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PHP - Retrieve Mysql Query From Checkbox Arrays
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Query About How To Retrieve A Password From The Database And Compare To The One The User Has Entered
I do not have code yet, i just want a general idea how to get started.
I have a database with +/- 15 columns. 6 people are using this database. Not all columns are relevant for each user.
So my idea was that each user will be able to make his preference by checking checkboxes for each column -> store this in the database so that when he logs in , his preference will be retrieved and used to make the right query.
second question, how do i make the headers so that they are the same als the preferences from the user ?
Just put me on the right track (or if someone has it on the shelf, post the code)
thanks in advance
Hello, Hope someone can help me cause i been at it all day and google woul'dn't help me. I been writing a little script which generates a list of numbers you can check and make a list of the numbers that have been checked. Now when i use $_get to the next page everything works but now i need to take the url and use $_get back to the generated check box list and it needs to know by the url which box had been checked and checked that one so the list can be altered. here is my code sofar Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>AH plaatjes.</title> </head> <body name="top"> Meer info beneden aan de pagina. <a href="#beneden">Naar beneden.</a> <p> <script language=JavaScript> function set(n) { temp = document.form1.elements.length ; for (i=0; i < temp; i++) { document.form1.elements[i].checked=n; } } function checkall() { void(d=document); void(el=d.getElementsByName('check')); for(i=0;i<el.length;i++) void(el[i].checked=1) } //invert function invers(){ temp = document.form1.elements.length ; for (i=0; i < temp; i++){ if(document.form1.elements[i].checked == 1){document.form1.elements[i].checked = 0;} else {document.form1.elements[i].checked = 1} } } </script> </p> <form id="form1" name="form1" method="get" action="./readlist.php"> <label>Naam eigenaar lijstje:<input name="naam" type="text" /></label> <label>Lijst van selectie plaatjes<select name="collect"> <option value="0">selecteer optie!</option> <option value="1">in decollectie</option> <option value="2">nog niet in collectie</option> <option value="3">dubbele collectie</option> </select></label> <p> <?php //TO Do trying to get the checkboxes checked with get and array ///////////////// do { $i = $i+1; echo " <input type=\"checkbox\" name=\"checked[]\" id=\"check\" value=\"". $i ."\"/> <label for=\"". $i ."\">". $i ."</label> <br /> "; if($i > 324){break;} }// end do while($i < 325); ?> </p><input name="check" type="submit" value="Print lijst" /> <input type=button onClick="checkall()" value="selecteer alles" name="button"> <input name=button onclick="invers()" type=button value=" Keer selectie om "> <INPUT name=button onclick=set(0) type=button value=" Reset "> </form> <p><a name="beneden">De geselecteerde nummers komen overzichtelijk in een lijstje. Zo heb je heel overzichtelijk een lijst met de nummers die je al hebt of juist nog niet hebt. Die kan je dan doorsturen selecteren en kopieren met je rechtermuis knop en naar je kennissen of vrienden sturen.</a> ook kan je de url (webadres) kopieren en doorgeven.</p> <p><a href="#top">Naar boven.</a></p> </body> </html> Now what i need is when you fill out an url like http://localhost/ah/index.php?checked%5B%5D=2&checked%5B%5D=3 it needs to check the same boxes. please help me out thanks in advance Hi, Im battling here to get "only" certain values from a "akey" and "value" query.. I have a list of items around 200 id's strong, i only want to pull cirtain values from the list, the table structure is like so: id, akey, value // i don't know the values of the specific akey's or their id's but i do know the akey value. what i am trying to do is only pull the values that are in the "getConfigTitle's" list below (this list is only a sample the actual list is around 100 strong) here is my code sample: $query="SELECT akey,value FROM settings WHERE LOWER(akey) LIKE getConfigTitles();"; $settingsList=doSelectSql($query); foreach ($settingsList as $set) { $r=array(); $r['CONFIGTITLE']=getConfigTitles(); $r['KEY'] = $set->akey; $r['SETTING'] = $set->value; $rows[]=$r; } function getConfigTitles() { $titles=array(); $titles['search']= "search" ; $titles['viewprofile']= "viewprofile" ; $titles['editprofile']= "editprofile" ; $titles['dashboard']= "dashboard" ; $titles['preview']= "preview" ; return $titles; } Hi, after following lots of advice and changing to MySqli I am running into a few probs. This is me just probably missing something stupid, I know what I want, but can't figure out what query I should use and where I should place it. All the queries I have tried have failed.
I just need a query that gets the $current_stored_password from the password field on the database, to confirm the last check
elseif
($current_password !== $current_stored_password) {
include 'includes/overall/header.php';
echo $current_password . ' AND ' . $_POST['current_password'] . ' Password and password again do not match';
include 'includes/overall/header.php';
}
Here is the whole script.
<?php
session_start();
error_reporting(0);
//ini_set('display_errors', '1');
require( 'database.php' );
$username = $_SESSION['loggedinuser'];
$current_stored_password = $_SESSION['password'];
$current_password = $_POST['current_password'];
$password = mysqli_real_escape_string($con, md5( $_POST['password']));
$password_again = mysqli_real_escape_string($con, md5( $_POST['password_again']));
// Run checks
if (isset($_POST['current_password'], $_POST['password'], $_POST['password_again'])) {
if( strlen( $_POST['current_password'] ) < 8 )
{
include('includes/overall/header.php');
echo "Password Must Be 8 or More Characters.";
include('includes/overall/footer.php');
}
elseif( strlen( $_POST['password'] ) < 8 )
{
include('includes/overall/header.php');
echo "Password Must Be 8 or More Characters.";
include('includes/overall/footer.php');
}
elseif
( strlen( $_POST['password_again'] ) < 8 )
{
include('includes/overall/header.php');
echo "Password Must Be 8 or More Characters.";
include('includes/overall/footer.php');
}
elseif
($password !== $password_again) {
include 'includes/overall/header.php';
echo ' Password and password again do not match';
include 'includes/overall/header.php';
}
elseif
($current_password !== $current_stored_password) {
include 'includes/overall/header.php';
echo $current_password . ' AND ' . $_POST['current_password'] . ' Password and password again do not match';
include 'includes/overall/header.php';
} else {
// Define a query to run
$query = "UPDATE `user` SET `password` = '$password' WHERE `username` = '$username'";
// Query the database
$result = mysqli_query($con,$query);
// Check if the query failed
if( !$result )
{
die('There was a problem executing the query ('.$query.'):<br>('.mysqli_errno($con).') '.mysqli_error($con));
}
else {
include 'includes/overall/header.php';
echo 'Password has been changed';
include 'includes/overall/footer.php';
}
}
}
// Close the connection
mysqli_close($con);
?>
At the moment the message displayed when the form is submitted is
echo $current_password . ' AND ' . $_POST['current_password'] . ' Password and password again do not match';How do I retrieve the password from the database to compare against the current password entered by the user? Any help is much appreciated. PS. Yes I know I have repeated code and that md5 is not secure, but I am just building onto a template I got and will be making changes to shorten the code and secure the password soon I am simply trying to keep a check box checked once selected. What I have works, but not correctly. Because I am calling each array element in my checkbox like name="checkbox[]" And I am using this as the input return the check: <input type="checkbox" name="checkbox[]" value="checkOneValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> I have 5 checkboxes that use the same code! And as I said it works, but returns ALL checkboxes as selected when submitted. I only want the actual selected boxes to remained checked. Any insight on a work around? The problem is I cannot solve how to identify unique array values as they are all named the same... Maybe I am not thinking right on all of this. Here is my full source code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Checkbox Echoing Test</title> </head> <body> <form name="" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> One <input type="checkbox" name="checkbox[]" value="checkOneValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Two <input type="checkbox" name="checkbox[]" value="checkTwoValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Three <input type="checkbox" name="checkbox[]" value="checkThreeValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Four <input type="checkbox" name="checkbox[]" value="checkFourValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> Five <input type="checkbox" name="checkbox[]" value="checkFiveValue" <?php if(isset($_POST['checkbox'])) echo "checked"; ?> /> <br /> <input type="submit" name="submit" value="Echo Checkbox Data!" /> </form> <?php if (isset($_POST['checkbox']) && (isset($_POST['submit']))) { $checkbox = $_POST['checkbox']; foreach ($checkbox as $checkboxValue) { var_dump($checkboxValue); if (!empty($checkboxValue)) { echo "<br />$checkboxValue is checked"; } } }; // End of foreach loop if (!isset($_POST['checkbox']) && (isset($_POST['submit']))) { echo "<br />No checkboxes were selected!"; }; ?> </body> </html> Hi folks, Complete No0b here when it comes to PHP and MySQL. I am in the middle of creating a PHP website. What I want to do is have the contents of a page in a MySQL table and have PHP gather the page content and display it on the page. Here is what I have in my home.tpl file: Code: [Select] <?php $query = "SELECT home, FROM $database_name"; $result = mysql_query($query); ?> And, in my index.php I simply call that home.tpl to display the data by using: Code: [Select] <?php include 'templates/default/home.tpl'; ?> Now, all I get is a blank page on index.php. Is there something else I should be doing? Remember, I am a complete No0b! Thanks folks. Hi, Im trying to retrieve HTML from a mysql database but nothing i've tried seems to work. The HTML im trying to retrieve is an iframe with a link and styles (code from amazon associates). Im trying to display links to specific products on amazon from the product page on my site. All data about the product is retrieved from the database so i have code to select the amazon link row in my database table but i cant get it to display. It says the html isnt a string so i cant echo it, fair enough. I have tried using the following code: Code: [Select] $get_buylink_sql = "SELECT mobo_buylink FROM mobo WHERE mobo_id = $mobo_id"; $get_buylink_res = mysqli_query($mysqli, $get_buylink_sql) or die(mysqli_error($mysqli)); while ($buylink = mysqli_fetch_array($get_buylink_res)) { echo"<iframe src=\"".$buylink."\" style=\"width:120px;height:240px;\" scrolling=\"no\" marginwidth=\"0\" marginheight=\"0\" frameborder=\"0\"></iframe>"; } mysqli_free_result($get_buylink_res); mysqli_close($mysqli);I have also tried putting the whole iframe code in the database which didnt work either. The mobo_id variable works fine for retrieving the rest of the data and i need to get the amazon link from the same record. I hope i've put this in a way you can understand, but if not i'll try and explain better and give you a link to my site if needed. Thanks, Alex I want to use session to do a query and will I be able to do this? I have a session that was gathered from login and now i was to use this session to do a query If Yes, How? I insert multiple id from my checkbox to mysql database using php post form. in e.x i insert id (checkbox value table test) to mysql. no i need to any function for retrieve data from mysql and print to my page with my e.x output.(print horizontal list name of table test where data = userid) my checkbox value ( name table is test ) : Code: [Select] 01 ---id----- name ---- 02 ---1 ----- test1 ---- 03 ---2 ----- test2 ---- 04 ---3 ----- test3 ---- 05 ---4 ----- test4 ---- 06 ---5 ----- test5 ---- 07 ---6 ----- test6 ---- 08 ---7 ----- test7 ---- 09 ---8 ----- test8 ---- 10 ---9 ----- test9 ---- mysql data Insert ( name of table usertest ): Code: [Select] 1 ---id----- data ---- userid ----- 2 ---1 ----- 1:4:6:9 ---- 2 ----- 3 ---2 ----- 1:2:3:4 ---- 5 ----- 4 ---3 ----- 1:2 ---- 7 ----- example outout : ( print horizontal list name of table test where data = userid ) print? Code: [Select] 1 user id 2 choise : test1 - test4 - test6 - test9 Thanks Hello everybody!
I am trying to figure out how to obtain all the data related to a key, but I've got no results so far and I am becoming really frustated, let's see if any of you could help me out with this.
Imagine I have a table with several columns, but we bother about two of them, let's say we have serial numbers of some product, on the left Incoming serial number (we can repair or swap the unit), on the right the outcoming serial number (same if we have repared the unit, different if we swap it for another unit).
Then we have, for example:
A -> A (Unit A enters and we repaired it)
A -> B (Same unit came another day for some reason and we couldn't repair it, so we swap it by giving B to the customer)
B -> C (Unluckily B was defective so we have to change it again)
C -> C (C had another problem and we repaired it)
We have that in the database from different days and the such, so now, we want to know the historical and we know "C". If we perform a SELECT * FROM... WHERE incoming/outcoming serial number = "C" we'll get:
B -> C
C -> C
So we should seek now for B and keep going... but I cannot proceed correctly, 'cause if I SELECT using B I'll get again B -> C (and A -> B, what I want), but when do I know I have to finish? How could I implement this as a function or whatever? showing every not repeated line from the beginning.
Could your minds help mine? Thank you very much in advance!.
Hi, My output in html is : Code: [Select] <uL><li id="B1"></li> <li id="B2"></li> <li id="B3"></li> <li id="B4"></li> <li id="B5"></li> <li id="B6"></li> <li id="B7"></li> <li id="B8"></li> <li id="B9"></li> <li id="B10"></li> <li id="B11"></li> <li id="B12" class="active"></li> <li id="B13" class="no"></li> <li id="B14" class="no"></li> <li id="B15" class="no"></li> <li id="B16" class="no"></li> <li id="B17" class="no"></li> <li id="B18" class="no"></li> <li id="B19" class="no"></li> <li id="B20" class="no"></li> </ul> If MySQL query result is equal to `6`, then `<li>` tag with `id` equal to "`B12`" should have class "`active`". All the `<li>` elements occuring after this active element should have class "`no`". This shows images of horizontal rating between `0` and `10` and between 0.5 Example : 0 .5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 6.5 7 7.5 8 8.5 9 9.5 10 In the example above elements from `0` to `5` will be blue, element `6` will be white and elements from `7` to `10` are black. How could I generate this using PHP and/or MySQL? Thanks, XXXX chirstmas XXXX I have created a drop down list and it does retrieve information from mysql but now I want to use what is been selected to retrieve information. How Do I do this? <?php MYSQL_CONNECT(localhost,'root','') OR DIE("Unable to connect to database"); @mysql_select_db(Examination) or die( "Unable to select database"); $query=("SELECT * FROM subject"); $result=mysql_query($query) or die ("Unable to Make the Query:" . mysql_error() ); echo "<select name=myselect>"; while($row=mysql_fetch_array($result)){ echo "<OPTION VALUE=".$row['Sub_ID'].">".$row['Sub_Name']."</OPTION>"; } echo "</select>"; ?> Hello guys, I am a new programmer and i am building a new website. I would like to give me your advice for the following problem: I want to build a webpage, in which there will be a <div id="book-content"> ...............</div> part. Inside this div i would like to dynamically display pages from a book. Each page will have text, scripting code blocks, blocks with the output of each scripting code, and images. There will be a bar on the left of the webpage in which the user can select which page of the book he wants to load. For example...My web page will look something like this... Code: [Select] <HTML> <HEAD> </HEAD> <BODY> <DIV ID="PAGE-HEADER"> //LOGO OF THE WEB PAGE </DIV> <DIV ID="PAGE-MENU"> //PAGE MENU </DIV> <DIV ID="BOOK-INDEX" WITH FLOAT:LEFT > //HERE A WILL SHOW THE CHAPTERS OF THE BOOK AND THE PAGES OF EACH CHAPTER </DIV> <DIV ID="BOOK-PAGE"> //THE PAGE SELECTED FROM THE PREVIOUS 'BOOK-INDEX' MENU WILL BE DISPLAYED HERE WITH A MYSQL QUERY ****** </DIV> </BODY> </HTML> Then in a mysql database, i would like to have records with a text field, that will contain for example the followng: <h1> Chapter 1: bla bla </h1> <p> in this chapter we will speak about bla bla bla.... </p> <div id="code"> int main() { int x,y; x=2; y=3; x=x+y; } </div> <p> this will outpout the following:</p> <div id="code output"> x=5! </div> I would like to get this html code from the database, and then show it in the <div id=BOOK-PAGE> div. But i dont want to use php eval(). Also, if i store the code to a file and then include it, i will have too may files(equal to the book's number of pages etc 100). Any ideas? Hello, im new here, and i have little experience to php and mysql as i started for 2 weeks ago. I started out with some tutorials and feeling im getting the hang of it. Enough of me, lets get to the point: <?php $con = mysql_connect('localhost',$user,$pass)or die(mysql_error()); $selectdb = mysql_select_db($selectdb)or die(mysql_error()); $sql = "SELECT * From table"; $result = mysql_query($sql); $num = mysql_num_rows($result); $myarray = array($result); $i =0; while ($i < $num){ echo $myarray[$i]; $i++; } ?> Here i have written a dummyscript that does what the original script does, it tries to fetch the keys from the table and then trying to loop it and echo out the results. The output in the browser is this: Resource id #3 I know this probably is a simple fix but i cant seem to get it sorted out. Hope some of you could help me get this baby work, or maybe have another way of doing it more "simple". Thanks in advance! Dan-Levi I wonder whether someone can help me please. I've found http://www.plus2net.com/php_tutorial/ajax-listbox.php tutorial to create a drop down menu using mySQL table data, which, in turn returns a list of results on the page. Following this tutorial I've put together the tables in my database and the required scripts as shown in the tutorial with the one exception, the "z_db.php" file, which I've assumed to be: Code: [Select] <?php mysql_connect("host", "user", "password")or die(mysql_error()); mysql_select_db("database"); ?> The problem I have, is that when I try and run this, I receive the following error: Quote Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /homepages/2/d333603417/htdocs/development/catsearch.php on line 91 which is this line in the search form: echo "</head><body onload="ajaxFunction()";>";. I must admit I've guessed as to the structure of the 'z_db.php' file should look like because this is not shown so perhaps this is the problem. I just wondered wether someone could perhaps take a look at this please and let me know where I've gone wrong. Many thanks and kind regards I m trying to fetch a image from mysql (blob) with header..here is my coding..."<?php include("db.php"); $query=mysql_query("select * from table where id='3' "); $row=mysql_fetch_array($query); $r=$row['image']; header("content-type:image"); echo $r; ?>" i want to fetch another fields from the database....but when i try to echo another fields...the page shows error or it does not echo other fields of database....please help me...how can i resolve it...i want to fetch other fields from database,like'username'password'firstname'lastname and image...thanks in advance... I have been having a bit of difficultly understanding how to submit a single checkbox values for a list of names and saving it in a MySQL database. The way it is meant to work is that a list of names from a table (Table1) is produced on the screen through a query. I have a checkbox that appears beside each individual name and if I tick the box I want it to save the value '1' to the database, otherwise the value remains as zero. When I tick the necessary boxes I wish to save it to another table (Table2, it is separate from Table1). The name and value needs to be saved to it. The problems that arises is how do I save the checkbox value for each individual name? Will I need to use a checkbox array or can I treat each name as independent? Hopefully you understand what I mean. hi i have a mysql table with upddate and updtime field as follows: upddate updtime 2011-02-25 11:03:05 2011-01-28 08:01:09 2011-02-20 07:00:08 2011-02-15 06:10:02 2011-02-05 10:21:04 2011-02-09 10:20:25 the data types for upddate is mysql date and for updtime its mysql time In my php page i use Code: [Select] <?php echo $date = date("d M Y",strtotime($row_rs1['upddate'])); ?> to retrieve date and the results displays as 25 Feb 2011. And for time right now im using Code: [Select] <?php echo $row_rs1['updtime']; ?> which displays time as 11:03:05 I want to display time as HH:MM only, how can i do it? I tired something earlier, with no luck... so I'm taking a few steps back. I've been working this one complicated page for days... Here's what used to work: Code: [Select] //the current URL $page_name = $_SERVER["REQUEST_URI"]; //remove any old limit from query before requesting a new limit $tmp = array(); foreach ($_GET as $fld => $val) if ($fld != 'limit') $tmp[] = $fld . '=' . $val; $page_name = $_SERVER['SCRIPT_NAME'] . '?' . implode('&',$tmp); //sets the number of records to be displayed on the page <form> <select name="link"> <option value="<? echo "$page_name" ?>&limit=25">25 records per page</option> <option value="<? echo "$page_name" ?>&limit=50">50 records per page</option> <option value="<? echo "$page_name" ?>&limit=100">100 records per page</option> </select> </form> This grabs the current URL, and clears the &limit= string before a new limit is introduced to avoid: www.example.com/test.php?sub=math[]&sub[]=science&limit=25&limit=50&limit=100 The problem, is that my URL is already querying an array: www.example.com/test.php?sub[]=math&sub[]=science So now, when I apply the form above to this URL set the new limit to 50 records per page the URL actually becomes: www.example.com/test.php?sub=Array&limit=50 Warning: Invalid argument supplied for foreach() ... on line 147 I guess I've broken the array? Code: [Select] //line 147 echo "subject:<BR />"; if(!empty($_GET['sub'])) foreach($_GET['sub'] as $sub) { echo "$sub <BR />\n"; } ~Wayne I am not sure if the title is correct; I tried my best.
I'm a PHP/MySQL beginner and I really need some help.
I have a small script that I am using for sending SMS. I recently added a phonebook. The problem with the phonebook right now is that it's available to all users, i.e. they can all update and delete all rows. What I would like to do is make it so that each user can update and delete only their own contacts.
I have a table call contacts. Inside that table there is first name, last name, company and phonenumber.
How can I accomplish this with PHP & MySQL?
CREATE TABLE IF NOT EXISTS `contacts` ( `contact_id` int(10) NOT NULL AUTO_INCREMENT, `firstname` varchar(255) NOT NULL, `lastname` varchar(255) NOT NULL, `company` varchar(255) NOT NULL, `cell_no` text NOT NULL, PRIMARY KEY (`contact_id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; CREATE TABLE IF NOT EXISTS `users` ( `user_id` int(11) NOT NULL AUTO_INCREMENT, `users_name` varchar(30) NOT NULL, `uname` varchar(30) NOT NULL, `u_pass` varchar(60) NOT NULL, `utype` varchar(30) NOT NULL, `timezone` varchar(30) NOT NULL, `uapi_user` varchar(30) NOT NULL, `uapi_pass` varchar(60) NOT NULL, PRIMARY KEY (`user_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ;
<?php
if (isset($_POST['submit'])){
//form has been submitted1
$firstname = trim($_POST['firstname']);
$lastname = trim($_POST['lastname']);
$company = trim($_POST['company']);
$cellno = trim($_POST['cell_no']);
if($firstname == ''){
echo '<div class="alert alert-danger">First Name is not Valid!</div>';
exit;
}elseif($lastname == ''){
echo '<div class="alert alert-danger">Last Name is not Valid!</div>';
exit;
}elseif($company == ''){
echo '<div class="alert alert-danger">Company is not Valid!</div>';
exit;
}elseif($cellno == ''){
echo '<div class="alert alert-danger">Cellphone Number is not Valid!</div>';
exit;
}else{
$query = "Select cell_no from contacts where cell_no = '".$cellno."' ";
$result = mysql_query($query);
if (!mysql_num_rows($result)) {
$sql = "INSERT INTO contacts(firstname, lastname, company, cell_no)
values('{$firstname}','{$lastname}', '{$company}', '{$cellno}')";
$result = mysql_query($sql);
confirm_query($result);
//echo '<div class="alert alert-success">Successfully added.</div>';
//exit;
?>
<script type="text/javascript">
window.location = "contact_list.php";
</script>
<?php
}
else{
echo '<div class="alert alert-danger">Username. already exist!.</div>';
echo '<p><a href="new_contact.php" class="btn btn-success"> Back </a></p>';
exit;
}}
}else{
$firstname = "";
$lastname = "";
$company = "";
$cellno = "";
}
?>
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