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PHP - Does This Number Exist..
Basically this gets a number from a table on my DB, and displays the content relevent to that number...the second part checks for that number and gets other information according to that number...
what i want to do is make sure that the number from the first query exists in the table from the query, and if it doesn't print out and error saying "there is no information" or whatever.. anyone have an idea? hopefully this makes sense Code: [Select] <?php require_once('Connections/myConnect.php'); $detnum = $_GET['Details']; $detinfo = mysql_query("SELECT* FROM `Agency Stores - Table 1` WHERE F11=".$detnum); $det = mysql_fetch_array($detinfo); $salesnum = $det['F3']; $salesinfo = mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum); $sales = mysql_fetch_array($salesinfo); if(mysql_query("SELECT* FROM `By Agency Store _` WHERE store_store=".$salesnum)){ } ?> Similar Tutorialsi have error where my code should update existing data where id exist, it get updated ..but the others data is disappeared .only the data updated is remained $sql1 ="select*from semakan_dokumen where email='$stdEmail'";
$sqlsearch1 = mysqli_query($dbconfig,$sql1);
$resultcount1 = mysqli_num_rows($sqlsearch1);
if($resultcount1 > 0){
$query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3',sijil_sekolah= '$fileName4', sijil_dip= '$fileName5',sej_julai='$fileName6',bm_julai='$fileName7',muet='$fileName8', mid1='$fileName9',yuran= '$fileName10',umpa_bend1= '$fileName11',umpa_bend2='$fileName12',bpkp='$fileName13', penaja='$fileName14',kesihatan= '$fileName15', jhepa='$fileName16' where email= '$stdEmail' ");
}else{
//filezip
$query1 = "INSERT INTO semakan_dokumen (email,surat_tawaran,ic,sijil_lahir,sijil_spm,sijil_sekolah,sijil_dip,sej_julai,bm_julai,muet,mid1,yuran,umpa_bend1,umpa_bend2,bpkp,penaja,kesihatan,jhepa) VALUES ('$stdEmail','$fileName','$fileName1','$fileName2','$fileName3','$fileName4','$fileName5','$fileName6','$fileName7','$fileName8','$fileName9','$fileName10','$fileName11','$fileName12','$fileName13','$fileName14','$fileName15','$fileName16')";
}
I'm getting the dreaded " Invalid parameter number: number of bound variables does not match number of tokens" error and I've looked at this for days. Here is what my table looks like:
| id | int(4) | NO | PRI | NULL | auto_increment | | user_id | int(4) | NO | | NULL | | | recipient | varchar(30) | NO | | NULL | | | subject | varchar(25) | YES | | NULL | | | cc_email | varchar(30) | YES | | NULL | | | reply | varchar(20) | YES | | NULL | | | location | varchar(50) | YES | | NULL | | | stationery | varchar(40) | YES | | NULL | | | ink_color | varchar(12) | YES | | NULL | | | fontchosen | varchar(30) | YES | | NULL | | | message | varchar(500) | NO | | NULL | | | attachment | varchar(40) | YES | | NULL | | | messageDate | datetime | YES | | NULL |Here are my params:
$params = array(
':user_id' => $userid,
':recipient' => $this->message_vars['recipient'],
':subject' => $this->message_vars['subject'],
':cc_email' => $this->message_vars['cc_email'],
':reply' => $this->message_vars['reply'],
':location' => $this->message_vars['location'],
':stationery' => $this->message_vars['stationery'],
':ink_color' => $this->message_vars['ink_color'],
':fontchosen' => $this->message_vars['fontchosen'],
':message' => $messageInput,
':attachment' => $this->message_vars['attachment'],
':messageDate' => $date );
Here is my sql:
$sql = "INSERT INTO messages (user_id,recipient, subject, cc_email, reply, location,stationery, ink_color, fontchosen, message,attachment) VALUES( $userid, :recipient, :subject, :cc_email, :reply, :location, :stationery, :ink_color, :fontchosen, $messageInput, :attachment, $date);";
And lastly, here is how I am calling it:
$dbh = parent::$dbh;
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_WARNING);
if (empty($dbh)) return false;
$stmt = $dbh->prepare($sql);
$stmt->execute($params) or die(print_r($stmt->errorInfo(), true));
if (!$stmt) { print_r($dbh->errorInfo()); }
I know my userid is valid and and the date is set above (I've echo'd these out to make sure). Since the id is auto_increment, I do not put that in my sql (though I've tried that too), nor in my params (tried that too). What am I missing? I feel certain it is something small, but I have spent days checking commas, semi-colons and spelling. Can anyone see what I'm doing wrong?
Hello,
I have problem durring binding update query. I can't find what is causing problem.
public function Update(Entry $e)
{
try
{
$query = "update entry set string = $e->string,delimiter=$e->delimiter where entryid= $e->id";
$stmt = $this->db->mysqli->prepare($query);
$stmt->bind_param('ssi',$e->string,$e->delimiter,$e->id);
$stmt->close();
}
catch(Exception $ex)
{
print 'Error: ' .$ex->getMessage();
}
}
When I run function update I'm getting next error:Warning: mysqli_stmt::bind_param(): Number of variables doesn't match number of parameters in prepared statement
Can you help me to solve this problem ?
Edited by danchi, 17 October 2014 - 10:25 AM. I need to display a number(the number is retrieved from the db) in the form input field such that only the last 4 digits is visbile, the remaining can be masked as * or X or whatever is applicable. I know the last 4 can be obtained as follows: Code: [Select] $number=substr($number,-4,4); But when i hit the submit button the form validates the input field and checks if the number is a valid number of a specific format. Therefore when I click on the submit button then I should still be able to unmask the masked numbers or do something similar that would help me validate the whole number. Code: [Select] <input type="text" name="no" value="<?php if(!empty($number)){ echo $number;} ?>"> if so how would they be used in a mysql query? hi, im having trouble adding a get variable to a url if one already exists. eg current url = http://www.example.com/index.php?var1=something i want to be able to change this to new url = http://www.example.com/index.php?var1=something&var2=another even so i can have a few get variable there. I can add the first var through a form or link, but how would i add more through a link or through the header function? I am positivly stuck. Thanks Hi.. So what i want to do is basicly to check if id XX exist in my database. How can this be done? Im thinking of something like: if(xx exist){do this} else{do this} Iv'e tried google etc before i posted here, but couldent really find anything where i found a soutable answer.. Hope someone can help! (: Hi all, I want to make a script that identifies if an image JPG file exists. Would somthing like this work? <?php $file = "images/image.jpg"; if ($file > 0) { echo "file exists"; } else { echo "no file"; } ?> hello, i am having an issue with tables using incorrect data. i have 2 columns, first is employee name, second is location if the employee doesnt have a location for the current day, it is telling me he is at the same location as the guy in the row above him. i need this to be blank. is this possible? hi, i have a select which gets todays schedule for each user. sometimes that user doesnt have anything for todays date and it will display the info from the user above him. how can i make it so it stays blank if there is no record? Does the concept of a "Namespace" exist in PHP? If so, how do you use them? This is a snippet from ASP.NET that made me ask this question... Quote <%@ Import Namespace="System.Data" %> <%@ Import Namespace="System.Data.SqlClient" %> TomTees Hi all - I have a form that let's a user upload an image to their specified folder. The folder is determined by the "password" the user inputs. The "password" is really just the folder name on my server, so if "michael83" was entered as a password, the directory would be "images/uploaded/michael83". That works great now, thanks to a forum user, litebearer. Thanks again. Here's my second question: I'm working on a "history" page so that a user can input their "password" and view their upload history. The form works right now. If you enter a "password" (folder name) that exists, the code will spit out the contents / files. So, now I'm looking for two things: (1) if a user enters a "password" (folder name) that exists, but there are no files in the folder, "There are no files in the $dir directory." will be echoed; and (2) if a "password" (folder name) is entered that does NOT exist, "The directory $dir does not exist." will be echoed. Here's my code so far (minus the if statements I'm looking for): $dir = $_POST['password']; $path = "images/uploaded/". $dir; $dir_handle = @opendir($path); while ($file = readdir($dir_handle)) { if($file == "." || $file == ".." ) continue; if(isset($_POST['Submit'])) $url = "http://www.mysite.com/". $path . "/" . $file; { echo "<a href=\"$url\">$url</a><br />"; }} closedir($dir_handle); As always, many thanks in advance for any help on this. Gud pm!! So i made this script to check if a username and password exist but it kinda fails me. It gives me a database connection error from my confirm_query() which means it returned false? so here's my code: Code: [Select] function check_if_exist($username, $password) { global $connection; $query = "SELECT username, hashed_password"; $query .= "FROM users "; $query .= "WHERE username = '$username' "; $query .= "AND hashed_password = '$password' "; $query .= " LIMIT 1"; $result_set = mysql_query($query, $connection); confirm_query($result_set); if(mysql_num_rows($result_set) == 1) { return true; } else { return false; } } my confirm_query(): Code: [Select] function confirm_query($result) { if(!$result) { die("Database connection failure ". mysql_error()); } } I have a another script to check if the email exist and it works perfectly, i dunno why this won't work properly.. maybe another simple mistake.. Any ideas or Violent reaction? Thanks! This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=357281.0 hi, im getting the error Quote Fatal error: Call to undefined function notification() in C:\xampp\htdocs\xampp\index.php on line 21 after including the functions.php file i wrote. It does include it but the data isnt being recognised from it. If i copy/paste the notification() function into index.php it works. Can someone tell me why so i can fix it? I'm writing a dropdown menu of countries states/regions, that pulls from an xml file... but some countries don't have a specific state/region (IE Antarctica). If they don't, then the XML file isn't formatted in the same way There is more to this, but the relevant part is he echo "<select name=\"statename\">\n"; echo "<option value=\"\">Select a state</option>\n"; $statexml = simplexml_load_file($state); foreach ($statexml->geoname as $statelink) { if($statelink) { echo "<option value='{$statelink->name}'>{$statelink->name}</option>\n"; } else { echo "<option value='none'>none</option>\n"; } } echo "</select>"; A state xml with results looks like this: Code: [Select] <?xml version="1.0" encoding="UTF-8" standalone="no"?> <geonames style="MEDIUM"> <totalResultsCount>51</totalResultsCount> <geoname> <name>Alabama</name> ...etc, etc </geoname> <geoname> <name>Alaska</name> ...etc, etc </geoname> </geonames> And an xml with no results looks like this: Code: [Select] <?xml version="1.0" encoding="UTF-8" standalone="no"?> <geonames> <status message="no children for Antarctica 6697173" value="15"/> </geonames> Saying the if($statelink) isn't working, as any country without a state simply doesn't display the 'none' selection. Code: [Select] <select name="statename"> <option value="">Select a state</option> </select> Any help?? Hello, i want to check whether image exist or not, but i can't get any data about it. I have tried everything: getimagesize, file_exist, filesize, etc. <? $info = @getimagesize('http://jargames.eu/ic.php?lf=files/All phone/240x320/007-quantum_of_solace_240x320.jar'); if(isset($info['mime'])){echo 'Image exist';} else{echo 'Image doesnt exist';} ?> Ty, for your help. Here is my code so far (I say it's PDO but it pretty much isn't. What is the object here? The database connection? LOL!);
$sql =
"
SELECT
SUM(IF(`sent` != 'N' , 1 , 0 )) as 'Emails Sent',
SUM(IF(`completed` NOT IN('N','paper') , 1 , 0 )) as 'Completed Electronically',
SUM(IF(`completed` = 'paper' , 1 , 0 )) as 'Completed Manually',
SUM(IF(`completed` != 'N' , 1 , 0 )) as 'Total Number Completed',
SUM(IF(`remindercount` = '1' , 1 , 0 )) as 'Reminder Sent Once',
SUM(IF(`remindercount` = '2' , 1 , 0 )) as 'Reminder Sent Twice',
SUM(IF(`remindercount` = '3' , 1 , 0 )) as 'Reminder Sent Thrice'
FROM `tokens_$survey_id`
";
$statement = $dbh->prepare($sql);
$statement->execute();
$result = $statement->fetch(PDO::FETCH_OBJ);
foreach($result as $key => $value) {
echo "<tr>
<td>$key</td>
<td>$value</td>
</tr>";
}
This is all well and good if the tokens_$survey_id table is actually there. Sometimes, for a genuine reason, there won't be a tokens table for that particular survey. How do I account for this? At the moment I get an error..Warning: Invalid argument supplied for foreach() in /var/www/html/index.php on line 149I tried this but I am not satisfied this is correct;
if(!$result) {
die();
}
I don't want the code to die! If I take out the die() statement then this if is ignored for some reason I don't understand.
I need to insert data into a table if it doesn't exist or update if it does. Can someone give me an example of this code. im using mySQL 5.1.42 im using phpMyAdmin 3.1.o Is it possible to check if multiple rows exist at the same time. For example, if a row with the id "1" and another row with id "2" exists, and return something like true then false if only the first exists?
I have a file that provides tens of thousands to check and it takes forever. I know this sounds bad off the start, but it's not something that is run normally. Only to update my database with new additions.
Is there any good way to check a lot at once? I know you can insert many at a time and save a lot of time.
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