PHP - Need Some Type Of Assistance

hi there,

i am fairly new to OOPs in php, i get an error when i declare the argument type (as object) in a function and pass the same type (object).



class eBlast {
       public static function getEmail(object $result) {
           return $result->email;
       }
}

$r = mysql_fetch_object($query);
eBlast::getEmail($r);

echo gettype($r); // outputs: object



error is :

Code: [Select]
Catchable fatal error: Argument 1 passed to eBlast::getEmail() must be an instance of object, instance of stdClass given, called in C:\wamp\www\integra\client\pl_eblast\admin\send_emails.php on line 145 and defined in C:\wamp\www\integra\client\pl_eblast\app\app.eBlast.php on line 8
if i remove the type declaration in the function it works, but just would like to know why it shows error when pass the same type, also isnt mysql_fetch_object is the instance of stdclass?

thanks in advance!

ok... I'm still struggling with PHP syntax, my editor's linting keeps flagging a line as incorrect. it's supposed to read as " when d1 minus 1 is less than or equal to d2 with d2 being less than or equal to d1 plus 1" so in other words its supposed to be true if d2 is between d1 minus 1 and d1 plus 1, inclusive. I don't want d2 being the previous number, the same number or the next number relative to d1. The same goes for d3, d4, and d5 (4 and 5 are un coded because why code in errors).

That being said... This isn't exactly my correct goal but I'm not sure how to code what I really want...
Rules
a 3 - 5 digit combo (0 - 99 per digit) whe
1. the numbers are not in order. (1,2,3,4 or 55,56,57,58,59 or 4,3,2,1 or 59,58,57,56,55)
2. no more than 2 numbers in the combo may be the same. (45,12,67,12,78 is ok 17,35,17,24,17 is not)
3. repeat numbers may not occur next to each other (45,12,67,12,78 = valid 45,67,12,12,78 = invalid)

I can't seem to find a good way to test this without the commands I know from other languages like CountIf, Iffn and RandSamp. (those are Ti-Basic commands)

I know "please do it for me" is frowned upon, and hate saying it (I'd rather learn to do it myself), but if anyone can explain how to do this I'd really appreciate it.

Edited March 23, 2019 by Karaethon

Hello all,
I wrote a script that will upload an avatar to a users profile and to do this the user has to get a randomly generated pin that is stored to thier profile info in a MySQL db what i am trying to accomplish with this code is once the form is submitted this code checks the database to see if the ID is there and that the pin matches if so then it continues to upload the file if not it stops displays an error and the upload form. For some reason the script continues to upload even when i input fake values that are not in the DB .... i know its something simple that im jsut over looking so perhaps a fresh set of eyes will help...


<?php

include './config.php';

include './access.php';
// Receiving variables
@$steamid = addslashes($_POST['steamid']);
@$pin = addslashes($_POST['pin']);
@$avatar_Name1 = $_FILES['avatar']['name'];
@$avatar_Size = $_FILES['avatar']['size'];
@$avatar_Temp = $_FILES['avatar']['tmp_name'];
@$avatar_Mime_Type = $_FILES['avatar']['type'];

@$ava_strQuery1 = "SELECT * FROM $member_table WHERE authid='$steamid' AND private_pin='$pin'";
@$ava_host1 = "$hostname";
@$ava_user1 = "$username";
@$ava_pw1 = "$password";
@$ava_db1 = "$database";
$ava_link1 = mysql_connect($ava_host1, $ava_user1, $ava_pw1);
if (!$ava_link1) {
 die('Could not connect: ' . mysql_error());
}
$ava_db_selected1 = mysql_select_db($ava_db1, $ava_link1);
if (!$ava_db_selected1) {
die ('Can not use $ava_db1 : ' . mysql_error());
}
//upload file and insert new record if ID and PIN match
$ava_result1 = mysql_query($ava_strQuery1);
if (!$ava_result1) {

function findexts ($avatar_Name1) 
{ 
$filename = strtolower($avatar_Name1) ; 
$exts = split("[/\\.]", $avatar_Name1) ; 
$n = count($exts)-1; 
$exts = $exts[$n]; 
return $exts; 
}
$ext = findexts ($_FILES['avatar']['name']) ;
$ran = rand () ;
$ran2 = $ran.".";
$avatar_Name = $ran2.$ext;

//Checking/Making Folder
function RecursiveMkdir($path)
 {
   if (!file_exists($path)) 
   { 
      RecursiveMkdir(dirname($path));
      mkdir($path, 0777);
    }
  }


// Validation
if (strlen($steamid) <15)
{
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please enter a valid steamid <br>(ex: STEAM_0:0:00000)</font></p><p align='center'><a href='avatar.php'>BACK</a></p>");
}
if (strlen($steamid) >20)
{
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please enter a valid steamid <br>(ex: STEAM_0:0:00000)</font></p><p align='center'><a href='avatar.php'>BACK</a></p>");
}

if (strlen($steamid) == 0 )
{
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please enter a valid steamid <br>(ex: STEAM_0:0:00000)</font></p><p align='center'><a href='avatar.php'>BACK</a></p>");
}

if (strlen($pin) !=12)
{
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please enter a valid pin<br>Dont have a pin? click <a href='#'>here</a></font></p><p align='center'><a href='avatar.php'>BACK</a></p>");
}

if (strlen($pin) == 0 )
{
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please enter a valid pin<br>Dont have a pin? click <a href='#'>here</a></font></p><p align='center'><a href='avatar.php'>BACK</a></p>");
}

if( $avatar_Size == 0)
{
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please select an image that is 50KB or less in size and its type is .jpg, .gif, or .png</font></p><p align='center'><a href='avatar_upload.php'>BACK</a></p>");
}
if( $avatar_Size >51200)
{

//delete file 
unlink($avatar_Temp);
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please select an image that is 50KB or less in size and its type is .jpg, .gif, or .png</font></p><p align='center'><a href='avatar_upload.php'>BACK</a></p>");
}
if( $avatar_Mime_Type != "image/gif" AND $avatar_Mime_Type != "image/jpeg" AND $avatar_Mime_Type != "image/pjpeg" AND $avatar_Mime_Type != "image/png" AND $avatar_Mime_Type != "image/x-png")
{
unlink($avatar_Temp);
die("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Please select an image that is 50KB or less in size and its type is .jpg, .gif, or .png</font></p><p align='center'><a href='avatar_upload.php'>BACK</a></p>");
}
$uploadFile = "avatars/".$avatar_Name ;
if (!is_dir(dirname($uploadFile)))
  {
    @RecursiveMkdir(dirname($uploadFile)); 
  }
else
  {
  @chmod(dirname($uploadFile), 0777);
  }
@move_uploaded_file( $avatar_Temp , $uploadFile); 
chmod($uploadFile, 0644);
$avatar_URL = "*************/".$avatar_Name ;

//saving record to MySQL database
@$ava_strQuery = "UPDATE $member_table SET avatar ='$avatar_Name' WHERE authid='$steamid' AND private_pin='$pin'";
@$ava_host = "$hostname";
@$ava_user = "$username";
@$ava_pw = "$password";
@$ava_db = "$database";
$ava_link = mysql_connect($ava_host, $ava_user, $ava_pw);
if (!$ava_link) {
 die('Could not connect: ' . mysql_error());
}
$ava_db_selected = mysql_select_db($ava_db, $ava_link);
if (!$ava_db_selected) {
die ('Can not use $ava_db : ' . mysql_error());
}

//insert new record
$ava_result = mysql_query($ava_strQuery);
if (!$ava_result) {
 die('Invalid query: ' . mysql_error());
}
mysql_close($ava_link);

 echo("<p align='center'><font face='Arial' size='3' color='#66CCFF'>Image uploaded OK!</font></p><p align='center'></p>");
 echo "<div align='center'>";
 echo "<p><img src=$avatar_URL></p>";
 include ('./includes/avatar_upload.php');
 echo "</div>";
}else{ //if ID and PIN dont match display error and form

echo "Wrong SteamID/Pin Please Try Again...";

echo "<br />";

include ('./includes/avatar_upload.php');
}
mysql_close($ava_link1);
?>

So I have the following and for some reason or another it's not wanting to work with me. If I do the query directly in phpmyadmin it will return the number, however for some reason when I throw it into a variable it won't return anything. I have a feeling it's because of the text string? How do you properly represent a string of text that has a space between it?

1st query get's the name from another table:

$query = "SELECT name FROM info WHERE userdid = 4";
$data = mysqli_query($dbc, $query);
$row = mysqli_fetch_array($data);

$tname = $row['name'];


Table: testing
rows: number name
data: 4      Testing This

$query1 = "SELECT number FROM testing WHERE name = '" . $tname . "'";
$data1 = mysqli_query($dbc, $query1);
$row1 = mysqli_query($data1);

$numreturn = $row1['number'];

// Do stuff