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PHP - How Best To Store An Image?
Well, I am storing some of images on my server, but I have to type in the name myself which gets a bit boring and I may overwrite an old image by accident, so, I was thinking of having mysql auto increment the image names. But will this be suitable for images, or should it be text.
Similar Tutorialshi i want to store url to images in database for logged in users (where id = $id) and recall the image hopefully using --------------------- <img src="<?php echo row['link']; ?>" /> or similar and need help with the sql update string any ideas please help i been stuck with this for some time and now decided to ask around in this forum for help, please help if you can. I was wondering if there is any way to let visitor chose image background of div and store it in session so every page have same background? Hey, i need help storing an image in my database via the URL(image location) at the moment my php code is storing the image in a folder on the directory called upload. here is the code: <?php // Where the file is going to be placed $target_path = "upload /"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); $target_path = "upload/"; $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { echo "The file ". basename $_FILES['uploadedfile']['name']). " has been uploaded"; } else{ echo "There was an error uploading the file, please try again!"; } ?> Click <a href="products.php">HERE</a> to go back to form if someone could help me i'd be very grateful Hello, I have a variable called $Price, We are getting it through Mysql Database using While loop. We getting the data from database in ordered by ID. Now then i have requirement to store that data into Low to High form ... Like we are receiving $price lke unordered form .. 50 14 35 25 00 145 52 Here i just want to store it in Low to high form like 00, 14,25,35 ... and so on .. Please suggest me the appropriate code. While($myrow=mysql_fetch_array($result, MYSQL_ASSOC)) { some codes return value $price. // want to store in array } $array($price) // here want to store in Low to high with key value. Hi, I want to maintain users who log in a webpage and each time they leave, I want to record the current time, so this sounds silly but do I just set in my db table in a field that tracks a user's last log in with DEFAULT: CURRENT_TIMESTAMP? db structu user_id lastActivity lastSession (stores TIMESTAMP of last time user logged in) Any help much appreciated Hi, I am writing a advertisement system, where i have two fields Ad_Start_date Ad_End_Date i was always confused, in doing this things regarding date whether to use datetime or timestamp in mysql Thanks, Hi,
I am building a website that will contain listings, there will be a categories page which will bring the user to the subcategories for that category then the user can see all listings linked to that subcategory. At the minute I am just linking each page using basic href tags to go to the page name.php and all my pages end up being homepage.com/clickedlink.php.
How do I change my URL's so that if i click on a certain category the url changes to page name.php?category=chosen category?
Thanks
It seems that in the following script I am not able to make $page contain some values as it always acts as it contains 0. The script will give you more idea about what I wanna do with it. Code: [Select] <?php include('dbinfo.inc'); session_start(); $connect= mysql_connect($host,$dbuser,$password) or die("connect to database fails"); mysql_select_db($dbname, $connect); //This will set the number of messages we want to display on each page $rows_per_page = 5; function show_msg() { echo "<tr align='center'> <td>$row[message]</td> </tr> <tr><td><strong>Sent By: $_SESSION[username] ON Date: $row[date]</strong></td></tr> <tr><td></td></tr>"; } //This will set the necessay variables required to set the page layout function page_vars() { $sql = "select * from msgs"; $result = mysql_query($sql, $connect); $numrows = mysql_num_rows($result); $total_pages = ceil($numrows/$rows_per_page); //Check whether page is given or not if(isset($_GET["page"])) { $page = $_GET["page"]; } else { $page = 1; } if($page < 1): { $page = 1; } elseif($page > $total_pages): { $page = $total_pages; } endif; } if($_SESSION[loggedin] == TRUE && $_SESSION[actype] == lecturer) { echo "<form action='postmsg.php' method='POST'>"; echo "<table width='80%' border='1'><tr align='center'><td><strong>To send a new message type it in the below box and press SUBMIT</strong> </td></tr>"; echo "<tr align='center'> <td><textarea name='msgarea' cols='40' row='5'></textarea></td> </tr> <tr align='center'> <td><input type='submit' value='Send Message' /></td> </tr> </table>"; $limit .= 'LIMIT '.($page - 1)*$rows_per_page.', '.$rows_per_page; echo $limit; $sql = "select * from 'msgs' $limit"; $result = mysql_query($sql); echo "<table width='80%' border='1'>"; $row = mysql_fetch_assoc($result); while($row) { show_msg(); } } else { page_vars(); $limit .= 'LIMIT '.($page - 1)*$rows_per_page.', '.$rows_per_page; $sql = "select * from msgs $limit"; $result = mysql_query($sql,$connect); echo "<table width='80%' border='1'>"; while($row = mysql_fetch_assoc($result)) { show_msg(); } echo "<tr align='center'> <td> <a href='$_SERVER[php_self]?page=1'>First Page</a> <a href='$_SERVER[php_self]?page=($page - 1)'>$page</a> <a href='$_SERVER[php_self]?page=$page'>$page</a> <a href='$_SERVER[php_self]?page=($page + 1)'>$page</a> <a href='$_SERVER[php_self]?page=($total_pages)'>>>>Last Page</a> </td> </tr>"; echo "</table>"; } ?> now when i echo $limit it always shows "-5, 5" , that's not what i want from this script. Instead I want limit to store "0, 1" with the same concept not direct because it will change according to what $_GET[page] holds. Hope I will get the solution here.... how do i get a drop down value and store it in a another table as of now i am getting the value from one table showing it on drop down now once that is selected i need to insert it into another table. <html> <?php mysql_connect('localhost','root','') or die('Could not connect to mysql ' . mysql_error()); mysql_select_db("dbtest") or die(mysql_error()); if(isset($_POST['submit'])) { //$name=$_POST['val']; $id = $_POST['select']; $id=$row['name']; ?> <input type="text" name="name2" value="<?php echo $row['name'] ?>"><br /> <?php $query = "INSERT INTO sub (`sub`) values('" . $id . "')"; $result = mysql_query($query); if($query) { echo "query executed"; } } ?> <form id="name" action="<?php $_POST['SERVER_SELF'] ?>" method="POST" > <input type="text" name="name1"><br /> <select name="select" id="select"> <?php $query = "SELECT name,id FROM main"; $result = mysql_query($query); if($query) { while($row = mysql_fetch_array($result)) { $options .= '<option value="' . $row['name'] . '">' . $row['name'] . '</option>'; // $out .= "<option value=\" . $row['name'] . \" >' . $row['name'] . '</option>"; } } echo $options; ?> </select> <input type="submit" name="submit1"> </form> </html> Thanks the above seem to work. Hey Guys, Im currently working on this sport management system where managers can control their team. At the moment im trying to add a feature where if a player is injured on your team, the manager can click an 'injury' button and say how long he will be injured for. Although, what i would like to do with this feature is when it's stored into the database i want to make it so that when his injury time runs out he will become available again (not injured). How would i go about doing this feature? Cheers Browny Hey I created a drop box and got a form for that. Now when I click on submit I want the data to be compaired with the data inside the mysql. For example: Subject name = Subject id the drop down list contains subject names. And this should be compaired with the subject id and store the id into a new table called test. <Html> <?php session_start(); include '../Database/connection.php'; ?> <body> <form action="try1.php" method="post"> <?PHP include '../Database/subject_sql.php'; $result=mysql_query($query) or die ("Unable to Make the Query:" . mysql_error() ); echo "<select name=myselect>"; while($row=mysql_fetch_array($result)){ echo "<OPTION VALUE=".$row['Sub_ID'].">".$row['Sub_Name']."</OPTION>"; } echo "</select>"; ?> <input type="submit" value="submit"/> </form> </body> </html> Hey Guys. I am writing a function that will output to the user if a store is open or not.
I wrote a fucntions named is_store_open() with a variable called $day which will have the current day of the week assigned to it.
Lets say it is Saturday. it finds the case for "Saturday" and checks the opening time and closing time for Saturday.
The problem that I am facing, is when the store is open past midnight on Saturday. It then won't check the case for saturday.
Instead will check the case for Sunday. Which is not what I want, becuase it will show the store as closed when its open still open on "Saturday"
I wrote a function below that checks to see if the previous day closing hours are greater then the current time. If its true then return true and I guess that should fix the problem.
But when I wrote that it would give me an error saying that $saturday_close is undefined. I'm guessing its becuase its in a switch satement, and it does not equal to that day.
I'm a little bit confused on how to set this up. If anyone has a suggestion I would really apprecaite your help. Thanks!
function is_store_open(){
$set_time = strtotime("tomorrow"); // Lets just sat its Sunday for testing purposes
$day = date("l", $set_time);
$time_now = mktime("00", "00", "00"); // Now lets say the time now is 12:00am
switch ($day) {
case "Saturday":
$open = "11:00";
$saturday_close = "1:00";
break;
case "Sunday";
if($saturday_close > $time_now ){//If the $monday_close hours are greater then the current time return false the store is still open
return true;
} else {
$open = "2:00";
$close = "22:00";
}
break;
}
}// End of function
if(is_store_open()) {
echo "Oh no! There is still a glitch in the system the store needs to remain open";
} else {
echo "The store is still open on Saturday";
}
Anyone could help or giude how to secure this script by storing session into database?
login.php
<?php
//Start session
session_start();
//Include database connection details
require_once('config.php');
//Get ip
function get_client_ip() {
$ipaddress = '';
if ($_SERVER['HTTP_CLIENT_IP'])
$ipaddress = $_SERVER['HTTP_CLIENT_IP'];
else if($_SERVER['HTTP_X_FORWARDED_FOR'])
$ipaddress = $_SERVER['HTTP_X_FORWARDED_FOR'];
else if($_SERVER['HTTP_X_FORWARDED'])
$ipaddress = $_SERVER['HTTP_X_FORWARDED'];
else if($_SERVER['HTTP_FORWARDED_FOR'])
$ipaddress = $_SERVER['HTTP_FORWARDED_FOR'];
else if($_SERVER['HTTP_FORWARDED'])
$ipaddress = $_SERVER['HTTP_FORWARDED'];
else if($_SERVER['REMOTE_ADDR'])
$ipaddress = $_SERVER['REMOTE_ADDR'];
else
$ipaddress = 'UNKNOWN';
return $ipaddress;
}
//Array to store validation errors
$errmsg_arr = array();
//Validation error flag
$errflag = false;
//Function to sanitize values received from the form. Prevents SQL injection
function clean($str) {
$str = @trim($str);
if(get_magic_quotes_gpc()) {
$str = stripslashes($str);
}
return mysql_real_escape_string($str);
}
//Sanitize the POST values
$login = clean($_POST['login']);
$password = clean($_POST['password']);
$ip = get_client_ip();
//Input Validations
if($login == '') {
$errmsg_arr[] = 'Login ID missing';
$errflag = true;
}
if($password == '') {
$errmsg_arr[] = 'Password missing';
$errflag = true;
}
/* if($login != '' || $password != '') {
if($login !='admin' && $ip !=''.$log_ip.''){
$errmsg_arr[] = 'Your IP <b>'.$ip.'</b> is not recognized...';
$errflag = true;
}
}
*/
//If there are input validations, redirect back to the login form
if($errflag) {
$_SESSION['ERRMSG_ARR'] = $errmsg_arr;
session_write_close();
//header("location: index.php");
echo ('<meta http-equiv="refresh" content="0;url=index.php">');
exit();
}
//Create query
$qry="SELECT * FROM members WHERE login='$login' AND passwd='".$_POST['password']."'";
$result=mysql_query($qry);
//Check whether the query was successful or not
if($result) {
if(mysql_num_rows($result) == 1) {
//Login Successful
session_regenerate_id();
$member = mysql_fetch_assoc($result);
$_SESSION['SESS_MEMBER_ID'] = $member['member_id'];
$_SESSION['SESS_LOGIN_NAME'] = $member['login'];
$_SESSION['SESS_PASS'] = $member['passwd'];
session_write_close();
//header("location: member-index.php");
echo ('<meta http-equiv="refresh" content="0;url=member-index.php">');
exit();
}else {
//Login failed
//header("location: login-failed.php");
echo ('<meta http-equiv="refresh" content="0;url=login-failed.php">');
exit();
}
}else {
die("Query failed");
}
?>
auth.php (included on top of all php pages
<?php
//Start session
session_start();
//Check whether the session variable SESS_MEMBER_ID is present or not
if(!isset($_SESSION['SESS_MEMBER_ID']) || (trim($_SESSION['SESS_MEMBER_ID']) == '')) {
//header("location: access-denied.php");
echo ('<meta http-equiv="refresh" content="0;url=access-denied.php">');
exit();
}
?>
hello, um i got a form that stored an array of variables upon users clicks. it submits to another page fine as an array and i can print them using if(!empty($_POST['langSpoken'])) { echo "\n<p><strong>You selected the following LangSpoken:</strong></p>\n<ul>"; foreach($langSpoken as $lang) { // exclude any items with chars we don't want, just in case someone is playing if(!preg_match('/^[-A-Z0-9\., ]+$/iD', $lang)) continue; // print the lang echo "\n\t<li>" . htmlspecialchars($lang) . "</li>"; } echo "\n</ul>"; } else { echo "\n<p>No items selected</p>"; } it prints a list a of array like english spanish but i need to store each one in one variable so i can store in a database is there a way? thanks What is the better way, in terms of best practice and also speed of storing PHP objects in a database? Is it: Serialize Code: [Select] $SQL = "INSERT INTO my_table (my_object) VALUES ('" . seralize($php_object). "')"; OR JSON Code: [Select] $SQL = "INSERT INTO my_table (my_object) VALUES ('" . json_encode($php_object). "')"; Any idea which is faster serialize() / unserialize() or json_ecode() / json_decode()? Hi, I am trying to store the view rate of articles so that I can retrieve them later on by "the most popular". I have searched around but cannot find a straight answer. Can anyone point me towards the right direction? Edit: Never mind, I was over complicating the logic behind this. I added the ability for Users to "preview" their Comments before submitting them. I just realized that when they click "Preview" that their Comments appear above the Comments form box - similar to how PHPFreaks works - but that the Comments form box loses it's data since the page reload causes this to lose things... <li> <label for="comments">Comments:</label> <textarea id="comments" name="comments" cols="50" rows="15"><?php if (isset($comments)){echo nl2br(htmlentities($comments, ENT_QUOTES));} ?></textarea> <?php if (!empty($errors['comments'])){ echo '<span class="error">' . $errors['comments'] . '</span>'; } ?> </li> What is the easiest way to maintain form persistence? (I really would like to avoid having to store things in my database during the preview.) How does PHPFreaks do things? I was going to use a SESSION, but since this is a Comments field that can take up to 65,535 characters, that probably won't work?! Any ideas? Debbie How to Store the search criteria like if user serach for a particular job and want to store that search ? Should i create anyother table to store critaria .... i have no idea what to do in this case/ thankx in advance This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=327616.0 i'm trying to get all the results from a query search into an array and them have another query search the results from that array againts a different table to get the right results. Here is my code: Code: [Select] $name = $_GET['name']; //lets say $name = 'california' $get_state = mysql_query("SELECT * FROM locations WHERE state LIKE '$name'") or die(mysql_error()); $num_states = mysql_num_rows($get_state); $location_array = array(); $i = 0; while($state = mysql_fetch_assoc($get_state)){ $location_array[$i][] = $state['id']; $i++; } $get_buildings = mysql_query("SELECT * FROM points WHERE location_id='".implode(",", $location_array)."' ORDER BY name ASC") or die(mysql_error()); However i can't get any results. I tried outputing the array by imploding it and all i got was "array, array, array, array," I hope someone here can help me out. |
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