PHP - Possibly Stupid But I Need Help!

Hi All,

first of all.  Sorry for signing up to the site and then immediately asking for help.  I hate doing it but always seems to be the way people get involved with forums these days and it seems I am no different...  So thank you in advance if you are kind enough to answer!

Among many personal flaws, my issue is a technical one regarding the ability to retain session variables.  Unfortunately whilst the website itself is not complicated, the problem is not as simple as just running session_start(); and letting it get on and do its own thing.

So the problem exists around a relatively simple contact form and the basic Turing test that it uses to prove the user is human.  The script adds a value to the $_SESSION variable and then on the next page load, tests to see if the variable is still there.  As per this little function:

function cookiesEnabled()
{
    if ($_SESSION['cookiesEnabledTest'])
        $_SESSION['cookiesEnabled'] = true;
    else
        $_SESSION['cookiesEnabledTest'] = true;
}

Now for what must be 95% of all users, the variable is still there, proving the the session is being maintained as the user navigates the site.  Unfortunately a small group of computers appear to be having difficulties with this for a not too clear reason.

The computers have varying browser user agents indicating that they are all (so far) using one of the following:

MSIE 8
MSIE 7
MSIE 7 in what appears to be MSIE 6 compatibility mode

Now in testing, I can't get MSIE 8 or MSIE 7 to produce the same effect, with exception to MSIE 8 in "InPrivate" browsing mode.  In this mode it is easy to see that there is no cookie txt file being created and thus no way of the browser to pass back the session id on the next page load.

I can't think of any detail that I have missed out, but if there is anything I have left unclear, please let me know!

Thanks again!

Felix

Code: [Select]
$code = array("03","09");
if (!in_array($_POST['CODE'], $code));
message("Sorry, not today");
my $_POST['CODE'] is

<input type=hidden name=CODE value='03'>

still not being validated.. hmm

I'm sure this is just a stupid mistake, but can someone please help me figure it out? 

I have one page with a dropdown that is populated from our database, I have submit to pull through to the next page but nothing shows up on the next page (app/approval).  I've tried adding some echo statments, but they all show up blank. 

Code: [Select]
<?
require ('includes/getconfig.inc');
require ('includes/auth.inc');
require ('includes/dbfunctions.inc');
include (dirname(__FILE__).'/../includes/menuhead.inc');
include ('apptable_functions.inc');

$sql="SELECT pol_id, pol_policy_number FROM policies";
$result=myload($sql);
$items = count($result);
$options="";

for($x=0; $x<=$items; $x++)
{
$id=$result[$x]['pol_id'];
$thing=$result[$x]['pol_policy_number'];
    $options.="<OPTION VALUE=\"$id\">".$thing;



}
?>

Select a case number to see the payout approval.
<br>
<form action="app/approval.php" method='post'>
<SELECT NAME=pol_policy_number>
<?=$options?>
</SELECT>
<input name="Submit" type="submit" Value="Submit Policy Number"/>
</form>
<br>
Code: [Select]
<?
require ('includes/getconfig.inc');
require ('includes/auth.inc');
require ('includes/dbfunctions.inc');

$pol_number = $_POST['pol_policy_number'];

echo "$pol_number";
?>

Quote

Notice: Use of undefined constant d - assumed 'd' in /home/rayth/public_html/forum/shout.php on line 11

Strict Standards: date() [function.date]: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'UTC' for 'UTC/0.0/no DST' instead in /home/rayth/public_html/forum/shout.php on line 11

Notice: Use of undefined constant F - assumed 'F' in /home/rayth/public_html/forum/shout.php on line 11

Strict Standards: date() [function.date]: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'UTC' for 'UTC/0.0/no DST' instead in /home/rayth/public_html/forum/shout.php on line 11

Notice: Use of undefined constant Y - assumed 'Y' in /home/rayth/public_html/forum/shout.php on line 11

Strict Standards: date() [function.date]: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'UTC' for 'UTC/0.0/no DST' instead in /home/rayth/public_html/forum/shout.php on line 11



I keep getting this.
Line 11:
$Date = date(d)." ".date(F)." ".date(Y);

For some reason both admin and home return home's contents but everything else returns it's own contents...


<?php if(!isset($_GET['p'])) {
$result = mysql_query("SELECT * FROM body WHERE name='home'");
?>
<script type="text/javascript">alert("home");</script>
<?php
} else{
$result = mysql_query("SELECT * FROM body WHERE name='" . $_GET['p'] . "'");
?>
<script type="text/javascript">alert("SELECT * FROM body WHERE name='<?php echo $_GET['p']; ?>'");</script>
<?php
}

$row = mysql_fetch_array($result);

function changeStuff($str) {
$str = str_replace("[link=","<a href='",$str);
$str = str_replace("[/link]","</a>",$str);

$str = str_replace("[img]http://","<img src='",$str);
$str = str_replace("[/img]","' />",$str);

$str = str_replace("[b]","<b>",$str);
$str = str_replace("[/b]","</b>",$str);

return $str;
}
?>
if(!isset($_GET['p'])) {
include("home.php");
} else{
include($_GET['p'] . ".php");
}
echo changeStuff($row['content']);
?>

There are three rows in my body table. They are as follows
1) (name) = home
    (content) = this is home page
2) (name) = admin
    (content) = this is admin page
3) (name) = eq
    (content) = this is equipment page

When $_GET['p'] = home
It displays this is home page

When $_GET['p'] = admin
It displays this is home page

When $_GET['p'] = eq
It displays this is equipment page

The javascript alerts are all displaying the correct information so i don't understand what is fudging it up...

Stupid question probably pretty obvious. but..
I am trying to add a href to an image echo And I can't seem to code this right.

Here is a text link echo call:
Code: [Select]
echo '<div id="nav_image_title" align="center" valign="middle" ><a href="'. $sess->url( URL .'index.php?page=shop.browse&amp;category_id=' . $categories[$kp]['category_child_id']). '">'.$categories[$kp]['category_name'].'</a></div>';
And I want to add that "a href" to this image:
Code: [Select]
echo '<div>'. ps_product::image_tag( $categories[$kp]["category_thumb_image"], "alt=\"".$categories[$kp]["category_name"]."\"", 0, "category") . '</div>';
I not sure if it's just too many hours working today..
But how do I add that link to that image.

Thanks for any help anyone can give..
!!!

I'm not sure what I'm doing wrong here.

I'm trying to get this to show the schedule for each person in the database. It does show the schedule, but it only shows one day in each box, and it's the last day.

So, if the last day is October 28th, it populates every box with the schedule for the 28th.

Code: [Select]
<?php

$query  = "SELECT * FROM employees WHERE day > '$current_date' AND day < '$get_date'";
$result = mysql_query($query);

while($row = mysql_fetch_array($result))
{

$id = $row['id'];
$position = $row['position'];
$pay_rate = $row['pay_rate']; 
$total_hours = $row['total_hours'];
$total_pay = $row['total_pay'];
$start_time = date("g:i a", strtotime($row['start_time']));
$end_time = date("g:i a", strtotime($row['end_time']));
$work_day = date("l", strtotime($row['day']));
$day = date("F j", strtotime($row['day']));
if($end_time == "24:00:00"){
$end_time ="Close";};
$schedule = $start_time ."<br />". $end_time;
$first = $row['first_n'];
$last = $row['last_n'];

if ($work_day == "Monday"){
$name[$last.", ".$first] = $schedule;
}
if ($work_day == "Tuesday"){
$name[$last.", ".$first] = $schedule;
}
if ($work_day == "Wednesday"){
$name[$last.", ".$first] = $schedule;
}
if ($work_day == "Thursday"){
$name[$last.", ".$first] = $schedule;
}
if ($work_day == "Friday"){
$name[$last.", ".$first] = $schedule;
}
if ($work_day == "Saturday"){
$name[$last.", ".$first] = $schedule;
}
if ($work_day == "Sunday"){
$name[$last.", ".$first] = $schedule;
}
}
foreach ($name as $n => $s) {
?>     
      <tr>
        <td align="left" valign="top"><?php echo $n; ?></td>
        <td align="left" valign="top"><?php echo $position; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="center" valign="top"><?php echo $s; ?></td>
        <td align="right" valign="top">&nbsp;</td>
      </tr>
<?
}
?>

Can somebody see what I'm doing wrong?

Thanks in advance

Hi.
I am making a login script for my website and i want it to also not just check for the username and password but to also check for the value 1 in the field beta.
Heres what i got


<?php
ob_start();
Mysql info

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

// Define $myusername and $mypassword 
$myusername=$_POST['myusername']; 
$mypassword=$_POST['mypassword'];

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);

$sql="SELECT * FROM $tbl_name WHERE username=md5('$myusername') and password=md5('$mypassword')and beta= '1'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword"); 
header("location:login_success.php");
}
else {
echo "Wrong Username or Password Or Not Beta Tester";
}

ob_end_flush();
?>



The login fully works but the check for the 1 dont. How whould i do this?

I beleive that my code is "ok" overall, but i am getting a syntax error on lines 6 & 26, pretty sure im making a stupid mistake here,

Code is a plugin for a PHP IRC Bot, basically a toggle on/off command via "!radio" to send meta data from the audio stream every 5minutes.


<?php
  require_once('shoutcast_class.php');
  $radio = false;
  class plugRadio{

public static function onCommandRadio(

  if($radio == false)

$radio = true;

$dh->reply('3 Info Stream : ON', $event->getName(), $dh->getCommandTrailing());

while($radio == true){

  event $event, 

  datahelper $dh = null, 

  $help = 'use !Radio to toggle stream info On/Off')

  {

$display_array = array("Stream Title", "Stream Genre", "Stream URL", "Current Song", "Server Status", "Stream Status", "Listener Peak", "Average Listen Time", "Stream Title", "Content Type", "Stream Genre", "Stream URL", "Current Song");

$radio = new Radio("radio.anonops.ru:8000");

$data_array = $radio->getServerInfo($display_array);

$dh->reply('15,1 #RadioPayback | 9,1On Air: '.$data_array[8].' 15,1| 9,1Now Playing: '.$data_array[12].' ', $event->getName(), $dh->getCommandTrailing());

$event->delete();

flush();

    sleep(300);

  }

}

  if($radio == true)

$radio = false;

$dh->reply('4 Info Stream : OFF', $event->getName(), $dh->getCommandTrailing());
  }
?>

all i am doing is trying to left join my column row  "to_id" and "from_id"

i can successfully left join to_id but once i try to add "from_id" to the "ON" clause it makes all my data blank

Code: [Select]
SELECT gold_logs.*,name,star
FROM gold_logs LEFT JOIN ibf_members ON to_id = ibf_members.id
WHERE to_id = 1


That query works fine, but when i try to add my "from_id" column the query works with no error's but no results are shown

Code: [Select]
SELECT gold_logs.*,name,star
FROM gold_logs LEFT JOIN ibf_members ON (to_id = ibf_members.id AND from_id = ibf_members.id)
WHERE to_id = 1

I have a bunch of quasi-static values that must be available to the application.  Most of them are set based on settings in a configuration file.  Others are based on GET, COOKIE, or SESSION values, and utilize the database to get the actual values.  The values will never be written to or modified by the application, only read.   It seems to me that I could create some sort of superclass which includes static methods and properties, and I could access any value by something like superclass::get('some.value');  I could design the class so that the values are queried from the DB or obtained from a parsed file only the first time they are requested, and for future requests, retrieved from a static property.   That being said, I have been told from more than one person that I am just doing it "wrong".   Please let me know what is wrong about it.   Thank you

Okay, So I have a dropdown box:
Code: [Select]
<select name="imgsize">
 <option value="small">480 x 360</option>
 <option value="medium">720 x 540</option>
 <option value="big">1200 x 900</option>
 <option value="large">1440 x 1080</option>
 </select>
and I have code that gets the size:
Code: [Select]
$resizeimg = $_REQUEST["imgsize"];
But I cannot get it to work with an if statement:
Code: [Select]
if ($resizeimg == "large")
    {
    }

It just comes up with about 50 lines of gibberish. I have used error_reporting(-1); but that is not coming up with any errors.
Could anyone help please. Its probably so simple, but my mind is drawing a blank

Hi there,

Can anyone show me how I can grab the value "c87cc576092fe1a0f5ac3d50091694b4" out of this string, it changes.

Also its coming from a socket a $buffer variable, so How can I do this without grabbing everything else aswell, ie all the data after it too

Quote

$buffer = fgets($fp, 4096);      

   /*** recieve data looks like this - <dd><input type="hidden" name="sid" value="c87cc576092fe1a0f5ac3d50091694b4" />

    fclose($fp);
}

fclose($Handle);



If someone could show me how to do this, I think you can do it with the split function, i just dont know how. if someone could show. i'd be SO greatful

Hi guys,

im needing to grab information out of a mysql database field called "clientname" thats inside a table called "clients"

how do i retrieve the clients name in html and display it?

heres what i have so far, am just needing the code to retrieve...



$host = localhost;
$dbuser = user;
$dbpass = pass;
$dbname = mydb;

$connection = mysql_connect($host, $dbuser, $dbpass);
$db = mysql_select_db($dbname, $connection);

// code to retrieve a particular clients details

 




Cheers,

Hi There

I have a simple cms system that I have built but for some reason the login script wont let me login to the cms. Strange thing is the script seems to works on the original database but when I changed the details to a new db it doesnt work.

I have made the necessary changes for the connecting to the db etc but it just wont let me login.

Can anyone help

The url is drmonlinemarketing.com/cms2/loginadmin.php

try login with username demo
                                      password test


thanks

shalli