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PHP - Formatting Mysql Results In Php
What's the best way to format results from a MySQL table? I've found very vague examples of PHP code utilizing html tables. Below is my current PHP. Thanks!
<?php $con = mysql_connect("localhost","xxxxx","xxxxx") or die('Could not connect: ' . mysql_error()); mysql_select_db("addresses", $con); $result = mysql_query("SELECT * FROM addresses"); while($row = mysql_fetch_array($result)) { echo $row['first_name'] . " " . $row['last_name'] . " " . $row['extra_info'] . " " . $row['address'] . " " . $row['city'] . " " . $row['state'] . " " . $row['zip']; echo "<br />"; } mysql_close($con); ?> Similar TutorialsHello. I am interested in taking a result returned from a database and having it displayed in a certain way/style on the user's screen; For example, the user enters text into a field and hits "submit" - the data is saved in the database then displayed to the user (This part I have working just fine so far due to help I received here.) My question is if I would like to, for example, have said text not simply dumped to the top of the screen, inline, but nicely formatted in a boxed, text area, I assume I will use HTML/CSS, and I was wondering if anyone had any good links/tutorials regarding this topic so I may look further into it (my search thus far has not turned up the correct topic or results). Thank-you in advance for any assistance. ~Matty I have a mysql database that has your typical data in it, ie. name address, etc. The problem I am having is with the address. The address is setup as a varchar with 200 as the length and the data is street, city, st, zip on 1 line. I need to format the output with street on 1 line and city, st, zip on another. I cannot change input format because of the way the program uses the address string to fetch the lat and lng before it writes it to the database. Is there a way to add a line break or <br> to the address before it is written or change it after it is written using sql or php script or possible as I format the output? The street, city, st, zip are separated by commas in the record. Thanks in advance for all the reply's Hi, Whenever it comes to dates I go blank and just hear/read "blah blah blah". I'm sure there's a name for a condition like that but it's causing me a problem right now. I am making a RSS feed aggregator, inserting RSS feed posts into a mysql db and want to be able to extract those posts in order by date. (so that I can create a new feed of the last posts of multiple rss feeds) My problem is that the pubDate format for feeds is Fri, 29 Oct 2010 11:22:58 +0000 and that doesn't work with mysql. Apart from having to reformat the date I have to take into consideration the +0000 part could be different depending on where in the world the feed was published. Any pointers would be gratefully received! Any ideas how I can turn "2010-10-20 19:10:56" to 20th October 2010, 19:10 Thanks lots guys, Jake How would I put today date for instance into mysql_query? I just want the date and have the format be year, month, day. The format in the database looks like 2010-04-05. That being used as an example. And I have three drop down menus, which you can select the year, month, and day, but it doesn't seem to be working. What am I doing wrong? Hello Everyone, I think this might be a bit of a challenge but its always worth getting some input for solutions. I'm using jqplot to create graphs from data held in a database. And im having trouble thinking of a way to lay the data out in an acceptable way. To plot a line the javascript takes a statement in this form: line1 = [['x-axis1'],y-axis1],['x-axis2',y-axis2] I'm running this query to get the data: <?php $query2 = "SELECT * FROM tracker WHERE username = '" . mysql_real_escape_string($usera) . "'"; $result = mysql_query($query2) or die('Error, query failed : ' . mysql_error()); while($row = mysql_fetch_assoc($result)) { $data[] = $row; } ?> This returns things like this: $data[0]['date'], $data[0]['reps'] $data[1]['date'], $data[1]['reps'] etc... Values are likely to be added or removed so I need to construct a loop of some kind to format it like this, line1 = [['{$data[0]['date']}',{$data[0]['reps']}],['{$data[1]['date']}',{$data[1]['reps']}],['{$data[2]['date']}'],{$data[2]['reps']}]]; Can someone point me in the right direction? Thanks in Advanced I'm trying to modify code from a book called "PHP with MySQL" where data is read from a MySQL db, edited via a form and written back. It's all technically working but the data is written to the screen from left to right as follows (where the top row is the heading and the second row is the data retrieved from the database in an edit box.): First Name | Last Name | <David> | <Beckham> | I have tons of fields (but only have firstname/lastname in the script for now), so the headings scroll left to right on the screen and I find it really annoying. I'd like things to go top-to-bottom so it looks like this: First Name | <David> Last Name | <Beckham> I've been playing around with the code and trying to add <tr>'s here and there but I can't get it. At best, it looks like this: First Name Last Name <David> <Beckham> I'm hoping it's something simple, but I just can't see it. Any help would be appreciated... the full code is below Code: [Select] # cat editrecord.php <html> <head> <style> body {font-family:arial;} .error {font-weight:bold; color:#FF0000;} </style> <title>Edit Contact Records</title> </head> <body> <h2>Edit Contact Records:</h2> <? //connect to the database include("dbinfo.php"); $link = mysqli_connect($server, $username, $password, $database); // has the form been submitted? if ($_POST) { foreach($_POST as $k => $v) { $v = trim($v); $$k = $v; } // build UPDATE query $update = "UPDATE contact_records SET firstname='$firstname', lastname='$lastname' WHERE Id=$id"; // execute query and check for success if (!mysqli_query($link, $update)) { $msg = "Error updating data"; } else { $msg = "Record successfully updated:"; // write table row confirming data $table_row = ' <tr> <td>' . $firstname . '</td> <td>' . $lastname . '</td> </tr>'; } // if not posted, check that an Id has been passed via the URL } else { if (!IsSet($_GET['id'])) { $msg = "No customer selected!"; } else { $id = $_GET['id']; //build and execute the query $select = "SELECT firstname, lastname FROM contact_records where id=$id"; $result = mysqli_query($link, $select); // check that the record exists if (mysqli_num_rows($result)<1) { $msg = "No customer with that ID found!"; } else { // set vars for form code $form_start = "<form method=\"post\"action=\"" . $_SERVER['PHP_SELF'] . "\">"; $form_end = ' <tr> <td colspan="2"><input type="submit" value="Submit changes" /></td> <td colspan="3"><input type="reset" value="Cancel" /></td> </tr> </form>'; // assign the results to an array while ($row = mysqli_fetch_array($result)) { $firstname = $row['firstname']; $lastname = $row['lastname']; // write table row with form fields $table_row = ' <tr> <td><input type="text" name="firstname" value="' . $firstname . '" size="10" /></td> <td><input type="text" name="lastname" value="' . $lastname . '" size="10" /></td> </tr>'; } // end 'if record exists' if } //end 'if ID given in URL' if } // end 'if form posted' if } // close connection mysqli_close($link); // print error/success message echo (IsSet($msg)) ? "<div class=\"error\">$msg</div>" : ""; ?> <table border="1" cellpadding="5"> <!-- Show start-of-form code if form needed --> <? echo (IsSet($form_start)) ? $form_start : ""; ?> <input type="hidden" name="id" value="<? echo $id ?>" /> <tr> <th>First Name</th> <th>Last Name</th> </tr> <!-- Show appropriate table row code (none set if there were errors) --> <? echo (IsSet($table_row)) ? $table_row : ""; ?> <!-- Show end-of-form code if we are displaying the form --> <? echo (IsSet($form_end)) ? $form_end : ""; ?> </table> <br /><a href="records.php">Back to customer list</a> </body> </html> Hello, This is query in MySQL Quote mysql> LOAD DATA LOCAL INFILE '/var/www/html/numbers.csv' INTO TABLE details FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n' (number); Query OK, 0 rows affected (0.00 sec) Records: 2200 Deleted: 0 Skipped: 1200 Warnings: 0 Now, I am trying to run the same query in PHP and display the same results.... (i.e. Records, Deleted, Skipped) Quote <?php $db=mysql_connect("localhost", "user", "1234") or die(mysql_error()); $dname="database"; mysql_select_db($dname)or die(mysql_error()); $sqlstatement="LOAD DATA LOCAL INFILE '/var/www/html/numbers.csv' INTO TABLE details FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n' (number)" ; mysql_query($sqlstatement) or die(mysql_error());; echo "it is done!"; ?> Tried mysql_fetch_array, row but could not get it to work... please help guys How can I limit the amount of time my while loop to only show the first 4 rows of my SQL table?
I am using this code to loop my whole table:
while($row = $results->fetch(PDO::FETCH_ASSOC))
{
echo '
<li>Mileage: '.number_format($row["Mileage"]).'</li>
<li>Engine size: '.$row["EngineSize"].'cc</li>
';} ?>
I only want to loop through the first 4 rows of my SQL table, I then want to duplicate the same code but start at the 5th row until the 8th row of the table, how can I do this?
Thanks, NickI have a problem displaying the results of a table, It shows them in one long list and I'd like them to show as 2 or 3. I had a look around and the most favoured way to this I found was to split the results either by odd/even or using percentages but Im having trouble implementing it into my script. How would I go about adding the odd/even way to this: <?php $query = mysql_query('SELECT * FROM users ORDER BY Username'); while ($row = mysql_fetch_array($query)) { if ($row['UserID']) ?> <b>Username:</b> <span class=class1><a href="aeditprofile.php?username=<? echo $row['Username'] ?>"><? echo $row['Username'] ?></a></span><br> <b>Group:</b> <? echo $row['Level'] ?></color><br /><hr> <?php } ?> Essentially I'm after getting something like this: Name Name Name Group Group Group and so on down the page.... I'm working on a website that uses a database to display the employees from different states. Below is the code I'm using and everything works great, but I can't figure out why all the results are getting posted twice. I'm trying to isolate just one state so we can have a different contact page for each state. Thanks for any help! Please let me know if you need more information. (I'm attaching a screenshot of what's happening as well.) Code: [Select] <? include "public/public_common.php"; //Open Database Connection $db = open_db_connection(); $sql = "SELECT DISTINCT state_full = 'california' from users where active = 'Y' and show_on_contactus = 'Y'"; $results = mysql_query($sql, $db); if(!mysql_num_rows($results) == FALSE) { while($row = mysql_fetch_array($results, MYSQL_BOTH)) { echo "<ul id=\"directors\">\n"; $state_sql = "SELECT * from users where active = 'Y' and show_on_contactus = 'Y' and state_full = 'california' order by last_name"; $state_results = mysql_query($state_sql, $db); if(!mysql_num_rows($results) == FALSE) { while($state_row = mysql_fetch_array($state_results, MYSQL_BOTH)) { echo "<li>\n"; echo " <div class=\"fl dirimg\">\n"; if($state_row[photo] == "") { echo "<img border=\"0\" width=\"61\" height=\"85\" src=\"images/exe_placeholder.jpg\" alt=\"$state_row[first_name] $state_row[last_name]\" />\n"; } else { echo "<img border=\"0\" width=\"61\" height=\"85\" src=\"n2team/pictures/$state_row[photo]\" alt=\"$state_row[firstname] $state_row[last_name]\" />\n"; } echo " </div>\n"; echo " <span class=\"fr\">$state_row[first_name] $state_row[last_name]<br />\n"; echo " $state_row[title]<br />\n"; echo " $state_row[city], $state_row[state]<br />\n"; //echo " <a href=\"mailto:$state_row[email]\">$state_row[email]</a></span></li>\n"; } } echo "</ul>\n"; } } ?> this is my code but i want to have a pice so if their is no results the it will put in a message like "No Results" but i cant figger it out <?php $host="localhost"; $username="xxxxx"; $password="xxxxxx"; $db_name="xxxxxxx"; $tbl_name="Shows"; // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name WHERE Month='April'and Year='2011' order by Day asc "; $result=mysql_query($sql); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <td> <table width="400" border="1" cellspacing="0" cellpadding="3"> <?php while($rows=mysql_fetch_array($result)){ ?> <span class="elevenbold"><? echo $rows['Day']; ?> <? echo $rows['Month']; ?> <br><strong class="elevenboldblue"><? echo $rows['Song']; ?></strong><br><? echo $rows['Data']; ?></span><br><br> <?php } ?> </table> </td> </tr> </table> <?php mysql_close(); ?> Hey everyone. So I am coding a badge system for my website usersystem. I am trying to think how I'll handle issues before actually starting to code it and one issue I just can't seem to figure out how to handle.. How would I limit the amount of MySQL results to show per line. Eg. A user has 6 badges but I'd only like to show 2 per line. So in total it'd show 3 lines with 2 badges per line. If that makes any sense? Is there any way possible to actually do this? I would like to know what is the best method (the most intelligent and comfortable for users) to paginate a result table with PHP/MySQL? Provided I have a result set of 100 pages. Method 1: <select> <option>1</option> .... </select> Method 2: Link on Page 1, 2, 3 ... 100 If there is any algorithm with PHP for automated these displays, please demonstrate it. Hi all, In order to teach myself php I am developing a simple cms system to display my graphic design work. Basically I am working on developing a simple portfolio website powered by a custom made CMS. So far, I can create new posts which are being stored in a MySQL db. My index page runs a sql query to get the latest posts and sorts them by category. Currently the results look like this: Quote Title1 Category A Text Title2 Category A Text Title3 Category B Text Title4 Category B Text The code to generate this looks like this: $content = mysql_query("SELECT * FROM posts ORDER BY category, date DESC"); while($row = mysql_fetch_array($content)) { echo '<h2 class="post_title">'.$row['title'].'</a></h2>'; echo '<p class="cat">category: '.$row['category'].'</p>'; echo '<p class="post_body">'.$row['body'].'</p>'; echo '<p class="image">image: '.$row['image'].'</p>'; echo '<p class="lowerlefttext_metainfo">by <span class="lowerlefttext_author">'.$row['author'].'</span> on '.$row['date'].'</p>'; } What I would like however is this: Category A Title 1 Text Title 2 Text Category B Title 3 Text Title4 Text I am not sure how to do this elegantly without having to code an sql query per category, which I don't think is efficient? Thank you! Hey Everybody, I am writing a SUPER SIMPLE script and for some reason I cannot figure this issue out. I guess I'm too close to the situation and have spent too many hours staring at this script. Here's the problem: I am running a basic SQL query through php that should return multiple rows of data and instead returns the first row multiple times. I'm not sure what the problem is, but I'm sure YOU can help! <?php //Get Invoice Rows $sql = 'SELECT * FROM timecard WHERE INVOICE_ID=\'1000\''; $result = mysql_query($sql); $rows = mysql_fetch_array($result); $num = mysql_num_rows($result); //Build Current Invoice $i=0; $invoice = '<table class="invoice" cellspacing="0" cellpadding="0">'; $invoice .= '<tr class="heading"><td>#</td><td>Invoice</td><td>Date</td><td>Time In</td><td>Time Out</td><td>Hours</td><td>$/Hr</td><td>Sub Total</td></tr>'; while($i < $num){ if( $i%2 ) { $eo = 'odd'; } else { $eo = 'even'; } $invoice .= '<tr id="invoiceRow" class="'.$eo.'"><td>'.$rows[0].'</td><td>PHG'.$rows[1].'</td><td>'.$rows[2].', '.$rows[4].' '.$rows[3].', '.$rows[5].'</td><td>'.$rows[6].'</td><td>'.$rows[7].'</td><td>'.$rows[8].'</td><td>'.$rows[9].'</td><td>'.$rows[10].'</td></tr>'; $runningTotal[$i] = $rows[10]; $i++; } //Get Total $total = array_sum($runningTotal); $invoice .= '<tr><td colspan="7" style="background-color: #000000; color: #ffffff; font-weight: bold; padding-left: 5px;">Total</td><td align="right" style="background-color: #333333; font-weight: bold; color: #FFFFFF; padding-right: 5px;">'.$total.'</td>'; $invoice .= '</table>'; echo $invoice; ?> Much thanks in advance for anyone that is able to resolve this problem, even just a try is nice!! Thank You, E Here is my HTML code: Code: [Select] <html> <head> <title>Simple Search Form</title> </head> <body> <form name="searchform" method="get" action="/search.php"> Select Gender: <select name="gender"> <option value="Male">Male</option> <option value="Female">Female</option> </select> Select City: <select name="gender"> <option value="all">All Cities</option> <option value="newyork">New York</option> <option value="toronto">Toronto</option> <option value="london">London</option> <option value="paris">Paris</option> </select> <form> </body> </html> Here is my PHP code: <?php // get the data from the search form # get the gender (male or female) $gender = $_GET['gender']; # get the city $city = $_GET['city']; // connect to mysql and select db mysql_connect('localhost', 'root', 'pass') or die(mysql_error()); mysql_select_db($test_db); // send query $query = mysql_query("SELECT * FROM `visitors_location` WHERE gender='$gender' AND city='$city'"); $count = mysql_num_rows($query); // display data while ( $show = mysql_fetch_assoc($query) ) { echo $gender . " " . $city; } ?> My script basically shows # of males or females in a specific city. How can I show all males in all cities? In other words, let's say I want to show # of Females from all those 4 cities combined. I don't know how to do that. Can someone please help me? I'm having two issues:
(1) The correct mysql query for multiple rows
(2) The if/elseif/else to pull data from these rows, and process it based on the row data
I'm only pulling data where A=1 and B=1,2 -- so two possible entries there (call them B1 and B2). I need a php if statement to choose whether the output of B is one of two urls (b1=google,b2=bing). The actual script is far more complex, with more than just 1,2 from B. I've stripped all the excesses down to this one if/else issue and the db query. The output php doesn't matter here. And I can add more elseif once this problem is solved.
<?php
mysql_connect(localhost, $db_username, $db_password);
@mysql_select_db($db_database) or die("No connection");
$query = "Select * FROM table WHERE column='stuff' AND parent='1,2' ORDER BY id DESC LIMIT 10";
$query_result = mysql_query($query);
$num_rows = mysql_num_rows($query_result);
mysql_close();
?>
<?php
for($i=0; $i< $num_rows; $i++){ //start a loop
$stuff = mysql_result($query_result, $i, "column");
$row = mysql_fetch_assoc($query_result, $i);
if($row['parent'] == 1) {
$url = 'http://google.com';
} else {
$url = 'http://www.bing.com';
}
?>
My own first attempt at a if/then was 500.
I got help on another site to redo it (new code shown here), but the new if/else always show the else (Bing).
It was also at this time that I learned that "1,2" only showed 1.
Hoping that this site is far more friendly than StackOverflow.
.
Edited by kpmedia, 17 December 2014 - 07:22 PM. I've got a page that displays all my blog entries on a single page. When you click on a specific entry, it pulls the post ID and loads the page specifically. From there, I wanted to have the option to click either onto the next or previous post by finding the next or previous ID in the database.. however, I know that sometimes posts are deleted, etc. so the ID's won't exactly be in order. What direction should I take with this? |
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