PHP - If Any Integer Is In This Spot

So I am trying to take a string value of dollars (posted from a form) and times it by 100 to get the cents Integer value of the dollars.  For some reason if I do this with something like 278.53  I end up with 27852.  Same concept for 278.59 ends up as 27858.  I don't understand why or how to make it work.  I've tried many things and nothing has made it work.

$price = '278.53'; // posted from the form
$cents = $price * 100; // converting to cents.
end_result = (int)$cents // This will end up being 27852 not 27853.

 

Hey,


I have this brainstorm whether I should store id's as integers or text? I mean in my database, since my IDs start from like 1319129364 which is a rather large number, I was thinking if it would be better to save it as text? Which case requires less memory ?

Ive got a simple function that's counting percentages of the results, and what I want is when the first line does $variable / 100 - to go on 2 decimals(ex. 0.72142141 what I want is to write 0.72).

Code: [Select]
function postotak(){
$p = $bodovi / 100;
$postotak = $p * 100;

I want to round off an integer vaule to 10-6 grd from

52.71666666  to  52716666

0.926888888  to  926888

does anyone know a simple way to do this?

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Hi Guys!

I have a method that get's all devices that share a specific ID. Foreach of those device UID's, I am trying to send a APN (Apple Push Notification) using the easyAPN's class.

The method that is having the problem is $apns->newMessage($id);

It seems to think I am not passing a valid integer for $id.

The $id is an array like so Array ( => 1 )

I have also tried passing just the value of the array like so $apns->newMessage($id[0]).

No matter what I do.. I keep getting this error...

"Notice: TO id was not an integer. 1) Messages_model::send_apns -> File: sendMessage.php (line 28) 2) APNS::queueMessage -> File: messages_model.php (line 195) 3) APNS::_triggerError -> File: class_APNS.php (line 599)"

Here is my method... please let me know where I've gone wrong with the $id.

function send_apns($data)
{
include 'apn_classes/class_DbConnect.php';
include 'apn_classes/class_APNS.php';

$message = new Messages_model();
$db = new DbConnect();
$db->show_errors();
$apns = new APNS($db);

//get uid's for aid
$sql = "SELECT `devices`.`uid` FROM `devices` WHERE `devices`.`aid` = '".$data['target']."'";
//echo $sql;
$query = mysql_query($sql);
if(mysql_num_rows($query))
{
while($uid_data = mysql_fetch_array($query))
$uids[] = array(
"uid" => $uid_data['uid']
);
}

//make sure there is a uid
if(!empty($uids))
{
//check the device apn pid
foreach($uids as $uid)
{
$sql = "SELECT `apns_devices`.`pid` FROM `apns_devices` WHERE `apns_devices`.`deviceuid` = '".$uid['uid']."'";
//echo "$sql";
$query = mysql_query($sql);
if(mysql_num_rows($query) > 0)
{
while($pid_data = mysql_fetch_array($query))
{
$pids[] = array(
"pid" => $pid_data['pid'],
);

if(!empty($pids))
{
foreach ($pids as $pid)
{
$id = array($pid['pid']);
print_r($id);
//Send APN
$apns->newMessage($id[0]);
$apns->addMessageBadge(128);
$apns->addMessageAlert($data['message']);
$apns->addMessageSound('chime');
//$apns->addMessageCustom('acme2');
$apns->queueMessage();
$apns->processQueue();
}
}
}
}
}

}
else 
{
echo "Device Does not Exist";
}



}

I am making a online Bible with search function. I was able to do the boolean search for text keywords without much trouble. Now I want a user to be able to type in an exact verse into search form and have that verse display in results.

IE: User types in John 3:16 and search result displays that verse. The following works if the user types John:3:16. I cannot figure out how to do this without requiring the user to type a : after book name.
Code: [Select]
if($search_type=='verse'){

$query2 = explode(":", $query);
$bookquery = $query2[0];
$chapterquery = $query2[1];
$versequery = $query2[2];

$result4 = $db->sql_query("select * FROM Bible$version WHERE book = '$bookquery' AND chapter= '$chapterquery' AND verse ='$versequery'");
while ($row = $db->sql_fetchrow($result4)) {
$book = $row['book'];
$chapter = $row['chapter'];
$verse = $row['verse'];
$scripture = $row['scripture'];

echo "<b><a href=\"modules.php?name=Bible&amp;call=chapter&amp;viewbook=$book&amp;viewchapter=$chapter&amp;version=$version\">$book</a>&nbsp;$chapter:$verse</b>";
echo "<br>";
echo "$scripture";
echo "<hr>";
}

if(!$query){
echo "<b>You did NOT enter any keywords.</b><br>";
}
if(!$scripture){
echo "<b>No results found.</b>";
}

}

}

Is there a function to find first integer in the string and insert a : before it?

How can I modify the following code to not display $hash_row['total'], but to display the sum of the counted "total" value + 1?  Is there a way that I can assign that variable in the "select query" area (for instance, "COUNT(hr.hasher_id) + 1 as total1"), and then call $hash_row['total1] in the result table?

I'm not sure if the syntax exists to add an integer value to a COUNT value and assign to a new variable...

Code: [Select]
<?php 
include "modules/dbase_connection.php";

#create MySQL connection
$sql_connection = sql_connect("blah","blah","blah","blah");

# select the Hashers and  hashes by total number<br />
$hash_query = "
SELECT
ha.*,
COUNT(hr.hasher_id) as total
FROM
hashers as ha,
hash_records as hr
WHERE
hr.hasher_id = ha.hasher_id
GROUP BY
         hr.hasher_id
ORDER BY
total DESC
";

$hash_result = mysql_query($hash_query) or die(mysql_error());

$x = 1;


while($hash_row = mysql_fetch_array($hash_result))
{
#display the table header
if($x == 1) {
echo '
<br />
<table align="left">
<br />
<tbody>
<tr><br /><td colspan="2"><strong>Potential On-Sec</strong></td><br /></tr>';

         $x++;
}

echo '<tr><br /><td>' . $hash_row['hasher_name'] . '</td><br /><td>' . $hash_row['total'] . '</td><br /><td>- ' . $hash_row['real_name'] . '</td><br /></tr>';
}
echo '</tbody></table></td><br />';

?>

When I post the data to mysql I want to submit the value as an integer.  How can I make this $12,000 be 12000?

This is a cross between HTML, PHP, and MySQL.  I'm not exactly sure which to blame (other than myself of course)

I'm collecting a bid price in a standard form

<input type="number" name="maxbid" value="<?php echo $maxbid ?>"/>

I have recalled the value from the database where I store it and display it in the field if it exists.  If the field has never been entered, the field shows nothing.  It's not required that a bid be entered.  There are other fields of data that may be updated and this field is left blank.

On the page called by the submit button I'm retrieving the fields

$maxbid=$_POST[maxbid];

Then I store the fields in the database either with an INSERT or an UPDATE

if(mysql_num_rows(mysql_query("SELECT id FROM data WHERE id = '$id'")))
{
echo "Updating.....";
mysql_query("UPDATE data SET maxbid='$maxbid', name='$name' where id='$id'");
} else
{
echo "Inserting.....";
mysql_query("INSERT INTO data (id, maxbid,name)
VALUES ('$id','$maxbid',$'name')");
}

I know I'm not handling the Numeric values correctly, and I'm having a hard time finding the correct method for doing so.  Right now, if the name is entered byt the maxbid is left blank, nothing gets inserted or updated.  if I enter both the maxbid and the name it works.  I can't have maxbid show up as a 0, I need it to be blank if nothing is entered.

Also when I check $maxbid, it's not an INTEGER (per INTVAL) when I check it, even though maxbid in the table is an INTEGER.  When I pass it around, it seems to lose it's INTEGER value, but still shows as a number.

I know this sounds confusing, heck I'm confused.  If someone could point me to a good tutorial, I'd figure it all out, but most tutorials don't get into the data type that much, and the combination of the form, passing the variables, reading the values from the database, etc. is what's causing me grief.

Any guidance would be appreciated.

Hey, I am echoing out:

Code: [Select]
$source = implode(',', $arr2);
echo $source;
which is a array, and it echo's out: "2,2,2"

I am trying to find a php function to add each array, so the result will be "6".

Possible?

how can i convert string type into integer like when using parseInt in javascript...however i use (int)$string but not working

i have this
$string1="10";
$string2="5";

and i wish to add both string ....using (int) still treat $string1 and $string2 as string so i get 105 as a result instead of 15

Hi, not sure if this is posted in the right place (think it should be in the Regex section  ) but hopefully someone can help me out a bit.

I have the following string for example which is stored in a variable called $var.

Quote

This is a reference [ref=17][/ref] number


I wish to extract only the number after the equals sign and store it as a variable. So I am using the following code to do so:

$ref_num = preg_replace("/.*?\[ref\=(.*?)\]\[\/ref\].*?/is", "$1", $var);

The only problem is, I can omit the text before the integer and the tags themselves but I still get the text after the [/ref] section and I cannot get rid of it. It seems my .*? placed after it doesn't work like it does at the beginning.

Can anyone offer any help at all, it will be greatly appreciated - I'm fairly new to using Preg_replace so I still don't know how best to form Regular Expressions.

Thanks, Dan


EDIT-
I have found a workaround which I will post below - however I would still like to solve it the way I planned originally which is the way I posted here. Here's what I did - because I know the integer is never going to be more than 5 characters long, I used the replace from before but added a substring like so.

$ref = substr(preg_replace("/.*?\[ref\=(.*?)\]\[\/ref\]/is", "$1", $var),0,5);

This grabbed the first 5 characters whether it was a number or not, then I used this to strip any non-numerical characters. Finally I added an intval to convert it to an integer rather than a string.

$ref = intval(preg_replace ('/[^\d\s]/', '', $ref));

Hi, 

I'm by no means an expert in php but I use and continually try and figure out how to update some very old soccer stats scripts that break from time to time when newer versions of php are released.

Anyway, I would appreciate any pointers with this error please:

Warning: mysqli_query() expects parameter 3 to be integer, object given in /blah/blah/blah.php on line 81 

The code is:

79 -  mysqli_query($connection,"INSERT INTO seasons SET
80 -  SeasonID = '$seasonid',
81 -  SeasonPlayerID = '$player_id'",$connection)
82 -  or die(mysqli_error($connection));

Server is running php 7.2.28

Thanks in advance.

Hello guys, I have a form where you can select a score between 0 and 10(only integers). I want to check if the value that I recive, is integer.   Im using this code(exemple):

$integer =  intval($_POST["p1"]);
    if(is_int($integer)){
        echo 'INT';
    } else {
        echo 'NO INT';
    }

My problem is that if it recive letters, the conversion converts it to 0, and it says that it is integer. So with this method I should discard the 0.   You guys know a method to avoid that?   Thank you guys

I have an integer that I'd like to validate to ensure that it is a valid number between 1 and 99999999999999999999(20 digits).

I'm thinking about using the following, but I'm not sure what the max range is on the FILTER_VALIDATE_INT options.

return filter_var($_REQUEST['r'], FILTER_VALIDATE_INT, array("options" => array("min_range"=>1, "max_range"=>99999999999999999999)));