PHP - Mysql Multi-query Insert
Similar TutorialsHello, I have been at this for awhile now and cant seem to figure it out. I have 2 separate arrays like shown below and I am trying to insert each value into my database using one update query. I have tried a for loop inside each array, but only one column populates. I have tried breaking the values outside their for loop, etc, etc. Does anyone know a way this can be done? Code: [Select] //Cars $cars = array('ford', 'toyota', 'bmw'); //Places $places =arrray('Orlando','California','Texas'); foreach ($cars as $car){ foreach ($places as $place){ $place .=$place; } mysql_query("INSERT INTO vehicles (cars, places) VALUES ('" . $car. "', '" . $place . "'')"); } If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> Dear All Members here is my table data.. (4 Columns/1row in mysql table)
id order_no order_date miles How to split(miles) single column into (state, miles) two columns and output like following 5 columns /4rows in mysql using php code.
(5 Columns in mysql table) id order_no order_date state miles 310 001 02-15-2020 MI 108.53 310 001 02-15-2020 Oh 194.57 310 001 02-15-2020 PA 182.22
310 001 02-15-2020 WA 238.57 ------------------my php code -----------
<?php
if(isset($_POST["add"]))
$miles = explode("\r\n", $_POST["miles"]);
$query = $dbh->prepare($sql);
$lastInsertId = $dbh->lastInsertId(); if($query->execute()) {
$sql = "update tis_invoice set flag='1' where order_no=:order_no"; $query->execute();
} ----------------- my form code ------------------
<?php -- Can any one help how to correct my code..present nothing inserted on table
Thank You Edited February 8, 2020 by karthicbabuHello Friends, Now i m stuck with simple insert query . here's the code Code: [Select] <?php include_once("conf.php"); $firstName=$_POST['fname']; $lastName=$_POST['lname']; $email=$_POST['email']; $dob=$_POST['dob']; $password=$_POST['pass']; $fname= stripslashes($firstName); $lname=stripslashes($lastName); $mail= mysql_real_escape_string($email); $password= mysql_real_escape_string($password); mysql_select_db('site'); $statement="Insert into Accounts(Name,lastName,emailId,DOB,password) VALUES($fname,$lname,$mail,$dob,$password)"; $query=mysql_real_escape_string($statement); mysql_query($query) or die("Cannot save data:</br> ".mysql_error()); echo "Data Saved Successfully"; ?> Now please explain me why i m getting the following error Cannot save data: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '@gmail.com,1988/12/20,password)' at line 1 Any help will be highly appreciated! Hello every body,, i want to create a new database (auto generate duty assigned using form) in PHP and mysql..
i have four input fields:-
Name, Subject, Class & weekly lectures
now i want to insert name,subject & class into database, when i insert number of weekly lecture in field four..
insert automaticlly in database multiple time which i write in field four (weekly lecture)
database: table structure i have already is:::
id-name-subject-class-period-monday-tuesday-wednesday-thursday-friday-saturday
anybody please help me to create this database or just insert query ....
Hi, Here is an extract of my while loop while ($personquery = mysql_fetch_array($personfetch, MYSQL_ASSOC)) { echo "$personfetch[first_name]"; } This will list each person now I want to do an INSERT to the database on every single member that is being listed I can only get it to INSERT for the one. Thanks I have tried many ways of storing an array of data that comes from a multiple selection form into a mysql table, including serialization. I am currently trying to do it by forming a string, and using the string in the insert query, but keep getting errors, or just nothing happening. I am not sure what I am doing wrong. Code: [Select] $categoryString = array(); if ($categoryArray){ foreach ($categoryArray as $category){ $categoryString[] = $category.'<br />';} } $categoryquery= "INSERT INTO categoryname VALUES('$categoryString')"; mysql_query($categoryquery); Thank you for your time as always. How can i use single quote for values? $qry='insert into tablename values('a','b');'; I am really just a beginner in PHP but I've got a task to create a simple hotel booking system by using PHP and MySQL. It works in several steps, described in separate .php files. All of them seem to work fine, except the last one. In this last file I want to add all the data into a MySQL database table. I would like to do this by creating a record for each date, a guest is spending in a hotel (so that when booking, another loop checks whether the room is not occupied yet for that date). I decided to use a for-loop for that, but it doesn't seem to be working (the records just don't get inserted into the table). I checked all the variables by echo-ing them and they are all right. I also tried the query without the loop and it works as well. So I guess there is some other problem. This particular .php file looks as follow: <?php session_start(); include('db_config.php'); $name=($_POST['name']); $telephone=addslashes($_POST['telephone']); $email=addslashes($_POST['email']); $code=md5($email.time()); $checkout_date=$_SESSION['checkout']; $checkin_unix=$_SESSION['checkin_unix']; $checkout_unix=$_SESSION['checkout_unix']; $roomtype=$_SESSION['roomtype']; $checkin_date=$_SESSION['checkin']; for ($stay_date=$checkin_unix; ; $stay_date=$stay_date+24*60*60) { if ($stay_date=$checkout_unix){ break; } mysql_query("INSERT INTO reservations VALUES( '', '$roomtype', 'pending', 'date ('d/m/Y', $stay_date)', '$stay_date', '$checkout_date', '$name', '$telephone', '$email', '$code' )"); } ?> I would appreciate any kind of help, any idea. I have created a registration page to access my website. After the user registrate himself should appear an alert saying that the registration was OK and a redirect to main.php page... however for some reason if I create an insert statement the alert and the redirect don't appear... If I remove the insert the alert and the redirect works... why? This is part of the code of my 3 files: registration.php (ajax call) $('#submit').click(function() {var username2 = $('#uname2').val(); var password2 = $('#psw2').val(); $.ajax({ url: 'ajax/response.php', type: 'GET', data: {username2 : username2, password2: password2}, success: function(data) { if(data === 'correct') { alert("Username and Password have been created!"); //don' work with the insert location.replace("main.php"); //don' work with the insert } else { alert("Username or password are not correct... please register yourself!"); } } }); }); response.php (answer to ajax call) if(isset($_GET['username2']) && isset($_GET['password2'])) {$username2 = $_GET['username2']; $password2 = $_GET['password2']; if (checkUser($pdo, $username2) === true) { echo 'duplicate'; } else { insertUserPwd($pdo, $username2, $password2); //including this line the redirect and the alert doesn't work... the insert is OK echo 'correct'; } } data_access.php (the function works but doesn't permit alert and redirect to appear) function insertUserPwd(PDO $pdo, $usr, $pwd){ $data = [ 'id' => '', 'user' => $usr, 'password' => $pwd ]; $sql = "INSERT INTO users (id, user, password) VALUES (:id, :user, :password)"; $stmt= $pdo->prepare($sql); $stmt->execute($data); } Can someone help me to fix the code? hello, is there a way to insert something 17 times into a database and change the 3rd field one at a time (from 1-17)? Code: [Select] $sql = "INSERT INTO picks VALUES ( NULL, '" . mysql_real_escape_string($userid) ."', '" . mysql_real_escape_string($weekid) ."', '" . mysql_real_escape_string($pickid) ."' )"; mysql_query($sql) or die('Error, Check you fields and try again.'); im trying to do a multi insert form using for loop. the concept is specifying a number and then using it in the for loop. the loop then makes a number of fields depending on the specified number. after that i use another for loop to insert the grouped fields together. code for specifying desired number Code: [Select] <? if ($_GET[num]=="") { ?><form name="form1" method="post" action="multiup.php?num=1"> <input name="num" type="text" value="10" maxlength="2"> <input type="submit" name="button" id="button" value="Submit"> </form><? } ?> Code: [Select] <? } else { ?><form name="form2" method="post" action="multiup2.php"> <input name="adder" type="hidden" value=""> <input name="num" type="hidden" value="<? echo $_POST[num]; ?>"> code for displaying fields <? for ($i=1;$i<=$_POST[num];$i++) { echo "groupnumber<br /> <input name='eno$i' type='text' value='$i'> Thumb <input name='thumb$i' type='text'> link1<br /> ";} ?> the insert code Code: [Select] <? if(isset($_POST['submit']) && ($_POST['submit'] == "Submit")) { $con = mysql_connect("lalalalala"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("kiphi_main", $con); for ($i=1;$i<=$_POST[num];$i++) { $title="$eno$i"; $sql="INSERT INTO articles (title) VALUES ('$_POST[$title]')"; } } if (!mysql_query($sql,$con)) {echo testest;}?> problem is i cant get it to work... should i try a different approach? Hello I have this multi dimensional array which needs to be inserted to the database table.
[business] => Array ( [title] => Email Marketing [URL] => email-marketing [category] => 3 [region] => 2 ) [description_] => Array ( [text] => Some desc ) [logo_] => Array ( [blob] => mainlogo.png ) [location_] => Array ( [text] => Array ( [0] => Lemara Main Office [1] => Themi branch [2] => Sinoni branch ) [priority] => Array ( [0] => 1 [1] => 2 [2] => 3 ) ) [photo_] => Array ( [path] => Array ( [0] => lemaraphoto.png [1] => themiphoto.png [2] => sinoniphoto.png ) ) [video_] => Array ( [path] => Array ( [0] => lemaravideo.mp4 [1] => themivideo.mp4 [2] => sinonivideo.mp4 ) ) [product_] => Array ( [p_id] => Array ( [0] => product photo [1] => product 3 photo [2] => Product 2 photo ) [text] => Array ( [0] => product desc [1] => product 3 desc [2] => product 2 desc ) [expire] => Array ( [0] => product expire [1] => product 3 expire [2] => Product 2 expire ) [title] => Array ( [0] => product [1] => Product 3 [2] => Product 2 ) ) [service_] => Array ( [p_id] => Array ( [0] => Service 2 photo [1] => service 3 photo [2] => service photo ) [text] => Array ( [0] => service 2 desc [1] => service 3 desc [2] => service desc ) [expire] => Array ( [0] => Service 2 expire [1] => service 3 expire [2] => service expire ) [title] => Array ( [0] => Service 2 [1] => service 3 [2] => service ) ) )That's the data. The database table, the table field and the corresponding value to be inserted in to the database. I'm using CodeIgniter any help would be appreciated. I have managed to make it wotk in this format [[business] => Array ( [title] => Email Marketing [URL] => email-marketing [category] => 3 [region] => 2 ) [description_] => Array ( [text] => Some desc ) [logo_] => Array ( [blob] => mainlogo.png ) ]I used this code to do it function add_bz($data){ $this->db->trans_start(); $er=0; foreach($data as $table => $sql){ if($table==="business"){ $this->db->insert($table, $sql); $id = $this->db->insert_id(); } else { array_merge($sql, array('idd' => $id)); $this->db->insert($table, $sql);} } $this->db->trans_complete(); if ($this->db->trans_status() === FALSE){print "Transaction Fails";return FALSE;} return TRUE; }Thanks in advance. could anyone please help me with the code which is i have already displayed data as a multi select list but now i need to select one or more from them and insert into another database table. would be appreciate your help. thanx How i can delete record from table `order` and move it to `order2`
the table `order2` structure is exactly like table `order`.here is the code that i made.
<? include("connection.php"); $id_product=$_GET["pid"]; $sql_delete="DELETE FROM `order` WHERE id_product='$id_product'"; $result=mysql_query($sql_delete) or die("Error in sql due to ".mysql_error()); if ($result) header("Location: order_list.php"); ?> Hi Chaps, I'm trying to put together a Nested Set Model (Hierarchical Data), but I have having problems when it comes to deleting/updating the 'nested' table. I'm using this as a guide: http://dev.mysql.com/tech-resources/articles/hierarchical-data.html But when trying to run a query, such as: SELECT @myLeft := lft, @myRight := rgt, @myWidth := rgt - lft + 1 FROM nested_category WHERE name = 'GAME CONSOLES'; DELETE FROM nested_category WHERE lft BETWEEN @myLeft AND @myRight; UPDATE nested_category SET rgt = rgt - @myWidth WHERE rgt > @myRight; UPDATE nested_category SET lft = lft - @myWidth WHERE lft > @myRight; I get a MySQL syntax error. This code works fine in something such as Windows Command Prompt, but not in PHP. Is there a special way to run multiple queries in 1 PHP script? Many thanks Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; $params = array(); $sqlFilters = ""; if(isset($filtertown)) { $sqlFilters .= " AND town =:town"; $params["town"] = $filtertown; } if(isset($filterinstagram) && !empty($filterinstagram)) { $sqlFilters .= " AND instagram >=:instagram"; $params["instagram"] = $filterinstagram; } if(isset($filtertwitter) && !empty($filtertwitter)) { $sqlFilters .= " AND twitter >=:twitter"; $params["twitter"] = $filtertwitter; } if(isset($filterfacebook) && !empty($filterfacebook)) { $sqlFilters .= " AND facebook >=:facebook"; $params["facebook"] = $filterfacebook; } if(isset($filterpinterest) && !empty($filterpinterest)) { $sqlFilters .= " AND pinterest >=:pinterest"; $params["pinterest"] = $filterpinterest; } if(isset($filteryoutube) && !empty($filteryoutube)) { $sqlFilters .= " AND youtube >=:youtube"; $params["youtube"] = $filteryoutube; } if (isset($userstatus)) { if ($userstatus == "active") { $sqlFilters .=" AND profilecomplete = 'yes'";} if ($userstatus == "incomplete") { $sqlFilters .=" AND profilecomplete IS NULL";} if ($userstatus == "block") { $sqlFilters .=" AND status = 'block'";} if ($userstatus == "cancel") { $sqlFilters .=" AND status = 'cancel'";} if ($userstatus == "showall") { $sqlFilters .=" AND status IS NULL";} } if (isset($search)) { if (isset($searchfirstname)) { $sqlFilters .= " AND firstname LIKE :searchfirstname"; $params["searchfirstname"] = $searchfirstname; } if (isset($searchsurname)) { $sqlFilters .= " AND surname LIKE :searchsurname"; $params["searchsurname"] = $searchsurname; } } if (isset($sort)) { $sqlStart = "SELECT * FROM users WHERE usertype = 'influencer'"; $sqlEnd = " ORDER BY `$col` $order LIMIT $offset, $rowsPerPage;"; $sql = $sqlStart.$sqlFilters.$sqlEnd; $sqlfiltercount = $sqlStart.$sqlFilters; $result = $pdo->prepare($sql); $result->execute($params); $resultfiltercount = $pdo->prepare($sqlfiltercount); $resultfiltercount->execute($params); $num_users = $result->rowCount(); $num_usersfiltered = $resultfiltercount->rowCount(); } else { $sqlStart = "SELECT * FROM users WHERE usertype = 'influencer'"; $sqlEnd = " LIMIT $offset, $rowsPerPage;"; $sql = $sqlStart.$sqlFilters.$sqlEnd; // sqlfiltercount removes the LIMIT to show ALL users on this userstatus filter $sqlfiltercount = $sqlStart.$sqlFilters; $result = $pdo->prepare($sql); $result->execute($params); $num_users = $result->rowCount(); echo "$sqlfiltercount"; $resultfiltercount = $pdo->query($sqlfiltercount); $num_usersfiltered = $resultfiltercount->rowCount(); } Hi there. I am writing a tool that displays a list of users. The page has pagination, set at 99 per page. This script combines the various filters added by the administrator, but if they select Active, Blocked or a few others, it bypasses that and runs the bottom {} brackets of query. You have the $num_users which is the total on screen at the time, plus the secondary count of TOTAL users in the system. This count is then show by 'users' on the page.
This runs fine on my local machine running php7.2, but on the live 7.2 server, it's showing nothing. No errors. If I comment out the $resultfiltercount lines, the page loads, but of course no count. Why might it be getting upset at that, and why would it not throw errors on screen at me? I need some help with the query for a form that selects values across multiple columns, and allow users to select multiple values in several columns. http://brinsterinc.com/tpa/tpasearch.php I assume you build the where clause for the sql by determining if there is an option value has been selected in the single-value select boxes. But how do I handle the multi-select list boxes? I'm desperate for help! Need to get somewhere with this over the weekend! TIA! Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 |