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PHP - Echo Not Working
echo will not print out a value. I do the simple string " " and it doesn't even do that. It's just blank in my browser. I use netbeans and firefox and chrome. Any idea as to what I'm doing wrong? Simple code snippet:
<html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"/> <title>PHP Testing</title> </head> <body> <?php echo "print me"; ?> </body> </html> Thanks for any future help. Similar Tutorialshi there all. hope i can get your help. i am creating a php page that talks to mysql tabes. i want to print query into my html page inside html tags. the first echo in my code works but the one embedded inside the html code prints nothing to the page. look at my code if it helps: <html><body> <?php mysql_connect("localhost", "root", "123456") or die("Connection Failed"); mysql_select_db("man_utd")or die("Connection Failed"); $name = $_POST['members']; $query = "select * from members where username = 'burns'"; $result = mysql_query($query); while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) { echo $line['pass']; } ?> <table border="0" cellspacing="2" cellpadding="2"> <tr> <th><font face="Arial, Helvetica, sans-serif"><?php echo $line['pass']; ?></font></th> <th><font face="Arial, Helvetica, sans-serif">Value2</font></th> <th><font face="Arial, Helvetica, sans-serif">Value3</font></th> <th><font face="Arial, Helvetica, sans-serif">Value4</font></th> <th><font face="Arial, Helvetica, sans-serif">Value5</font></th> </tr> </body> </html> thanks all for any help This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=320829.0 Please help, when I run this search and enter something in the search thats not in the database, it doesnt reply with "Your query returned 0 results" as it should. I tjust stays blank Here's the section of code in question... if ($search) // perform search only if a string was entered. { mysql_connect($host, $user, $pass) or die ("Problem connecting to Database"); $srch="%".$search."%"; $query = "select * from tvads WHERE advert LIKE '$srch' ORDER BY advert, year DESC, details ASC LIMIT 0,30"; $result = mysql_db_query("cookuk_pn", $query); if ($result) { $count = 1; print "<table border=\"0\" cellpadding=\"0\" cellspacing=\"0\" bordercolor=\"#0000FF\" width=\"900\">"; print "<tr><td width=\"200\" height=\"30\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Advert / Description</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Year</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Artist</font></b></u></td>"; print "<td width=\"200\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Track</font></b></u></td>"; print "<td width=\"80\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Buy Album</font></b></u></td>"; print "<td width=\"100\" align=\"left\"><u><b><font face=\"arial\" size=\"2\" color=\"#800080\">Download MP3</font></b></u></td></tr>"; while ($row = mysql_fetch_array($result)) { // Begin while $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['advert']. "</font><br>"; $data .= "<font face=\"arial\" size=\"1\" color=\"#000080\"><i>" .$row['details']. "</i></font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['year']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['artist']. "</font></td>"; $data .= "<td width=\"200\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['track']. "</font></td>"; $data .= "<td width=\"80\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['asin_ref']. "</font></td>"; $data .= "<td width=\"100\" height=\"30\" align=\"left\"><font face=\"arial\" size=\"1\">" .$row['mp3_ref']. "</font></td></tr>"; $count++; } // end while $data .="</table>"; echo $data; } else { echo "problems...."; } } else { echo "Your query returned 0 Results"; } ?> Hello all, I'm passing variables through a URL. This will work: echo $v4; But neither of these will: echo "<a href='test.php?v4=$v4'>Places</a>"; echo "<a href='test.php?v4=".$v4."> Places</a>"; It WILL work if I hardcode v4, like so: echo "<a href='test.php?v4=Utah'>Places</a>"; But that's useless to me, as I don't want to have to write 50 If statements for every database entry. Does anyone know how to fix this? Thanks! My variable which should be storing XML data and echos it to the screen is echoing the data as a string without the XML structure Below is my code but it is still not working: Code: [Select] $view = $_GET['view']; $xml_data = "http://www.website.com/STRATA/" . $view .".xml"; $handle = fopen($xml_data, 'r'); $Data = fread($handle, 10000); fclose($handle); echo $Data; Hi, This is my first post in this forum and am a PHP beginner. I have written a script in php and need to use echo to see the values of variables etc. However I dont get the output on the screen while using echo . I am using Xampp server with Apache. The startup.html file code is
<!DOCTYPE HTML>
</head>
and the test.php code is <?php
$lat = $_REQUEST['latitude'];
echo 'latitude- '.$lat . ', longitude- ' . $lon; Please help regards
Sanjish Hi, Im trying to pull an email from an url, and then echo the email as value into a email form-- under the "from" heading. The echo is not working i get blanks. here is the code: <?php $thisurl='$_SERVER['REQUEST_URI']'; $thepart = explode('/', $thisurl); $themail='$thepart[2]'; ?> <form method="post" action="sendit.php"> To: <br><input type="text" name="to" size="44" value="<?php for($i=1; $i<=$lines; $i=$i+1) { $names[$i] = str_replace("<br>", "", $names[$i]); $names[$i] = str_replace("\n", "", $names[$i]); echo $names[$i].';'; } ?>"><br> From: <br><input type="text" name="email" size="44" value="<?php echo '$themail'; ?>" readonly><br> Subject: <br><input type="text" name="subject" size="44" /><br><br> OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Hi
I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems.
1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?
for($x = 1;$x<=40;$x++) {
$lines = file("$filename.html");
echo $lines[rand(0, count($lines)-1)]."<br>";
}
I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one.
2nd Problem:
As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?
My code:
if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}
If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.
Hi Freaks, You guys helped me yesterday & now I have expanded on what I was doing & now need more help. From my limited knowledge I'm trying to add theses strings together. (I'm a printer) Its all adding up correctly until the end. *$row['markup'] is only multiplying the last string and not the complete echo...I have indicated the last string in blue. <?php echo ($row['laminating']*$row['qty'])+($row['Stock1']*$row['qty'])+($row['cutting']+$row['production']+$row['additional']+$row['pluscover']+$row['selfcover'])*$row['markup'];?> What I need to do is add up everything in red and * by my markup value (12%) <?php echo ($row['laminating']*$row['qty'])+($row['Stock1']*$row['qty'])+($row['cutting']+$row['production']+$row['additional']+$row['pluscover']+$row['selfcover'])*$row['markup'];?> any help would be appreciated! cuzzmunger Hi, I can't figure out how to echo <br/> after 14 characters every line from text. Any idea's? Cyto Hi freaks, Yes im a noob... I have some data in a db that im echoing out, but the last row wont multiply? The rest works great... I have tried having the data as the following: 1.12 or 0.12 & I have tried having it as a var. Do I need to have a % in there somewhere? Im adding up all the data then I want to multiply by 12% (*$row['markup']) <?php echo $row['Stock1']*$row['qty']+$row['cutting']+$row['production']+$row['additional']+$row['pluscover']+$row['selfcover']*$row['markup'];?> any help would be appreciated. cuzzmunger. For some reason, I can only get 1 row to echo out when there are actually multiple rows in the database that should be echoing. Here is what I have: $result = mysql_query("SELECT * FROM boards WHERE boardname='$board' ORDER BY id LIMIT 10"); $post = mysql_fetch_assoc($result); echo stripslashes($post['message']) . "<br>\n" . " --- ".stripslashes($post['username']). " on ".stripslashes($post['time']) ."\n<hr width=90%>\n"; It pulls the one record great, but it only shows one record... I want to keep it to 10 records, thus the LIMIT in there (which I think I did right...), but it won't even show the ones in there right now (under 10, so that's not an issue yet). Hi, I have created a class "friendClass" and tried to echo it. It prints nothing without any errors, not sure what was it going on? Any helps would be appreciated! Code: [Select] class friendClass{ //attributes - variable public $name; public $sex; public $title; public $country; //methods - function public function eat(){} public function watch(){} public function drive(){} public function speak(){} } $friend1 = new friendClass; $friend2 = new friendClass; $friend3 = new friendClass; $friend4 = new friendClass; $friend1 -> name = "Bach"; $friend1 -> title = "Muscian"; $friend1 -> sex = "Male"; $friend1 -> country = "Germany"; $friend1 -> eat("Bread"); $friend1 -> speak("German"); $friend1 -> drive("Horse"); $friend1 -> watch("Beethoven"); echo "Name is: ".$friend1->name; Hi all, I have a page which simply pulls info from a database by id: <?php include ('connect.php'); $id = $_GET['id']; $query = mysql_query("SELECT * FROM JOBS WHERE id=$id"); if (!$query) { echo "Could not run query: " . mysql_error(); exit; } $row = mysql_fetch_row($query); { echo "<body><h3>" . $row[1]. "</h3>"; echo "<h4>" . $row[2] . "</h4>"; echo "<h4>" . $row[3] . "</h4>"; echo "<h5>Duties & Responsibilities:</h5><ul>"; echo "<li><strong>" . $row[4] . "</strong>" . $row[5] . "</li>"; echo "<li><strong>" . $row[6] . "</strong>" . $row[7] . "</li>"; echo "<li><strong>" . $row[8] . "</strong>" . $row[9] . "</li>"; echo "<li><strong>" . $row[10] . "</strong>" . $row[11] . "</li>"; } ?> However in some cases the rows in the database may only contain data upto row 6 for example, how would I go about coding this so that it only displays rows that exist. If row 6 exists then 7 always will too as the information is connected. I am manually added this stuff into phpmyadmin as I do not need a form as once it is complete then it will not need to be added to. Also row 8 and 9 may contain data but 6 and 7 may not Many Thanks How do I echo the day from the db? It just displays day and I want it to display the day that was set. <select name="date_of_birth" id="date_of_birth"> <option value="">Day</option> <?php $isset = isset($_POST['date_of_birth']); for($day = 1; $day <= 31; ++$day) { echo '<option'; if ($isset && $_POST['date_of_birth'] === $day) { echo ' selected="selected"'; } echo ">${day}</option>\n\t\t\t\t\t\t"; } ?> </select> |
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