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PHP - Sql Update Is Not Working, Can You Check My Syntax?
Hi, I joined new here, and I am really having hard time figuring out what's wrong with the code below which isn't working.
if (isset($_POST['privacy_submit'])) { if (($_SERVER['REQUEST_METHOD'] == "POST")) { $privacy_upd = mysql_query("UPDATE clf_privacy_terms SET 'p_bannerads' = '".$_POST['p_bannerads']."', 'p_shareinfo' = '".$_POST['p_shareinfo']."', 'p_crossmarketing' = '".$_POST['p_crossmarketing']."', 'p_tacking' = '".$_POST['p_tacking']."', 'p_sendcommunication' = '".$_POST['p_sendcommunication']."', 'p_under13' = '".$_POST['p_under13']."', 'p_internationally' = '".$_POST['p_internationally']."', 'p_discloselegal' = '".$_POST['p_discloselegal']."', 'p_server_country' = '".$_POST['p_server_country']."', 'p_forums' = '".$_POST['p_forums']."', 'p_newslettermodule' = '".$_POST['p_newslettermodule']."', 'p_membershipmodule' = '".$_POST['p_membershipmodule']."' ") or die(mysql_error()); $msg="Successfully Updated!"; } } else { $msg="<font color=\"red\">Incorrect method of submission.</font> Please try again."; } ?> <h2>Privacy Policy</h2> <?php if ($privacy_upd) { echo ($msg); } ?> <form class="box" name="privacy_upd" action="gen.php" method="post"> ......................................................................................... ........................ MySQL Error returns the following: Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''p_bannerads' = 'do not', 'p_shareinfo' = 'do not', 'p_cross' at line 2 Let me know if any of your guys can solve it for me, I would appreciate since I am not able to solve it for last two days already. Thank you... Similar TutorialsI have been pulling my hair out for the lasy 3 hours i am trying to update a MySql table but i cant get it too work, i just keep getting MySql error #1064 - You have an error in your SQL syntax; if i just update 1 field it works fine but if i try to update more than 1 field it dosent work, Help Please! <?php $root = $_SERVER['DOCUMENT_ROOT']; require("$root/include/mysqldb.php"); require("$root/include/incpost.php"); $con = mysql_connect("$dbhost","$dbuser","$dbpass"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("$dbame", $con); mysql_query("UPDATE Reg_Profile_p SET build='$build' col='$col' size='$size' WHERE uin = '$uinco'"); ?> I have been looking at this code most of the morning and do not have a clue what is wrong with the code. I am hoping its not a stupid mistake, can someone please help me out? thank you
<title>Inputing Travel Detials</title>
<header>
<h1 align="center"> Adding Travel Detials </h1>
<body>
<p> <center><img src="cyberwarfareimage1.png" alt="Squadron logo" style="width:200px;height:200px" style="middle"></center>
<table border="1">
<tr>
<td><a href="index.php"> Home Page </a></td>
<td><a href="administratorhomepage.html">Administrator Home Page </a></td>
<td><a href="viewhomepage.html">View Home Page </a></td>
<td><a href="Inputhomepage.html">Input Home Page </a></td>
<td><a href="traveldetials.html">Enter More Travel Detials </a></td>
</table>
</p>
<?php
include "connection.php";
$Applicant_ID = $_POST["Applicant_ID"];
$Method_Of_Travel = $_POST["Method_Of_Travel"];
$Cost = $_POST["Cost"];
$ETA = $_POST["ETA"];
$Main_Gate_Advised = $_POST["Main_Gate_Advised"];
$query = ("UPDATE `int_board_applicant` SET `Method_Of_Travel`=`$Method_Of_Travel', `Cost`=`$Cost', `ETA`='$ETA', `Main_Gate_Advised`='$Main_Gate_Advised' WHERE `Applicant_ID`='$Applicant_ID'");
$result = mysqli_query($dbhandle, $query)
or die(mysqli_error($dbhandle));
if($result){ echo "Success!"; }
else{ echo "Error."; }
// successfully insert data into database, displays message "Successful".
if($query){
echo "Successful";
}
else {
echo "Data not Submitted";
}
//closing the connection
mysqli_close($dbhandle)
?>
Ok this is puzzleing. I am geting "Could not delete data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1". but its is deleting the entry that needs to be removed. The "1" is the entry. Just not sure what is causing the error. I do have another delete php but I have put that on the back burning for the time being.
<?php $con = mysqli_connect("localhost","user","password","part_inventory"); // Check connection if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); exit(); } else { $result = mysqli_query($con, "SELECT * FROM amp20 "); $amp20ptid = $_POST['amp20ptid']; // escape variables for security $amp20ptid = mysqli_real_escape_string($con, $_POST['amp20ptid']); mysqli_query($con, "DELETE FROM amp20 WHERE amp20ptid = '$amp20ptid'"); if (!mysqli_query($con, $amp20ptid)); { die('Could not delete data: ' . mysqli_error($con)); } echo "Part has been deleted to the database!!!\n"; mysqli_close($con); } ?> Hi guys
I have this code below and all works fine when submitting this online application apart from when someone types either ' # & into one of the comment fields in which it throws up the error. Have tried various fixes from across the internet but no joy. Can anyone offer suggestions?
<?php
$con = mysql_connect("localhost:3306","root","password");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db('sfapp', $con);
$sql="INSERT INTO 'sfapp' ('surname_add','forename_add','dob_add','hometele_add','mobiletele_add','homeadd_add','siblings_add','schoolname_add','headname_add','schooladd_add','schooltele_add','schoolem_add','alevel_add','personstate_add','nameprovided_add','pe_add','se_add','PredGrade_Art','PredGrade_AScience','PredGrade_BusStudies','PredGrade_Electronics','PredGrade_EnglishLang','PredGrade_EnglishLit','PredGrade_French','PredGrade_German','PredGrade_Geog','PredGrade_Graphics','PredGrade_History','PredGrade_Maths','PredGrade_SepScience','PredGrade_ProductDesign','PredGrade_Spanish','PredGrade_Other','Gender_Male','Gender_Female','Sub_EnglishLit','Sub_Maths','Sub_FurtherMaths','Sub_Biology','Sub_Chemistry','Sub_Physics','Sub_French','Sub_German','Sub_Spanish','Sub_Geography','Sub_History','Sub_RE','Sub_FineArt','Sub_Business','Sub_Computing','Sub_GlobPersp','Sub_DramaAndTheatre','Sub_PE','Sub_Dance','Sub_Politics','Sub_Psychology','Sub_Sociology','readprospect_chk','Sib_Yes','Sib_No','Current_Student_Yes','Current_Student_No','I_Understand_chk','Current_Education_chk','Local_Care_chk','Staff_Cwhls_chk','Sub_Film')
VALUES
('$_POST[surname_add]','$_POST[forename_add]','$_POST[dob_add]','$_POST[hometele_add]','$_POST[mobiletele_add]','$_POST[homeadd_add]','$_POST[siblings_add]','$_POST[schoolname_add]','$_POST[headname_add]','$_POST[schooladd_add]','$_POST[schooltele_add]','$_POST[schoolem_add]','$_POST[alevel_add]','$_POST[personstate_add]','$_POST[nameprovided_add]','$_POST[pe_add]','$_POST[se_add]','$_POST[PredGrade_Art]','$_POST[PredGrade_AScience]','$_POST[PredGrade_BusStudies]','$_POST[PredGrade_Electronics]','$_POST[PredGrade_EnglishLang]','$_POST[PredGrade_EnglishLit]','$_POST[PredGrade_French]','$_POST[PredGrade_German]','$_POST[PredGrade_Geog]','$_POST[PredGrade_Graphics]','$_POST[PredGrade_History]','$_POST[PredGrade_Maths]','$_POST[PredGrade_SepScience]','$_POST[PredGrade_ProductDesign]','$_POST[PredGrade_Spanish]','$_POST[PredGrade_Other]','$_POST[Gender_Male]','$_POST[Gender_Female]','$_POST[Sub_EnglishLit]','$_POST[Sub_Maths]','$_POST[Sub_FurtherMaths]','$_POST[Sub_Biology]','$_POST[Sub_Chemistry]','$_POST[Sub_Physics]','$_POST[Sub_French]','$_POST[Sub_German]','$_POST[Sub_Spanish]','$_POST[Sub_Geography]','$_POST[Sub_History]','$_POST[Sub_RE]','$_POST[Sub_FineArt]','$_POST[Sub_Business]','$_POST[Sub_Computing]','$_POST[Sub_GlobPersp]','$_POST[Sub_DramaAndTheatre]','$_POST[Sub_PE]','$_POST[Sub_Dance]','$_POST[Sub_Politics]','$_POST[Sub_Psychology]','$_POST[Sub_Sociology]','$_POST[readprospect_chk]','$_POST[Sib_Yes]','$_POST[Sib_No]','$_POST[Current_Student_Yes]','$_POST[Current_Student_No]','$_POST[I_Understand_chk]','$_POST[Current_Education_chk]','$_POST[Local_Care_chk]','$_POST[Staff_Cwhls_chk]','$_POST[Sub_Film]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
?>
<?php
//if "email" variable is filled out, send email
if (isset($_REQUEST['pe_add'])) {
//Email information
$admin_email = $_REQUEST['pe_add'];
$forename = $_REQUEST['forename_add'];
$email = "autoreply@testing.com";
$subject = "Application";
$desc =
"Dear $forename
Thank you for submitting your online application, we will be in touch shortly.
"
;
//send email
mail($admin_email, "$subject", "$desc", "From:" . $email);
//Email response
echo "Thank you for contacting us!";
}
//if "email" variable is not filled out, display the form
else {
?>
If you are seeing this, you need to go back and fill out the Personal Email section!
<?php
}
header("location:complete.php");
mysql_close($con)
?>
Thanks in advance.
Hi all, I am new to PHP and wish to use it simply to collect form data and email it to myself. From what I have gathered from PHP tutorials I have write the following script but I am getting syntax error warnings and cant figure out why. Can somebody please tell me where I am going wrong and if this script will actually work? The line I am getting errors on is Code: [Select] <?php //message contains $message = "Name:$name</br>Email:$email</br>Phone:$phone</br>Preferred Date:$date</br>Best Time To Contact:$time"; ?> Thank you in advance. Code: [Select] <body> <?php //my email $recipient = "info@hairlosslasergroup.co.uk"; //persons name $name = htmlspecialchars($_POST['name']); //persons email $email = htmlspecialchars($_POST['email']); if (!preg_match("/([\w\-]+\@[\w\-]+\.[\w\-]+)/",$email)) { die("E-mail address not valid"); } //persons phone number $phone = htmlspecialchars($_POST['phone']); //preferred date $date = htmlspecialchars($_POST['comments']); //best time $time = htmlspecialchars($_POST['time']); //check required fields $required = check_input($_POST['required'], "Please go back and complete all required fields"); //email subject $subject = ($_POST['subject'] //message contains $message = "Name:$name</br>Email:$email</br>Phone:$phone</br>Preferred Date:$date</br>Best Time To Contact:$time"; //message mail($recipient, $subject, $message); //redirect to thank you page header('Location:$redirect'); ?> </body> </html> I used to have a straight forward piece of code that updated multiple rows of info using a foreach loop. However, ever since I've introduced a textarea box into the mix, it's been throwing up syntax errors. Here's my textarea box: Code: [Select] <textarea id=\"detail[]\" name=\"detail[]\" rows=\"7\" cols=\"35\" wrap=\"hard\">$data[detail]</textarea> And here's my UPDATE query: Code: [Select] foreach($_POST['mid'] as $key=>$val) { mysql_query("UPDATE val_mworks SET mworks_percent = ".$_POST['percent'][$key].", mworks_detail = ".$_POST['detail'][$key].", mworks_qty = ".$_POST['qty'][$key]." WHERE mworks_id = $val ") or die(mysql_error()); } Can anyone see anything obvious that I'm doing wrong? Hello I have the following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM players WHERE ((NOT inactive_player) AND ((players.Player_Last_Name = 'p' at line 3 I think my error is in the statement below... Code: [Select] echo "1"; $getNewPlayers = "SELECT players.Player_number, players.Player_name, FROM players WHERE ((NOT inactive_player) AND ((players.Player_Last_Name = 'player_find%'))) ORDER BY player_name"; $rsNewPlayers = mysql_query($getNewPlayers, $link) or die (mysql_error()); $varNewCount = mysql_num_rows($rsNewPlayers); echo $varNewCount['Player_name']; Can you tell me where the error is and how I might go about to fix it? Thanks,
<?php
//COOKIE CHECKER
if (isset($_COOKIE["person"])){
if (filter_var($_COOKIE["person"], FILTER_VALIDATE_INT)){
$user_id = $_COOKIE["person"];
//DATABASE CONNECTION VARIABLES
$myserver ="localhost";
$myname = "username";
$mypassword = "password";
$mydb ="dbname";
/*SQL CONNECTION*/
// Create connection
$conn = new mysqli($myserver, $myname, $mypassword, $mydb);
// Check connection
if ($conn->connect_error) {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>
<H1>Decline of the Han - Three Kingdoms</H1>';
die("Connection failed: " . $conn->connect_error);
echo '</BODY>
</HTML>';
}
else {
//COUNT USER
$cquery = "SELECT COUNT(*) AS usercheck FROM Players WHERE ID = ?";
$cid = $conn->prepare($cquery);
$cid->bind_param('i', $user_id);
$cid->execute();
$cid->bind_result($usercheck);
$cid->fetch();
if ($usercheck ==1){
if (isset($_POST["profile"])){
if(!filter_var($_POST["profile"], FILTER_SANITIZE_STRING)){
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">Unable to filter bio <a href="biography.php">return</a></P>';
echo '</BODY>
</HTML>';
}
else {
$profile = $_POST["profile"];
$sql = "UPDATE Player_Data SET Bio =? WHERE ID=?";
$q = $conn->prepare($sql);
$q->bind_param("si", $profile, $user_id);
$q->execute();
echo '<P>Biography altered <a href="biography.php">return</a></P>';
//close connection
$conn->close();
}
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">'.$usercheck.' '.$user_id.'</P>';
echo '<P class="error">No such user found!</P>';
//close connection
$conn->close();
//foot
echo '</BODY>
</HTML>';
}
//end connection check
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">ERROR invalid cookie!</P>';
echo '</BODY>
</HTML>';
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">No cookie detected!<br><a href="login.php">login</a></P>';
echo '</BODY>
</HTML>';
}
?>
I have an error in the update, but I am not seeing where I made it. Its annoying because the update won't execute and anything beyond the update isn't visible in the html source code in the browser, so it is likely to be a syntax error, but where?
<?php
//COOKIE CHECKER
if (isset($_COOKIE["person"])){
if (filter_var($_COOKIE["person"], FILTER_VALIDATE_INT)){
$user_id = $_COOKIE["person"];
//DATABASE CONNECTION VARIABLES
$myserver ="localhost";
$myname = "username";
$mypassword = "password";
$mydb ="dbname";
/*SQL CONNECTION*/
// Create connection
$conn = new mysqli($myserver, $myname, $mypassword, $mydb);
// Check connection
if ($conn->connect_error) {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>
<H1>Decline of the Han - Three Kingdoms</H1>';
die("Connection failed: " . $conn->connect_error);
echo '</BODY>
</HTML>';
}
else {
//COUNT USER
$cquery = "SELECT COUNT(*) AS usercheck FROM Players WHERE ID = ?";
$cid = $conn->prepare($cquery);
$cid->bind_param('i', $user_id);
$cid->execute();
$cid->bind_result($usercheck);
$cid->fetch();
if ($usercheck ==1){
if (isset($_POST["profile"])){
if(!filter_var($_POST["profile"], FILTER_SANITIZE_STRING)){
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">Unable to filter bio <a href="biography.php">return</a></P>';
echo '</BODY>
</HTML>';
}
else {
$profile = $_POST["profile"];
$sql = "UPDATE Player_Data SET Bio =? WHERE ID=?";
$q = $conn->prepare($sql);
$q->bind_param("si", $profile, $user_id);
$q->execute();
echo '<P>Biography altered <a href="biography.php">return</a></P>';
//close connection
$conn->close();
}
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">'.$usercheck.' '.$user_id.'</P>';
echo '<P class="error">No such user found!</P>';
//close connection
$conn->close();
//foot
echo '</BODY>
</HTML>';
}
//end connection check
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">ERROR invalid cookie!</P>';
echo '</BODY>
</HTML>';
}
}
else {
echo '<!DOCTYPE HTML>
<HTML>
<HEAD>
<TITLE>test</TITLE>
</HEAD>
<BODY>';
echo '<P class="error">No cookie detected!<br><a href="login.php">login</a></P>';
echo '</BODY>
</HTML>';
}
?>
I have an error in the update, but I am not seeing where I made it. Its annoying because the update won't execute and anything beyond the update isn't visible in the html source code in the browser, so it is likely to be a syntax error, but where?
$pastelink = "<br /><a href='view.php?paste=$lol&language=$language'>$name</a>"; mysql_query("INSERT INTO recent (url) VALUES ('$pastelink')"); That query won't run, however if I do this: $test = $_POST['name']; //$pastelink = "<br /><a href='view.php?paste=$lol&language=$language'>$name</a>"; mysql_query("INSERT INTO recent (url) VALUES ('$test')"); It will run, is this because of the single quotes in $pastelink? & If so, how can I fix it? Hi, I have been trying to make a page which shows a number of thumbnails, populated by images and text from a database, this I got working perfectly fine, but as I am now trying to make it so users can log in and edit or delete each one, it has all started to go a bit wrong and I was wondering if anyone could spot why?!? It is currently bringing up this message on the screen: Error fetching entries from the database, error: Statement: SELECT image,id,projecttitle,projectcode,FROM portfolio ORDER BY id DESC LIMIT 16 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM portfolio ORDER BY id DESC LIMIT 16' at line 1 Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in /Users/mdfcows/Sites/atelier/portfolio.php on line 129 I don't quite know how to get it to print out the full nature of the error, but this is the code I am using: Code: [Select] <?php $max_items2 = 16; /* max number of news items to show */ require_once('config.php'); $db2 = mysql_connect (DB_HOST,DB_USER,DB_PASSWORD); if(!$db2) { die('Failed to connect to server: ' . mysql_error()); } mysql_select_db (DB_DATABASE,$db2); function displayNews($all2 = 0) { global $db2, $max_items2; if ($all2 == 0) { /* query for news up to $max_items */ $query9 = "SELECT image,id,projecttitle,projectcode," . "FROM portfolio ORDER BY id DESC LIMIT $max_items2"; } else { /* query for all news */ $query9 = "SELECT image,id,projecttitle,projectcode," . "FROM portfolio ORDER BY id DESC"; } $result9 = mysql_query($query9) or print("<p>Error fetching entries from the database, error: " . "Statement: " . $query9 . "</p>" . mysql_error()); while ($row9 = mysql_fetch_assoc ($result9)) { $title = htmlentities ($row9['projecttitle']); $news = nl2br (strip_tags ($row9['projectcode'], '<a><b><i><u>')); $image = $row9['image']; $id = $row9['id']; /* display the data */ ?> <div class="boxgrid captionfull"> <a id="<?php echo $id ?>" <a class='visit' href="project.php?id=<?php echo $news ?>"> <?php echo $image; if(strstr($image, 'jpg') or (strstr($image, 'png')) or (strstr($image, 'gif')) or (strstr($image, 'bmp')) or (strstr($image, 'jpeg')) ) { echo "<img class='cpimg' src='images/portfolio/$image' alt='' />"; }else { echo "";} ?>"></a> <div class="cover boxcaption" style="top: 122px; "> <p align="left"><?php echo $title ?></p> </div> </div> <?php //Check whether the session variable SESS_MEMBER_ID is present or not if(isset($_SESSION['SESS_MEMBER_ID']) || (!trim($_SESSION['SESS_MEMBER_ID']) == '')) { echo "<form class='editbtn' action='editportfolio.php' method='POST'>"; echo "<input type='hidden' name='idf' value='$id' />"; echo "<input src='images/editbtn.png' type='image' value='Edit' />"; echo "</form>"; echo "<form class='editbtn' action='deletportfolio.php' method='POST'>"; echo "<input type='hidden' name='ide' value='$id' />"; echo "<input src='images/delbtn.png' type='image' value='Delete' />"; echo "</form>"; } else { echo ""; } } } /* this is where the script decides what do do */ echo "\n"; switch($_GET['action']) { case 'all': displayNews(1); break; default: displayNews(); } echo "\n"; ?> <?php //Check whether the session variable SESS_MEMBER_ID is present or not if(isset($_SESSION['SESS_MEMBER_ID']) || (!trim($_SESSION['SESS_MEMBER_ID']) == '')) { echo "<span class='show_all'>"; echo "<a class='show' href='admincp.php'> Admin</a>"; echo "</span>"; echo "<span class='show_all'>"; echo "<a class='show' href='logout.php'> Logout</a>"; echo "</span>"; } else { echo ""; } ?> with the line, " while ($row9 = mysql_fetch_assoc ($result9)) {" being line 129 any help would be much appreciated! Thank you, Martin how to update the record of one table in which condition is that the it should similar to the other table feild only. e.g field of table1 will update only when the feild1 of table1 is equal to field2 of table2 in php?? while im using following command mysql_select_db("db1",$con); $query = "SELECT table2.feild1 , table2.feild1 " . "FROM table2, table1 " . "WHERE table1.feild2 = table2.feild1 "; $data = mysql_query($query) or die(mysql_error()); $sql="UPDATE table2 SET feild2='$_POST[value2]', feild3='$_POST[value3]' WHERE table1.feild2 = $data "; im developing a voting system where you can vote for multiple choices using checkboxes.. upon submitting the vote form, votecounts must automatically be updated.. values for votecount will come from the checkbox value 1. ive been having a hard time trying to figure out hot to update multiple rows with checkbox values..any help would be appreciated..thanks in advance! here's the code: Code: [Select] $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form_vote")) $i=1;{ while ($i<= $totalRows_rs_candi) { $updateSQL = "UPDATE tbl_candidates SET votecount={$_POST['votecount']} WHERE user_id={$_POST['candi']}"; mysql_select_db($database_organizazone_db, $organizazone_db); $Result1 = mysql_query($updateSQL, $organizazone_db) or die(mysql_error()); $i++; } if (isset($_SERVER['QUERY_STRING'])) { $updateGoTo = "vote_success.php"; } header(sprintf("Location: %s", $updateGoTo)); } Code: [Select] <form id="form_vote" name="form_vote" method="POST" action="<?php echo $editFormAction; ?>"> <table border="1"> <tr> <td> </td> <td>user_id</td> <td>l_name</td> <td>course_id</td> <td>yearlevel</td> <td>about</td> </tr> <?php $i=1; do { ?> <tr> <td><span id="sprycheckbox1"> <input name="votecount[<?php echo $i ?>]" type="checkbox" id="votecount" value="1" /> <span class="checkboxMinSelectionsMsg">Minimum number of selections not met.</span></span> <label for="votecount[]"></label></td> <td><label for="candi"></label> <input name="candi" type="text" disabled="disabled" id="candi" value="<?php echo $row_rs_candi['user_id']; ?>" readonly="readonly" /></td> <td><?php echo $row_rs_candi['l_name'].' ,'.$row_rs_candi['f_name'].' '.$row_rs_candi['m_name']; ?></td> <td><?php echo $row_rs_candi['course_id']; ?></td> <td><?php echo $row_rs_candi['yearlevel']; ?></td> <td><?php echo $row_rs_candi['about_me']; ?></td> </tr> <?php $i++; ?> <?php } while ($row_rs_candi = mysql_fetch_assoc($rs_candi)); ?> </table> I'm trying to get some code to work that will update a field to show a checkbox either checked or not checked.
The field either uses a Y or N. Y is checked, N not checked. A code that I have tried displays the correct result for the box either checked or not checked.
input type="checkbox" name="obcDisplay" value="Y" <?=($r['obcDisplay'] == 'Y') ? 'checked="checked"' : ''; ?>/>But I want the ability to change when the form is submitted. so if I bring up a page and the checkbox is checked (Y) and I submint, I want the database to update to N and the other way around. Hey all, Let's say I want to do something like this: Code: [Select] <?php function exists($a){ $b ||= $a; } echo exists(1); ?> Basically, every time exists is called, it will only assign b to a if b isn't already initialized. What's the most effective way to achieve the equivalent in php? ternary? Thanks for response. Right I want to make a request to my db to check the no. of rows it has. If it has changed, refresh the chat page. else wait. I have tried to check for last db update, that never worked as well. Well here is my code. Code: [Select] //this is my refresh script below $result = mysql_query("SELECT * FROM chatmessages"); $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; while(0){ $num_rows_temp = mysql_num_rows($result); if ($num_rows != $num_rows_temp){ $$num_rows=$num_rows_temp; echo "<script>"; echo "window.location.replace('chatlog.php')"; echo "</script>"; }else{ sleep(2); } } I assume $num_rows != $num_rows_temp is wrong as it does not seem to do anything. Any help would be welcome. thanks. When I echo the POST, it echoes the correct value. The MySQL portion seems to just ignore it all together. I've tried changing the dropdown option to just a text field, same thing occurred. I have text fields right above this particular one that update just fine with the SAME exactly scripting. if POST, update query, done. Works. This one for some reason will not. MySQL portion: if ($_POST['bUpdate']){ mysql_query("UPDATE `Patients` SET `b` = '$_POST[bUpdate]' WHERE `id` = '".$_GET['id']."'"); } echo $_POST['bUpdate']; Form Portion: Code: [Select] <tr onmouseover="color(this, '#baecff');" onmouseout="uncolor(this);"> <td width="310" colspan="2" align="center"><span class="fontoptions">Postcard Status </span><br /> <? if ($data['b'] == 1){ echo '<select name="bUpdate"><option value="1" selected>Yes</option><option value="0">No</option></select>'; } else { echo '<select name="bUpdate"><option value="1">Yes</option><option value="0" selected>No</option></select>'; } ?> </td> </tr> if ($content['size'] == "sizel") {$content['size'] = "Large";} echo "{$content['size']}"; This doesn't work and just echo's "sizel". Why? I was able to install CKEditor and the plugin "Syntax Highlighter".
Yet the plugin does not work. This is how the code comes out:
<div> <H1>You are Writing this Post</H1> <form action="insert.php" method="POST"> <input type="text" name="title" /> <br /> <textarea type="text" name="post"></textarea> <br /> <input type="submit&qAny suggestions? Edited by glassfish, 03 October 2014 - 06:16 AM. Hello all, I have tried the following syntax to update a record from the $_POST method, and I cannot get it to update the record. Can anyone spot where I'm going wrong in my code Code: [Select] <?php $idstudent = $_POST["idstudent"]; $childname = $_POST["childname"]; $parentname = $_POST["parentname"]; $dated = $_POST["dated"]; $datem = $_POST["datem"]; $datey = $_POST["datey"]; $dob = $datey ."-". $datem ."-".$dated; $age = $_POST["age"]; $lastupdate = date("Y\-m\-d"); $gender = $_POST["gender"]; $address1 = $_POST["address1"]; $address2= $_POST["address2"]; $city = $_POST["city"]; $postcode = $_POST["postcode"]; $phone = $_POST["phone"]; $mobile = $_POST["mobile"]; $email = $_POST["email"]; $pass= $_POST["password"]; $height = $_POST["height"]; $neck = $_POST["neck"]; $chest = $_POST["chest"]; $hips = $_POST["hips"]; $waist = $_POST["waist"]; $insideleg = $_POST["insideleg"]; $dress = $_POST["dress"]; $shoe = $_POST["shoes"]; $haircolour = $_POST["haircolour"]; $hairlength = $_POST["hairstyle"]; $eyes = $_POST["eyecolour"]; $ethnicity = $_POST["ethnicity"]; $image = $_POST["image"]; $approve = "0"; $actor = $_POST["actor"]; $standin = $_POST["standin"]; $voiceover = $_POST["voiceover"]; $stagecombat = $_POST["stagecombat"]; $daballet = $_POST["daballet"]; $dasalsa = $_POST["dasalsa"]; $dabreak = $_POST["dabreak"]; $dadisco = $_POST["dadisco"]; $dahiphop = $_POST["dahiphop"]; $dajazz = $_POST["dajazz"]; $damodern = $_POST["damodern"]; $dastreet = $_POST["dastreet"]; $datap = $_POST["datap"]; $dacontemp = $_POST["dacontemp"]; $dafreestyle = $_POST["dafreestyle"]; $daswing = $_POST["daswing"]; $dawaltz = $_POST["dawaltz"]; include ('../../source/db_config.php'); $db = mysql_connect($host,$username,$password) or die(mysql_error()); mysql_select_db($database, $db) or die(mysql_error()); $update = "UPDATE 'students' SET 'childname'='$childname', 'parentname'='$parentname', 'dob'='$dob', 'age'='$age', 'lastupdate'='$lastupdate', 'gender'='$gender', 'address1'='$address1', 'address2'='$address2', 'city'='$city', 'postcode'='$postcode', 'phone'='$phone', 'mobile'='$mobile', 'email'='$email', 'password'='$pass', 'height'='$height', 'neck'='$neck', 'chest'='$chest', 'hips'='$hips', 'waist'='$waist', 'insideleg'='$insideleg', 'dress'='$dress', 'shoe'='$shoe', 'haircolour'='$haircolour', 'hairlength'='$hairlength', 'eyes'='$eyes', 'ethnicity'='$ethnicity', 'actor'='$actor', 'standin'='$standin', 'stagecombat'='$stagecombat', 'daballet'='$daballet', 'dasalsa'='$dasalsa', 'dabreak'='$dabreak', 'dadisco'='$dadisco', 'dahiphop'='$dahiphop', 'dajazz'='$dajazz', 'damodern'='$damodern', 'dastreet'='$dastreet', 'datap'='$datap', 'dacontemp'='$dacontemp', 'dafreestyle'='$dafreestyle', 'daswing'='$daswing', 'dawaltz'='$dawaltz' WHERE 'id'='$idstudent'"; mysql_query($update); ?> Don't worry about the password either.. it is passed through md5 encryption. But any help will be greatly appreciated |
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