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PHP - Mixing Html And Php Variable Names In An Echo Statement
I'm trying to input the results from a query into html, but I'm just getting the variable names rather than their values. I used single quotes for the echo statement, but I think I must need to switch to double to do that. But then I have problems with the double quotes from the class names (ex. class="SideBoxTitle").
Code: [Select] <?php // get user's videos from database $conn = mysqli_connect($dbhost, $dbuser, $dbpass) or die("MySQL Error: " . mysql_error()); $query = "SELECT * FROM haas12_test.videos"; $result = mysqli_query($conn, $query) or die ("Couldn't execute query."); while($row = mysqli_fetch_assoc($result)) { extract($row); echo ' <div id="topBox" class="mainVideoSideBoxes" > <div class="SideBoxTitle" ><h3> $vidtitle </h3> </div><!-- close SideBoxTitle --> <div class="sideBoxVidContainer"> <div class="SideBoxScreenCast" > $vidurl </div><!-- close SideBoxScreenCast --> <div class="SideBoxDesc" ><p> $viddesc </p> </div><!-- close SideBoxDesc --> </div><!-- close sideBoxVidContainer --> </div><!-- close mainVideoSideBoxes --> </div><!-- close mainVideoSideBoxes --> '; // end echo staement } ?> Similar TutorialsI have to put a link that can be clicked around the first name and last name variables in the echo statement below. I also need to add a variable from the Select query to the link such as: 'www.phpfreaks.com/admin/customers.php?page=1&cID="VARIABLE HERE" &action=edit' I've tried a bunch of things and none seem to work. while($row = mysql_fetch_array($result)){ echo '<tr><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>' . $row['plan_id'] . '</td></tr>'; David Code: [Select] echo("<p class=\"commentboxContainer\"><table width=100% border=0> <tr> <td bgcolor=\"#EEE\"><strong><p class=fltlft>$name </strong>says:</p></td> </tr> </table> <table width=100% border=0 bgcolor=\"#EEE\"> <tr> <td width=40%><img src=../images/Icons/People/Anonymous.png width=64 height=64 border=1 /></td> <td width=60%>$comment',0,6</td> </tr> </table> <table width=100% border=0> <tr> <td bgcolor=\"#EEE\" ><p class=fltlft><em>$email</em></p></td> </tr> <tr> <td bgcolor=\"#EEE\" ><p class=fltlft>added on $time</p></td> </tr> </table></p><br>"); Here's my echo statement for displaying comments by users. I want to add a substr (); function to limit the amount of characters of the $comment field. That way if a user makes a long comment it doesn't push the page down. I tried putting it after the echo (); but that didn't work. I also tried putting it before $comment and that didn't even work. I know that if I make two separate echo statements, this can be done, but the field "$comment" is displayed within a table that is part of the original echo statement, so what do I do? Hey, I posted a thread before about a news cms I've been developing. And right now I'm trying to flesh out the css of the articles I post on the home page. Now the problem I having is everytime I place a <span class=""></span> or <p class=""></p> or even <div class=""></div>, my web page does NOT load, and instead gives me an error. Code: [Select] Parse error: syntax error, unexpected T_STRING in /home/content/d/j/s/djsmiley/html/index.php on line 405 Now, I know it's possible to add css to a PHP echo statement, but I'm clearly doing something wrong. Here's the code for the php echo statement with the css included: Code: [Select] <? include("dbconnect.php"); //include the file to connect to the database $getnews = mysql_query("SELECT * FROM mynews ORDER BY id DESC"); //query the database for all of the news while($r=mysql_fetch_array($getnews)){ //while there are rows in the table extract($r); //remove the $r so its just $variable echo("<br><span class="NewsID">$type</span> <span class=h2>$title</span><br><br> <em>posted by <strong>$user</strong> | added on $time</em><br><br> $message<br><br> <label class="fltlft2"><img src="../../Websites/DJSmiley.Net/images/Icons/Arrows/Right.png" width="20" height="20"/></label><a href=$url>Read more - $url</a> <div class="newsLikeShareRate"> <table width="100%" border="0"> <tr> <td width="3%" height="21"><script src="http://connect.facebook.net/en_US/all.js#xfbml=1"></script> <fb:like href="$url" show_faces="true" width="450" font="arial"></fb:like> </td> <td width="65%"><a name="fb_share" id="fb_share4" type="icon_link" share_url="$url">Share</a> <script src="http://static.ak.fbcdn.net/connect.php/js/FB.Share" type="text/javascript"></script></td> <td width="32%">Rate this article: </td> </tr> </table> </div>"); } ?> If you're wondering why there's a facebook script in there, I made it to where everytime a new post is added, a facebook like and share button are added, and are assigned the url I specify when the article is posted. Well, I think that's it for the code. Can anyone tell me what I'm doing wrong? Hi all. I have this code. <?php $ext = ' <form action="/members/clubs/view-activity.php" method="post" name="venuefrm"> <button type="submit" id="close" class="link"><span>View Activity</span></button> <input name="activity" type="hidden" value="<?php echo $activites['activityID']; ?>" /> </form>'; ?> The code falls down at the value="<?php echo $activites['activityID']; ?>" part. Can someone please show me how I break into php to write this part properly as I dont understand an it is obviously wrong. Thanks Danny I'm redoing my login script using functions and a basic switch function checking against a $_GET variable (hope you guys know what I'm talking about). What I want to do is create two functions: 1 that displays the login form and 1 that processes the information The form tag would look like this: <form action=\"<?php $_SERVER['PHP_SELF']?>?action=process\" method=\"post\"> </form> Here's my switch statement: Code: [Select] <?php //**************************************** //****************Action****************** //**************************************** switch ($_GET["action"]) { default: case "index": if (!$_SESSION["member"]) { if (!$timeout) { display_form(); } else { echo $timeout_error; } } else { echo "You are already logged in."; } break; case "process": if (!$_SESSION["member"]) { if (!$timeout) { process_form(); } else { echo $timeout_error; } } else { echo "You are already logged in."; } break; } ?> This runs as soon as "login.php" loads. It'll automatically run the commands under case "default" and "index". It'll first check to see if the member's logged in. If not, it'll then check to see if "$timeout" is true ($timeout becomes true if the member has attempted to login 5 times and failed). If not, it'll display the login form, by running "display_form()". Once the form has been filled and submitted, the commands under case "process" will be performed. Again it will first check to see if the member's logged in. If not, it'll check to see if "$timeout" is true. If not, it'll start validating the forms. For the validation, I've created a variable called "$errors_found", and scripted one if statement checking to see if the email and password exist. If so, the variables "$rm_field_un" and "$rm_field_pw" become true, as well as "$errors_found". So, back to submission of the form... If "$errors_found" is true, display the form (when the form is displayed, there will be an if statement within that says "<?php if ($rm_field_un) { echo "Username is wrong."; } ?>", which will be displayed right underneath the username field and label. Same with the password elements). If "$errors_found" is not true, go ahead and register the member. Now, here's where I need help, because I'm really confused as to how to accomplish this. The "display_form()" function will contain a single variable called "$login_form". It will contain a value of the HTML constructed login form, and the function will return the variable. Remember how I stated in the third paragraph up that I will have <php> statements within the form which would display errors if necessary? Well, how do I put those if statements within the HTML, which is contained within the variable? If that last question confuses you, allow me to present you with an instance: Code: [Select] <?php function display_form() { $login_form = " <form name=\"login_form\" method=\"post\" action=\"<?php $_SERVER['PHP_SELF']?>?action=process\"> Username: <input type=\"text\"> <?php if ($rm_field_un) { echo "Username is wrong"; } ?> "; return $login_form; } ?> See what I mean? This code confuses me ALOT. I'm not sure if the <php> tags are needed as it is already contained within existing ones, or what. Can somebody please help me out? Any and all help is much appreciated. =D This serves more or less a meaningless purpose for my testing, but I've been trying to echo out the names of the tables that are being used in my UPDATE and SELECT queries and I have yet found a way to do this.. Did some research on php.net and Google and did not find anything that seems to directly address this.. My guess is it's so stupid simple, I probably will have an answer by the time I wake up.. But id there are any suggestions on this, Id be glad to take. OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hi im trying to mix php and html in a form however when i do this the whole page disapears and i dont know why the working form is: http://valiantflight.comlu.com/emailer/contact.php <html> <head> <title>Contact Us</title> </head> <body> <fieldset> <legend>Contact Us</legend> <form action="contact.php" method="post"> <input type="hidden" name="frmsubmit"> Your Email:*<br> <input type="text" name="email"><br> Subject:*<br> <select name="subject"> <option value=""></option> <option value="1">Recruitment</option> <option value="2">Absense</option> <option value="3">Enquiry</option> </select> <br> Message:*<br> <textarea name="message" cols="50" rows="5"></textarea> <br> <?php require_once('recaptchalib.php'); $publickey = "6LeB8LwSAAAAAKwvC3HWJNwWw9vYiSEkvFEvDduD"; // you got this from the signup page echo recaptcha_get_html($publickey); ?> <br> <input name"Submit" type="submit" value="Send Email"> </form> Required fields are marked with a *<br><br> <?php if(isset($_POST['frmsubmit'])){ $email = $_POST['email']; $subject = $_POST['subject']; $message = $_POST['message']; //checcking that all relevent information is entered and correct require_once('recaptchalib.php'); $privatekey = "6LeB8LwSAAAAAA_0IIEnAxL5uOau0TBm83Iog7Ey"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if(!$message || !$email || !$subject) { $errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>"; } if (!$resp->is_valid) { $errmessage ="<font color='red'>The text entered does not match the picture provided.</font>"; } //Sending the email if nothing is wrong if(!$errmessage) { header("location:send.php?subject=".$subject."&email=".$email."&message=".$message.""); }else{ echo $errmessage; } } ?> </fieldset> <br><br><br> </body> </html> and the one that doesnt work is: http://valiantflight.comlu.com/emailer/test/contact.php <html> <head> <title>Contact Us</title> </head> <body> <fieldset> <legend>Contact Us</legend> <form action="contact.php" method="post"> <?php if(isset($_POST['frmsubmit'])){ $email = $_POST['email']; $subject = $_POST['subject']; $message = $_POST['message']; //checcking that all relevent information is entered and correct ?> <input type="hidden" name="frmsubmit"> Your Email:*<br> <input type="text" name="email"> <?php if(!$email) { $errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>"; echo("<font color='red'><br>Please enter your email.</font>"); } ?> <br> Subject:*<br> <select name="subject"> <option value=""></option> <option value="1">Recruitment</option> <option value="2">Absense</option> <option value="3">Enquiry</option> </select> <?php if(!$subject) { $errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>"; echo("<font color='red'><br>Please select a subject.</font>"); } ?> <br> Message:*<br> <textarea name="message" cols="50" rows="5"></textarea> <?php if(!$message) { $errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>"; echo("<font color='red'><br>Please enter a message to send.</font>"); } ?> <br> <?php require_once('recaptchalib.php'); $publickey = "6LeB8LwSAAAAAKwvC3HWJNwWw9vYiSEkvFEvDduD"; // you got this from the signup page echo recaptcha_get_html($publickey); require_once('recaptchalib.php'); $privatekey = "6LeB8LwSAAAAAA_0IIEnAxL5uOau0TBm83Iog7Ey"; $resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]); if (!$resp->is_valid) { $errmessage ="<font color='red'>Some parts of the form have not been entered correctly and have been marked above</font>"; echo("<font color='red'>The text you entered does not match the picture provided.</font>"); } ?> <br> <input name"Submit" type="submit" value="Send Email"> </form> Required fields are marked with a *<br><br> <?php //Sending the email if nothing is wrong if(!$errmessage) { header("location:send.php?subject=".$subject."&email=".$email."&message=".$message.""); }else{ echo $errmessage; } } ?> </fieldset> <br><br><br> </body> </html> If anyone can help it would be really great Thanks, Blink359 As you can see here I have the following code Code: [Select] <?php session_start(); session_register('hazard2'); //INITIALIZE ERROR VARIABLES $errorFound = false; $errorIcon['hazard2'] = ''; if (isset($_POST['submitbutton'])) { //SET SESSION VARIABLES $_SESSION['hazard2'] = $_POST['hazard2']; //TEST FORM INFORMATION if(count($_POST['hazard2']) != 3) { $errorFound = true; $errorIcon['hazard2'] = 'Error Question 2'; } //IF NO ERRORS WERE FOUND, CONTINUE PROCESSING if (!$errorFound) { header( "Location: hazardresult.php" ); } } ?> It's lazy I know, but the script is on a file called hazard2.php, is there anyway to have all of the hazard2's in the code come from the file name. So when I make hazard3, I don't have to change all the hazard2's to hazard3's Thank you Hello, I'm having some issues with PHP thinking that the variables that I send it are the actual columns in my database. First, I pull off Quadratic_Functions and introductory_problem from http://localhost:8888/algebra_book/Chapters/Quadratic_Functions/introductory_problem.php using the code below: Code: [Select] $chapter_page = $_SERVER['PHP_SELF']; $chapter_page_array = explode('/',$chapter_page); $size =count($chapter_page_array); $chapter = $chapter_page_array[$size-2]; $page = $chapter_page_array[$size-1]; $page_array = explode('.', $page); $page = $page_array[0]; Based on my printing of the variables $chapter and $page I think that it's doing what I want it to do. I then use the following function: Code: [Select] $supplemental_id = getSupplementalId($dbRead,$chapter,$page); to check out if the there's a supplemental_id for the Quadratic_Function chapter and introductory_problem page name via: Code: [Select] function getSupplementalId($read,$user_id,$chapter,$page) { $sql = "SELECT supplemental_id FROM instructors_supplemental WHERE page_name = $page AND chapter_name='$chapter"; return $read->fetchRow($sql); } If I stick in actual values, as seen below, the thing runs fine. Code: [Select] $sql = "SELECT supplemental_id FROM instructors_supplemental WHERE page_name = 'introductory_problem' AND chapter_name='Quadratic_Functions'"; But if I run it in the abstract version, with variables for page and chapter name (the first version), I get Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'introductory_problem' in 'where clause'' in... It's almost as if it thinks that my variables are the names of the columns. Any thoughts would be appreciated.... Hi There, I would like to place the last for month names into an variable- for example: February 2011 January 2011 December 2010 November 2010 But I would like them to all have the same variable ($date) - so when I use it in a mssql_fetch_assoc - it increments with every instance of $date, as there will be one instance of $date for every row returned, getting older with every row. Hope that is enough info? Cheers Matt Hi, I'm trying to edit some database fields, I have text1, text2, text3, text4, text5, text6 etc.. They are displayed on the index.php page, with an edit link so the user can choose which set to edit // Extract details from database $sql = "SELECT * FROM data WHERE id=1"; $stmt = $db->prepare($sql); $stmt->execute(); $e = $stmt->fetch(); <h1><?php echo $e['text1']) ?></h1> <p><?php echo ($e['text2']); ?></p> <p><a href="edit.php">EDIT</a></p> <h1><?php echo $e['text3']) ?></h1> <p><?php echo ($e['text4']); ?></p> <p><a href="edit.php">EDIT</a></p> <h1><?php echo $e['text5']) ?></h1> <p><?php echo ($e['text6']); ?></p> <p><a href="edit.php">EDIT</a></p>
edit.php: // Extract details from database $sql = "SELECT * FROM data WHERE id=1"; $stmt = $db->prepare($sql); $stmt->execute(); $e = $stmt->fetch(); <form method="post" action="process.php" enctype="multipart/form-data"> <label>Page Title <input type="text" name="text1" maxlength="90" value="<?php echo $e['text1'] ?>" /> </label> <br> <label>Title Text</label> <textarea name="text2"><?php echo $e['text2'] ?></textarea> <input id="button" type="submit" name="submit" value="Save Changes" /> and then update them: process.php $sql = "UPDATE data SET text1=?, text2=? WHERE id=1 LIMIT 1"; $stmt = $db->prepare($sql); $stmt->execute( array( $_POST['text1'], $_POST['text2'] ) ); $stmt->closeCursor(); Question: How can I pass the form values dynamically from the index.php page so I don't have to hard code text1, text2 etc into the edit.php and process.php page and have a different update & process page for each set of data?
Thanks in advance. The Code Below is for my Colony Building page for my game. That particular code is supposed to display the number of buildings built, which it does, and also allow me to change the number of buildings built, which it doesn't. The code is part of a loop that displays all the possible buildings of a given type, in this case Iron Mines, that can be built on the colony. Basically what I need to know is, how do I change the name of the column that is being updated as the code loops. Currently it is setting all the forms to alter the number of Basic iron mines on a colony. I am hoping I can somehow call the names of all the columns into an array and use the same code that picks which column value i am selecting, the $?(an array)[$b](an incrementing number to call the correct array value): $?[$b]. Then I would replace Basic, in the column part of the UPDATE code with the array and result selector so that the first time i include() the code it creates the form and sets it to alter Basic, but the second time it sets the code to alter the value in the next column. Code: [Select] <?php $dbhost = 'localhost:3306'; $dbuser = 'root'; $dbpass = 'root'; $dbname = 'aosdb'; $conn = mysql_connect($dbhost,$dbuser,$dbpass) or die ('Error connecting to mysql'); mysql_select_db($dbname); $b=1; $queryp = "SELECT * FROM IMBuilt WHERE idcol = $idcol"; $resultp = mysql_query($queryp); $Base = mysql_fetch_row($resultp); if(isset($_POST["built"])) { if($_POST) { $Badd = $Base[$b]+$_POST["built"]; $queryi="UPDATE IMBuilt SET Basic=$Badd WHERE idcol = $idcol"; mysql_query($queryi); } } $queryf = "SELECT * FROM IMBuilt WHERE idcol = $idcol"; $resultf = mysql_query($queryf); $Basic = mysql_fetch_row($resultf); ?> <p class="bd" id="built">| Built: <?php echo $Basic[$b] ?> |</p> <form class="bd" method="post" action="IronMineList.php"><input type="varchar" name="built"><input type="submit" value="Build"></form> </div> I am having a problem echoing a line of code. I am doing this on my local machine. Anyway, here are the to files involved... home.php <?php include $_SERVER['DOCUMENT_ROOT'] . '/includes/helpers.inc.php'; include $_SERVER['DOCUMENT_ROOT'] . '/includes/doctype.inc.php'; include $_SERVER['DOCUMENT_ROOT'] . '/includes/head.inc.php'; ?> </head> <body> <div id="wrapper"> <!-- start horizontal navigation --> <?php include $_SERVER['DOCUMENT_ROOT'] . '/includes/topnav.inc.php'; ?> <!-- end horizontal navigation --> <div id="content"> <h1><?php echo htmlout($cattitle); ?></h1> <span class="desc"><?php echo ($catdesc); ?></span> <?php include $_SERVER['DOCUMENT_ROOT'] . '/info.php'; ?> </div> <!-- start footer --> <?php include $_SERVER['DOCUMENT_ROOT'] . '/includes/footer.inc.php'; ?> <!-- end footer --> </div> </body> </html> and info.php <?php $result = mysqli_query($link, 'SELECT * From includes where catid ='.$_GET['id']); if (!$result) { $error = 'Error getting categories: ' . mysqli_error($link); include 'error.php'; exit(); } while ($row = mysqli_fetch_array($result)) { $inc[] = array('id' => $row['id'], 'include' => $row['include'], 'inc_orderby' => $row['inc_orderby'], 'inc_avail' => $row['inc_avail']); } foreach ($inc as $include): { echo "include $_SERVER['DOCUMENT_ROOT'] . '/includes/' . $row['include'];"; } endforeach; ?> I can't get the echo statement at the bottom of info.php echo "include $_SERVER['DOCUMENT_ROOT'] . '/includes/' . $row['include'];"; to show up correctly on the home.php page in this spot. include $_SERVER['DOCUMENT_ROOT'] . '/info.php'; what i am attempting to do is loop through some additional information relevant to the page a user selects on the site and display it. (I still have to set up some qualifying statements but this was just the first step to see if anything would show up) This is the parse error I get. Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\info.php on line 18 I've tried messing with the quotes in the echo statement cause I'm sure they aren't right but I never came up with a quote combination that worked. I'm assuming that is the problem. Anyway thanks for taking a look. Welcome member. I am able to get data added to my db and when it gets to the welcome page I want it to welcome $firstname but it comes up blank. How can I fix my echo statement. <?php session_id(); session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Welcome</title> </head> <body> <?php /* Program: New_member.php * Desc: Displays the new member welcome page. Greets * member by name and gives a choice to enter * restricted section or go back to main page. */ if (@$_SESSION['auth'] != "yes") @include('Connections/connect_to_mysql.php'); $result = mysql_query("SELECT firstname FROM `Members` WHERE id='{$_SESSION['id']}'"); $row = mysql_fetch_array($result); echo "<html> <head><title>New Member Welcome</title></head> <body> <h2 style='margin-top: .7in; text-align: center'> Welcome, $firstName </h2>\n"; ?> <p>Your new Member accounts lets you enter the members only section of our web site. You'll find special discounts, a profile of matches, live advise for experts, and much more.</p> <p>Your new Member ID and password were emailed to you. Store them carefully for future use.</p> <div style="text-align: center"> <p style="margin-top: .5in; font-weight: bold"> Glad you could join us!</p> <form action="profile.php" method="post"> <input type="submit" value="Enter the Members Only Section"> </form> <form action="index.php" method="post"> <input type="submit" value="Go to Main Page"> </form> </div> </body> </html> I am building a website that uses session variables extensively. The site is getting a little complicated, and I am starting to lose track of which session variables are assigned, and what their values are. Is there some way where I can create a piece of code that will display all of the existing session variables and their values? I am using the Twitch API to tell if a user is live. I'm new to the Twitch API and PhP so please forgive me if I make any mistakes. Expand the Spoiler tags below to see the code. The code below SHOULD be telling me if a channel is not live or not. It tells me if they are live, but not if they are not live. I don't understand.
Spoiler
<?php
if (!empty($_GET['channel']))
{
$channel = $_GET['channel'];
$dataArray = json_decode(@file_get_contents('https://api.twitch.tv/kraken/streams?channel='.$channel), true);
foreach ((array) $dataArray['streams'] as $mydata)
{
if (!empty($mydata['_id']))
{
echo "Channel is live<br><br>";
$uptime = $mydata['created_at'];
$uptime = str_replace("Z", "UTC", $uptime);
$uptime = preg_replace("/T/", "", $uptime, 1);
echo "Twitch Uptime: ".$uptime."<br />";
date_default_timezone_set('UTC');
$localUptime = date('Y-m-dh:i:sT', time());
echo "UTC Local Time: ".$localUptime;
}
else
{
echo "Channel is not live";
}
}
} else {
echo "No channel";
}
?>
Hello,
I am working on this function that echo's out images from my database restricted to 10 images with 4 default images if the database is empty.
<?php
$query = mysql_query('SELECT image_id, image_expiry FROM images ORDER BY RAND() LIMIT 10');
$i = 0;
class myCounter3 implements Countable {
public function count() {
static $count = 0;
return ++$count;
}
}
$counter = new myCounter3;
while ($row = mysql_fetch_array($query))
{
if($i % 10 === 0)
{
}
echo '<img src="http://www.mysite.com/'.$row['image_id'].'.jpg" width="300" height="auto"/>';
$i++;
}
for (; $i <= 4; $i++) {
echo '<img src="http://www.mysite.com/default.jpg" width="300" height="auto"/>'
}
?>
I need to include an image expiry function with the function above, but I am not sure how to properly include it.
Here is my planned expiry function (each image as an expiry date).
$today = date("Y-m-d", time());
$expiry = $row['image_expiry']
if( $today > $expiry)
{
## ignore expired image
}
else
{
## display image
}
Bottom line I need to exclude expired images from being echoed out in the first function.
Thanks in advance. Everything I have tried hasn't worked.
Hello guys im new to php i been coding for like a week now, i need some help here i have been stuck for like 6 hours XD,is it possible to write an IF Statement inside an echo? //this is what i want to do // echo a table and a delete button // and if you click on the delete button it echoes out "DELETED" echo " <table width='528px'> <tr> <td> </td> <td> <center><font size='5'>$tittle</font></center><br> </td> </tr> <tr> <td> </td> <td> $message </td> </tr> <tr> <td> </td> <td> <font size='1'>Posted By:<font color='green'>$author</font> on <font color='gray'>$date</font> at <font color='gray'>$time</font></font> <input id='delete' name='delete' type='submit' value='Delete' > if ($_POST['delete']) { echo "DELETED"; } <td> </td> </tr><br><br> </table> "; I want to add a space after $item in the below statement so that there is more space between the output of Item and Qty. |
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