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PHP - Syntax Question
Code: [Select]
<form action="<?= $_SERVER['PHP_SELF'] ?>" method="post"> <input type="submit" name="submit" value="Refresh" /> </form> the above works fine for a refresh button ... but does not if I replace <? with <php? Similar TutorialsHi,
I'm very new to PHP, 2 days in fact, but I've done some programming in other languages. I'm trying to do something pretty basic here. I've inherited a site built on WordPress and I'm trying to override one of the php files contained in a wordpress plugin to do what I want.
I have this line:
<label>
<?php if ( ! $account_required ) echo '<small>' . __( '(optional)', 'wp-jm' ) . '</small>'; ?>
</label>
I understand what the code is doing, if condition is false, then output the HTML <small> tag, I want to add and else condition to the above, that outputs the word "required" in place of where the word optional is. So if $account_required = false then shows the optional in parenthesis as it does now, otherwise I want to show the word "required" in the parenthesis. Super simple, but just can't get the syntax quite right.
Also, can someone explain the double underscore part, specifically this: __( '(optional)', 'wp-jm' ) I understand in PHP periods are used to concatenate, but what is the leading double underscore right before the word "optional" in parenthesis? it's as if there is some function being called or referenced. The end result when the HTML is rendered is "(optional)", but what's up with the leading underscore and the reference to "wp-jm" I assume that there is some plugin or something...
Any help appreciated.
Thanks....
Edited by westside, 11 September 2014 - 05:30 PM. Quick question, When I run the code below I get an undefined index error for the array. If I define all the indexes I have no problem making it work correctly. I thought writing it like I did below would define the indexes as they are needed. What am I doing wrong? Thanks for looking, $call_data = array(); if($call_segment['did_digits'] == '3300'){ //Check if call was answered if($call_segment['answered'] == 'No'){ $call_data['3300']['abandoned'] ++; } else{ if(in_array($call_segment['finished_on'],$phoneroom_ext)){ $call_data['3300']['phoneroom'] ++; } elseif(in_array($call_segment['finished_on'],$anoka_ext)){ $call_data['3300']['store'] ++; } } } I often see the colon ( : ) being used in syntax however, no amount of searching through my text books or checking php.net reveals to me exactly what this is used for, when it is used and the exact definition of it's value. Intuitively it seems to mean ' or ' but I can't be sure when || is the proper operator for 'or' Can anyone point me towards a url for a succinct explanation ? thanks VJ I have a query: $query ="select * FROM telephone_admin where name Like ' ".$_GET['answer']." ' "; I would like to add % before and after so that the query will search for result which contains the PHP variable $_GET['answer'] before or after, but the problem is how can I add % before or after ' ".$_GET['answer']." ' within the query?? Thanks! Hi all, new to PHP and had a syntax question. I have the following code: print "<p>{$row['comment_createdate']}; This prints out a date from my sqlquery as a database datetime. I need to format it to display "Monday June 15, 2010 5:15 pm". I'm not sure how/where to attach a date() function to the record. (If it matters, the line above is inside of a loop going through several records). This really applies to attaching functions to columns within a recordset in general. Many thanks ahead of time. I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you
<title>Inputing Travel Detials</title>
<header>
<h1 align="center"> Adding Travel Detials </h1>
<body>
<p> <center><img src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
<table border="1">
<tr>
<td><a href="index.php"> Home Page </a></td>
<td><a href="administratorhomepage.html">Administrator Home Page </a></td>
<td><a href="viewhomepage.html">View Home Page </a></td>
<td><a href="Inputhomepage.html">Input Home Page </a></td>
<td><a href="traveldetials.html">Enter More Travel Detials </a></td>
</table>
</p>
<?php
include "connection.php";
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
$result = mysqli_query($dbhandle, $query)
or die(mysqli_error($dbhandle));
if($result){ echo "Success!"; }
else{ echo "Error."; }
// successfully insert data into database, displays message "Successful".
if($query){
echo "Successful";
}
else {
echo "Data not Submitted";
}
//closing the connection
mysqli_close($dbhandle)
?>
Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Hi guys
I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?
<?php
$con = mysql_connect("localhost:3306","root","password");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('sfapp', $con);
$sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')
VALUES
('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
?>
<?php
//if "email" variable is filled out, send email
if (isset($_REQUEST['pe_add'])) {
//Email information
$admin_email = $_REQUEST['pe_add'];
$forename = $_REQUEST['forename_add'];
$email = "autoreply@testing.com";
$subject = "Application";
$desc =
"Dear $forename
Thank you for submitting your online application, we will be in touch shortly.
"
;
//send email
mail($admin_email, "$subject", "$desc", "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
If you are seeing this, you need to go back and fill out the Personal Email section!
<?php
}
header("location:complete.php");
mysql_close($con)
?>
Thanks in advance.
Hi.. I create mysql syntax for query testing before i input to my php code here is my mysql code: Code: [Select] set @t = 0; set @rqty=31968; SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN @t+OUTPUT_QTY > @rqty THEN @rqty -@t ELSE OUTPUT_QTY END as qty, @t := @t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (@t < @rqty); and i attach the sample output of the above query. Now that query test is work i will input that code to my php codes. $sql = "SELECT SKUCode, Materials, Comp, Qty FROM bom WHERE SKUCode = '$SKUCode'"; $res = mysql_query($sql, $con); ($row = mysql_fetch_assoc($res)); $Materials = $row['Materials']; $Qty = $row['Qty']; $Comp = $row['Comp']; //P28 //-----Compute Req Qty and Save to table---// $ReqQty = $Qty * $POReq; // 31968 $sql = "UPDATE bom SET ReqQty = '$ReqQty' WHERE SKUCode = '$SKUCode' AND Materials = '$Materials'"; $resReqQty = mysql_query($sql, $con); $t = 0; $sql = "SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN $t+OUTPUT_QTY > $ReqQty THEN $ReqQty -$t ELSE OUTPUT_QTY END as qty, $t := $t + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '$Comp' AND ($t < $ReqQty)"; when I echo the query: I got this: SELECT LOT_CODE as code, DATE_ENTRY, CASE WHEN 0+OUTPUT_QTY > 31968 THEN 31968 -0 ELSE OUTPUT_QTY END as qty, 0 := 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = 'P28' AND (0 < 31968) then I run it to the sql and I got an error: Error Code : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':= 0 + d.OUTPUT_QTY as cumulative FROM dipping d WHERE SUBSTR(LOT_CODE, 9,4) = '' at line 1 (0 ms taken) Any help is highly appreciated Thank you so much Which of the below syntax is the better to be using? $bal = 100; if($bal > 100) { echo "you have over 100 pounds; } else { echo "you have less than 100 pounds"; } if ($bal > 100); echo "you have over than 100"; else ; echo "you have less than 100"; endif; The issue is there seems to be NO syntax error. 1. There is no relevant code before or after this line. 2. Yes, one would think a ! should be there as did I (I didn't write the code), however, even with the ! it still gives the same error. if (function_exists('gzcompress')) die(FUNCTION_NOT_FOUND); is giving me a syntax error, unexpected 'if', expecting 'function' or 'const' I am updating this code from PHP5.3 to PHP7.4 and I can't figure out what the syntax problem is since PHP allows this. I am using Eclipse PHP to do the conversion. when in a form, I wish to build a conditional that if the response to a radio button is a value of 2 (female), it will display an input requesting for users maiden name. If not 2 goes to the next input statement. Here is code I was experimenting with: <html> <body> <form action="" name="test" method='POST'> <input type="radio" id="sex" value=1 checked><label>Male</label> <input type="radio" id="sex" value=2><label>Femaleale</label> <?php $result = "value"; if ($result == 2) echo "<input type='int' id='gradYear' size='3' required>"; else echo "Not a female!" ?> <input type="submit" value="GO"> </form> </body> </html> The code passes debug, however, Not a Female is displayed. My question is - Can I do this and if so, what value do I test against id='sex' or value. I tried each one but gave the same results. I realize that $_POST[sex] would be used after the submit button is clicked. But this has me stumped. Thanks for the assis in advance. Is this proper syntax? if (($news['accounttyperaw'] !== 0) || ($news['accounttyperaw'] !== 1)) Hi, I need to append a language session to a url and I am a bit confused on how to do it. What is wrong with this? Code: [Select] <?php require_once('header_'.echo ($_SESSION['session_idioma']).'.php'); ?> Thanks Hi, I'm trying to redirect like this: Code: [Select] header("Location: PC_images_display.php?imagenupdated=true&id_categoria = $row_images_update_RS['id_categoria']"); } but the variable $row_images_update_RS['id_categoria'] is being passed and causes a 500 error...I know it must be a syntax error ut I can't figure it out... Thanks in advance Hi, i,m trying to echo a "a href" based on the language session of my page like this: Code: [Select] ?php if ($_SESSION['session_idioma'])=="eng" { echo '<a href="preordering.php"><img src="img/top_banner_'.$_SESSION['session_idioma'].'.jpg" width="744" height="182"></a>'; } { else echo '<a href="ordering.php"><img src="img/top_banner_'.$_SESSION['session_idioma'].'.jpg" width="744" height="182"></a>'; }?>but I'm getting a blank page wit no errors...must be a syntax error that I can't spot... In a piece of code like this: mysql_query("INSERT into users VALUES ('".$_POST['username']."', '".$_POST['password']."')") or die(mysql_error()); What is the difference between ('".$_POST['username'])."') (".$_POST['username']).') (.$_POST['username'].) and ($_POST['username']) ?? Will all four of these work? Does anyone know where in the PHP manual I can find explanation for these syntaxes? I'm trying to update each row in my table with $upoin. But doesn't. No errors shown but it dosen't update the database (table) with $upoin. $count1 = array_sum($count); $upoin = $count1; $query=mysql_query("SELECT * FROM table"); $rownum=mysql_num_rows($query); for($i=0;$i<$rownum;$i++) { $query=mysql_query("SELECT * FROM table LIMIT $i,1"); while($select=mysql_fetch_array($query)) { $update=mysql_query("UPDATE table SET cat_num=$upoin"); } } Help fix the code. Thanks, Ruth \-) I just came up with a line of code that I am not able to understand what's it doing. The code is: Code: [Select] function cost() { return $this->costStrategy->cost($this); } here costStrategy is a class property which holds a reference to the object of type CostStrategy class and cost() is a method defined in CostStrategy. i would like to display statistics information and show this on a map with multiple markers i have initially created for a single marker the example is at http://www.sudhakargolakaram.co.in/files/stats.php for this i have written the following in the php file echo (' <script type="text/javascript" src="jquery-1.3.2.min.js"></script> <script src="maps api key"></script> <script src="jquery.googlemaps1.01.js"></script> '); $lat="-36.847385"; $lon="174.765735"; echo(' <script type="text/javascript"> $(document).ready(function() { $("#map_canvas").googleMaps({ markers: { latitude: '); echo $lat; echo(', longitude: '); echo $lon; echo(' } }); }); </script> '); ?> this is working fine however i would like to get the values of the latitude and longitude values from mysql using select query and pass the values of latitude and longitude to the javascript code using a while loop the code to display multiple markers is <script type="text/javascript"> $(document).ready(function() { $('#map_canvas').googleMaps({ markers: [{ latitude: 37.4416, longitude: -122.1516 },{ latitude: 37.4516, longitude: -122.1616 },{ latitude: 37.4566, longitude: -122.1666 }] }); }); </script> this multiple markers is quite different to single marker as this does not have },{ for the last marker in terms of the syntax of the php code how can i write the php code so that i will get the output in the browser as mentioned above for multiple markers thanks |
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