PHP - Form Submit --- Return Error: 4?

Here is my code :

https://paiza.io/projects/SUiG5qp_wttfcrQn-0Mwew?language=php FYI -> [index.htm -> LineNo : 781 & 782]

After successfully received payment response page return 404 error

The form & CC-Avenue Payment Gateway Request page working good, after customer paid the response page return 404 error.

How can i solve the error?

Edited May 22, 2019 by aveeva

Hey Guys,

Im working with a form and need some help.

So at the moment i have got it working so that if the user doesn't select the values from the drop down list, an error will occur saying 'Please select all fields'.

What i want to do now is make it so that if this error occurs, the value of the drop down list will stay as it is an NOT reset. Could someone help me out?

* Note that the code below is currently ok, basically it checks if there is a value, if not it will say "Select Player".

Code: [Select]

<td>Prop</td>
    <td><select name="prop1" style="width: 150px">
<option value="<? echo $row['prop1']; ?>"><? if (empty($row['prop1'])) { echo "Select Player"; } else { echo $row['prop1'];  } ?></option>
<?php echo $option_str; ?>
    </select></td>
    <td>16.</td>
    <td><select name="r16" style="width: 150px">
<option value="<? echo $row['r16']; ?>"><? if (empty($row['r16'])) { echo "Select Player"; } else { echo $row['r16'];  } ?></option>
      <?php echo $option_str; ?>
    </select></td>

Hey all. I'm a noob so bare with me. Just started studying php and have an assignment due. At this phase of the project I have to create a form where a user can register data and I should retrieve that data and store it in my database. Now I have already created the form (student_reg.php) and a separate file with php code (demo.php)

My database is name "registration" and I am trying to put this info in the "student" table. It has about 15 fields but for now I am only trying trying to insert the 1 field of data to test if it works. Dont know if that may cause problems?

So far my demo.php connects to the database successfully. The problem I am having is the information I submit does not showing in the database field. However, I have an id field in my case a student number field which is set to auto increment so it automatically updates (1,2,3,4) with each new sumbitted info. When I submit the info the id field gets updated each time with a new row ( so i assume some information is somehow going through ) however the info I entered will remain blank in its field. :banghead:

Heres my form (student_reg.php)

Code: [Select]
<div id="apdiv3">

<FORM action = "demo.php" method ="post ">

<p>Course name:</p>
<INPUT TYPE = "text"  name="input"/>
<INPUT TYPE = "Submit" VALUE = "Submit"/>
</div>
</FORM>

and heres my php code to retrieve the form info

Code: [Select]
<?PHP


include 'includes/config.php';

//connect to database
$link=mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);



//error check
if (!$link)
{
die('could not connect: ' . mysql_error());
}

$db_selected=mysql_select_db(DB_NAME, $link);



// error check
if (!$db_selected)
{
die('can\t use ' . DB_NAME . ': ' . mysql_error());
}
// Connected to database



// retrieve form data
$value=(isset($_POST['input']));

$sql = "INSERT INTO student (sname) VALUES ('$value')";


if (!mysql_query($sql))
{
die ('Error: ' . mysql_error());
}
mysql_close();


?>

I also recieved a notice "undefined index" or something like that from this part of the code "$value=(isset($_POST['input']));" before I inserted "isset" to the code. I'm not sure if what I did fixed the problem or only hid it, or whether that notice was related to the problem I'm having of not retrieving the info.

Haha sorry guys know this is probably childs play for you but I just started out and really need to fix this so I can catch up with this project. Feel free to add tips and comments on other areas. Thanks :mrgreen:

Hi all,

What I am trying to achieve is, I thought quite simple!

Basically, a user signs up and chooses a package, form is submitted, details added to the database, email sent to customer, then I want to direct them to a paypal payment screen, this is where I am having issues!

Is their any way in php to submit a form without user interaction? Here is my code for the form process page
Code: [Select]
<?php
include('config.php');
require('scripts/class.phpmailer.php');

$package = $_POST['select1'];
$name = $_POST['name'];
$email = $_POST['email'];
$password = md5($_POST['password']);

$domain = $_POST['domain'];
$a_username = $_POST['a_username'];
$a_password = $_POST['a_password'];


$query=mysql_query("INSERT INTO orders (package, name, email, password, domain, a_username, a_password)
VALUES
('$package', '$name', '$email', '$password', '$domain', '$a_username', '$a_password')");

if (!$query)
{
echo "fail<br>";
echo mysql_error();
}

else
{
$id = mysql_insert_id();
$query1=mysql_query("INSERT INTO customers (id, name, email, password)
values
('$id', '$name', '$email', '$password')");

if (!$query1)
{
echo "fail<br>";
echo mysql_error();
}


if($package=="Reseller Hosting")
{

//email stuff here - all works - just cutting it to keep the code short


if(!$mail->Send())
{
   echo "Message could not be sent. <p>";
   echo "Mailer Error: " . $mail->ErrorInfo;
   exit;
}
?>


<form name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick-subscriptions">
<input type="hidden" name="business" value="subscription@jollyhosting.com">
<input type="hidden" name="currency_code" value="USD">
<input type="hidden" name="item_name" value="Jolly Hosting Reseller Packages">
<input type="hidden" name="no_shipping" value="1">

<!--1st month -->
<input type="hidden" name="currency_code" value="USD"> 
<input type="hidden" name="a3" value="3.00">
<input type="hidden" name="p3" value="1">
<input type="hidden" name="t3" value="M">
<input type="hidden" name="src" value="1">
<input type="hidden" name="sra" value="1">
</form>';


<?php
}

//last
}
//end
?>

Hi-
the code below lets me upload a CSV file to my database if I have 1 field in my database and 1 column in my CSV.
I need to add to my db "player_id" from the CVS file and "event_name" and "event_type" from the form... any ideas???

here's the code:
Code: [Select]
<?php
$hoststring =""; 
$database = "";
$username = "";
$password = "";
$makeconnection = mysql_pconnect($hoststring, $username, $password);
?>
<?php
ob_start();
mysql_select_db($database, $makeconnection);
$sql_get_players="
SELECT * 
FROM tabel 
ORDER BY player_id ASC";
//
$get_players = mysql_query($sql_get_players, $makeconnection) or die(mysql_error());
$row_get_players = mysql_fetch_assoc($get_players);
//
$message = null;
$allowed_extensions = array('csv');
$upload_path = '.'; //same directory

if (!empty($_FILES['file'])) {

if ($_FILES['file']['error'] == 0) {
// check extension
$file = explode(".", $_FILES['file']['name']);
$extension = array_pop($file);

if (in_array($extension, $allowed_extensions)) {

if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) {

if (($handle = fopen($upload_path.'/'.$_FILES['file']['name'], "r")) !== false) {
$keys = array();
$out = array();
$insert = array();
$line = 1;

while (($row = fgetcsv($handle, 0, ',', '"')) !== FALSE) {

foreach($row as $key => $value) {    

if ($line === 1) {
$keys[$key] = $value;       
} else {       
$out[$line][$key] = $value;              
}       
}                
$line++;          
}        

fclose($handle);            

if (!empty($keys) && !empty($out)) {        
$db = new PDO(
'mysql:host=host;dbname=db', 
'user', 
'pw');   

$db->exec("SET CHARACTER SET utf8");        

foreach($out as $key => $value) {        
$sql  = "INSERT INTO `table` (`";
$sql .= implode("`player_id`", $keys);    
$sql .= "`) VALUES (";    
$sql .= implode(", ", array_fill(0, count($keys), "?"));    
$sql .= ")";    
$statement = $db->prepare($sql);    
$statement->execute($value);       
}      

$message = '<span>File has been uploaded successfully</span>';      
}
}
}
} else {
$message = '<span>Only .csv file format is allowed</span>';
}
} else {
$message = '<span>There was a problem with your file</span>';
}
}
ob_flush();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>CSV File Upload</title>
</head>
<body>

<form class="form" action="" method="post" enctype="multipart/form-data">
<h3>Select Your File</h3>
<p><?php echo $message; ?></p>
<input type="file" name="file" id="file" size="30" />
<br/>
<label>Event Name:</label><input name="event_name" type="text" value="" />
<br/>
<label>Event Type:</label><input name="event_type" type="text" value="" />
<br/>
<input type="submit" id="btn" class="button" value="Submit" />
</form>

<br/>
<h3>Results:</h3>
<?php do { ?>
<p><?php echo $row_get_players['player_id'];?></p>
<?php } while ($row_get_players = mysql_fetch_assoc($get_players)); ?>
</body>
</html>

Hello,

Curious to know if someone could point me in the right direction, been struggling with this for a bit now.

I have a HTML page with a search field, I can enter a search term and hit the submit button and I am directed to my search.php page with the appropriate results. What I am looking to accomplish is having the search results from the search.php page displayed in a text area below my search field in my HTML page. I have included an image to better describe what I am looking to accomplish:



Additionally below is the source from my HTML page and search.php page:

page.html


<form  name="search" action='search.php' method="post">
<input type="text" class="myinputstyle" name="search" value="search" onClick="this.value=''"/><br>
<input type="submit" value="submit" class="myinputstyle">
</form>


search.php


<?php
  $search = "%" . $_POST["search"] . "%";

  mysql_connect ("localhost", "game_over", "Ge7Ooc9uPiedee3oos9xoh4th");
  mysql_select_db ("game_over");

  $query = "SELECT * FROM game_over WHERE first_name LIKE '$search'";
  $result = mysql_query ($query);
  if ($result) {
    while ($row = mysql_fetch_array ($result)) {

    echo "Name: {$row['name']} " .
         "{$row['lname']} <br>" .
         "Email: {$row['email]} <br>" .
    }
  }
?>


Any insight would be most appreciated.

Thank you.

Whenever I hit submit I get an internal server error. Here is the code:

<?php $modsToBeChecked = str_replace(
"\r",
"\n",
str_replace( "\r\n", "\n", $_POST[ 'modsToBeChecked' ] )
);
$modsToBeChecked = explode( "\n", $modsToBeChecked );


var_dump( $modsToBeChecked );?>

$modsToBeChecked is passed in from a textarea form. It is suppose to treat each line in the textbox as one element of the array. Here is the form code in case you need it:

<form  action=""><textarea name="modsToBeChecked" rows="25" cols="50"></textarea>
<input type="submit">
</form>

I can't submit php form using IE 8.  This works fine on Firefox very well.
I tried following code but none of them is working.   
1.  <button type="submit">Submit</button>

2.  <input type="submit" value="Submit" name="submit">


 I would appreciate if any one help me in this.

hello everyone, I have a php form, everything works, I do not carry any header() at the end of the form because I have to stay on the same page and because I feel it wipes out the message you sent the form successfully, but for this though if reloading  the page shows me the popup asking me to resend the form.  how can i solve?  I found a function in js with replacestate but I saw that it doesn't work with mobile Safari.

if ( window.history.replaceState ) { window.history.replaceState( null, null, window.location.href ); }

 

Can anybody see as to why, if any, this form takes forever to execute?
Code: [Select]
<?php
if(isset($_POST['submitted'])){
    $z = $_POST['zipcode'];
    $r = $_POST['radius'];
    
    $sql = mysql_query("SELECT DISTINCT m.LocAddZip, m.MktName,m.LocAddSt,m.LocAddCity,m.LocAddState,m.x1,m.y1,z1.lat,z2.long
    FROM mrk m, zip z1, zip z2
    WHERE m.LocAddZip = z1.zipcode
    AND z2.zipcode = $z
    AND ( 3963 * acos( truncate( sin( z2.lat / 57.2958 ) * sin( z1.lat / 57.2958 ) + cos( z2.lat / 57.2958 ) * cos( z1.lat / 57.2958 ) * cos( z1.long / 57.2958 - z2.long / 57.2958 ) , 8 ) ) ) <= $r ")
    
    or die(mysql_error());
        while($row = mysql_fetch_array( $sql )) {
            $store = $row['MktName']."<br />";
            $store .= $row['LocAddSt']."<br />";
            $store .= $row['LocAddCity'].", ".$row['LocAddState']." ".$row['LocAddZip'];
            $lat1 = $row['lat'];
            $lon1 = $row['long'];
            $lat2 = $row['y1'];
            $lon2 = $row['x1'];
            $dis = distance($lat1, $lon1, $lat2, $lon2);
     
            echo "<p>".$store."</p>";        
            echo ceil($dis) . " mile(s) away";
            echo "<hr/>";
        }
}
?>

I get a timeout error sometimes, and sometimes I don't.
Is it the form, or would it be on the server?

Thanks in advance

Hi, I have setup a basic enquiry form with a Captcha - once the code has been inserted and is correct I want to action the form (submit) in PHP.

<?php

session_start();
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$vResult = '';
if(strtolower($_SESSION['security_code']) != strtolower($_POST['security_code'])){
$vResult = 'Invalid code!';
}
else{
"/enquiry.php"
}
}
?>

I want to submit the form to /enquiry.php - I tried header(Location.. and realised that just redirects, and doesn't submit the form.

Any suggestions or tips would be great.

Cheers,

Paul

Code: [Select]
<?php
 
if (isset($_POST['checking'])) { echo $_POST['checking']; }
if (isset($_POST['test'])) { echo $_POST['test']; }
 
?>
 
 
<form id="testform2" action="testform.php" method="post">
 
<select name="checking" onchange="this.form.submit()"><option value="5">5</option><option value="6">6</option></select>
<input type="text" name"test" id="test">
 <a href="#" onclick="this.form.submit()">submit it!</a>
</form>


It works when I try to submit by selecting a new value from the dropdown box but when I try to click the link it won't display the text field value. That is a test case for a problem I m having in one of my codes.

Hi,
I want to submit a form using ajax ans jquery with two fields input text and file.

Code: [Select]
<script>
$(document).ready(
function()
{


$('#basicinfofrm').ajaxForm(function() {
url: ''+PN+'.php',
type:'POST',
data:'action=yes&'+frmFeilds,
success: function(html)
{ 
 alert(html);

}

    }).submit();
</script>
<form action='' method='post'>
    <label>name</label>
    <input type='text' name='txtname' />
    <input type='file' name  = 'txtfile' />
   <input type='submit' value='save' />
</form>

but is is not working...
can anyone tell me how to?
i don't want to refresh my page
Thanks

for example, I will like

harrypotter as the hyperlink and it holding a hidden value "books"

I have a form on my website and when the user submits it I want all the server processing to be done using AJAX so the page doesn't refresh.  I was wondering what the best way to do this is because if your form has a submit button doesn't that automatically refresh the page?

Thanks for any help.