PHP - Question On Queries
whats the differance between
mysql_query("UPDATE banned SET time and doing $safe4 = "UPDATE banned SET time mysql_query($safe4); is there a reason as to why do it the 2nd way i mentioned? if someone could please explain it to me so i wont be in confusion on this anymore Similar TutorialsGood day everyone. I go by the nickname Sbosh and I am a newbie in PHP. I am currently learning php using video tutorials. I need help with regards to php queries. I have the following code: "SELECT 'food', 'calories' FROM 'diet' ORDER BY 'id'" which is supposed to display content from a table inside phpmyadmin which i created manually using phpmyadmin. But It gives an error saying i must check the MariaDB version on how to right this query, something like that. Please assist on the proper way of writing this code. Again I am a newbie in PHP and just starting to learn, so your help will be highly appreciated. Hello all, I've tried several ways to calculate a commission in the multi level marketing script, but it all ended up with nothing, recursive functions, nested sets nothing worked, and i'm running out of time to keep trying I've made multiple queries on the same table, and it's working, but only the first 3 queries, not more, I tried to perform it 4 times (although I need the queries to be performed 13 times) but still only 3 times example: A recruited B and C, and B recruited D, and D recruited E.... what's supposed to happen is A takes a commission on B, C, D, and E but now it only takes commission on the first three, and no commission for anyone comes after that, and the same for B, C, D, and E each takes commission on only 3 members down the line, and no more here is the queries Code: [Select] <? $result = mysql_query("SELECT * FROM users"); echo "<table width='589' border='1'> <tr> <th>ID</th> <th>Name</th> <th>National ID</th> <th>Commission</th> </tr>"; while($row = mysql_fetch_array($result)) { $query = mysql_query("SELECT * from users where recruiteris = '".$row['id']."'"); $num_rows=mysql_num_rows($query); $id1 = $row['id']; $commission = $num_rows; $_SESSION['id1'] = $id1; echo "<tr>"; while ($roww = mysql_fetch_array($query)) { $querry=mysql_query("select * from users where recruiteris = '".$roww['id']."'"); $num_rowss = mysql_num_rows($querry); while ($rowws= mysql_fetch_array($querry)) { $var3= '10'; $querrys=mysql_query("select * from users where recruiteris = '".$rowws['id']."'"); $num_rowsss = mysql_num_rows($querrys); while ($rowwss= mysql_fetch_array($querrys)) { $querryss=mysql_query("select * from users where recruiteris = '".$rowwss['id']."'"); $num_rowssss = mysql_num_rows($querryss); while ($rowwsss= mysql_fetch_array($querryss)) { $querryr=mysql_query("select * from users where recruiteris = '".$rowwsss['id']."'"); $num_rowssr = mysql_num_rows($querryr); } } } } $total= ($commission + $num_rowws + $num_rowwss + $num_rowwsss + $num_rowss + $num_rowssr) * $var3; echo "<td><a href=\"user.php?id=".$row['id']."\">".$row['id']."</a></td>"; echo "<td>" . $row['fname'] .''. $row['lname'] ." </td>"; echo"<td> ". $row['nid'] ." </td>"; echo "<td>".$total."</td> </tr>"; } echo "</table>"; ?> Hey guys - me again! I have a discount box, where i wish to check two "if" queries. These are i) the 'uniquecode' and ii) the 'uses' - so a code can only be used a set amount of times. 1) How do i state that question in php, bearing in mind the "if uses > 0" needs to relate to the same row as the unique code entered? 2) Also, i have stored the session price in $_SESSION['sessionprice'] - is this the best way to do this, and if not how should i store the current price. 3) Lastly, and how do I do the php mathematics of "$_SESSION['sessionprice'] minus the discount" - again bearing in mind the "discount" needs to relate to the same row as the unique code entered? (as different codes will have different discounts). This is how far i've gotten: Code: [Select] <?php //connection settings bla bla bla $uniquecode = $_POST['discountcode']; mysql_connect($localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $discountcodecheck = mysql_query("SELECT uniquecode FROM discounttable WHERE uniquecode = '".$uniquecode."'"); $remainingusescheck = mysql_query("SELECT uses FROM discounttable WHERE uniquecode = '".$uniquecode."'"); if (mysql_num_rows($discountcodecheck) > 0) and if (mysql_num_rows($remainingusescheck) > 0) // <-- this "and if" doesn't work { // discount calculation: // session price minus the unique code's corresponding discount // update $_session['discountammount'] } else { ?><script type="text/javascript"> alert("Discount Code Entered Is Either Not Valid Or Has Been Previously Used."); history.back(); </script><?php } // rest of code and close connection ?> Any help or comments will, as always be politely welcomed and appreciated Cheers, Tom. ive had these queries working okay until i checked on it today, it's not working anymore.. these are the errors::: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\arrastre\add.php on line 105 Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\arrastre\add.php on line 117 if(isset($_POST['add'])){ if($billnmbr=="" or $orno=="" or $payor=="" or $arrastre=="" or $wharfage=="" or $total=="" or $date=="" or $tcl==""){ echo "At least one field was left blank."; } else{ $query = mysql_query("select * from `arrastre` WHERE `billnmbr`='$billnmbr'"); /*****************this is my line 105************/ $count = mysql_num_rows($query); if($count==1){ echo "This billnumber is already in the database."; } else{ $bll = strtoupper($billnmbr); $payr = strtoupper($payor); $query="insert into `arrastre` (`billnmbr`, `orno`, `payor`, `arrastre`, `wharfage`, `total`, `date`, `tcl`) values ('$bll', '$orno', '$payr', '$arrastre', '$wharfage', '$total', '$date', '$tcl')"; $result=mysql_query($query); $query = mysql_query("select * from `arrastre` where `billnmbr`= '$billnmbr'", $link); /************and this is my line 117*************/ $count = mysql_num_rows($query); if($count==1){ echo "last bill number added: ".$billnmbr; } } Thank you very much for your time and have a nice day. noob question: I have following two queries I'd like to combined into one - how is this done? $temp = @mysql_query("SELECT * FROM purchased_leads WHERE leadID = '{$_REQUEST[leadid]}'"); "SELECT refundNotes FROM leads WHERE leadID = '{$_REQUEST[leadid]}'" I'm trying to figure out how to combine these queries, to decrease server load and load time, but I'm not so good with MySQL queries. Does anyone have any ideas, any help is greatly appreciated, I've been tinkering with this for days now.
$Actv = 0; $ActvCount = -1; $ActvUpgrade = 0; $ActvRenewal = 0; $ActvVehicleAdds = 0; $result2 = mysql_query("SELECT * FROM tblOperators WHERE OperatorLocale = 'USA' and OperatorStatus = 'ACTIVE' and Team = 'RENEWALS'"); while($row2 = mysql_fetch_array($result2)) { $operID = $row2['OperatorID']; $result = mysql_query("SELECT * FROM tblUserPayments WHERE OperatorID = '$operID' AND PaymentStatus='OK' AND PaymentDate LIKE '$currentDate%'"); while($row = mysql_fetch_array($result)) { if($row['PaymentReason'] == 'ACTIVATION'){ ++$ActvCount; //if($row['PaymentMethod'] == 'CREDITCARD'){ $ActvUpgrade += $row['ChargeAmount']; //} } elseif($row['PaymentReason'] == 'UPGRADE'){ $userid = $row['UserID']; $paymentdate = $row['PaymentDate']; $result1 = mysql_query("SELECT * FROM tblRenewalInvoices WHERE UserID='$userid' AND ('$paymentdate' >= DATE_SUB(DueDate, INTERVAL 90 DAY) AND '$paymentdate' < DATE_ADD(DueDate, INTERVAL 15 DAY)) AND ParentInvoiceID IS NULL ORDER BY InvoiceNum DESC LIMIT 1"); if( $row1 = mysql_fetch_array($result1)) { $packageid = $row['PackageID']; $pack = mysql_query("SELECT * FROM tblUserPackages WHERE PackageID='$packageid';"); if($pack1 = mysql_fetch_array($pack)){ $expDate = $pack1['ExpirationDate']; $dueDate = $row1['DueDate']; $days = mysql_fetch_row(mysql_query("SELECT TO_DAYS('$expDate')-TO_DAYS('$dueDate');")); $months = (int)( ((int)$days + 14) / 30.4); $years = (int) ( ((int)$days + 182) / 365); $Intervals = 0; if($years > 0){ $Intervals = $years; } if(($pack1['Package'] or 'GPS-SVL') or ($pack1['Package'] == 'GPS-1') or ($pack1['Package'] == 'GPS-1PLUS')){ if($Intervals > 1){ //if($row['PaymentMethod'] == 'CREDITCARD'){ $Actv += $row['ChargeAmount']; //} } else{ //if($row['PaymentMethod'] == 'CREDITCARD'){ $ActvRenewal += $row['ChargeAmount']; //} } } else{ $Actv += $row['ChargeAmount']; } } else{ } } else{ //if($row['PaymentMethod'] == 'CREDITCARD') $ActvUpgrade += $row['ChargeAmount']; } } elseif($row['PaymentReason'] == 'ADDVEHICLE'){ //if($row['PaymentMethod'] == 'CREDITCARD') $ActvVehicleAdds += $row['ChargeAmount']; } } $result = mysql_query("SELECT * FROM tblRenewalCalls WHERE OperatorID = '$operID' AND PayStatus='OK' AND DateSubmitted LIKE '$currentDate%'"); while( $row = mysql_fetch_array($result) ) { if($row['Charged']){ if ((int)$row['RenewYears'] > 1) { $Actv += $row['RenewTotal']; } else{ $ActvRenewal += $row['RenewTotal']; } } } } $total = $Actv+$ActvRenewal+$ActvUpgrade+$ActvVehicleAdds; $ActvRenewal = $total - ($ActvVehicleAdds + $ActvUpgrade); $upgradeEarned = $ActvUpgrade; $renewalEarned = $ActvRenewal; This must be easy enough, but I'm a noob so go easy on me, please :-)
I have two pieces of code and they're working well on their own. All I need is to put these two conditions into one query.
The first one:
<?php function childtheme_cat_limited_blog( $query ) { if ( $query->is_home() && $query->is_main_query() ) { $query->set( 'events_categories', 'mycategory1' ); } } add_action( 'pre_get_posts', 'childtheme_cat_limited_blog' ); ?>And the second: <?php function childtheme_cat_limited_blog( $query ) { if ( $query->is_home() && $query->is_main_query() ) { $query->set( 'category_name', 'mycategory2' ); } } add_action( 'pre_get_posts', 'childtheme_cat_limited_blog' ); ?>I'm sure it's a piece a cake for you guys, but I can't figure it out for the life of me, so any help would be greatly appreciated! Thank you! (My goal is here to display posts from two categories on a homepage of a Wordpress site, but to complicate things the two categories are from two different post types.) Can any boy clarify these queries. How do I find out if an array has values posted to each of its elements? I need to know that EVERY element has been filled out. How can I send variables from a PHP script to another URL using POST without using forms and hidden variables? how can i join the two queries so that they function as one. for example, if $keywords or $username is empty then the result will be null.
$query1 = "SELECT * FROM forums WHERE MATCH (topics) AGAINST ('$keywords' IN BOOLEAN MODE)"; $query2 = "SELECT * FROM users WHERE username='$username"; This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331128.0 I need two queries cause I don't know how to put them into one. Problem here is I need to know the field Liters from the database in the first query to subtract it from the second query to be able to calculate the average fuel consumption of the chosen range.
This is my code, hope you can help
function getContent() { include 'connection.php'; $dx = date('m', strtotime('today - 30 days')); if (!isset($_POST["month_select"])) { $month = $dx; $year = "2014"; } else { $month = $_POST["month_select"]; $year = $_POST["year_select"]; } //last fuel fill value $query2 = "SELECT d.liter as FirstFill FROM members AS m LEFT OUTER JOIN diesel AS d ON d.userid = m.id WHERE YEAR(dato) = $year AND MONTH(dato) = $month AND d.liter > 0 ORDER BY d.id ASC LIMIT 1"; $sql2=$oDB->prepare($query2); $sql2->execute(); $row2 = $sql2->fetchAll(); return $row2; $FirstFill = $row2['FirstFill']; $query = "SELECT m.username, m.id, 10 * (SUM(d.liter) - $FirstFill) / (MAX(d.km) - MIN(d.km)) as AvgFuel FROM members AS m LEFT OUTER JOIN diesel AS d ON d.userid = m.id WHERE YEAR(dato) = $year AND MONTH(dato) = $month AND d.liter > 0 GROUP BY m.id ORDER BY AvgFuel ASC"; $sql=$oDB->prepare($query); $sql->execute(); $row = $sql->fetchAll(); return $row; } Edited by Aero77, 23 May 2014 - 12:39 PM. Here is the original query: Code: [Select] $query_extract = mysql_query("SELECT downloads,date,title,username,views,id FROM skins ORDER BY id DESC LIMIT 100"); Is it possible to also grab the row username from the table users, without making multiple queries? Hi everyone I have the following PHP code $sql.= "INSERT INTO `data` (`info`, `write`, `date`) VALUES"; $sql.= "("; for ($c=0; $c < $num; $c++) { $sql.= '"'.str_replace('"', "", $data[$c]).'",'; } $sql.= "'".date('Y-m-d')."');"; If I print $sql; I get Code: [Select] INSERT INTO `data` (`info`, `write`, `date`) VALUES("data99","n",'2010-10-05'); INSERT INTO `data` (`info`, `write`, `date`) VALUES("data101","y",'2010-10-05'); INSERT INTO `data` (`info`, `write`, `date`) VALUES("data876","n",'2010-10-05'); what would I need to do to my PHP code in order for it to process each QUERY either all at once or one at a time Whatever I try, it either inserts nothing, or just does the first INSERT Any ideas? Thanks Hello, in short, here is my problem: There are 2 tables: a table called postcodes, which contains UK postcodes and a table called wp_bp_xprofile_data (i want to integrate this search with the Buddypress plugin's tables) which contains the user data. I tried searching this, but to be honest, i didn't quite know how to go about it.. Here is what i have: $query1 = "SELECT value, user_id, (SQRT(POW((b.x - a.x), 2) + POW((b.y - a.y), 2))/1000) * 0.621 AS distance FROM postcodes a, postcodes b, wp_bp_xprofile_data WHERE a.outcode = '"$postcode"' AND b.outcode = wp_bp_xprofile_data.value HAVING (distance < '"$area"') ORDER BY distance asc "; $result1=mysql_query($query1) or die(mysql_error()); echo "<p style=\"font-size:10px;line-height:14px;color:#888;\">Straight line distances shown.<br>"; echo "<table border=\"0\" cellspacing=\"0\" cellpadding=\"0\" width=\"100%\" ><tr>"; // display results while ($list = mysql_fetch_array($result1)) { $user_postcode = $list['value']; $distance = $list['distance']; $distance = round($distance); echo "<td align=\"right\">$distance miles away</td></tr>"; echo "<tr><td colspan=\"3\" align=\"left\" width=\"130px\">$user_postcode </td>"; echo "<td align=\"right\"><a href=\"blahblah\">Directions using Google Maps</a></td>"; echo "<tr><td align=\"left\"> </td><tr>"; echo "</tr>"; } echo "</table>"; Code: ("wp_bp_xprofile_data") [Select] id field_id user_id value 1 1 1 admin 8 3 3 NW10 6 1 3 Test User 1 9 4 3 IT, Web Development 11 1 4 Test User 2 12 3 4 HA5 13 4 4 Test, It, Some Work Code: ("postcodes") [Select] outcode x y latitude longitude B10 392900 804900 57 -2 AB11 394500 805300 57 -2 AB12 393300 801100 57 -2 AB13 385600 801900 57 -2 AB14 383600 801100 57 -2 Here is an example of what i need: field_id "3" corresponds to a postcode. My script so far, can search a postcode and return results with the postcodes sorted by distance. What i'm trying to do, is also get the username on the result (i.e the 'value' column again..). in short, im trying to search a postcode, find it on wp_bp_xprofile_data, associate it with the correspondent user, and return both. Someone told me i need to INNER JOIN, but im lost.. The end result im looking for is if i type the search: "NW9 1AA" It returns: Test User 1 NW10 Test User 2 HA5 (the code sorts them by distance. So far i can get it to return the postcode, but cannot associate the relevant name. Can anyone help me with this? I hope this is in the right forum. Thanks for your attention. Hi all I have a site with 4 SQL queries that I need to paginate so that it returns 10 hits per page maximum. Basically there will be varying values of adverts in each SQL table. Here's my code: Code: [Select] <!-- Get Trader premium adverts --> <?php $gettraderads = mysql_query("SELECT * FROM `trade-adverts` WHERE type = 'premium' AND paid = 1 AND categoryid = 1 AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); $numtraderads = mysql_num_rows($gettraderads); while ($showtraderads = mysql_fetch_array($gettraderads)) { include('trader-ad-cell.php'); } ?> <!-- Get Trader standard adverts --> <?php $gettraderads = mysql_query("SELECT * FROM `trade-adverts` WHERE type = 'standard' AND categoryid = 1 AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); $numtraderads = mysql_num_rows($gettraderads); while ($showtraderads = mysql_fetch_array($gettraderads)) { include('trader-ad-cell.php'); } ?> <!-- Get premium adverts --> <?php $getads = mysql_query("SELECT * FROM `adverts` WHERE categoryid = 1 AND type = 'premium' AND paid = 1 AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); while ($showads = mysql_fetch_array($getads)) { include('ad-cell.php'); } ?> <!-- Get standard adverts --> <?php $getads = mysql_query("SELECT * FROM `adverts` WHERE categoryid = 1 AND type = 'standard' AND live = 1 AND approved = 1 AND dateexpired >= '".$todaysdate."' ORDER BY id DESC "); while ($showads = mysql_fetch_array($getads)) { include('standard-ad-cell.php'); } ?> Many thanks for your help Pete I was wondering if it is possible to perform the following query. Say I have a list of names each with an id number ranging from 1 to 10. Is it possible to perform a query where you list all of these records while repeating one records. For example could I do a query that lists record number 6 then 10, 9, 8, 7, 6 etc. Or another example would be listing record number 10, then 10, 9, 8, 7, 6 etc? Thanks for any help. The whole code is below, followed by the part that isn't producing. It all works extremely well until the last part, and I have two instances of setting a variable to mysql_fetch_assoc that work. Not sure why the third attempt doesn't. I'm just trying to have a separate area that outputs 'msg'. Code: [Select] $sql = "SELECT * FROM players as p INNER JOIN schools as s WHERE p.tid = s.id ORDER BY status, playerLast"; $results = mysql_query($sql); echo '<div class="roster">'; $team = mysql_fetch_assoc($results); echo '<div class="team_info"> <div class="school">' . $team['school'] . '</div> <div class="coach">Coach ' .$team['coachFirst'] . ' ' . $team['coachLast'] .'</div> <div>Sectional: ' . $team['sectional'] . '</div> <div>Class: ' . $team['class'] . 'A</div> '; echo '</div>'; $currentStatus = false; //Flag to detect change in status while($player = mysql_fetch_assoc($results)) { if($currentStatus != $player['status']) { //Status has changed, display status header $currentStatus = $player['status']; echo '<br><b>'; if ($currentStatus == '1') {echo 'Returning Starters';} elseif ($currentStatus == '2') {echo 'Key Returners';} elseif ($currentStatus == '3') {echo 'Varsity Newcomers';} elseif ($currentStatus == '4') {echo 'Key Freshmen';} echo '</b><br>'; // echo "<div><b>{$currentStatus}</b></div>\n"; } //Display player info echo $player['playerFirst'] . ' ' . $player['playerLast'] . ', ' . $player['feet'] . '\'' . $player['inches'] . '",' . $player['position'] . ', ' . $player['year'] . ';<br>'; } //Player comments echo '<hr>'; echo '<div class="coach_comments"><span class="player_name">hello'; while($comments = mysql_fetch_assoc($results)) { echo $comments['playerFisrt'] . ' ' . $comments['playerLast'] . ': </span>' . $comments['msg']; } echo '</div>'; echo '</div>'; It's all working until what's below. All I get out of it is the "hello", which is just a test to make sure it wasn't a CSS issue. Quote //Player comments echo '<hr>'; echo '<div class="coach_comments"><span class="player_name">hello'; while($comments = mysql_fetch_assoc($results)) { echo $comments['playerFisrt'] . ' ' . $comments['playerLast'] . ': </span>' . $comments['msg']; } echo '</div>'; echo '</div>'; // Check for this userID if exsist in cp_credits $sql = "SELECT * FROM `cp_credits` WHERE account_id = $userid"; // Execute Query $r = mysqli_query($dbc, $sql); // If there are result in $r if($r){ // Print a message indicating success or not: while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)){ $user_balance = $row['balance']; $user_last_donation_date = $row['last_donation_date']; } } else{ $user_balance = "nothing"; $user_last_donation_date = "nothing"; } but either of my else statement does not work. Whats wrong with this? |