PHP - Adding 'include' Into A Variable?
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Similar TutorialsHey Guys. I am trying to include a file. The file path gets returns from an objects method. When a run is_file() on the returned data it returns true, but does not include it!!! Can anyone please help me solve this!!
class StoreInitialization { public function loadConfigFile(){ $config_file="../store/demo/store_configuration.php"; return $config_file; }Client Code $store_config_file = $store_initialization->loadConfigFile(); require($store_config_file); Hi all I have a string in an include file for a javascript lightbox value. I need this value to increase by one every time it loops. Here's my code: $fetchproducts = mysql_query(" SELECT * FROM `products` "); while($returnedProduct = mysql_fetch_array($fetchproducts)) { include('product-cell.php'); } The string is called $lightboxcount in the product-cell.php file Can I fit a ++ into the code above? Many thanks for your help Pete This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=352099.0 Hi all I am writing a code to update customer details. It all works great until I get to the last line of code that directs the user to the next page: include ('profile-success.php'); I need it to be the following page: profile-success.php?username=$username Can anyone show me how to edit the line to include the url variable? I keep getting this error: Warning: include() [function.include]: Failed opening 'profile-success.php?username=$username' for inclusion (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home/cndvizp/public_html/prints2impress.co.uk/upload/update-profile.php on line 96 Thanks Pete. I want to include a variable (for example an object $user) in each PHP page. Previously I declared $var in an include file then included that file in every page, however it generates an error in Zend Studio and it's also not very good programming style. I want to know how I can do it any other way. I was thinking of using constants but I don't know if constants should be used for this purpose and also I do not think constants can be defined as objects. Thank you very much for your help. I am developing a page that displays info from a database based on a variable called "ID". On this page is a form that when submitted runs an external function file to first error check the form and then insert it into the database. The problem i'm having is if i include the page which had to form to display the error message on, it doesn't load the right info from the database because its not loading based on the ID. So is there an alternative way to write: include ("toDo.php?ID=".$ToDoID); Any help is much appreciated.
Hi All, I've been trying to access xml data from an API feed, but it needs a Variable to be passed to an include file without a form. the include is at the header of the page. in the code below, i'm trying to retrieve the variable $project_add from the $xml_2 feed. $proj_add_ID comes from another feed and is being passed ok. foreach ($projects_1 as $proj_1) { $job_no =$proj_1['job_no']; $job_name =$proj_1['job_name']; $job_status =$proj_1['job_status']; $job_staff =$proj_1['job_staff']; $job_due =$proj_1['job_due']; $clr_1 = $colors_1[$job_status]; if ($err_2) { echo "cURL Error #:" . $err_2; } else { $_POST['job_id']= $job_no; $xml_2=simplexml_load_string($response_2) or die("Error: Cannot create object"); $proj_add = $xml_2->xpath("CustomFields/CustomField[ID ='$proj_add_ID']"); foreach($proj_add as $item_2) { $project_add = "$item_2->Text"; } echo "<div class='row no-gutters'>"; echo "<div class='col-sm bg-white border rounded'><a href='managejob.php?job_id=$job_no' class='text-left ml-1'><strong>$job_no</strong></a></div>"; echo "<div class='col-sm-2 bg-white border rounded'><p class='text-left ml-1'>$job_name</p></div>"; echo "<div class='col-sm-2 bg-white border rounded'><p class='text-left ml-1'></p>$project_add</div>"; echo "<div class='col-sm-2 bg-white border rounded'>" . state_dropdown_1($job_no, $job_status, $clr_1) . "</div>"; echo "<div class='col-sm-2 bg-white border rounded'><p class='text-left ml-1'>$job_staff</p></div>"; echo "<div class='col-sm-2 bg-white border rounded'><form action='CALL_API_PUTTaskDate.php' method='POST'>" . "<input type='hidden' name='task_ID' value ='". $jdata['task_ID'] ."'>" . "<input type='hidden' name='est_min' value ='". $jdata['est_min'] ."'>" . "<input class ='form-control bg-white text-dark font-weight-bold' type='date' name='start_date' value='" . date('Y-m-d', strtotime( $jdata['display_date_1'] )) . "' onchange='this.form.submit()'>" . "</form></div>"; echo "<div class='col-sm bg-white border rounded'><p class='text-left ml-1 mt-1'><strong>" . date('d/m/Y', strtotime( $jdata['display_date'])) . "</strong></p></div></div>"; } The include file is like this / collect Custom Felds if ($_SERVER["REQUEST_METHOD"] == "POST") { // collect value of status input field $job_no = $_REQUEST['job_id']; } if (isset($_POST['job_id'])) { $job_no = $_POST['job_id']; } if (isset($_GET['job_id'])) { $job_no = $_GET['job_id']; } $curl_2 = curl_init(); curl_setopt_array($curl_2, array( CURLOPT_URL => "https://api.xxx.com/job.api/get/$job_no/customfield?apiKey=xxx&accountKey=xxx", CURLOPT_RETURNTRANSFER => true, CURLOPT_ENCODING => "", CURLOPT_MAXREDIRS => 10, CURLOPT_TIMEOUT => 30, CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1, CURLOPT_CUSTOMREQUEST => "GET", CURLOPT_HTTPHEADER => array( "Accept: */*", "Accept-Encoding: gzip, deflate", "Cache-Control: no-cache", "Connection: keep-alive", "Host: api.xxx.com", "Postman-Token: xxx", "User-Agent: PostmanRuntime/7.17.1", "cache-control: no-cache" ), )); $response_2 = curl_exec($curl_2); $err_2 = curl_error($curl_2); curl_close($curl_2); The problem is the variable $job_no isn't getting passed to CURLOPT_URL so it's not retrieving the data required. i need to be able to retrieve this data without submitting a form as it's in a foreach loop and the Id is specific to each iteration. is there a way to do this? I have been able to achieve this by putting the include within the div tags that it will be displayed but it just slows down everything too much and hangs. Any help will be much appreciated. Kind regards, Michael Bennington. Hello I have a website that I am trying to upgrade so that all the data can be placed into a MySql database. I know what I need but I do not know if it is possible with PHP and MySql. I need to insert into a Href link a variable so that when the link is clicked it would initiate a MySql search for data. The variable would contain the Key id of the person whose name was clicked. This is very difficult to explain so a visit to the static website may help understand what I am trying to achieve, www.westonheritage.co.uk If you go to the second page by clicking the key then click on any of the surnames listed. I have the database setup on localhost and can get out the data I require. Kind regards My catalog uses a template file to list product details. One part of it is responsible for putting these details into nifty little tabs: <?php $template = '{magictabs style=black_rounded, tabwidth=110px}'; $template .= 'Technical Specifications'; $template .= '::'; $template .= '<table colspan="3"><tr><td>'; $template .= $details; $template .= '</td></tr></table>'; $template .= '||||'; ?> I don't want it to output $details, I want it to output a separate script instead. How do I include this separate file as a variable? I want this: <?php include('specs.php'); ?> to replace the $details variable. Hello all, I am a beginner at PHP and trying to form an IF statement, I'm running into a problem which I cannot seem to solve. Due to my lack of syntax knowledge I would appreciate if someone could point me in the right direction. The combo variables are sent to this page through a form and defined as these variables at the top of the page. e.g $combo0 = $_POST["combo0"]; When the results are displayed any form field which was left blank or empty I want to show "N/A" if data is detected in being sent through the form I then want the "Else" statement to take affect. Currently when I run the below statement N/A is echoed despite if data was sent through the form fields or not.... if (empty($scrap)) { echo "<h3>Submitted Scrap Results</h3> No scrap parts were booked off"; } elseif (empty($combo0) || empty($combo1) || empty($combo2) || empty($combo3) || empty($combo4)) { echo "N/A"; } else { echo "<h3>Submitted Scrap Results</h3> <b>Reason:</b> " .$combo0." - ".$combo1." - ".$combo2." - ".$combo3." - ".$combo4." <br /> <b>on machine</b> " .$mid. " - <b>No. Scrap</b> " .$noscrap. ""; } Anyone any ideas? Ok it's abit complicated so i'll try to explain as best as I can. Upon registration a file is created with your username that was registered and also a file for your profile named after your username so it would be /profiles/usernamesprofilehere.php. I put a code into the profile that is: Code: [Select] include ("/home/giacjrdi/public_html/mysite/profiles/profileinfo/$username.info.php"); echo "<center><b><br /> $user's Profile <br /></b></center>"; $username is calling the cookie's username while $user is calling the account's username. eg if I try to view "bob"'s profile but logged in as "fred" since the include function is under $username which is cookies, it will retrieve "fred"'s information and post it on "bob"'s profile. The only sollution i can think of would be to store a username variable in the url and use it for the include function. Hi all, I am trying to add the echo " AND "; below to the variable $model if the $_POST['purchasetype'] has a value. how can you add echos within IF statements to a variable, if at all possible? Many thanks, <?php if ($_POST[model] !="") { $model = "model='". $_POST['model'] ."'"; if ($_POST['purchasetype'] !="") { echo " AND "; } } else { $model = ""; } ?> Hi im trying to set that if a certain statement is echoed then set variables to an amount but they dont seem to be inserting into the table Code: [Select] if ($match_qutoe == "".$username2." lands a uppercut"){ $points = "4"; $fighter = $username2; } $query = mysql_query("INSERT INTO fight (bluecornerusername, redcornerusername, round, fighter, points, statement) VALUES('$username', '$username2', '$round', '$fighter', '$points', '$match_quote')"); its only $points and $fighter that are not inserting Thanks Hi, I'm just starting PHP and I ran into a simple problem (that I can fix), but I just want to understand why my first approach doesn't work. I was testing multiplications and additions and the result I got was unexpected. Here is the code that doesn't work: Code: [Select] <?php $number1 = 5; $number2 = 10; print $number1." multiplied by ".$number2." + 1000 = ".$number1*$number2+1000; ?> Obviously, what I want as a result when I'm displaying the page is: "5 multiplied by 10 + 1000 = 1050" What I get: "1005". That's right, nothing else. On top of getting an erroneous answer, the sentence that's supposed to display right before the equation doesn't display at all. It's even worse if I switch it around like that: Code: [Select] print $number1." multiplied by ".$number2." + 1000 = ".1000+$number1*$number2; I get an error message and nothing displays. The obvious solution works: using a parenthesis at the beginning and at the end of the equation, which I should do regardless, but still, it's bugging me and since I just started learning PHP today, I want to understand how the code is compiled / interpreted so I don't make stupid mistakes like this one. Thanks in advance for the replies. I cant figure out how to add $recieved into this needs to take place of time hope someone knows how to do this what im doing is adding in the UNIX time i want to offset Code: [Select] <?php $offset = date('m/d/Y/H:i:s', time()+$send1['time_offset']); ?> Hi, I have two variables: $latest_note and $notes. Whenever I update $latest_note, I also want this (and today's date) to be added to $notes, such that $notes becomes a sort of archive of all of the latest notes, listed by date. I tried creating a third variable called $full_notes and saying $full_notes = $latest_note.$notes; ... then when I run my mysql update, I set notes='$full_notes' but it's not working properly. Is there a way to simply add one variable to the beginning of another in the db directly, concatenating the two? Thanks! This is what I have $eeee = $_POST['forum_reply']; $eeee = strip_tags($eeee, '<p>'); echo $eeee; this is what prints out Quote Untitled document testinggg this is a print_r of $_Post Quote Array ( [forum_reply] => testinggg [form_reply_submit] => Reply ) Please someone tell me what in binary's name is going on! CanI put one INCLUDE statement INSIDE of another INCLUDE statement? Hi Guys.. Merry Christmas Im kinda new to this fantastic world of PHP and i have a little problem i hope you can help me with. Im trying to build a website where I use include() to genereate my content. On my index.php i have a menu which includes content in a content div from external .php pages, my structure kinda goes like this.. (simplified) site/ index.php content/ fronpage.php products.php contact.php The HTML looks like this. <div id="menu"> <ul> <li><a href="index.php?page=frontpage">frontpage</a></li> <li><a href="index.php?page=products">frontpage</a></li> <li><a href="index.php?page=contact">frontpage</a></li> </ul> </div <div id="main"> <?php include('/content/'.$_GET['page'].'.php'); ?> </div> This all works very fine, but my problem is, can I have a include inside an already included page? I would like to have a menu on my products.php site, but that page is already included from above, and i would like the menu on the products.php site to stay as the content from the nested include changes with input from the /products folder. my idea was something like this. site/ index.php content/ frontpage.php products.php contact.php products/ product1.php product2.php the HTML on the index.php is the same as above and then i would add the include() on the products.php page, so its kinda the same thing, but one inside the other. HTML inside the products.php folder <div id="sub_menu"> <ul> <li><a href="#">frontpage</a></li> <li><a href="#">frontpage</a></li> <li><a href="#">frontpage</a></li> </ul> </div <div id="sub_main"> <?php include('/content/products'.$_GET['#'].'.php'); ?> </div> I dont know how to link to the new files so they will be included while the first include still stays on the page. Any of you know how and if this can be done? Or maybe at better way to do it? Hope this made sense, my first PHP question Thanks Hi Still a new comer when it comes to PHP. I have a situation where I want to use an include within an include and I am having trouble with my file paths. My main header include, includes everything for each page of my site, beyond the opening of the body to incorporate my navigation etc conditionally loading in css, and loading in titles and meta data etc depending on the page in question. This header needs to reference another include called the-pod.php which is required for every page, the only trouble is I want to use / to reference the root of the server and this is breaking my code. I can't use ../../ etc as its a different path depending on where the master file is located. So my question is how do I get around this? Can the root of the server or path to the root be stored in a variable? and if so how would I write this. Any tips / advice will be greatly appreciated. |