
$cautotest_results = mysql_query("SELECT * FROM results WHERE cat ='1' ORDER BY cattotal DESC");
if(mysql_num_rows($cautotest_results) == '') { echo "<p>No Results Available."; } else {
echo "<table width=\"800\" border=\"0\" cellpadding=\"2\" cellspacing=\"2\" class=\"greywritinglight\" align=\"center\">
<tr align=\"center\">
<td>Competitor</td>
<td>Vehicle</td>
<td>Class</td>
<td>Skipton</td>
<td>Weston</td>
<td>King Bros</td>
<td>Normans</td>
<td>Norwood</td>
<td>Uniroyal</td>
<td>Total</td>
</tr>";
$x=1;
while($results_row = mysql_fetch_array($cautotest_results))
{
if($x%2): $rowbgcolor = "#FFFFFF"; else: $rowbgcolor = "#EEEEEE"; endif;
echo "<tr align=\"center\" bgcolor=\"" .$rowbgcolor. "\">";
echo "<td>" . $results_row['competitor'] . "</td>";
echo "<td>" . $results_row['catvehicle'] . "</td>";
echo "<td>" . $results_row['catclass'] . "</td>";
echo "<td>" . $results_row['cat1'] . "</td>";
echo "<td>" . $results_row['cat2'] . "</td>";
echo "<td>" . $results_row['cat3'] . "</td>";
echo "<td>" . $results_row['cat4'] . "</td>";
echo "<td>" . $results_row['cat5'] . "</td>";
echo "<td>" . $results_row['cat6'] . "</td>";
echo "<td>" . $total . "</td>";
echo "</tr>";
$x++;
}
echo "</table>";
}
?>
Its the top line of coding... and the echo .total. at the bottom.
If you could please correct me I would be ever so grateful.
If you need more info please just ask. All help is appreciated.
JTM.
Edited by JTM, 17 August 2014 - 12:45 AM. Could some one please guide me to a possible script to accomplish this task.... I want to pull and display two separate things that are in two separate places and display them as one link on a page. I have figured out how to display the data to a page and also how to display the files to a page separately but need to accomplish this and join the 3 things together. I have a library table in the database that stores the product_code and product_name example: pk-pen(product_code) traditional fountain pen(product_name) ---- (this is where I need to get the data from) Then I have a folder on the server that is called library that has the pdf files in it. Each pdf file has the same name as the product_code that is in the database. example: pk-pen_ins.pdf What I need to accomplish is grabbing the product_code and product_name for the database and then go to the folder on the server and add the correct pdf file with that data and display it as a link on a page for customers to download. bee struggling with this and pasted code that i have to do each task separately but cant seem to get it all in one script to do the above. I understand that this could be asking for a lot here but I am new to this and would be forever in debt to your kindness. Thanks on this in advance So I put this in the wrong place so ill try again, I need to write a code to add the price of five items with a subtotal, with tax, and then a grand total. What is the best way to do this? Every way I have tried isnt working PLEASEEEEEE HELP!!! Using crimson editor How can I get it so the following work: echo utf8_decode($xml->healings[0]->$xmla[0]->descrip[0]); // NOT work echo utf8_decode($xmlb); // NOT work <?php $xml = simplexml_load_file('extra.xml'); $xmla = "test"; $xmlb = "$xml->healings[0]->".$xmla."[0]->descrip[0]"; echo utf8_decode($xml->healings[0]->test[0]->descrip[0]); // works echo utf8_decode($xml->healings[0]->$xmla[0]->descrip[0]); // NOT work echo utf8_decode($xmlb); // NOT work ?> Im making an E-learning system that when Student registers the Teacher will approve.. So i've got here a code that outputs all those who registered via Checkbox. Code: [Select] <form name="formapprove" method="POST" action="valval3.php" > <div id="apDiv12"><input type="image" src="images/Approve.png" name="approve" value="approve" width="170" height="35" border="0" > </div> <div id="apDiv11"> <input type="image" src="images/reject.png" name="reject" width="170" height="35" border="0" value="reject"> </div> <div id="apDiv14">'; $host="localhost"; $username="root"; $password=""; $db_name="dbreg"; $tbl_name="account"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); echo "<table border=\"5\" width=\"400\" >"; echo "<tr><th>List of Student to be approve</th>"; if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)) { echo "<tr><td>"; echo "<input type='checkbox' name='list[]' value='".$row['Username']."'>".$row['famname'].",".$row['gname']. ",".$row['mname']. ".<br/></td>"; echo "</tr></input>"; } } else { echo "<tr><td align=\"center\"> No Student to be Approve / Reject </td></tr>"; } echo' </form> Then the file "valval3.php" will be the one that will save the variables in my database.. Code: [Select] <?php session_start(); if(isset($_SESSION['uname2']) || ($_SESSION['section'])){ $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } if(isset($_POST['approve_x'], $_POST['approve_y'])) { mysql_select_db("dbreg", $con); $uname = $_SESSION['uname2']; $sec = $_SESSION['section']; $sql="SELECT * FROM account where sec='$sec'"; $result=mysql_query($sql); if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)) { $fullname = "" .$row['famname']. ", " .$row['gname']. " " .$row['mname']. "."; } foreach ($_POST['list'] as $checkbox) { $sql="SELECT * FROM account WHERE sec='$sec'"; } $result=mysql_query($sql); if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)) { $username = $row['Username']; $password = $row['Password']; $gname = $row['gname']; $mname = $row['mname']; $famname = $row['famname']; $sec = $row['sec']; $studnum = $row['studnum']; $fullname = "" .$row['famname']. ", " .$row['gname']. " " .$row['mname']. "."; $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $gname = stripslashes($gname); $famname = stripslashes($famname); $gname = mysql_real_escape_string($gname); $famname = mysql_real_escape_string($famname); $mname = stripslashes($mname); $mname = mysql_real_escape_string($mname); foreach ($_POST['list'] as $checkbox) { mysql_query("INSERT INTO dbaccount (Username, Password, gname, famname, mname, sec, studnum, fullname) VALUES ('$username', '$password', '$gname', '$famname', '$mname', '$sec', '$studnum', '$checkbox')") or die(mysql_error); mysql_query("DELETE FROM account WHERE sec='$sec'") or die(mysql_error); } echo '<script type="text/javascript"> {alert("Approved!");} </script>'; echo '<meta http-equiv="REFRESH" content="0;url=approvereject2.php">'; mysql_close($con); } } else { echo '<meta http-equiv="REFRESH" content="0;url=approvereject2.php">'; } }elseif(isset($_POST['reject_x'], $_POST['reject'])) { mysql_select_db("dbreg", $con); foreach ($_POST['list'] as $checkbox) { $sql="SELECT * FROM account WHERE sec='$sec'"; } $result=mysql_query($sql); if(mysql_num_rows($result)) { foreach ($_POST['list'] as $checkbox) { mysql_query("DELETE FROM account WHERE sec='$sec'") or die(mysql_error); } echo '<script type="text/javascript"> {alert("Rejected!");} </script>'; echo '<meta http-equiv="REFRESH" content="0;url=approvereject2.php">'; } else { echo '<meta http-equiv="REFRESH" content="0;url=approvereject2.php">'; } } else { echo '<meta http-equiv="REFRESH" content="0;url=approvereject2.php">'; } } } else { header("location:failunautho.php");; } ?> I tested my codes. Its only working if theres only 1 user registered ( which means one checkbox would appear in page) But when i tested to have 3 users registered and not yet approve, There would be an error saying.. Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 49 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 49 $username = mysql_real_escape_string($username); <-- line #49 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 50 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 50 $password = mysql_real_escape_string($password); <-line #50 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 54 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 54 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 55 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 55 $gname = mysql_real_escape_string($gname); <-line #54 $famname = mysql_real_escape_string($famname); <-line# 55 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 58 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 58 mname = mysql_real_escape_string($mname); <-line #58 Warning: mysql_query() [function.mysql-query]: Access denied for user 'ODBC'@'localhost' (using password: NO) in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 64 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\Documents and Settings\Ken\Desktop\xampplite\htdocs\Pages\valval3.php on line 64 mysql_error VALUES ('$username', '$password', '$gname', '$famname', '$mname', '$sec', '$studnum', '$checkbox')") or die(mysql_error) <-line #64 Then still it saves 3 variables.. but all the same. Hope Someone could help me .. Hi All I am fairly new to the PHP world so please excuse my ignorance. (I am trying!) Basically I bought a commercially available PHP script and created my own script to work alongside the bought one. What happened then is that the developers of the script I bought released a new version of the software. My script no longer works and is throwing up the following error PHP Fatal error: Using $this when not in object context in C:\wamp\www\classifieds\system\core\System.php on line 175 I've worked out that the script fails on this line, in the new version of the software. $dbhost = System::getSystemSettings('DBHOST'); On review of the commercial script's coding, I noticed that where the old version used the syntax above, the new version uses a syntax as shown below $this->appContext->getSystemSettings('DBHOST'); So I went and modified my script (mismatched.php) to read as follows $dbhost = $this->appContext->getSystemSettings('DBHOST'); But im now getting the following errors PHP Parse error: syntax error, unexpected T_REQUIRE_ONCE, expecting T_FUNCTION in C:\wamp\www\classifieds\admin\mismatched.php on line 5 I'd appreciate any ideas you may have that could help me get my script (mismatched.php) working again. Thanks again Ali I have a sql statement w/c suppose to output only those records w/c has a name of seller. But, it keeps showing all the records. Code: [Select] <?php session_start(); if(isset($_SESSION['name']) || ($_SESSION['contact']) || ($_SESSION['address']) ) { ini_set('display_errors', 0); $name = $_SESSION['name']; $contact = $_SESSION['contact']; $address = $_SESSION['address']; ?> <div id="apDiv1"> <?php echo "Name : $name"; echo "</br>"; echo "Name : $contact"; echo "</br>"; echo "Name : $address"; ?> <div id="apDiv2"> <?php $host="localhost"; $username="root"; $password=""; $db_name="feedbackdb"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM Feedbacks WHERE Seller = $name"; $result=mysql_query($sql); echo "<table border=\"5\" width=\"600\" >"; echo "<tr><th>Feedbacks</th><th>From</th><th> To </th>"; if(mysql_num_rows($result)) { while($row = mysql_fetch_assoc($result)) { echo "<tr><td>"; echo "" .$row['Feedback']."<br></td>"; echo "<td>".$row['From']."<br></td>"; echo "<td>".$row['Seller']."<br></td>"; echo "</tr>"; } } else { echo "<tr><td align=\"center\"> No Feedback</td></tr>"; } ?></div> </div> <?php } else { header("location:loginpage.php");; } ?> Hi I am beginning the first stages of a tumble log and am having some trouble, this works. <?php $connection = @mysql_connect('localhost','admin','asdf'); if(!$connection) ( die('Could not connect to the server!' .mysql_error()) ) ?> but if I add the following I get an error: <?php $connection = @mysql_connect('localhost','admin','asdf'); if(!$connection) ( die('Could not connect to the server!' .mysql_error()) ) if(!mysql_select_db('tumblelog')) ( die('Could not connect to database') ) ?> This is the error: Quote Parse error: syntax error, unexpected T_IF in E:\AppServ\www\tumblelog\database.php on line 10 I also tried this to solve the problem: <?php $connection = @mysql_connect('localhost','admin','glock123'); if(!$connection) ( die('Could not connect to the server!' .mysql_error()) ) $db = mysql_select_db('tumblelog')) if(!$db) ( die('nope') ) ?> that only gives me this error: Quote Parse error: syntax error, unexpected T_VARIABLE in E:\AppServ\www\tumblelog\database.php on line 9 this doesn't work. Please help fix this. $result1=mysql_query("SELECT * FROM applicants WHERE username = '$user' AND status = 'PendingXCD'"); if(mysql_num_rows($result1)) { $login = "&err=In progress."; echo($login); } else { $result=mysql_query("SELECT * FROM comp WHERE username = '$user' AND password ='$pass'"); if(mysql_num_rows ($result) == 0) { $login = "&err=Please retry."; echo($login); } else { $row = mysql_fetch_array($result); $user=$row['user']; $pass=$row['pass']; $login = "$user=" . $user . "$pass=" . $pass . "&err=Successful."; echo($login); } ?> I'm trying to update a field in my MySQL but instead of updating this makes the field BLANK. my code: $SomeVar = $_POST['finco']; mysql_query("UPDATE c_applicants SET streetz='$cts' WHERE username = '".$SomeVar."'"); $result = mysql_query($query); I have a small mp3 script and its running accurately ...i want to check the mp3 URL before playing it whether the mp3 link active or broken ....how to check the link is active or broken in php thanks Hai everbody; I am finishing my site to open for public but before i have a small problem! Actually I am using SMF forum software! I need this help very urgently ! Just need to add login (logout) & register in the template menu!! Please guys try to help me out !! I will join the index_template.php file for you to make the correction ! (sorry for my bad english) Thank You a LOT in advance Daya Is there a way i can make a php code for making a lesson then upload to my made system? Im newbie here. so basically, i need to make an e-learning system that lets the user make a lesson then upload it so that other user can view their made lesson.. Someone help me pls. |
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