PHP - Calling A Class Function With Var

Hi,

I need to be able to call a class based on variables.  E.G.

I would normally do:
Code: [Select]
$action = new pattern1()
but i would like to be able to do it dynamicaly:
Code: [Select]
$patNum = 1;
$action = new pattern.$patNum.()
Im wondering if that's possible?  If so what would the correct syntax be?

Many Thanks.

I have a PHP config file called config.php.

inside the file is simular to this:

Quote

<?php
class JConfig {
   var $offline = '0';
   var $editor = 'tinymce';
   var $list_limit = '20';
}
?>


From another file, i have included config.php, but how do I call $editor to get "tinymce"?

Thanks

This is probably a quick one. I am pretty new to OOP, in fact somewhat a novice. I am working a lot more with objects lately as my previous "flat" php experience doesn't allow me to create clean and expandable applications. Of course though, questions will always pop up (that's what you guys are for?)

One concept I am having trouble understanding, is the method to call a class.

What is the difference between?:

Code: [Select]
<?php $cat = new class(); ?>
and just simply:

Code: [Select]
<?php  new class(); ?>
Both appear to have the same output from my small amount of practice, but the first way seems strange to me. Being that I am very new to OO PHP, the first way looks like it is just defining a var. But in reality it is calling the class and running it? This seems very backwards to me and I am having a hell of a time understanding it. I am aware that the first way seems to be the "proper" way, but just can't fathom it.

Could someone explain this to me a little further?
thanks much,

I am working on a site that was made a while ago and on a custom page I am making I am needing to call up variables and my brain is too fried to think up the solution for this.  The standing code is this:

class site{
var $name = 'Site';
var $data = 'on';
{

What I need to do is callup the variables, such as $name, as simple as possible.  How would I do this?

Does anyone know if it's possible to call a class with an arbitrary number of variables?  I'll explain what I mean.
Here is my class construct definition:
Code: [Select]
function __construct($file, $outFile = 'newpdf.pdf', $fontSize = 70, $alpha=0.6, $overlayMsg = 'N O T  F O R  S H O P', $degrees = 45) {
I know that I have to pass over the $file variable for it to work now.  But can I create the class passing just the $file var and the $overlayMsg var?  Everything else I would want to leave as default.  How would I do that?
Thanks
Mike

Hi

How do I turn this:
Code: [Select]
if($LCname=='Business_solutions'){
$newChild  = Business_solutions::find_by_id(1);
}

In to something like this:
Code: [Select]
$newChild  = $LCname::find_by_id(1);


I'm calling lots of class's, and want to make it more dynamic.
The 2nd example would be perfect, but that does not work.

Is there an alternative?

Thanks

I am calling an object from another class in the constructor of first class but when I call it in another function it does not access it's object. Here is the code.
Code: [Select]
<?php
/* This is controller.php used to control the flow of data between view.php and 
model.php. This file cotains all the controlling mechanism of the data 
It was created on 11th Feb 2011 By Narjis Fatima for an Open Source Project and
contains all the includes to the database etc.
*/
include ("view.php");
include ("functions.php");


$name = stripslashes($_GET['username']);
$email = stripslashes($_GET['email']);
//echo "in controller.php";
check_validate_input($name, $email);
$newUser = new controller($name, $email);
$action=$_GET['t'];
$newUser->display_view($action);


class controller
{
public $my_model;    //is an object of model class
public $user_info;//=array('id' , 'username' ,'role','email','interests','location', 'homepage');
    function __construct($name,$email)
    {
  
    $my_model = new model();
    $user_info =  $my_model->check_members($name,$email); echo "<pre>";
    print_r  ($user_info);

    }
    function __destruct()
    {
    }
    function display_view($token)
    {
    echo "In display function";
    echo "<pre>";
    print_r  ($user_info);
    if ($this->user_info == NULL)
    {
        if (($token=="register"))
        {
          show_registration_form();
        } 
        else{   
          show_mailing_form();  
        }
    }
    if ($this->user_info['role'] == "admin")
    {
         $myView = new view();
         $myView->view_admin_menu();
    }
     if ($this->user_info['role'] == "user")
    {
         $myView = new view();
         $myView->view_user_menu() ;
    }
    }//close of function display_view()
} 



/* name and email cominfg from index.php would be checked by the controoler class 
to be checked if it a vaild name and email. The database would be connected n the 
model.php*/
  
?>

The code for model.php is as follows
Code: [Select]
<?php
//This is model.php created on 10th Feb 2011  .It deals with daytabase connection
//
//By NArjis Fatima
//For the project of EDUForge an Open Source Software 
//include ("register.php");
class model{
public $dbh;
public $user_arr=array('username','password','email','location','interest','homepage');
//cunstructor of model class

//function to connect to database
function __construct(){
          try{
    $this->dbh = new PDO("mysql:host=localhost;dbname=phpfaqproject",'root','');
//echo "connected";
      }
  catch(PDOException $e){
  echo $e-> getMessage();
} 
}
public function check_members($username,$email)
{
   //get_connected();
   
   
   $sql = "SELECT * FROM account WHERE (username='" .$username ."' AND email='"
      .$email."')";
       $sth = $this->dbh->prepare($sql);
      $sth->execute();
  
    
    $result = $sth->fetch();
   /* echo('<pre>');        
    print_r($result);*/
    return ($result);
      
}
 public function insert_data($user_info)
 {
 //$user_info = $user_in;
 //$dbh;
 try{
$dbh = new PDO("mysql:host=localhost;dbname=phpfaqproject",'root','');
//echo "connected";
}
catch(PDOException $e){
echo $e-> getMessage();
} 
         $dbh->exec("INSERT INTO account (username, userpassword, email, role, location, interest, homepage)
       VALUES ('" .$user_info['username']."','".$user_info['password'] 
      ."','".$user_info['email']."', 'user','".$user_info['location']."','".$user_info['interests']
      ."','".$user_info['homepage']."')");
}
 
}
?>


Please somebody help me. I am really stuck.
I am also sending my attachment.

I am calling my class constructor with the following code
class controller{
function _construct($name,$pass){
 session_start();
 get_model_class($name, $pass);
 echo "I\'m in controller";

}
} 
function get_model_class($username, $password){
$my_model = new  model();  
$my_model->check_users($username,$password);
}


$username = $_POST['username'];
$password = $_POST['password'];
echo "in controller.php";
$newUser = new controller($username,$password);

but it is not entering the constructor

Dear all ,

i am trying the following :

i have a class named ACCOUNT with many properties in .some of these properties are array , it is like this :
Code: [Select]
class ACCOUNT
{

    PRIVATE $DB_LINK;
    PRIVATE $COMP;
    PRIVATE $BRANCH;
    PRIVATE $CURRENCY;
    PRIVATE $GL;
    PRIVATE $CIF;
    PRIVATE $SL;
    PRIVATE $EXIST;
    PRIVATE $STATUS;
    private $ACCOUNT_NAME=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>'');
    private $ACCOUNT_BALANCE =ARRAY('FC_YTD','CV_YTD','CV_BAL','YTD_BAL','BLOCKED_CV','BLOCKED_FC');
    private $CY_NAME=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>'');
    private $ACCOUNT_NAME_USR=ARRAY("LA"=>'',"LE"=>'',"SA"=>'',"SE"=>'');
    private $LEDGER_NAME= ARRAY("LA"=>'',"LE"=>'');



i have created the following method to call any property

[code]    FUNCTION GET_SPECIFEC_ATT($ATT,$LANG)
    {
    $ATT=$ATT."['L$LANG']";
    ECHO $this->$ATT;

    }
but i am getting the below error :
Notice:  Undefined property: ACCOUNT::$BRANCH_NAME['LA'] in D:\wamp\www\EBANK\account.class on line 186

if i used this :
Code: [Select]
    echo $this->BRANCH_NAME['LA'];
it is working fine .
and the method is working fine i can iam trying to call property which is NOT an array.


Can you please help me in what iam doing wrong ?


Thanks in advance

I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous.

class locationbox

{
   function location()
   {
   
   
   $databaseconnect = new databaseconnect();
         $databaseconnect -> connection();{

$result = mysql_query("SELECT * FROM locations");

while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in
  {
  echo "<option>" . $row['location'] . "</option>";
    }
   
}
}}

Hi all,

I have two classes. Registration and Connection.

Inside a registration.php I include my header.php, which then includes my connection.php...

So all the classes should be declared when the page is loaded.

This is my code:


registration.php:

<?php include ('assets/header.php'); ?> 
        
    <?php
        class registration{                    
            public $fields = array("username", "email", "password");
            public $data = array();
            public $table = "users";
            public $dateTime = "";
            public $datePos = 0;
            public $dateEntryName = "date";
            
            function timeStamp(){
                return($this->dateTime = date("Y-m-d H:i:s"));
            }
            
            function insertRow($data, $table){      
                    
                    foreach($this->fields as $key => $value){
                        mysql_query("INSERT INTO graphs ($this->fields)
                        VALUES ('$data[$key]')");
                    }
                    
                    mysql_close($connection->connect);
            }
            
            function validateFields(){
            
                $connection = new connection(); 
                $connection->connect();
                        
                foreach($this->fields as $key => $value){
                    array_push($this->data, $_POST[$this->fields[$key]]);
                }
                $this->dateTime = $this->timeStamp();
                array_unshift($this->data, $this->dateTime);                
                array_unshift($this->fields, $this->dateEntryName);   
                
                foreach($this->data as $value){
                    echo "$value";
                }
                
                $this->insertRow($this->data, $this->table);
            }
        }
        
        $registration = new registration();
        $registration->validateFields();
    ?>

<?php include ('assets/footer.php'); ?>



At this point I cannot find my connection class defined on another included/included page.



                $connection = new connection(); 
                $connection->connect;





config.php (included within header.php)

<?
    class connection{ 
        public $dbname = '**';   
        public $dbHost = '**';
        public $dbUser = '**';
        public $dbPass = '**';
        public $connect;
        
        function connect(){
            $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql');
            mysql_select_db($this->dbname, $this->connect);
        }
    }
?>



Any ideas how to call it properly?

Question 1) Is the only and proper way to call a parent function "parent::function()"?  Are there other/better ways from within a child function?

Question 2) What are the deciding factors for when to make a function or attribute static?  How do you make that decision?  Assuming 5.3...

Thanks.

This is a bit of a more advanced question so I am hoping there are some advanced programmers online at this time . Anyways basically I want to be able to "queue" functions from a class in a single call and am wondering if I am doing it correctly or if there is a better way to do it. Here is my code:


<?php
class test {
     private static $one;
     private static $two;
     private static $three;

     public function callOne($val){
          $one .= $val;
          return $this;
     }
     
     public function callTwo($val){
          $two .= $val;
          return $this;
     }

     public function callThree($val){
           $three .= $val;
           return $this;
     }

     public function print(){
          echo $this->one.' '.$this->two.' '.$this->three;
     }
}
?>


now when I want to call this I can do:

$test = new test();
$test->callOne('one')->callTwo('two')->callThree('three');
$test->callOne('another one');
$test->print();


Is there a better way to do this or is there a different method of doing this? Just wanna make sure I am doing it right lol.

I am using simple machines forum, and by placing a link to ssi.php in the top of my php page Code: [Select]
<?php require_once('/forum/SSI.php');?>I am able to use some ssi functions. My problem is calling another function from within a function. My first function is this:
Code: [Select]
<?php

$allowed_groups = array(1,5);
$can_see = FALSE;
foreach ($allowed_groups as $allowed)
if (in_array($allowed, $user_info['groups']))
{
$can_see = TRUE;
break;
}

if ($can_see)
{
echo '
<div>
this is text that i want certain groups to see
</div>';
}
else
{
//message or section to show if they are not allowed.
echo 'this is text that i dont want certain groups to see';



}
?>
This is my second function:
Code: [Select]
<?php ssi_welcome(); ?>
I want to put the second function inside the first function, like so:
Code: [Select]
if ($can_see)
{
echo '
<div>
<?php ssi_welcome(); ?>
</div>';
this just gives me the "<?php ssi_welcome(); ?>" displayed on the actual site, it is not calling the separate function.

I have tried different approaches, e.g. $function ssi_welcome;  but all it does is display this as text as well..

Please can some one point me in the right direction. Thank you

Hi, I got a little problem with calling a PHP function from a href.
I got my site all set up, and am calling the function like this:

Code: [Select]
<?php echo '<a href="'.changeRecentPosts().'" class="image">' ?>
This does indeed work, but it calls the function every time I refresh my page.. Which isn't the effect I was trying to achieve.

I tried to change it to : Code: [Select]
<?php echo '<a href="#" onClick="'.changeRecentPosts().'" class="image">' ?> But that didn't work either.

It also seems it only calls it when I refresh my page, but never when I click it (I guess because PHP is handeled before HTML or something similar?).

If you can think of any way (even in AJAX, or whatever other language...) feel free to, I think I can figure it all out.

Thank you!