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PHP - Preg_replace() Pattern "/ /" Delimiter Will Not Work With $_post Variable.
preg_replace() asks that "Delimiter must not be alphanumeric or backslash" in the pattern. So I changed
$new_text = preg_replace($_POST['withthis'] ,$_POST['withthis'],$_POST['text']); to this $replacethis = $_POST['replacethis']; $new_text = preg_replace("/$replacethis/",$_POST['withthis'],$_POST['text']); It works fine, but out of curiosity, is there any way to have the POST variable as a parameter directly, and why does it not work? Just to try it, I attempted: "/$_POST['withthis']/" and $_POST["/'withthis'/"] and both do not work. str_replace is a better option I think, but I am just trying to get a better understanding of this delimiter rule. Thanks for your time! Similar Tutorialshello, I was wondering what is the point of writing for a dropdown: <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> or for a checkbox/ radio button: <?php if ($_POST['cb/radioID'] == "value") { echo "checked"; } ?> I guess it's for after submit, if there is any error, the values filled will still be echoed in the inputfield, or am i wrong? But then if that is true, i have a php search box where i use AJAX object to to send all the input they filled in after submit. But after pushing submit the inputted values remain. I guess when using AJAX to send the information i don't need <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> in my html forms? Little confused Can maybe somebody bring clearness Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, I have set up 2 php pages page 1 - add_entry2.php In this page I have a invoice table created where I can dynamically add/delete rows. This has a View Bill button which takes me to page 2- add_entry3.php In this page it shows up the rows added in page 1 in read only format, so if the user wants to modify the data that he/she entered then he must Click on <back> that i have provided in the page 2 which will direct him to page 1 Now the problem starts here on click of Back the dynamically added rows dissappear..which is frustrating..I know its something to do with my code..but can anyone help me fix it. One more thing is that i dont want to store the data into DB till the finalise button is clicked on page 2 so that means till page 2 is submitted nothing goes to DB from Page 1. I am able to retain values if I use the code Code: [Select] <form action="add_entry2.php" name="eval_edit" method="post" format="html"> i,e if I submit back to the same page and retrieve values form $_POST but If I use the code Code: [Select] <input type="button" value="Back" onClick="history.go(-1);return true;">to get back to add_entry2.ph it looses all the values. Is there any other way to code the BACK link retaining my $_POST values(Do you think $_SESSION would work in this case?) Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob I want to post some form identifyer when I hit submit, so that I can use this in an SQL query. Previously I used the below code and would retrieve either page1.php or page2.php etc from $_POST['subject']); Code: [Select] <td> <select name="subject" id="subject" onchange="gotourl(this.value)"> <option value="" >Please Select</option> <option value="page1.php" >page1</option> <option value="page2.php">page2</option> <option value="page3.php">page3</option> </select> </td> will this work? Code: [Select] <form id="form1" name="form1" value="tableName" method="post" action=""> $_POST['form1']) returns tableName...... Thanks Code: [Select] <?php if (isset($_POST['submit'])) { // Grab the selected value $optionValue = $_POST['subscriptionLevel']; // Grab the id of the selected value ** HOW DO I DO THIS? ** $optionID = ?????????????????????????; } ?> <html> <body> <form name="form" method="post" action=""> <table> <tr> <td> <label for="subscriptionLevel"></label> <select name="subscriptionLevel" id="subscriptionLevel"> <?php do { ?> <option id="<?php echo $dbRowResult['sub_level']; ?>" value="<?php echo $dbRowResult['sub_price']; ?>"><?php echo $dbRowResult['sub_desc']; ?></option> <?php } while ($dbRowResult = $db->dbGetRow($dbQueryResult)); ?> </select> </td> <td> <label> <input type="submit" name="submit" id="submit" value="submit"> </label> </td> </tr> </table> </form> </body> </html> How do I grab the id of the selected value? Thank you. Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 Hi All, I'm having trouble with an email I'm trying to send out. While testing my code, the email that my script sends has the "Reply-To" email address in the headers but when I click "reply", the recipient's email, $to in the code below, is inserted instead of the "Reply-To" email. Am I missing anything? Thanks for the help in advance! $to = "abc@email.com"; $headers = "From: " .$admin_name. "<" .$admin_email. ">\r\n"; $headers .= "Reply-To: " .$host_name. "<" .$host_email. ">\r\n"; $headers .= 'MIME-Version: 1.0' . "\r\n"; $headers .= 'Content-type: text/html; charset=iso-8859-1' . "<br>"; $subject = "Subject"; $body = "Body"; mail($to, $subject, $body, $headers); okay.. so I found a list of bad words on line that I want to work into my website's insert. I took the time to create a long comma-delimited list and I'm trying to use this in my page but I keep getting errors. I'm not sure what I'm supposed to be escaping because of the many numerous characters in this list. Might someone help? As I didn't want to post a bunch of foul words on this forum, I posted it he http://snipt.org/xmpgk You might not want to visit if you don't like bad words. As the list currently is, I'm getting this error: Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting ')' in /home/jeffro/public_html/all/xyzman/inserttodb.php on line 114 ....right on the line where $newwords begins. I'm trying to send a submission to the following Craigslist form that uses javascript to trigger an auto submit. The user selects "For Sale" on my form and it will pass the data in a hidden div to the proper selection on the craigslist page. Heres the page it would be passing to. I know I will have to pass it in the URL. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <base href="https://post.craigslist.org"> <title>houston craigslist | choose type</title> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <link type="text/css" rel="stylesheet" media="all" href="/styles/craigslist.css?v=9"> </head> <body id="pp"> <table width="100%" id="header" summary="header"> <tr valign="top"> <td><a href="http://houston.craigslist.org/"><b>houston craigslist</b></a> > choose type<br></td> <td width="10%" class="highlight" style="text-align: right; white-space: nowrap;"> <font size="2" face="sans-serif" color="#7a7a7a">[ logged in as <a href="https://accounts.craigslist.org/login"><b>kennymahaffey@gmail.com</b></a> ] [ <a href="https://accounts.craigslist.org/logout">logout</a> ]</font> <br></td> </tr> </table> <hr> <blockquote> <div class="highlight"> <i>Please post to a single geographic area and category only -- cross-posting to multiple cities or categories is not allowed</i> </div> <h4>What type of posting is this:</h4> <form action="https://post.craigslist.org/k/kInfxI4M4RGIA7PWTF5SWg/HjdlJ" method="POST"> <blockquote> <label> <input type="radio" name="id" value="jo" onclick="form.submit(); return false;">job offered </label> <br> <label> <input type="radio" name="id" value="jw" onclick="form.submit(); return false;">resume / job wanted </label> <br> <br> <label> <input type="radio" name="id" value="ho" onclick="form.submit(); return false;">housing offered </label> <br> <label> <input type="radio" name="id" value="hw" onclick="form.submit(); return false;">housing wanted </label> <br> <br> <label> <input type="radio" name="id" value="fs" onclick="form.submit(); return false;">for sale </label> <i>(please do not post prohibited <sup><a target="_blank" href="http://www.craigslist.org/about/prohibited.items">[?]</a></sup> or recalled <sup><a target="_blank" href="http://www.craigslist.org/about/recalled_items">[?]</a></sup> items)</i> <br> <label> <input type="radio" name="id" value="iw" onclick="form.submit(); return false;">item wanted </label> <br> <br> <label> <input type="radio" name="id" value="go" onclick="form.submit(); return false;">gig offered </label> <i>(I'm hiring for a short-term, small or odd job)</i> <br> <label> <input type="radio" name="id" value="so" onclick="form.submit(); return false;">service offered </label> <br> <br> <label> <input type="radio" name="id" value="p" onclick="form.submit(); return false;">personal / romance </label> <br> <br> <label> <input type="radio" name="id" value="c" onclick="form.submit(); return false;">community </label> <br> <label> <input type="radio" name="id" value="e" onclick="form.submit(); return false;">event </label> <br> <br> </blockquote> <input type="hidden" name="U2FsdGVkX:18yNDg2NDI0O:A8dZroeLa8K5Y677RwK4hzBe2OPdD3XxLUDb5lS9LllELhxNpMqXZIwAWDxJ.7Wo4A" value="U2FsdGVkX18yNDg2NDI0OFjS1qgWn_NKgmgnh5qCZ9aK2m7eOmS-uAAM_Pwu8VHN"> <button type="submit" name="go" value="Continue">Continue</button> </form> </blockquote> This is what I have $eeee = $_POST['forum_reply']; $eeee = strip_tags($eeee, '<p>'); echo $eeee; this is what prints out Quote Untitled document testinggg this is a print_r of $_Post Quote Array ( [forum_reply] => testinggg [form_reply_submit] => Reply ) Please someone tell me what in binary's name is going on! I get the following error when I try to pass a value to a methiod in a loop: Warning: Attempt to assign property of non-object in /Users/staceyschaller/Sites/dev_zone/ckwv2/classes/class.php on line 670 This one has me very baffled. It will work the first time, and seems to work every other time, so I have no clue what is wrong. Here is the code: This code is part of my "display" class: function display_partner ($type,$loc,$rand=0,$narrow=0) { $this->partners = new partner($this->cxn); $display = ' <div id="cont_info" class="partner-list"> <div> <h3 class="settings">'.ucfirst($loc).' '.ucfirst($type).last_letter($type).'s</h3> </div> <div class="settings-value" style="height:12px;padding:0;margin:0;text-align:right;padding-right:10px;"> <a href="" class="trunc">Add your organization to this list</a></p> </div> <div style="height:2px;padding:0;margin:0;"> <hr class="account" /> </div> '; $ids = $this->partners->get_partners_list($type,$loc,$rand); for ($b=0;$b<sizeof($ids->id);$b++) { $this->partnerID = $ids->id[$b]; $display .= ($narrow)? $this->card_partner_narr():$this->card_partner(); if ($b!=(sizeof($ids->id)-1)) { $display .= '<hr class="account" />'; } } if (sizeof($ids->id)==0) { $display .= '<div style="color:#999999;display:line;text-align:center;height:20px;">No Partners found for '.ucfirst($loc).' '.ucfirst($type).'</div>'; } $display .= ' </div>'; return $display; } function card_partner () { $this->partners->set_partner_id($this->partnerID); $part_info = $this->partners->get_partner_info(); if ($part_info) { $display .= ' <table class="settings"> <tr> '.$this->show_if($part_info['partLogo']['val'],'<td class="settings-value" rowspan="2"><img src="'.LOGO_FOLDER.$part_info['partLogo']['val'].'" '.resize_img(LOGO_FOLDER.$part_info['partLogo']['val'],175).'alt="'.$part_info['partName']['val'].'" /></td>').' <td class="settings-value" colspan="2"><h5>'.$part_info['partName']['val'].'</h5></td> </tr> <tr> <td class="settings-value"> <span style="color:999999;">'.$part_info['partAddress']['val'].'<br /> '.$part_info['partCity']['val'].', '.$part_info['partST']['val'].' '.$part_info['partZIP']['val'].'<br /> '.$part_info['partPhone']['val'].'</span><br /> <a href="'.$this->form->show_href($part_info['partWeb']['val']).'" target="_blank">'.$part_info['partWeb']['val'].'</a> </td> <td class="settings-value">'.$part_info['partInfo']['val'].'</td> </tr> </table> '; } return $display; } This code is part of my "partners" class: function set_partner_id($partID) { echo '<p>partID: '.$partID.' '.gettype($partID).'<br> $this->partner->id: '.$this->partner->id.'</p>'; $this->partner->id = $partID; ///*** ERROR HAPPENS HERE ***/ echo '<p>id set: '.$this->partner->id.'<br> $this->partner->id: '.$this->partner->id.'</p><hr>'; } function get_partner_id() { return $this->partner->id; } // gets user info at login function get_partner_info() { $this->partner = $this->cxn->proc_info('partner','partID',$this->partner->id);//$this->partner->id return $this->partner; } The following is the output generated: partID: 24 string $this->partner->id: id set: 24 $this->partner->id: 24 partID: 26 string $this->partner->id: Warning: Attempt to assign property of non-object in /Users/staceyschaller/Sites/dev_zone/ckwv2/classes/class.php on line 670 id set: $this->partner->id: partID: 17 string $this->partner->id: id set: 17 $this->partner->id: 17 partID: 25 string $this->partner->id: Warning: Attempt to assign property of non-object in /Users/staceyschaller/Sites/dev_zone/ckwv2/classes/class.php on line 670 id set: $this->partner->id: As you can see, the value passes to $this->set_partner_id($partID) each time. It is formatted as a string. When it assigns the value to $this->partner->id, however, sometimes it works, and sometimes it doesn't. It's probably something obvious, but I've racked my brain to see what it is. Any ideas? Code: [Select] <?php session_start(); $index="1"; $_SESSION[$index]=2; echo "$_SESSION[$index]"; ?> Hi good day check how to have a variable "$index" inside session.. I'm trying to make the simplest login and this isnt working can someone explain why? thanks if ($_POST['user'] == 'admin' && $_POST['pass'] != '1234') { echo "fail"; } else { echo "win"; no matter what I do it says win Hi Guys Ever had the feeling your being a spoon and can't see the wood for the trees? Well, that's how I feel today. All I am trying to to is implement a variable in a "foreach" loop that increments by one through each iteration of the loop. I know how to do it in a "for" loop but can't for the life of me get it to work here. Here is the code: foreach ($cart as $prodcode => $qty) { $item = get_product_details($prodcode); echo '<input type="hidden" name="item_name_'.[b]$needavariablehere[/b].'" value="'.$item['description'].$_SESSION['finish'][$prodcode].$_SESSION['handles'][$prodcode].'" />' . "\n"; } Where I have highlighted $needavariablehere is where I want a number to appear i.e. if there is one item available and the foreach loop iterates once I want the number 1 here. If there are two items and the foreach loop iterates twice I want the output to have number 1 in the first line and number 2 the second time around and so on. How many times the foreach loop iterates is based on the $cart array which contains items in a shopping cart. Thanks for any help you can give guys. Hey, I wanted to know if there is any difference between catching a return value and assigning into a variable, and just catching the value when when you just simply call the function on its own. Here is what I mean below In the first example I called the return by simple calling the function. In the second example I catched the return value through a variable, and then echoed it out. Code: [Select] <?php // Example 1 function text (){ $string = "this is a string </br>"; return $string;} echo text(); // Example 2 function text (){ $string = "this is a string </br>"; return $string; } $new_value = text(); echo $new_value; } ?> |
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