PHP - Linking A Img Class

Hi,

I need to be able to call a class based on variables.  E.G.

I would normally do:
Code: [Select]
$action = new pattern1()
but i would like to be able to do it dynamicaly:
Code: [Select]
$patNum = 1;
$action = new pattern.$patNum.()
Im wondering if that's possible?  If so what would the correct syntax be?

Many Thanks.

I have two classes:

## Admin.php

<?php
class Admin
{
public function __construct()
{
include("Config.php");
}

/**
* deletes a client
* @returns true or false
*/
function deleteClient($id)
{
return mysql_query("DELETE FROM usernames WHERE id = '$id'");
}
}
?>


## Projects.php

<?php
class Projects
{
public function __construct()
{
include("Config.php");
$this->admin = $admin;
$this->dataFolder = $dataFolder;
}

/**
* Deletes a project
* @returns true or false
*/
function deleteProject($id)
{
$root  = $_SERVER['DOCUMENT_ROOT'];
$theDir  = $root . $this->dataFolder;
$sql  = mysql_query("SELECT * FROM projectData WHERE proj_id = '$id'");
while ($row = mysql_fetch_array($sql))
{
$mainFile = $row['path'];
$thumb = $row['thumbnail'];
if ($thumb != 'null')
{
unlink($theDir . "/" . substr($thumb,13));
}
unlink($theDir . "/" . substr($mainFile,13));
}
$delete = mysql_query("DELETE FROM projectData WHERE proj_id = '$id'");
$getDir = mysql_query("SELECT proj_path FROM projects WHERE id = '$id'");
$res = mysql_fetch_array($getDir);
rmdir($theDir . "/" . $res['proj_path']);
return mysql_query("DELETE FROM projects WHERE id = '$id'");
}
}
?>


How can I call deleteProject() from within Admin.php?

Hi people!

class FirstOne{

public function FunctionOne($FirstInput){
//do stuff and output value
return $value1;
}

}


Then:-


class SecondOne{

public function FunctionTwo($AnotherInput){
//do stuff and output value
return $value2;
}

}


What I want to know is this, if I want to use FunctionOne() in Class SecondOne do I do it like this:-

(Assume as I have instantiated the first class using $Test = new FirstOne(); )


class SecondOne{

function SecondedFunction(){
global $Test;
return $Test->FunctionOne();
}

public function FunctionTwo($AnotherInput){
//do stuff and output value
return $value2;
}

public function FunctionThree(){

//some code here
$this->Test->SecondedFunction();<--I think as I can omit the $this-> reference
}
}


My point is: Do I have to do it this way or is there way of having this done through __construct() that would negate the need for a third party function?

I have a version working, I just think that it is a little convoluted in the way as I have done it, so I thought I would ask you guys.

Any help/advice is appreciated.

Cheers
Rw

I have a class in which I have a function called connection. I am now trying to call this function from another class, but it will not work. It works if I put the code in from the other function rather than calling it but that defeats the purpous.

class locationbox

{
   function location()
   {
   
   
   $databaseconnect = new databaseconnect();
         $databaseconnect -> connection();{

$result = mysql_query("SELECT * FROM locations");

while($row = mysql_fetch_array($result)) // line that now gets the error, mysql_fetch_array() expects parameter 1 to be resource, boolean given //in
  {
  echo "<option>" . $row['location'] . "</option>";
    }
   
}
}}

How does one go about using one class inside another?

For example, building a class that does some series of functions, and uses a db abstraction layer class in the process?

I do know how to do this but I am curious about whether or not there is a "preferred" way to do this. I know there are a couple ways to use a class (I'll call Alpha_Class) within another class (I'll class Beta_Class)

Let's say we have this simple class (Beta_Class):

class beta {
    function foo(){
    
    }
}


If I wanted to use the Alpha Class within the Beta Class, I could any number of things. For example:

class beta {
    function foo(){
        $this->alpha = new alpha;
        //$this->alpha->bar();
    }
}


Or you could simply use the $GLOBALS array to store instantiated objects in:

$GLOBALS['alpha'] = new alpha;
class beta {
    function foo(){
        //GLOBALS['alpha']->bar();
    }
}


You could even declare Alpha_Class as a static class and thus would not need to be instantiated:

static class alpha {
    static function bar(){}
}

class beta {
    function foo(){
        //alpha::bar();
    }
}


Those are the only ways I can think of right now. Are there any other ways to accomplish this? I was wondering which way is the best in terms of readability and maintainability.

Hi all,

I have two classes. Registration and Connection.

Inside a registration.php I include my header.php, which then includes my connection.php...

So all the classes should be declared when the page is loaded.

This is my code:


registration.php:

<?php include ('assets/header.php'); ?> 
        
    <?php
        class registration{                    
            public $fields = array("username", "email", "password");
            public $data = array();
            public $table = "users";
            public $dateTime = "";
            public $datePos = 0;
            public $dateEntryName = "date";
            
            function timeStamp(){
                return($this->dateTime = date("Y-m-d H:i:s"));
            }
            
            function insertRow($data, $table){      
                    
                    foreach($this->fields as $key => $value){
                        mysql_query("INSERT INTO graphs ($this->fields)
                        VALUES ('$data[$key]')");
                    }
                    
                    mysql_close($connection->connect);
            }
            
            function validateFields(){
            
                $connection = new connection(); 
                $connection->connect();
                        
                foreach($this->fields as $key => $value){
                    array_push($this->data, $_POST[$this->fields[$key]]);
                }
                $this->dateTime = $this->timeStamp();
                array_unshift($this->data, $this->dateTime);                
                array_unshift($this->fields, $this->dateEntryName);   
                
                foreach($this->data as $value){
                    echo "$value";
                }
                
                $this->insertRow($this->data, $this->table);
            }
        }
        
        $registration = new registration();
        $registration->validateFields();
    ?>

<?php include ('assets/footer.php'); ?>



At this point I cannot find my connection class defined on another included/included page.



                $connection = new connection(); 
                $connection->connect;





config.php (included within header.php)

<?
    class connection{ 
        public $dbname = '**';   
        public $dbHost = '**';
        public $dbUser = '**';
        public $dbPass = '**';
        public $connect;
        
        function connect(){
            $this->connect = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass) or die ('Error connecting to mysql');
            mysql_select_db($this->dbname, $this->connect);
        }
    }
?>



Any ideas how to call it properly?

I found this code which makes a BMI Calculator (Form) for me however when I click on submit it takes the user back to the index page ie. domain.com/index.php. How do I change it to go to, say, domain.com/calculator.php ?    The code is below:

<?

/**
 * @package Module Body Mass Index Calculator for Joomla! 1.5
 * @version $Id: mod_bodymassindexcalculator.php 599 2010-03-20 23:26:33Z you $
**/


defined( '_JEXEC' ) or die( 'Restricted access' );

$heightcm=$_POST["heightcm"];
$weightkg=$_POST["weightkg"];

if ($heightcm!="" && $weightkg!="") {

$heightm = $heightcm / 100;
$bmi=round($weightkg / ($heightm*$heightm),1);

echo "Heigth, m: ".$heightm."<br />";
echo "Weigth, kg: ".$weightkg."<br />";
echo "Body Mass Index (BMI): ".$bmi."<br />";
echo "<strong>";

if ($bmi<16.5) {echo "Severely Underweight</strong><br />";}
if ($bmi>=16.5 && $bmi<=18.4) {echo "Underweight</strong><br />";}
if ($bmi>=18.5 && $bmi<=24.9) {echo "Normal</strong><br />";}
if ($bmi>=25 && $bmi<=29.9) {echo "Overweight</strong><br />";}
if ($bmi>=30 && $bmi<=34.9) {echo "Obese Class I</strong><br />";}
if ($bmi>=35 && $bmi<=39.9) {echo "Obese Class II</strong><br />";}
if ($bmi>=40) {echo "Obese Class III</strong><br />";}
echo "<br />";

}


$domain = $_SERVER['HTTP_HOST'];
$path = $_SERVER['SCRIPT_NAME'];
$queryString = $_SERVER['QUERY_STRING'];
$url = "http://" . $domain . $path;
$url3 = "http://" . $domain . $_SERVER['REQUEST_URI'];
$mystring1="?";
$s1=strpos($url3,$mystring1);
if($s1==0) {$url2=$url3;}
if($s1!=0) {$url2=substr($url3,0,$s1);}
$path = $url2;

//1 foot = 0.3048 meters
//1 inch = 2.54 centimeters
//1 pound = 0.45359237 kilograms

$n1=230;


echo "<table style=\"width: 100%\" cellspacing=\"0\" cellpadding=\"0\" align=\"center\"><tr><td valign=\"top\">";
//echo "<h3>BMI Calculator</h3>";
echo "<form action=\"".$path."\" method=\"post\" >";
echo "<strong>Height</strong><br />";
echo "<select name=\"heightcm\" >";
for ($i=30; $i<=$n1; $i++){ echo "<option value=\"$i\">".$i." cm / ".floor($i / 30.48)." ft ".round(($i-(floor($i / 30.48)*30.48)) / 2.54, 1)." in </option>";}
echo "</select>";
echo "<br />";
echo "<strong>Weight</strong><br />";
echo "<select name=\"weightkg\" >";
for ($i=30; $i<=$n1; $i++){ echo "<option value=\"$i\">".$i." kg / ".round($i / 0.45359237,2)." pounds </option>";}
echo "</select>";
echo "<br />";
//echo "<input name=\"searchterm\" type=text size=\"27\" class=\"ns1\">";
echo "<br />";
echo "<input type=\"submit\" value=\"Calculate\" name=\"B1\">";
echo "</form><br />";

//DON'T REMOVE THIS LINK - DO NOT VIOLATE GNU/GPL LICENSE!!!
echo "<a href=\"http://nutritioncaloriecounter.com\">Nutrition Calorie Counter</a>";
//DON'T REMOVE THIS LINK - DO NOT VIOLATE GNU/GPL LICENSE!!!
echo "</td></tr></table>";




?>

Well the title may seem a bit confusing, but heres an example:

Code: [Select]
<?php
class User{
   public $uid;
   public $username;
   protected $password;
   protected $email;
   public $usergroup;
   public $profile;
   

  public function __construct($id){
      // constructor code inside
  }

  public function getemail(){
      return $this->email;
  } 
   
  public function getusergroup(){
      return $this->usergroup;
  }

  public function getprofile(){
      $this->profile = new UserProfile($this->uid);
  }
}

class UserProfile(){
   protected $avatar;
   protected $bio;
   protected $gender;
   protected $favcolor;
   

  public function __construct($id){
      // constructor code inside
  }

  public function formatavatar(){
      // avatar formatting code inside
  }

  public function formatusername(){
      // format username?
  } 
}
?>

As you can see, the User class(an outer class) has a property called Profile, which can be instantiated as a UserProfile object(an inner class). The two objects have distinct functionalities, but there are times when the UserProfile object needs to access property and methods from the user object. I know its easy for outer class to access methods from inner class by using the single arrow access operator twice, but how about the other way around?

Lets say from the above example the userprofile can format the username displayed to the screen by adding a sun to the left of the username if the usergroup is admin, a moon if the usergroup is mod, and nothing if its just a member. The usergroup property is stored in the outer class, and can be accessed with this $user->getusergroup() method only. I know I can always do the hard way by passing a user object to the method's argument, but is there an easier way for the inner class UserProfile to access properties/methods for outerclass User? If so, how can I achieve that?

Hi:

I have a login file where a user goes to a db based on the dbtype selected.
Now
$dbtype1 links to a db on Server 1 ( that is the server on which this script is running and
$dbtype2 links to a db on Server 2

I created a connection-link file connectlink.php as under but  while $dbtype1 works without a problem  , $dbtype2 gives me an error 'no access to db' and user dbun1@localhost not found on db1.db .

What am I missing in the connectlink.php file please ? Thanks

login.php
===========

<?
......
if($_POST['submit']){
$dbtype = $_POST['dbtype'];

if ($dbtype == 'type1') 
   { $section = 'type1';    
     require("../x/type1/type1.php");
     } 

if ($dbtype == 'type2') 
   { $section = 'type2';    
     require("../x/type2/connectlink.php"); //the dir 'x' is a common name on both the servers''
     } 
    
//then it processes $userfile and give this 


Click <a href="'.$section.'/'.$userFile.'?Userid='.$userid.'"> here 

?>

connectlink.php
==============

<?
//this file contains db info, log and checks if user is authorised to access the db - ist check.

error_reporting(E_ERROR | E_PARSE | E_CORE_ERROR);

 $dbusername2='a';
 $dbpassword2='b';
 $dbname2='c';
 $servername = 'ip address of server or localhost ?';
 $link2=mysql_connect ("$servername","$dbusername2","$dbpassword2", true);
 if(!$link2){  die("Could not connect to MySQL");}
 mysql_select_db("$dbname2",$link2) or die ("could not open db".mysql_error());
 

 $dbusername1='d';
 $dbpassword1='e';
 $dbname1='f';
 $servername = 'localhost';
 $link1=mysql_connect ("$servername","$dbusername1","$dbpassword1", true);
 if(!$link1){  die("Could not connect to MySQL");}
 mysql_select_db("$dbname1",$link1) or die ("could not open db".mysql_error());

 
$sql = "SELECT * FROM Users WHERE Userid='$userid'",$link2;

$result = mysql_query($sql);
if  ($myrow = mysql_fetch_array($result)){
$login_success = 'Yes'; 
$status = "On";
....
        
               $sql2= "insert into Log (....) values(.....)",$link2;;
$result2 = mysql_query($sql2) or die  ('no access to database: ' . mysql_error());
//        echo mysql_error();      }
}

else 
{
  $failureMessage = '<p class="data"><center><font face="Verdana" size="2" color="red">Login Failure.  You are not authorised to access this database .<br /></font></center></p>';
    print $failureMessage;
$logoutMessage = 'Click <a href="../NEWDBS/mainlogout.php"> here </a>to logout </p>';

print $logoutMessage;


     exit;
  
}


?>

I got two lists on a website. One list includes bunch of items and simple info. Another list includes pictures of those items and detailed information. I would like to set it up that way when users clicks on item from list #1 it would automatically jump to an item with the picture and detailed info on a second list.

This topic has been moved to Miscellaneous.

http://www.phpfreaks.com/forums/index.php?topic=326928.0

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=321572.0

<?php 

$con = database_connect();
$sql = "SELECT *
FROM anime1, episode1
WHERE animeid='$animeid'";
$result = mysql_query($sql);
while ($row = mysql_fetch_assoc($result)) {
$title = $row['title'];
$ep = $row['ep'];
}


 ?>

keep giving me back error

Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\wamp\www\studying\take 2\addin12.php on line 45

is there a way in php to link from the root dir ?

like in html you just use the '/' at the start for the link " <a herf="/link.php" ></a> "

but i noticed this does not work when using php like include or require.

so is there anywey to tell a link to start from root dir? without using the ../../link.php