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PHP - Sessions Mixing

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Sessions Mixing	View Content

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Mixing Different Queries Together

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I have two seperate piece of code. One which sorts description and one which sorts price. However, I am looking to almalgamate them into one. I have tried the following however I appear to be way off.

I want to select a product description with one link and then select a price range. However, I want the price range to read the description.

<?phpif( isset($_GET['description' ; 'price' ]))
$description = $_GET['description' ; 'price'];
$query = "SELECT * FROM productfeed WHERE description like '%$description%' LIMIT 0, 10";
$query = "SELECT * FROM productfeed WHERE price like '%$price%' LIMIT 0, 10";
$fetchdata = mysql_query($query) or die("query: $query<br>
This has an error: " . mysql_error() . '<br>');while($row = mysql_fetch_array($fetchdata)) {
$id = $row['id'];
$image = $row['awImage'];
$link = $row['link'];
$description = $row['description'];
$fulldescription = $row['fulldescription'];
$price = $row['price'];

<?phpif( isset($_GET['description']))
$description = $_GET['description'];
$query = "SELECT * FROM productfeed WHERE description like '%$description%' LIMIT 0, 10";
$fetchdata = mysql_query($query) or die("query: $query<br>
This has an error: " . mysql_error() . '<br>');while($row = mysql_fetch_array($fetchdata)) {
$id = $row['id'];
$image = $row['awImage'];
$link = $row['link'];
$description = $row['description'];
$fulldescription = $row['fulldescription'];
$price = $row['price'];

<?phpif( isset($_GET['price']))
$price = $_GET['price'];
$query = "SELECT * FROM productfeed WHERE price like '%$price%' LIMIT 0, 10";
$fetchdata = mysql_query($query) or die("query: $query<br>
This has an error: " . mysql_error() . '<br>');while($row = mysql_fetch_array($fetchdata)) {
$id = $row['id'];
$image = $row['awImage'];
$link = $row['link'];
$description = $row['description'];
$fulldescription = $row['fulldescription'];
$price = $row['price'];

Mixing Languages

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Hi guys.

This is my first post here - so HELLO.

I am a very experienced software developer, but new to web work. I am building a software tool using PHP (primarily). As such, many of my questions will concern optimum solutions (in so far as they may be determined), best practices, and the unwritten standards that will surely have evolved through the PHP community over time.

My first question concerns the mixing of HTML and PHP. My efforts so far contain a mix, but it doesn't "feel" right. I am using straight XHTML, PHP echo, and also heredoc. I can post the code if folk think it may help. But what is the general view as to whether "mixing" like this is a good and accepted practice, or is another approach preferred?

Many thanks in advance for any replies.

S

Mixing Rgb Color Values

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Hi, Assume that I have 50 RGB color values and I want to mix all of them and reach to a final single value which is mixture of all. how can I do that in PHP. Thanks.

Page Going Blank When Mixing Php With Html

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Hi im trying to mix php and html in a form however when i do this the whole page disapears and i dont know why
the working form is:
http://valiantflight.comlu.com/emailer/contact.php
<html>
<head>
<title>Contact Us</title>
</head>
<body>
<fieldset>
<legend>Contact Us</legend>
<form action="contact.php" method="post">

<input type="hidden" name="frmsubmit">
Your Email:*<br>

<input type="text" name="email"><br>
Subject:*<br>
<select name="subject">
<option value=""></option>
<option value="1">Recruitment</option>
<option value="2">Absense</option>
<option value="3">Enquiry</option>
</select>

<br>
Message:*<br>
<textarea name="message" cols="50" rows="5"></textarea>

<br>
        <?php           require_once('recaptchalib.php');
           $publickey = "6LeB8LwSAAAAAKwvC3HWJNwWw9vYiSEkvFEvDduD"; // you got this from the signup page
           echo recaptcha_get_html($publickey);
         ?>

<br>
<input name"Submit" type="submit" value="Send Email">

</form>
Required fields are marked with a *<br><br>
<?php
if(isset($_POST['frmsubmit'])){
$email = $_POST['email'];
$subject = $_POST['subject'];
$message = $_POST['message'];

//checcking that all relevent information is entered and correct
require_once('recaptchalib.php');
$privatekey = "6LeB8LwSAAAAAA_0IIEnAxL5uOau0TBm83Iog7Ey";
$resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]);


if(!$message || !$email || !$subject)
{
$errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>";
}
if (!$resp->is_valid)
{
$errmessage ="<font color='red'>The text entered does not match the picture provided.</font>";

}

//Sending the email if nothing is wrong
if(!$errmessage)
{
header("location:send.php?subject=".$subject."&email=".$email."&message=".$message."");
}else{

echo $errmessage;
}
}
?>
</fieldset>
<br><br><br>
</body>
</html>
and the one that doesnt work is:
http://valiantflight.comlu.com/emailer/test/contact.php
<html>
<head>
<title>Contact Us</title>
</head>
<body>
<fieldset>
<legend>Contact Us</legend>
<form action="contact.php" method="post">
<?php
if(isset($_POST['frmsubmit'])){
$email = $_POST['email'];
$subject = $_POST['subject'];
$message = $_POST['message'];

//checcking that all relevent information is entered and correct
?>

<input type="hidden" name="frmsubmit">
Your Email:*<br>
<input type="text" name="email">
<?php
if(!$email)
{
$errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>";
echo("<font color='red'><br>Please enter your email.</font>");
}
?>
<br>
Subject:*<br>
<select name="subject">
<option value=""></option>
<option value="1">Recruitment</option>
<option value="2">Absense</option>
<option value="3">Enquiry</option>
</select>
<?php
if(!$subject)
{
$errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>";
echo("<font color='red'><br>Please select a subject.</font>");
}
?>

<br>
Message:*<br>
<textarea name="message" cols="50" rows="5"></textarea>
<?php

if(!$message)
{
$errmessage ="<font color='red'>The marked areas in the form have not been filled in correctly.</font>";
echo("<font color='red'><br>Please enter a message to send.</font>");
}

?>

<br>
        <?php
require_once('recaptchalib.php');
$publickey = "6LeB8LwSAAAAAKwvC3HWJNwWw9vYiSEkvFEvDduD"; // you got this from the signup page
echo recaptcha_get_html($publickey);
require_once('recaptchalib.php');
$privatekey = "6LeB8LwSAAAAAA_0IIEnAxL5uOau0TBm83Iog7Ey";
$resp = recaptcha_check_answer ($privatekey, $_SERVER["REMOTE_ADDR"], $_POST["recaptcha_challenge_field"], $_POST["recaptcha_response_field"]);
          if (!$resp->is_valid)
{
$errmessage ="<font color='red'>Some parts of the form have not been entered correctly and have been marked above</font>";
echo("<font color='red'>The text you entered does not match the picture provided.</font>");

}
?>

<br>
<input name"Submit" type="submit" value="Send Email">

</form>
Required fields are marked with a *<br><br>
<?php


//Sending the email if nothing is wrong
if(!$errmessage)
{
header("location:send.php?subject=".$subject."&email=".$email."&message=".$message."");
}else{

echo $errmessage;
}
}
?>
</fieldset>
<br><br><br>
</body>
</html>

If anyone can help it would be really great

Thanks,

Blink359

Range() - Mixing Letters With Numbers?

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Can I somehow mix letters with numbers to create an array with range()?

e.g. I want my array for postcode ranges such as array('AB1','AB2', 'AB3', 'AB4', 'AB5', 'Ab6', 'AB7', 'AB8', 'IV5', 'IV6', 'IV7', 'IV8', 'IV9', 'IV10');

I know I can do range(1,8); but was wondering if there was something along the lines of range("AB1", "AB8");

Function Prepare() On Null Mixing Object And Procedural

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Hi All,

I have the following code which works fine:

$mysqli = new mysqli("server", "user", "pass", "database");
if($mysqli->connect_error) {
exit('Could not connect');
}



$sql = "SELECT customer_contactname, customer_companyname, customer_phonenumber, customer_emailaddress, customer_address1, customer_address2, customer_city, customer_postcode
FROM ssm_customer WHERE customer_id = ?";

$stmt = $mysqli->prepare($sql);
$stmt->bind_param("s", $_GET['q']);
$stmt->execute();
$stmt->store_result();
$stmt->bind_result($ccontname, $ccompname, $cphoneno, $cemail, $cad1, $cad2, $ccity, $cpost);
$stmt->fetch();
$stmt->close();

however, when i use my dbconn.php as an include rather than the top section of this code, i get the following error: function prepare() on null

The error references the following

$stmt = $mysqli->prepare($sql);

In my database connection file, i am using the following:

$conn = mysqli_connect($db_servername, $db_username, $db_password, $db_name);

This seems to be the issue and i believe i am mixing procedural and object based but not sure why there should be a difference here?

when i used my database connection file, i do change $mysqli->prepare to $conn->prepare

Kind Regards

Edited February 4, 2019 by Adamhumbug

Mixing Html And Php Variable Names In An Echo Statement

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I'm trying to input the results from a query into html, but I'm just getting the variable names rather than their values. I used single quotes for the echo statement, but I think I must need to switch to double to do that. But then I have problems with the double quotes from the class names (ex. class="SideBoxTitle").

Code: [Select]
<?php
// get user's videos from database
$conn = mysqli_connect($dbhost, $dbuser, $dbpass)
or die("MySQL Error: " . mysql_error());

$query = "SELECT * FROM haas12_test.videos";

$result = mysqli_query($conn, $query)
or die ("Couldn't execute query.");

while($row = mysqli_fetch_assoc($result))
{
extract($row);

echo '
<div id="topBox"  class="mainVideoSideBoxes" >

      <div class="SideBoxTitle" ><h3> $vidtitle </h3> </div>
        <div class="sideBoxVidContainer">
            <div class="SideBoxScreenCast" > $vidurl </div>
            <div class="SideBoxDesc" ><p> $viddesc </p> </div>
        </div>

</div>

</div>
'; // end echo staement
}

?>

Dropdown Menu Mixing With Nav Menu

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So i have a <drop down> menu, and a <nav> menu on my left side of the page. I have a problem when i click at the first column of my drop down menu and it explores submenu, the submenu mixes with the nav menu that is under the drop down menu on the left. i could solve it with margin-top of the nav menu but i don't like the empty space beetwen them. I tried with putting overflow:visible; in CSS of my dropdown menu but it is still the same. drop down menu is seen but there is stil seen nav menu under and they are mixed. So basicly i want my dropdown menu to be priority, so when i clicks on my first column (only first column is problem because there under is nav menu the other are open nice) it will explore submenu and the part of nav menu that covers the submenu will be hidden. Here is the screen shot: Here is the code of head <dropdown> menu if someone finds the problem.

#menu, #menu ul {
	 
    margin: 0;
    padding: 0;
    list-style: none;
}

#menu {
	 
    width: 900px;
	margin-top:20px;
    margin-left:auto;
	margin-right:auto;
    border: 1px solid #222;
    background-color: #111;
    background-image: linear-gradient(#444, #111);
    border-radius: 6px;
    box-shadow: 0 1px 1px #777;
}

#menu:before,
#menu:after {
    content: "";
    display: table;
}

#menu:after {
    clear: both;
}

#menu {
    zoom:1;
}

#menu li {
	 
    float: left;
    border-right: 1px solid #222;
    box-shadow: 1px 0 0 #444;
    position: relative;
}

#menu a {
	 
    float: left;
    padding: 12px 30px;
    color: #999;
    text-transform: uppercase;
    font: bold 12px Arial, Helvetica;
    text-decoration: none;
    text-shadow: 0 1px 0 #000;
}

#menu li:hover > a {
    color: #fafafa;
}

*html #menu li a:hover { /* IE6 only */
    color: #fafafa;
}

#menu ul {
	
    margin: 20px 0 0 0;
    _margin: 0; /*IE6 only*/
    opacity: 0;
    visibility: hidden;
    position: absolute;
    top: 38px;
    left: 0;
    z-index: 1;    
    background: #444;   
    background: linear-gradient(#444, #111);
    box-shadow: 0 -1px 0 rgba(255,255,255,.3);  
    border-radius: 3px;
    transition: all .2s ease-in-out;
}

#menu li:hover > ul {
	
    opacity: 1;
    visibility: visible;
    margin: 0;
}

#menu ul ul {
	 
    top: 0;
    left: 150px;
    margin: 0 0 0 20px;
    _margin: 0; /*IE6 only*/
    box-shadow: -1px 0 0 rgba(255,255,255,.3);      
}

#menu ul li {
	 
    float: none;
    display: block;
    border: 0;
    _line-height: 0; /*IE6 only*/
    box-shadow: 0 1px 0 #111, 0 2px 0 #666;
}

#menu ul li:last-child {  
  
    box-shadow: none;    
}

#menu ul a { 
    
    padding: 10px;
    width: 130px;
    _height: 10px; /*IE6 only*/
    display: block;
    white-space: nowrap;
    float: none;
    text-transform: none;
}

#menu ul a:hover {
    background-color: #0186ba;
    background-image: linear-gradient(#04acec, #0186ba);
}

#menu ul li:first-child > a {
    border-radius: 3px 3px 0 0;
}

#menu ul li:first-child > a:after {
	 
    content: '';
    position: absolute;
    left: 40px;
    top: -6px;
    border-left: 6px solid transparent;
    border-right: 6px solid transparent;
    border-bottom: 6px solid #444;
}

#menu ul ul li:first-child a:after {
	 
    left: -6px;
    top: 50%;
    margin-top: -6px;
    border-left: 0; 
    border-bottom: 6px solid transparent;
    border-top: 6px solid transparent;
    border-right: 6px solid #3b3b3b;
}

#menu ul li:first-child a:hover:after {
    border-bottom-color: #04acec; 
}

#menu ul ul li:first-child a:hover:after {
    border-right-color: #0299d3; 
    border-bottom-color: transparent;   
}

#menu ul li:last-child > a {
    border-radius: 0 0 3px 3px;
}

Here is the code of <nav> menu if someone finds the problem.

#cssmenu {
	
	
	width:15%;
  padding: 0;
  margin-top: 50px;
  margin-left:auto;
  margin right:auto;
  float:left;
  border: 0;
  line-height: 1;
}
#cssmenu ul,
#cssmenu ul li,
#cssmenu ul ul {
  list-style: none;
  margin: 0;
  padding: 0;
}
#cssmenu ul {
  position: relative;
  z-index: 597;
  float: left;
}
#cssmenu ul li {
  float: left;
  min-height: 1px;
  line-height: 1em;
  vertical-align: middle;
  position: relative;
}
#cssmenu ul li.hover,
#cssmenu ul li:hover {
  position: relative;
  z-index: 599;
  cursor: default;
}
#cssmenu ul ul {
  visibility: hidden;
  position: absolute;
  top: 100%;
  left: 0px;
  z-index: 598;
  width: 100%;
}
#cssmenu ul ul li {
  float: none;
}
#cssmenu ul ul ul {
  top: -2px;
  right: 0;
}
#cssmenu ul li:hover > ul {
  visibility: visible;
}
#cssmenu ul ul {
  top: 1px;
  left: 99%;
}
#cssmenu ul li {
  float: none;
}
#cssmenu ul ul {
  margin-top: 1px;
}
#cssmenu ul ul li {
  font-weight: normal;
}
/* Custom CSS Styles */
#cssmenu {
  width: 200px;
  background: #333333;
  font-family: 'Oxygen Mono', Tahoma, Arial, sans-serif;
  zoom: 1;
  font-size: 12px;
}
#cssmenu:before {
  content: '';
  display: block;
}
#cssmenu:after {
  content: '';
  display: table;
  clear: both;
}
#cssmenu a {
  display: block;
  padding: 15px 20px;
  color: #ffffff;
  text-decoration: none;
  text-transform: uppercase;
}
#cssmenu > ul {
  width: 200px;
}
#cssmenu ul ul {
  width: 200px;
}
#cssmenu > ul > li > a {
  border-right: 4px solid #1b9bff;
  color: #ffffff;
}
#cssmenu > ul > li > a:hover {
  color: #ffffff;
}
#cssmenu > ul > li.active a {
  background: #1b9bff;
}
#cssmenu > ul > li a:hover,
#cssmenu > ul > li:hover a {
  background: #1b9bff;
}
#cssmenu li {
  position: relative;
}
#cssmenu ul li.has-sub > a:after {
  content: '+';
  position: absolute;
  top: 50%;
  right: 15px;
  margin-top: -6px;
}
#cssmenu ul ul li.first {
  -webkit-border-radius: 0 3px 0 0;
  -moz-border-radius: 0 3px 0 0;
  border-radius: 0 3px 0 0;
}
#cssmenu ul ul li.last {
  -webkit-border-radius: 0 0 3px 0;
  -moz-border-radius: 0 0 3px 0;
  border-radius: 0 0 3px 0;
  border-bottom: 0;
}
#cssmenu ul ul {
  -webkit-border-radius: 0 3px 3px 0;
  -moz-border-radius: 0 3px 3px 0;
  border-radius: 0 3px 3px 0;
}
#cssmenu ul ul {
  border: 1px solid #0082e7;
}
#cssmenu ul ul a {
  font-size: 12px;
  color: #ffffff;
}
#cssmenu ul ul a:hover {
  color: #ffffff;
}
#cssmenu ul ul li {
  border-bottom: 1px solid #0082e7;
}
#cssmenu ul ul li:hover > a {
  background: #4eb1ff;
  color: #ffffff;
}
#cssmenu.align-right > ul > li > a {
  border-left: 4px solid #1b9bff;
  border-right: none;
}
#cssmenu.align-right {
  float: right;
}
#cssmenu.align-right li {
  text-align: right;
}
#cssmenu.align-right ul li.has-sub > a:before {
  content: '+';
  position: absolute;
  top: 50%;
  left: 15px;
  margin-top: -6px;
}
#cssmenu.align-right ul li.has-sub > a:after {
  content: none;
}
#cssmenu.align-right ul ul {
  visibility: hidden;
  position: absolute;
  top: 0;
  left: -100%;
  z-index: 598;
  width: 100%;
}
#cssmenu.align-right ul ul li.first {
  -webkit-border-radius: 3px 0 0 0;
  -moz-border-radius: 3px 0 0 0;
  border-radius: 3px 0 0 0;
}
#cssmenu.align-right ul ul li.last {
  -webkit-border-radius: 0 0 0 3px;
  -moz-border-radius: 0 0 0 3px;
  border-radius: 0 0 0 3px;
}
#cssmenu.align-right ul ul {
  -webkit-border-radius: 3px 0 0 3px;
  -moz-border-radius: 3px 0 0 3px;
  border-radius: 3px 0 0 3px;
}

Edited by Dorkmind, 26 November 2014 - 05:00 PM.

Php Sessions

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I am new to SESSIONS and have a quick question about them.

I want to use sesssions on my site but was wondering if they would work for the follow senario.

Say a customer visits my url: http://www.mysite.com/?id=2

Now what i am doing is taking the id out of the URL using sessions and redirecting the user to http://www.mysite.com while my session ($_SESSION['id']) holds the value 2 in it. I have this working great, i believe it just looks better.

Now if my customer decides to buy my product via paypal and is directed off my site while he/she is paying for said item on paypal when they return could i still use some of the information that i stored in my session??

I know i could use post and get to pass through paypal but unfortunately i have to use sessions for what i am trying to do.

Help? (sessions)

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Basically I am trying to make a login with sessions but its just not working. Can someone look and see for any errors in what I wrote or snippet suggestions?
<?php
    //Start session
    session_start();

    //Include database connection details
    require_once('config.php');

    //Array to store validation errors
    $errmsg_arr = array();

    //Validation error flag
    $errflag = false;

    //Connect to mysql server
    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
        die('Failed to connect to server: ' . mysql_error());
    }

    //Select database
    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {
        die("Unable to select database");
    }

    //Function to sanitize values received from the form. Prevents SQL injection
    function clean($str) {
        $str = @trim($str);
        if(get_magic_quotes_gpc()) {
            $str = stripslashes($str);
        }
        return mysql_real_escape_string($str);
    }

    //Sanitize the POST values
    $username = clean($_POST['username']);
    $password = clean($_POST['password']);

    //Input Validations
    if($username == '') {
        $errmsg_arr[] = 'Username missing';
        $errflag = true;
    }
    if($password == '') {
        $errmsg_arr[] = 'Password missing';
        $errflag = true;
    }

    //If there are input validations, redirect back to the login form
    if($errflag) {
        $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
        session_write_close();
        header("location: login.php");
        exit();
    }

    //Create query
    $qry="SELECT * FROM users WHERE AND username='$username' AND password='$password'";
    $result=mysql_query($qry);

    //Check whether the query was successful or not
    if($result) {
        if(mysql_num_rows($result) == 1) {
            //Login Successful
            session_regenerate_id();
            $member = mysql_fetch_assoc($result);
            $_SESSION['SESS_MEMBER_ID'] = $member['member_id'];
            $_SESSION['SESS_USERNAME'] = $member['username'];
            $_SESSION['SESS_EMAIL'] = $member['email'];
            $_SESSION['SESS_BETAKEY'] = $member['betakey'];
            $_SESSION['SESS_PIN'] = $member['pin'];
            session_write_close();
            header("location: member-index.php");
            exit();
        }else {
            //Login failed
            $errmsg_arr[] = 'Username/Password Invalid';
            $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
            session_write_close();
            header("location: login.php");
            exit();
    }
    }else {
        die("Query failed");
    }
?>

Sessions

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Im makigna simple login system for a sight but i only want them to have to login if they want to go to the shopping cart i have t implement a session_start() on every page before the cart page so the home page products page etc etc and then on the cart page ive a simple function that checks if their logged in if not then it will direct them to the login page if they are they should just continue is this the correct way to do it ?

thanx

Php Sessions Help

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Kind of a n00b here.

on my main table (users) i named a column as "id", set it to auto-increment and as the primary key and created it like this:

CREATE TABLE `users` (
`id` int(20) NOT NULL auto_increment,
`full_name` varchar(200) collate latin1_general_ci NOT NULL default '',
`user_name` varchar(200) collate latin1_general_ci NOT NULL default '',
`user_pwd` varchar(200) collate latin1_general_ci NOT NULL default '',
`user_email` varchar(200) collate latin1_general_ci NOT NULL default '',
`activation_code` int(10) NOT NULL default '0',
`joined` date NOT NULL default '0000-00-00',
`country` varchar(100) collate latin1_general_ci NOT NULL default '',
`user_activated` int(1) NOT NULL default '0',
PRIMARY KEY (`id`)
)

On the second table i created it like this:

CREATE TABLE about_me
(
about_id int NOT NULL,
nick_name varchar(255),
descript varchar(255),
aim varchar(255),
cell varchar(255),
school varchar(255),
music varchar(255),
aspire varchar(255),
City varchar(255),
id int,
PRIMARY KEY (about_id),
FOREIGN KEY (id) REFERENCES users(id)
)

I believe i imported the key correctly into my new table (about_me).

Well I expected the id column to cascade down into this new table automatically which it didn't. RIght now if you log into my site and use the about me form, it posts to the new table "about_me" but it doesn't identify the user on the table with the primary key assigned to him from the first table (users). How do I use PHP sessions to identify the user by his/her id from the primary key in the table.

I attached the whole site. The php for the log in is a prefab and I'm attempting to do the about me part on my own, I'm having alot of trouble with the whole sessions thing.

I'm not really sure if I'm doing this correctly. so yeah any point in the right direction would be awesome!
-Mike

Ie And Sessions

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Hi

Something strange is happening and I can't understand it.

A user can access an availability page of accommodation and book ita room, this works fine, and goes from availability to the booking form and back quite well, carrying the room id of the accommdation and room/s selected in a session.

If they close the browser down and open the availability page again all the rooms are there as before, but when they select a room and go to the booking form the session of the room id and the rooms selected are empty.

If I do a session destroy and open the browser up again everything works fine again.

I have tried this in Chrome and Firefox and it seems to work fine

Any help would be appreciated

Sessions

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Hello everyone,

i'm new to php and i'm having hard time with sessions

i'm trying to create a php file with a drop down menu and when you select an item from the drop down menu, you could retreve it from another page.

for example:

a1.php

Code: [Select]
<?php session_start();
if(isset($_POST['color']))
{
$_SESSION['blue']='blue';
$_SESSION['red']='red';
$_SESSION['green']='green';
$_SESSION['orange']='orange';
}
?>
<html>
<body>
<form id="shirt" method="post" action="a2.php">
<p>
<select name="Size">
<option value="invalid">Select a size ...</option>
<option value="blue">blue</option>
<option value="red">red</option>
<option value="green">green</option>
<option value="orange">orange</option>
</select>
<br />
<input type="Submit" value="Add" name="Add" />
</p>
</form>
</body>
</html>

when the user chooses a color, it adds it to the session and then when the user clicks add, he is redirected to another page named a2.php which shows the color is added.

if the user goes back to the original page and adds the same color again it shows that he added the item again:

Color: ----------- Quantity:
Red ----------- 2

a2.php

Code: [Select]
<?php session_start();
$item_id = $_GET[id];
$action = $_GET[action];

switch($action)
{

case "add":
$_SESSION['color'][$item_id]++;
break;

case "remove":
$_SESSION['color'][$item_id]--;

if($_SESSION['color'][$item_id] == 0) unset($_SESSION['color'][$item_id]);
break;

case "empty":
unset($_SESSION['color']);
break;

}
?>

sorry if my question is not clear,

any help is appreciated

Thank You,

Sessions?

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I am trying to create a blog and visitor log, where I should be able to log in as admin and add the item and see the visitor log.
I want a password protected administration section and I want to use sessions on the administration section.

When I for example click on add post, I want it to log in and go to page addpost.php where I can enter my text.

This is what I've done so far. I would like to know what I have done wrong and how I should do to accomplish what I have mentioned above.

<?php
session_start();
if(isset($_POST['btnLogin']) || isset($_POST['addpost'])){
$txtUserId = $_REQUEST['txtUserId'];

$txtPassword = $_REQUEST['txtPassword'];

if (isset($_POST['txtUserId']) && isset($_POST['txtPassword'])) {

if ($_POST['txtUserId'] === 'admin' && $_POST['txtPassword'] === 'abc123') {

//$_SESSION['basic_is_logged_in'] = true;

echo "you are logged in";

}

elseif (empty($txtUserId) || empty($txtPassword))

{
echo "fill in username and password";
}
elseif ($_POST['txtUserId'] != 'admin'){

echo "wrong username";

}

elseif ($_POST['txtPassword'] != 'abc123'){
echo "wrong password";

}
}
}
?>
<?php
//if (!isset($_SESSION['basic_is_logged_in'])
//   || $_SESSION['basic_is_logged_in'] !== true)

?>

<html>
<head>
<title>Main User Page</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
</head>

<body>

<form method="post" name="frmLogin" id="frmLogin" action="main.php">
<table width="400" border="1" align="center" cellpadding="2" cellspacing="2">
<tr>
<td width="150">User Id</td>
<td><input name="txtUserId" type="text" id="txtUserId"></td>
</tr>
<tr>
<td width="150">Password</td>
<td><input name="txtPassword" type="password" id="txtPassword"></td>
</tr>
<tr>
<td><input type="submit" name="btnLogin" value="Login"></td>
</tr>
<tr>
<td><input type="submit" name="addpost" value="add post" /></td>
</tr>
<tr>
<td><input type="submit" name="showstat" value="Show visitors log" /></td>
</tr>
<tr>
<td><input type="submit" name="blogg" value="To blog (logout)" /></td>
</tr>

</table>
</form>

</body>
</html>

Sessions

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Hello,
Is there a problem in destroying a session and then starting it in the same file, for example:

session_name();
session_start();

session_destroy();

And lastly, if I create a variable $_SESSION['user'] under a session called 'one' i.e. session_name("one") and then create another variable $_SESSION['user'] under a session called 'two' i.e. session_name("two").
Are these two variables the same?

Sessions

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Hi all,

If I have a list of session ids, is it possible to use this list to determine which session is no longer active? Seems like it should be do-able but can't find help on it so I'm kinda guessing its not!

Thanks for any help,

Michael

Sessions Help

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I am in the process of opening my web site to the general public. Right now you have to have a username and password to see anything on the site. What I am looking to do is make it so anyone can see most things on the site. There will still be user accounts for things like admins and submitting ideas. What i have now is some links that look at the user rank and only show up if you are higher then a rank. What I need to do is make it so you don't need to log in to see the site but you still need to log in to edit things.

Here is my sessions scrip
Code: [Select]
<?php session_start();
if(!$_SESSION['login']){
$_SESSION['rank'];
$_SESSION['loggedinusername'] = $loggedinusername;
$_SESSION['loggedinuseremail'] = $loggedinuseremail;
header("location:login.php");
}
$rank=$_SESSION['rank'];
$loggedinusername=$_SESSION['loggedinusername'];
$loggedinuseremail=$_SESSION['loggedinuseremail'];
?>

How do I edit this so you are free to move around the site even if your not logged in?

Thanks

Sessions

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hey i think i may have stored session variables incorrectly
Code: [Select]
$_SESSION['tel'] = $_GET['Lat'];
$_SESSION['Lon'] = $_GET['Lon'];
$_SESSION['Lat'] = $_GET['Lat'];
is what i used to set the session variables with the data i then enter these into a table and they enter the correct information but two pages down the line i try to access them however i just get undefined variable when i set the variable is equal to the session.
Code: [Select]
$MyLon = $_SESSION['Lon'];
$MyLat = $_SESSION['Lat'];

the following is the errorr Quote

Notice: Undefined index: Lat in

Please Help With Sessions!

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I got a log-in form with database, it only logs if such username and password exists. I was told that if i wanna make a log-out button once logged-in, i need to add sessions to my code and idk how..

this is my code that checks if username/password exists, and if so it lets u log in, if not it displays a msg:

if(isset($_POST['loginsubmit'])){
if($username !="" && $password !="") {

///////////////////////////////Check for username/pass in database////////////////////////////
$nameexists = false;
$passexists = false;
$result = pg_query("SELECT name FROM duom WHERE name='".$username."'");
while ($row = pg_fetch_array($result)) {
if($row['name'] != ""){
$nameexists = true;
}
} if($nameexists) {
$result = pg_query("SELECT pass FROM duom WHERE name='".$username."'");
while ($row = pg_fetch_array($result)) {
if($row['pass'] == $password){
$passexists = true;
echo "Prisijungimas pavyko, jusu vartotojo vardas - ".$username."";
include"loggedinform.php";
} else {
echo "Slaptazodis netinka!";
}
/////////////////Starts session if password is correct////////////////////////////////////////////
if ($passexists){
//Here i want it to start the session if password is correct
}
//////////////////////////////////////////////////////////////////////////////////////////////////////////
}
} else {
echo "Tokio vartotojo nera!";
}
//////////////////////////////////////////////////////////////////////////////////////////////////////////

} else {
echo "Uzpildykite visus duomenys!";
}
}

Cant i just make smth like this?

if ($passexists){
session_start();
}