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PHP - Php Image Carousel Links
I have an image carousel where the hyperlink worked just fine in all browsers that I tested UNTIL recently, now it works on IE and Opera; it no longer seems to work on Firefox, Safari and Chrome. Can someone give me an idea as to why that would happen? Here's the webpage: http://www.myalaskacenter.com and here's the coding used: Code: [Select]
<?php echo '<div id="slider"><ul id="sliderContent">'; while ($Row = mysqli_fetch_assoc($Result)){ $EventName = $Row['EventTitle']; $url = $Row['ShoWareEventLink']; $image = $Row['eImage']; $description = $Row['BriefDescription']; $promoter = $Row['Presenter']; $starting = $Row['startDATE']; $ending = $Row['endDATE']; echo '<li class="sliderImage"><a href="' . $url . '"><img src="https://alaskapac.centertix.net/UPLImage/' . $image . '" alt="' . $EventName. '" title="' . $EventName . '" height="400" width="900" border="0" /></a><span class="right"><strong>' . $EventName . '</strong><br /><em><br />Presented by ' . $promoter . '</em><br />' . date("l, F j, Y", strtotime($starting)); if ($starting != $ending){ /**IF STARTING=ENDING =>NO ENDING SHOWN **/ echo '<br />to ' . date("l, F j, Y", strtotime($ending)); } echo '<br /><br />' . $description . '<br /><br /><a href="' . $url . '"><img src="https://alaskapac.centertix.net/UPLImage/z_BUY_Tickets_gold.gif" height="40" width="100" border="0" align="right" alt="' . $EventName . '" title="' . $EventName . '" /></a></span></li>'; } echo '<div class="clear sliderImage"></div></ul></div>'; ?>When I click to view the source in the non-working browsers, I cannot find an issue all the HTML looks like it should work. In fact there are two other "image carousels" on that page that do indeed work in these non-working browsers. Similar TutorialsWith my custom CMS I'm developing I have a menu structures type module where the admin can create a menu structures for their website. Inside the db is the links table and I'm trying to figure out what I can do if the link has an actual image. I created a field called link_image however I just thought of what if the link is apart of a sprite which would have most of the time 3 parts of the image (active, hover, normal) or whatever or has its own sprite. How should I handle this if I want to store this information in the database. Hello,
I have problem with JS slider. Here is demo website http://goo.gl/bPzpAo I can't make the slider to have similar size items (seems cutted). I can't get, what's wrong there? Someone could help me with this?? I tried to resize images, also li elements modifications, but no solution. If someone could help me, will be much appreciated!
Regards,
Zox
Hi all This is my first post but I hope someone can help. I am building a website using a theme that uses a template builder that includes a client scrolling carousel. When using it once it works fine... I need to use it 3 times. The second and third instance doesn't scroll and appears huge on the page. I am a novice at php but after a bit of research I believe its something to do with how the builder calls for the carousel and the ID. I am not sure how to amend the php to make each instance of the carousel have a different ID and consequently js and css div classes are called correctly. I hope this make sense and any help would be much appreciated Craig Hi there I've been working with some code to display a single record on page. This all works fine and I'm able to pull what I want from the database. My problems is trying to use that data and turning it into something else like a link. I have a field in the database called image url which contains rows of image urls. So here is the problem area of the code: Code: [Select] <?php //////Displaying Data///////////// $id=$_GET['id']; // Collecting data from query string if(!is_numeric($id)){ // Checking data it is a number or not echo "Data Error"; exit; } $fetch=mysql_query("select * from productfeeds where ProductID=$id "); $row=mysql_fetch_object($fetch); echo mysql_error(); echo "<table>"; echo " <tr><td><b>ProductID</b></td><td>$row->ProductID</td></tr> <tr><td><b>ProductName</b></td><td>$row->ProductName</td></tr> <tr><td><b>ProductPrice</b></td><td>$row->ProductPrice</td></tr> //problem area for me <tr><td><b>Image</b></td><td>$row->ImageURL</td></tr> echo "</table>"; I'm trying to edit this part of the code: <tr><td><b>Image</b></td><td>$row->ImageURL</td></tr> I've tried this: <tr><td><b>Image</b></td><td><a href='{$row['URL']}'> <img src='{$row['ImageURL']}'></a> and <tr><td><b>Image</b></td><td><a href='$row['URL']'> <img src='$row['ImageURL']'></a> //removed brackets but I'm just getting errors. Can you guys help please? Thank you very much. Hello,
I'm creating a website that takes flickr photos from areas that you click on the map and loads them into a jquery carousel called Slick Carousel. Everything works fine except for I have this strange issue where the autoplay only begins if you click to another window or you manually move the thumbnails to the left or right. Then it works fine. Can anyone look at the code and see if they can see what I'm doing wrong?
<!DOCTYPE html>
<html>
<head>
<!-- google maps api key -->
<script src="http://maps.google.com/maps/api/js?key=AIzaSyAM4sSbWxrbwyXvGHvbH6piG5AlqLjtAMc&sensor=true" type="text/javascript"></script>
<!-- jquery -->
<script src="js/jquery.1.11.1.min.js"></script>
<script src="js/jquery.ui.map.full.min.js"></script>
<!-- scripts for lightbox -->
<script src="js/lightbox.min.js"></script>
<!-- script for actual display of images -->
<!-- fonts -->
<link href='http://fonts.googleapis.com/css?family=Pacifico|Open+Sans' rel='stylesheet' type='text/css'>
<link rel="stylesheet" type="text/css" href="http://cdn.jsdelivr.net/jquery.slick/1.3.15/slick.css"/>
<link href="//maxcdn.bootstrapcdn.com/font-awesome/4.2.0/css/font-awesome.min.css" rel="stylesheet">
<link href="css/lightbox.css" rel="stylesheet" />
<link href="css/styles.css" rel="stylesheet" type="text/css">
</head>
<body>
<header>
<h1>Time Capsule <i class="fa fa-space-shuttle"></i> </h1>
<div id="drop_instructions">
<p>Ever wonder what a certain area looked like from the world's point of view? Now you can find out! Click on an area in the map and we'll show you that spot as the locals see it.</p>
</div>
</header>
<section class="clearfix">
<div id="map_canvas"></div>
<div id="imagebox" class="slider-for">
</div>
</section>
<div class="slider-nav">
</div>
<script type="text/javascript" src="http://cdn.jsdelivr.net/jquery.slick/1.3.15/slick.min.js"></script>
<script src="js/map.js"></script>
</body>
</html>
$(document).ready(function() {
$('#drop_instructions').hide();
$('#header').click(function(){
$('#drop_instructions').fadeToggle( "fast", "linear" );
});
//define lat and long globally so they can be used elsewhere
var lat=0;
var lng=0;
var city='';
var state='';
var StartLatLng = new google.maps.LatLng(28.4158, -81.2989);
$('#map_canvas').gmap({
'center': StartLatLng,
zoom: 10,
styles: [{"featureType":"landscape","stylers":[{"saturation":-100},{"lightness":65},{"visibility":"on"}]},{"featureType":"poi","stylers":[{"saturation":-100},{"lightness":51},{"visibility":"simplified"}]},{"featureType":"road.highway","stylers":[{"saturation":-100},{"visibility":"simplified"}]},{"featureType":"road.arterial","stylers":[{"saturation":-100},{"lightness":30},{"visibility":"on"}]},{"featureType":"road.local","stylers":[{"saturation":-100},{"lightness":40},{"visibility":"on"}]},{"featureType":"transit","stylers":[{"saturation":-100},{"visibility":"simplified"}]},{"featureType":"administrative.province","stylers":[{"visibility":"off"}]},{"featureType":"water","elementType":"labels","stylers":[{"visibility":"on"},{"lightness":-25},{"saturation":-100}]},{"featureType":"water","elementType":"geometry","stylers":[{"hue":"#ffff00"},{"lightness":-25},{"saturation":-97}]}]
})
.bind('init', function(event, map) {
$(map).click( function(event) {
//define date
var year = $("#year").val();
var month = $("#month").val();
var day = $("#day").val();
//give current value to lat/long on click
lat=event.latLng.lat();
lng=event.latLng.lng();
var latlng= event.latLng;
//input box with coordinates
$('#latlng').val(lat+', '+lng);
geocoder = new google.maps.Geocoder();
geocoder.geocode({'latLng': latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
//Check result 0
var result = results[0];
//look for locality tag and administrative_area_level_1
for(var i=0, len=result.address_components.length; i<len; i++) {
var ac = result.address_components[i];
if(ac.types.indexOf("locality") >= 0) city = ac.long_name;
if(ac.types.indexOf("administrative_area_level_1") >= 0) state = ac.long_name;
}
//only report if we got Good Stuff
if(city != '' && state != '' && year != '') {
console.log("Hello to you are in "+city+", "+state+"! The date you chose is: " + month + " " + day + ", " + year);
} else {
console.log("YOU FORGOT TO PICK A YEAR!");
}
} //end of getting city
//==============Image generation=================
//get location from map click and inject data into URL
var locationURL = "https://api.flickr.com/services/rest/?method=flickr.photos.search&api_key=a0f6800f62ea920f00472805d767ac5c&lat="+lat+"&lon="+lng+"&format=json&nojsoncallback=1";
$.ajax({
url: locationURL,
dataType: "json",
success:function(data){
var farmId;
var serverId;
var photoId;
var secret;
var title;
//hide instructions once content is generated
$('#instructions').fadeOut(500);
//title the images for the city clicked on
$('#images_title').append('<h3>'+city+' , '+state+'</h3>');
console.log(data);
//generate thumbnails user can click on
for (i=0; i < 20; i++){
farmId = data.photos.photo[i].farm;
serverId = data.photos.photo[i].server;
photoId = data.photos.photo[i].id;
secret = data.photos.photo[i].secret;
title = data.photos.photo[i].title;
// make the urls for the DOM
photoURL = "https://farm"+farmId+".staticflickr.com/"+serverId+"/"+photoId+"_"+secret+"_z.jpg";
thumbURL = "https://farm"+farmId+".staticflickr.com/"+serverId+"/"+photoId+"_"+secret+"_s.jpg";
//append the clickable thumbnails to the dom
$('.slider-for').slickAdd('<div><img src="'+photoURL+'" alt="'+title+'" /></div>');
$('.slider-nav').slickAdd('<div><img src="'+thumbURL+'" class="image_thumb" alt="'+title+'" /></a></div>');
}
//change background of page to an image that is displayed
$("body").css("background-image", "url('"+photoURL+"')");
}
});
});
});
});
});
$('.slider-for').slick({
slidesToShow: 1,
slidesToScroll: 1,
arrows: true,
fade: true,
asNavFor: '.slider-nav'
});
$('.slider-nav').slick({
arrows: true,
slidesToShow: 3,
slidesToScroll: 1,
asNavFor: '.slider-for',
dots: true,
centerMode: true,
focusOnSelect: true,
autoplay: true,
autoplaySpeed: 2000
});
Hi, I am trying to make a simple thumbnail gallery where you upload an image, the image gets resized, a thumbnail is created in the "images/small/" directory, and the main images are in the "images/" directory. I need to somehow read from both directories, and do an image link with the thumbnail linking to the larger image. I think that means displaying from two directories, I don't know how to do that, please any help greatly appreciated. Thank you. here is my code so far Code: [Select] <?php error_reporting(0); $change=""; $abc=""; define ("MAX_SIZE","400"); function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } $errors=0; if($_SERVER["REQUEST_METHOD"] == "POST") { $image =$_FILES["file"]["name"]; $uploadedfile = $_FILES['file']['tmp_name']; if ($image) { $filename = stripslashes($_FILES['file']['name']); $extension = getExtension($filename); $extension = strtolower($extension); if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { $change='<div class="msgdiv">Unknown Image extension </div> '; $errors=1; } else { $size=filesize($_FILES['file']['tmp_name']); if ($size > MAX_SIZE*1024) { $change='<div class="msgdiv">You have exceeded the size limit!</div> '; $errors=1; } if($extension=="jpg" || $extension=="jpeg" ) { $uploadedfile = $_FILES['file']['tmp_name']; $src = imagecreatefromjpeg($uploadedfile); } else if($extension=="png") { $uploadedfile = $_FILES['file']['tmp_name']; $src = imagecreatefrompng($uploadedfile); } else { $src = imagecreatefromgif($uploadedfile); } echo $scr; list($width,$height)=getimagesize($uploadedfile); //**Original**// //$newwidth=60; //$newheight=($height/$width)*$newwidth; //**Modified to use height instead of width**// //$newheight=350; //$newwidth=($width/$height)*$newheight; // **IF NOT resizing full image then just pass variables.**// $newheight=$height; $newwidth=$width; //***adjust tmp***// $tmp=imagecreatetruecolor($newwidth,$newheight); //Thumbs $newheight1=180; $newwidth1=($width/$height)*$newheight1; //**Original**// //$newwidth1=25; //$newheight1=($height/$width)*$newwidth1; $tmp1=imagecreatetruecolor($newwidth1,$newheight1); imagecopyresampled($tmp,$src,0,0,0,0,$newwidth,$newheight,$width,$height); imagecopyresampled($tmp1,$src,0,0,0,0,$newwidth1,$newheight1,$width,$height); $filename = "images/". $_FILES['file']['name']; $filename1 = "images/small/". $_FILES['file']['name']; imagejpeg($tmp,$filename,100); imagejpeg($tmp1,$filename1,100); imagedestroy($src); imagedestroy($tmp); imagedestroy($tmp1); }} } //If no errors registred, print the success message if(isset($_POST['Submit']) && !$errors) { // mysql_query("update {$prefix}users set img='$big',img_small='$small' where user_id='$user'"); $change=' <div class="msgdiv">Image Uploaded Successfully!</div>'; } ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xml:lang="en" xmlns="http://www.w3.org/1999/xhtml" lang="en"><head> <meta content="text/html; charset=UTF-8" http-equiv="Content-Type"> <meta content="en-us" http-equiv="Content-Language"> <title>picture demo</title> <link href=".css" media="screen, projection" rel="stylesheet" type="text/css"> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript" src="js/jquery_002.js"></script> <script type="text/javascript" src="js/displaymsg.js"></script> <script type="text/javascript" src="js/ajaxdelete.js"></script> <style type="text/css"> .help { font-size:11px; color:#006600; } body { color: #000000; background-color:#999999 ; background:#999999 url(<?php echo $user_row['img_src']; ?>) fixed repeat top left; font-family:"Lucida Grande", "Lucida Sans Unicode", Verdana, Arial, Helvetica, sans-serif; } .msgdiv{ width:759px; padding-top:8px; padding-bottom:8px; background-color: #fff; font-weight:bold; font-size:18px;-moz-border-radius: 6px;-webkit-border-radius: 6px; } #container{width:763px;margin:0 auto;padding:3px 0;text-align:left;position:relative; -moz-border-radius: 6px;-webkit-border-radius: 6px; background-color:#FFFFFF } </style> </head><body> <div align="center" id="err"> <?php echo $change; ?> </div> <div id="space"></div> <div id="container" > <div id="con"> <table width="502" cellpadding="0" cellspacing="0" id="main"> <tbody> <tr> <td width="500" height="238" valign="top" id="main_right"> <div id="posts"> <img src="<?php echo $filename; ?>" /> <img src="<?php echo $filename1; ?>" /> <form method="post" action="" enctype="multipart/form-data" name="form1"> <table width="500" border="0" align="center" cellpadding="0" cellspacing="0"> <tr><Td style="height:25px"> </Td></tr> <tr> <td width="150"><div align="right" class="titles">Picture : </div></td> <td width="350" align="left"> <div align="left"> <input size="25" name="file" type="file" style="font-family:Verdana, Arial, Helvetica, sans-serif; font-size:10pt" class="box"/> </div></td> </tr> <tr><Td></Td> <Td valign="top" height="35px" class="help">Image maximum size <b>400 </b>kb</span></Td> </tr> <tr><Td></Td><Td valign="top" height="35px"><input type="submit" id="mybut" value=" Upload " name="Submit"/></Td></tr> <tr> <td width="200"> </td> <td width="200"><table width="200" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="200" align="center"><div align="left"></div></td> <td width="100"> </td> </tr> </table></td> </tr> </table> </form> </div> </td> </tr> </tbody> </table> </div> </div> </body></html> Hi all new to php and this forum i have been looking around and im very impressed most questions get answered not like on some of the forums around.
Is there any one kind enough to help me out i have an api call via php and would like to output the results to owlcarousel where do i start with this.
Code i have is:
<?php
error_reporting(E_ALL); // Turn on all errors, warnings and notices for easier debugging
// API request variables
$endpoint = 'http://svcs.ebay.com/services/search/FindingService/v1'; // URL to call
$version = '1.0.0'; // API version supported by your application
$appid = 'YourAppID'; // Replace with your own AppID
$globalid = 'EBAY-GB'; // Global ID of the eBay site you want to search (e.g., EBAY-DE)
$query = 'tools'; // You may want to supply your own query
$safequery = urlencode($query); // Make the query URL-friendly
// Construct the findItemsByKeywords HTTP GET call
$apicall = "$endpoint?";
$apicall .= "OPERATION-NAME=findItemsIneBayStores";
$apicall .= "&SERVICE-VERSION=$version";
$apicall .= "&SECURITY-APPNAME=$appid";
$apicall .= "&GLOBAL-ID=$globalid";
$apicall .= "&keywords=$safequery";
$apicall .= "&storeName=yourstorename";
$apicall .= "&paginationInput.entriesPerPage=6";
$apicall .= "&paginationInput.pageNumber=1";
// Load the call and capture the document returned by eBay API
$resp = simplexml_load_file($apicall);
// Check to see if the request was successful, else print an error
if ($resp->ack == "Success") {
$results = '';
// If the response was loaded, parse it and build links
foreach ($resp->searchResult->item as $item) {
$pic = $item->galleryURL;
$link = $item->viewItemURL;
$title = $item->title;
$price = $item->currentPrice;
// For each SearchResultItem node, build a link and append it to $results
$results .= "<div id='item'><div class='img-wrap' align='center'><img src=\"$pic\" class='itemimg'></div> <div class='itemtxt' align='center'><a href=\"$link\">$title</a>$price</div></div>";
}
}
// If the response does not indicate 'Success,' print an error
else {
$results = "<h3>Oops! The request was not successful. Make sure you are using a valid ";
$results .= "AppID for the Production environment.</h3>";
}
?>
<html>
<head>
<body>
<table>
<tr>
<td>
<div id="result">
<?php echo $results;?>
</div>
</td>
</tr>
</table>
</body>
</html>
Im sure is pretty basic but being new to this i have no idea where to start,
any advice would be much appreciated.
thanks
Edited by didz666, 25 January 2015 - 02:22 PM. Hi I am trying to build a site which has an image gallery with links on it. I want to list the the images in different ways and I have successfully made it work with a "shuffle"-script like this: Code: [Select] <?php $links[] = Array("../r/ahlens.html", "k/k.jpg"); $links[] = Array("../r/brothers.html", "k/k.jpg"); $links[] = Array("../r/hm.html", "k/k.jpg"); $links[] = Array("../r/kappahl.html", "k/k.jpg"); $links[] = Array("../r/mq.html", "k/k.jpg"); $links[] = Array("sida1.php", "k/l.jpg"); $links[] = Array("../r/kappahl.html", "k/k.jpg"); $links[] = Array("../r/mq.html", "k/k.jpg"); $links[] = Array("../r/nk.html", "k/k.jpg"); shuffle($links); foreach($links as $link){ echo "<a href=\"${link[0]}\" ><img src=\"${link[1]}\" class=\"randomImage\" /></a> "; } ?> It works fine and opens a new page when clicked. Now I would like to make it listed by file name instead of shuffling. How do I do that without loosing the links? And can it be done with a Directory because there will be a lot more photos in the future? (I would also like the link to pages to be opened in a nice popup. Can I implement that?) Thanks in advance! I have installed the Carousel code using tutorial at http://www.wolf-howl.com/blogs/how-to-carousel/ now i amfacing a problem that every thing is working expect images thumbnail. here is the site http://www.digpk.com/ where i am try to make carousel. you can see the featured posts at top with missing thumbnails. Thanks in advance. picture of the problem is also attached. I've been working on developing a CMS blog and now I'm trying to create a slideshow wit Bootstrap Carousel on the homepage to present the dynamic content (images + text) using the data from table 'posts'. I tested this code, and it only presents one post. I mean, It's not possible to go to the next slide. I want to show all the posts on the slides. *The DB connection is already on the includes. The connection was written on a small file called DB.php Home.php
<header>
<div id="carouselExampleIndicators" class="carousel slide" data-ride="carousel">
<ol class="carousel-indicators">
<li data-target="#carouselExampleIndicators" data-slide-to="0" class="active"></li>
<li data-target="#carouselExampleIndicators" data-slide-to="1"></li>
<li data-target="#carouselExampleIndicators" data-slide-to="2"></li>
</ol>
<div class="carousel-inner" role="listbox">
<?php
// The default SQL query
$sql = "SELECT * FROM posts ORDER BY id desc";
$stmt = $ConnectingDB->query($sql);
while ($DataRows = $stmt->fetch()) {
$Id = $DataRows["id"];
$PostTitle = $DataRows["title"];
$Image = $DataRows["image"];
$PostText = $DataRows["post"];
?>
<!-- Slide -->
<div class="carousel-item active" style="background-image: url('uploads/<?php echo $Image; ?>')">
<div class="carousel-caption">
<div class="card-body black">
<h3 class="large-mistral-white"><?php echo $PostTitle; ?></h3>
<p class="small-times-white"><?php echo $PostText; ?></p>
</div>
</div>
</div>
<?php } ?>
</div>
<a class="carousel-control-prev" href="#carouselExampleIndicators" role="button" data-slide="prev">
<span class="carousel-control-prev-icon" aria-hidden="true"></span>
<span class="sr-only">Previous</span>
</a>
<a class="carousel-control-next" href="#carouselExampleIndicators" role="button" data-slide="next">
<span class="carousel-control-next-icon" aria-hidden="true"></span>
<span class="sr-only">Next</span>
</a>
</div>
</header>
DB.php <?php $DSN='mysql:host = localhost; dbname=everybody_blog'; $ConnectingDB = new PDO($DSN,'root',''); ?>
i have 8 division (div), i want to display 4 rows in 4 division and the remain 4 rows in the next 4 division here is my code structure for carousel
<div class="nyie-outer"> second row third row
fourth row fifth row sixth row seven throw eighth row
</div><!--/.second four rows here-->
sql code
CREATE TABLE product( php code
<?php how can i echo that result in those rows
<html> <?php $id = $_GET['id']; $dbusername="web148-matt"; $dbpassword="matt"; $dbdatabase="web148-matt"; mysql_connect(localhost,$dbusername,$dbpassword); @mysql_select_db($dbdatabase) or die( "Unable to select database"); mysql_query("UPDATE count SET clicks=clicks+1 WHERE id='$id'"); $sql = mysql_query("SELECT link FROM count WHERE id='$id'"); $fetch = mysql_fetch_row($sql); $result = mysql_query("SELECT * FROM count"); while($row = mysql_fetch_array($result)) { echo "<a href=" .$row['link']. ">Link</a>"; } ?> <a href='http://www.google.com'>Google</a> <a href='/index.php?id=2'>link2</a> </html> So I have been working on my website for a while which all is php&mysql based, now working on the social networking part building in similar functions like Facebook has. I encountered a difficulty with getting information back from a link. I've checked several sources how it is possible, with title 'Facebook Like URL data Extract Using jQuery PHP and Ajax' was the most popular answer, I get the scripts but all of these scripts work with html links only. My site all with php extensions and copy&paste my site links into these demos do not return anything . I checked the code and all of them using file_get_contents(), parsing through the html file so if i pass 'filename.php' it returns nothing supposing that php has not processed yet and the function gets the content of the php script with no data of course. So my question is that how it is possible to extract data from a link with php extension (on Facebook it works) or how to get php file executed for file_get_contents() to get back the html?
here is the link with code&demo iamusing: http://www.sanwebe.c...-php-and-jquery
thanks in advance.
Hi... I am really new to this. Please help me with this... as part of a gallery, I have categories and a thumbnail. As of now the title/link to the gallery shows up on the side of the thumbnail. How can I place the link below the thumbnail? Here is the code Code: [Select] $result_array[] = "<a href='viewgallery.php?cid=".$row[0]."'>".$row[1]."<img src='/photos/categoryimages/category".$row[0].".jpg' border=0 height='133px' width='200px' </a>"; Thank you for your help... ok so im trying to make a news website and i want to be able to include links inside me headline like most news website they talk about the stuff and include some links along the way how would i manage to do that. I would put all my story in the Release textarea Code: [Select] <form class="createheadline" action="createrelease.php" method="post" enctype="multipart/form-data"> <table> <tr> <td></td> <td><?php echo $msg;?></td> </tr> <tr> <td>Author:</td> <td><input type="text" name="author" size="30"/></td> </tr> <tr> <td>Date:</td> <td><input type="text" name="date" /></td> </tr> <tr> <td>Title:</td> <td><input type="text" name="title" size="30"/></td> </tr> <tr> <td>Main Picture</td> <td><input type="file" name="picture" /></td> </tr> <tr> <td>Release:</td> <td><textarea name="release" cols="75" rows="27"></textarea></td> </tr> <tr> <td></td> <td><input type="submit" name="submitbtn" /></td> </tr> </table> </form> I am trying to create a link with an ID from one of my MySQL records. $data = mysql_query("SELECT * FROM USERS"); $info = mysql_fetch_array($data); echo "<a href=a.php?'$info['id']'>hello</a>"; is what I am attempting, but this does not work. Any ideas? Hello dear friends, Let say we have Code: [Select] $to = "gigi"; then we have link like this Code: [Select] mysite.com/file.php?id=$1 We can change it to new form by add rule at .htaccess codes Code: [Select] RewriteRule -(.*)\.htm file.php?id=$1 So that the link be like this Code: [Select] mysite.com/$to-$id.htm it will works , Now what if i want to make the link like this Code: [Select] mysite.com/$id/$to.htm what will be the .htaccess code in this way ??? thanks Hey all, I'm currently coding a Few Blacklists for my Website, in which I want to code it so I'll have all blacklists on one page so the URL would be like: localhost/blacklist.php?user localhost/blacklist.php?staff I've got a Blacklist coded which all works well, just I've attempted using the $_GET function to change the code to the blacklist that they clicked on... <?php session_start(); include ("includes/config.php"); include ("includes/functions.php"); logincheck(); $Username = $_SESSION['username']; ?> <table width='50%' cellpadding='0' cellspacing='0' border='1' class='table' align='center'> <tr> <td class='header' align='center' colspan='4'>Other Blacklists:</td> </tr> <tr> <td align='center'><a href='?user' target='mainFrame'>User Blacklist</a></td><td align='center'><a href='?money' target='mainFrame'>Most Money</a></td><td align='center'><a href='?racewins.php' target='mainFrame'>Race Wins</a></td><td align='center'><a href='?racelose' target='mainFrame'>Race Loses</a></td> </tr> <tr> <td align='center'><a href='?miles' target='mainFrame'>Most Miles</a></td><td align='center'><a href='?fosbl' target='mainFrame'>Faster Or Slower</a></td><td align='center'><a href='?police' target='mainFrame'>Police Chase</a></td> </tr> </table> <br /> <table width='20%' cellpadding='0' cellspacing='0' border='1' class='table' align='center'> <tr> <td colspan='2' align='center' class='header'>User Blacklist:</td> </tr> <tr> <td align='center' class='omg' width='5%'>Num:</td><td align='center' class='omg' width='10%'>Username:</td> </tr> <?php if ($_GET['user']){ $Query = mysql_query("SELECT * FROM users WHERE userlevel = '1' OR userlevel = '5' ORDER BY rep DESC LIMIT 25"); for ($Place < 25; $This = mysql_fetch_object($Query);){ $Place = $Place+1; if ($This->username != $Username){ $Colour = "bgcolor=#424242"; }else{ $Colour = "bgcolor=#111111"; } print ("<tr><td width='5%' align='center' $Colour>$Place</td><td width='20%' align='center' $Colour><a href='profile.php?viewuser=".$This->username."'>$This->username</a></td></tr>"); } } ?> </table> <br /> Soon as I added the $_GET['user]{ it stopped showing the Blacklist completely. Sorry if it wasn't explained well, but hopefully you can catch what I'm trying to-do Thanks. Hi, I've been working on making my own FAQ system for my site with PHP & MySQL, I have the SQL displaying properly on the page but I cant seem to figure out how to make it so when the page loads just the questions show and when a question is clicked the answer shows below it. I've read a number of tutorials and when I do get it to work it will only show the answer to the first question when the link is clicked. Here is the code I'm using to display the info from the database: Code: [Select] <div id="faqSQL"> <?php foreach($result as $option) { ?> <div class="faq-question"><?php echo wordwrap($option['faqquestion'], 100, "\n", false);?></div> <div class="faq-answer"><?php echo wordwrap($option['faqanswer'], 100, "\n", false);?></div> <?php } ?> </div> If anyone can help it would be much appreciated. |
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