|
PHP - Form I Page I Modified Now Won't Post When Clicking "submit", Need Help
Hello.
I hope one of the PHP/HTML gurus here can help me. I have a web page that has been altered a bit to add some Google Analytics stuff and I've moved it to a 2nd directory. The original one works fine, the 2nd one won't post the form when I click the submit button. 1st URL https://www.theneutralizer.info/neutralizer 2nd URL: https://www.theneutralizer.info/neutralizer2 I have changed the action property to the correct script, and it does exist. But the problem is when clicking the button nothing happens. Anyone have any ideas? I can send the PHP code if needed, but since it's HTML output, it should work the way it is displayed in the browser. David Similar TutorialsCan someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Login.php Code: [Select] <?php session_start(); mysql_connect("localhost","root") or die(mysql_error()); mysql_select_db("cute") or die(mysql_error()); $username = $_POST['username']; $password = $_POST['pass']; if (isset($_POST["submit"])) { $log = "SELECT * FROM regis WHERE username = '$username'"; $login = mysql_query($log); $row = mysql_fetch_array($login); $number = mysql_num_rows($login); if ($number == 0) { print "That user does not exist in our database. <a href=registration.php><input type='button' value='Register'></a>"; } if ($number > 0) { if ($password == $row['password']) { $_SESSION['username'] = $row['username']; $_SESSION['userlevel'] = $row['userlevel']; $_SESSION['is_logged_in'] == 1; if($_SESSION['userlevel']==1) { $_SESSION['is_logged_in'] == 1; echo "<meta http-equiv='refresh' content='0; url=form2.php'>" ; } else if($_SESSION['userlevel']==0) { echo "<meta http-equiv='refresh' content='0; url=registration.php'>"; } } } } else { ?> <html> <head> <script type="text/javascript"> function a() { var x = document.login.username.value; var y = document.login.pass.value; if(x==""&& y=="") { alert("Please insert all message!"); return false; } if(x=="") { alert("Please insert an username!"); return false; } if(y=="") { alert("Please insert an password!"); return false; } } </script> </head> <body> <table border="0"> <form name="login" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" onsubmit="return a()"> <tr><td colspan=2><h1>Login</h1></td></tr> <tr><td>Username:</td> <td><input type="text" name="username" maxlength="40"></td></tr> <tr><td>Password:</td> <td><input type="password" name="pass" maxlength="50"></td></tr> <tr><td><input type="submit" name="submit" value="Register"></a></td> <td><input type="submit" name="submit" value="Login"></td></tr> </form> </body> <?php } ?> </html> after im redo my code and after im login there nothign happen but only blank page im wondering why I'm a very new PHP user (as in, I just started today) and need to make a set of navigation buttons which will take the user to "next" or "previous" pages. I assume that the $_GET function is involved, but I don't know how to do it. It needs to work like this: If the URL looks like "http://website.com/page1.php" I need the "next" button (a href image) to change it to "/page2.php", and while on page 2, for the "previous" button to take the user to "/page1.php" and so forth. How can I cause the page number to increment or decrease respective to the href image being clicked? Hi there, I am currently running into an issue with my Last-Modified header. I have a news artcle script which stores the publication date as Y-m-d, so I tried to send the following header via PHP: Code: [Select] header("Last-Modified: ".$articledate." 1:00:00 GMT"); However, when I test the headers with a header tool, it always shows: Thu, 01 Jan 1970 00:00:00 GMT instead of what I want it to show. I wonder what I would have to do to show the Last-Modified header correctly, as this is important to me as I need to index all my pages using the correct data. Please note that I cannot use the file date, as the pages are dynamic, so there is no real file to get the date from. Your help would be greatly appreciated. Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! I have the code below to output a list: Code: [Select] while ($row = mysql_fetch_array($rs_teambydate)) { echo "<tr><td width='200'>".$row['team_name']." (".$row['members_count'].")</td><td><input type='submit' name='".$row['team_name']."' value='Plunder'/></td>"; } This is all inside a form so I can use the following to get various includes: Code: [Select] <? if(isset($_POST['".$row['team_name']."'])){ include ('resources.php');} ?> My problem is this part : $_POST['".$row['team_name']."'], as this obviously doesn't work. Anyone know how I can add the "$row['team_name']" inside $_POST[' '] ? Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks I am having problems being able to find the data that needs to be posted in various translation websites. I think this is because the translation tools they have are using some kind of flash script to translate? So the new page isn't being loaded using the post data string?? I am not completely sure, anyways... I am using live http headers on firefox to try and get the content for the post data string. The sites I have tried to get the post data from are these: http://www.freetranslation.com/ http://www.free-translator.com/ I can get cURL to visit the page and do everything, I just cant find the post data string. or maybe I am way off here.. Thanks for any help cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; Hi. I have just one question (I have searched for an answer for this but have not been able to locate one): How do you go about changing the text on a "Submit Query" button to display simply "Submit"? Below is the current code for the page that displays said button. Thank-you in advance for any help or direction. <?php include 'connection.php'; $query = "SELECT * FROM people"; $result = mysql_query($query) or die(mysql_error()); while ($person = mysql_fetch_array($result)){ echo $person ['name']; echo $person ['descrip']; } ?> <H1>Add Your Review:</H1> <form action="create.php" method="post"> Subject <input type="text" name="inputName" value=""/> </br > Review <textarea cols="50" rows="4" name="inputDesc" value=""/></textarea> </br > <input type= "submit" name= "submit"/> </form> <html> <head></head> <body> <p>The current second is <span style='font-size:16px;font-weight:bold;color:red;position:absolute;right:25px;'><?php echo time(); ?></span> on this computer.</p> </body> </html> I have a table with a list of users and an edit button and delete button. When the edit button is pressed on a site it passes the user_id as p_id to the page that catches it and displays the data. The problem is when I click on the "update user" button, I get the following error:
Warning: Undefined variable $the_user_id in C:\xampp\htdocs\3-19-21(2) - SafetySite\admin\edit_user.php on line 10 The weird thing is I had another update user page with a table I created that ran the query to update the table in the database just fine. But as I created it, it didn't look all that great so I recreated the page and used a bootstrap table because of the much cleaner look. Both pages have the exact same PHP code, the only difference is the bootstrap table I added in. So I'm really at a loss with this. Other than the table and PHP code, there is a script at the bottom of the page for the table itself to allow for searching within the table, i'll include that as well. The PHP code is as follows:
<?php //THE "p_id" IS BROUGHT OVER FROM THE EDIT BUTTON ON VIEW_ALL_USERS if (isset($_GET['p_id'])) { $the_user_id = $_GET['p_id']; } // QUERY TO PULL THE SITE INFORMATION FROM THE p_id THAT WAS PULLED OVER $query = "SELECT * FROM users WHERE user_id = $the_user_id "; $select_user = mysqli_query($connection,$query); //SET VALUES FROM ARRAY TO VARIABLES while($row = mysqli_fetch_assoc($select_user)) { $user_id = $row['user_id']; $user_firstname = $row['user_firstname']; $user_lastname = $row['user_lastname']; $username = $row['username']; $user_email = $row['user_email']; $user_phone = $row['user_phone']; //$user_image = $row['user_image']; $user_title_id = $row['user_title_id']; $user_role_id = $row['user_role_id']; } THE UPDATE QUERY CODE....................................................................................................................
<?php if(isset($_POST['update_user'])) { $user_id = $_POST['user_id']; $user_firstname = $_POST['user_firstname']; $user_lastname = $_POST['user_lastname']; $username = $_POST['username']; $user_email = $_POST['user_email']; $user_phone = $_POST['user_phone']; //$user_image = $_POST['user_image']; $user_title_id = $_POST['user_title_id']; $user_role_id = $_POST['user_role_id'];
$query = "UPDATE users SET "; $query .= "user_id = '{$user_id}', "; $query .= "user_firstname = '{$user_firstname}', "; $query .= "user_lastname = '{$user_lastname}', "; $query .= "username = '{$username}', "; $query .= "user_email = '{$user_email}', "; $query .= "user_phone = '{$user_phone}', "; //$query .= "user_image = '{$user_image}', "; $query .= "user_title_id = '{$user_title_id}', "; $query .= "user_role_id = '{$user_role_id}' "; $query .= "WHERE user_id = '{$the_user_id}' "; $update_user = mysqli_query($connection,$query); if(! $update_user) { die("QUERY FAILED" . mysqli_error($connection)); } } ?> THE "UPDATE USER" BUTTON THE USER CLICKS ON TO UPDATE....................................................................................................................
<div class="col-1"> <button class="btn btn-primary" type="submit" name="update_user">Update User</button> </div>
Any Help is Greatly Appreciated! Edited March 23 by ZsereneI am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
I understand PRG ("post redirect get") as follows:
"index.php" welcomes visitor.
if(isset($_POST["finished"])) {
// insert all data into mySQL for upcoming INVOICE;
header("location:thank-you.php",true,303);
exit;
}
The "thank-you.php" page retrieves and displayes the mySQL data as an invoice.
QUESTIONS: Thank you, as always, I appreciate the help and the "pushes in the right direction."
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 Have got a form for the user to fill in. When they press submit the page SHOULD be sent to itself and update the database. When I load the page I keep getting undefined variable "submit" and also when i press button and bottom I get 404 message. <?php include "variables.php"; ?> <?php $date = date("M d, Y"); if ($submit) { // process form $db = mysql_connect($databaseserver, $databaseuser, $databasepass); mysql_select_db($databasename,$db); $sql = "UPDATE $playerstable SET staff = '$staff' WHERE name='$name'"; $result = mysql_query($sql); echo "Thank you! Information entered.<br><a href='$directory/Admin/index.php'>Return to admin panel</a>"; } else{ // display form ?> <form method="post" action="<?php echo $PHP_SELF?>"> <center> <table border="0" cellpadding="0" width="100%"> <tr> <td width="12%"> Name:</td> <td width="88%"><select size="1" name="name"> <?php $db = mysql_connect($databaseserver, $databaseuser, $databasepass); mysql_select_db($databasename,$db); $sortby = "name ASC"; $sql="SELECT * FROM $playerstable ORDER BY $sortby"; $result=mysql_query($sql,$db); $num = mysql_num_rows($result); $cur = 1; echo "<ol>"; while ($num >= $cur) { $row = mysql_fetch_array($result); $name = $row["name"]; ?> <option><?php echo "$name" ?></option> <?php $cur++; } echo "</ol>"; ?> </select></td> </tr> <tr> <td width="12%"> Staff:</td> <td width="88%"><select size="1" name="staff"> <option>Yes</option> <option>No</option> </select></td> </tr> </table> </center> <p> <input type="Submit" name="submit" value="Enter information"> </form> <?php } ?> I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? This topic has been moved to PHP Installation & Configuration. http://www.phpfreaks.com/forums/index.php?topic=347922.0 This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=326600.0 |
|||||||