PHP - Echo Out On One Line?

OK, have no idea what's going on... I've done this a million times... why wont this output!??
I must have a major brain meltdown and dont know it yet!!!

Code: [Select]
<?php

// this echoes just fine:
echo $_POST['testfield'];


// but this wont echo:
echo 
if (isset($_POST['testfield']))
{
$_POST['testfield'] = $test;
}
echo $test;


/// or even this DOESNT echo either!:
$_POST['testfield'] = $test;
echo $test;

?>

Hi All,

I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result.

Please help?

<?php   
$mysqli = mysqli_connect("removed", "removed", "removed", "removed");  
$sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'";  
$result = mysqli_query($mysqli, $sql);   
echo {$result['message']}; 
?>

what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video
after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

to do this i know that i need something like this to get the URL of the video
http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)
but how to only return just the URL is something idk how to do

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL


this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol

i have to read a single line from a csv,  its a really big file and i only need one column. i need the response to be a string ,i made a search and found the following code but i dont have any idea how to get a single line from a single string per run .

<?php
$row = 1;
//open the file
if (($handle = fopen("file.csv", "r")) !== FALSE)
{
    while (($data = fgetcsv($handle, 0, ",")) !== FALSE)
    {
        $num = count($data);
        echo "<p> $num fields in line $row: <br /></p>\n";
        $row++;
        for ($c=0; $c < $num; $c++)
        {
            echo $data[$c] . "<br />\n";
        }
    }
    fclose($handle);
}
?>

Edited by bores_escalovsk, 16 May 2014 - 06:38 PM.

Dear All

           Good Day, i am new to PHP (a beautiful server side scripting language). i want to send a mail with line by line message i tried with different types like by placing the things in table and using  <br /> but the thing is the tags are also visible in the message of the mail.

Here is my code:

$message1  = "Name       :".  $_REQUEST['name']."<br />";
$message1 .= "Surname    :".  $_REQUEST['surname']."<br />";
$message1 .= "Cellphone  :".  $_REQUEST['mobileno']."<br />";
$message1 .= "Telephone  :".  $_REQUEST['landno']."<br />";
$message1 .= "Fax        :".  $_REQUEST['fax']."<br />";
$message1 .= "Company    :".  $_REQUEST['company']."<br />";
$message1 .= "Email      :".  $_REQUEST['email']."<br />";
$message1 .= "Country    :".  $_REQUEST['country']."<br />";
$message1 .= "Enquity    :".  $_REQUEST['enquiry']."<br />";
$message1 .= "Date&Time  :".  $date."<br />";

For this code if try to print/echo it it is working fine it is displaying line by line, but using this variable ($message1) in the mail these <br /> are also visible.
Can any one guide me to resolve(to remove these tags from the message part) this issue.
Thanks in Advance. :confused:

Hi.

I want a simple textbox, that when submited, will replace very every new line, with the <br> tag.

What will happen, when it submits, it will take the contents of a textbox, add the <br> tag where a new line is suposed to be, and save the string to a MySQL Database.

I think this is the easiest way of allowing a user to edit what appears on a website when logged in, but if there is a easier way, then please tell me.

What I am trying to do, is a login page, and once logged in, you enter new text into the textbox, click submit, and on the website homepage, the main text will change to what was submitted. But if there is a new line, I think the only way in HTML to make one is to put a <br> tag, so I want the PHP to but that tag wherever there is a new line.

Sorry if I am confusing, I am not that advanced at PHP, but I would be very happy if you could supply me with the correct code. Time is running out...

If you do not understand me, please tell me

--
PHPLeader (not) 

So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code:


$con = mysql_connect("$host","$username","$password");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("main", $con);

$result = mysql_query("SELECT * FROM Vendor");

while($row = mysql_fetch_array($result))
  {
//I need to echo right here  .................. but I get a blank page when I try this. Please Help.
  echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>';
  }

mysql_close($con);

Result: A Blank page.
Thanks in advance!

I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas?

I have a script that reads a .gz file into an array and prints the name of each record but will not work on larger files. Is there a way to read 1 line at a time?
Here is the code I have so far.
Code: [Select]
<?php

if ($handle = opendir('.')) {

print "<ol>";
    
    while (false !== ($file = readdir($handle))) {
if($file != '..' && $file!="." && $file!="start_update.php" && $file!="sharons_dbinfo.inc.php" && $file!="root.php" && $file!="read_directory.php" && $file!="read_dir.php" && $file!="new_category.php" && $file!="index.php" && $file!="file_count.php" && $file!="dir_loop2.php" && $file!="dir_loop1.php" && $file!=".htaccess" && $file!="Answer.txt" && $file!="Crucial_Technology-Crucial_US_Product_Catalog_Data_Feed.txt"){
$filename = $file;
$go = filesize($filename);
if($go >= 1){
$filename2 = explode("-", $filename);
$filename2 = $filename2[0];
echo str_replace("_"," ",$filename2) . ' | Filesize is: ' . filesize($filename) . ' bytes<br>';
$gz = gzopen($filename, 'r');
$lines = gzfile($filename,10000);
foreach ($lines as $line) {
$line2 = explode(",", $line);
$line2 = str_replace("," , "-" , $line2);
    echo "<li>".str_replace("," , "-" , $line2[4])."</li><br>";
}

}
}
    }

    closedir($handle);
}
?>
</ol>

Hi   I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems. 1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?

for($x = 1;$x<=40;$x++) {
		$lines = file("$filename.html");
        echo $lines[rand(0, count($lines)-1)]."<br>";
        }

I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text  without the html code?P.S file_get_contents doesn't work either have tried that one.     2nd Problem:   As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file?   My code:

if($_POST['submitPasswordIT']){
if ($_POST['passIT']== $password ){
$my_file = file_get_contents("$filename.html");
echo $my_file;
}
else{
echo "You entered wrong password";
}
}

If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that.   

I'm so sorry to ask such a "newbee question," but believe me I have been on Google for the better part of the week trying to find an answer.   I'll start with the brief question. Then I'll give an example to show what I mean. Then, I'll give the BESTEST "pseudo-code" I could come up with (to PROVE that I've really given it my best).   Question: How do I make PHP loop through a big file, make the changes line by line, and to save the resultant file.   Example: I have a 100mb text file ("animals.txt") with 500,000 lines. If any lines have the word "cat" in it, I want to add "Be careful with cats!" to the end of the line:   From this: A fish and his tank. A cat and his toy. A bird and her cage. A frog and his lilly. A cat and her friend.   To this: A fish and his tank. A cat and his toy. Be careful with cats! A bird and her cage. A frog and his lilly. A cat and her friend. Be careful with cats!   The best "pseudo-code" I can come up with is:   <?php $data = file_get_contents("animals.txt"); $lines = explode(PHP_EOL,$data);

I want my application will send a email after 10 minutes of sending another email.

In my application

A user completes registration with payment Application sends the user a payment confirmation email

Now I want to

send another email 10 minutes After payment confirmation email with welcome tips

Below is the function where for user setup .

 

public function finishUserSetup($Sub){

    if($Sub == 0){
        $subscription = SubscriptionPlans::where('identifier', '=', "Monthly")->first();
        $expiry = date('Y-m-d', strtotime('+' . $subscription->months . ' months'));
        $sub_period = "monthly";
    
    } else{
        $subscription = SubscriptionPlans::where('identifier', '=', "Annually")->first();
        $expiry = date('Y-m-d', strtotime('+' . $subscription->months . ' months'));
        $sub_period = "annually";
    }

    $this->expiry_date = $expiry;
    $this->user_type = "SUB";
    $this->subscription_period = $sub_period;
    $this->update();

    $replaceArray = array(
        'fullname' => $this->forename . " " . $this->surname,
        'subscriptionName' => $subscription->name,
        );
    EmailTemplate::findAndSendTemplate("paymentconfirm", $this->email, $this->forename . " " . $this->surname, $replaceArray);

  }

In the above function the last line of code is the one which sends a payment confirmation email to the user which is

EmailTemplate::findAndSendTemplate("paymentconfirm", $this->email, $this->forename . " " . $this->surname, $replaceArray);

I want to execute the following line of code 10 minutes after the above one

 

EmailTemplate::findAndSendTemplate("WelcomeTips", $this->email, $this->forename . " " . $this->surname, $replaceArray);

 

 

How to do that. that is running the last line of code 10 minutes after  

Code: [Select]
<?php
$sum_num = mysql_query("SELECT SUM(likes) as totallikes FROM facebook");
echo $sum_num;

?>


i got this result Resource id #27
how to get a number only?
 

How do I echo the day from the db? It just displays day and I want it to display the day that was set.


<select name="date_of_birth" id="date_of_birth">
<option value="">Day</option>
<?php 

$isset = isset($_POST['date_of_birth']);

for($day = 1; $day <= 31; ++$day)
{
echo '<option';

if ($isset && $_POST['date_of_birth'] === $day)
{
echo ' selected="selected"';
}

echo ">${day}</option>\n\t\t\t\t\t\t";
}

?>
</select>

Code: [Select]
<span class="hotspot" onmouseover="tooltip.show('User ID :');" onmouseout="tooltip.hide();">
i want to know how to echo this above code