PHP - Hide All Files With Same Extension In Php File Directory?

I have a page using forms to help build listing templates for eBay. I have a folder where I have hundreds of logos stored. I know the logo names but not their extensions. . . . I have to test each potential (jpg, jpeg, gif, png, etc.) until I guess right. Here is an example code for the web form: <form action="extension_test2.php" method="post">
<p>Logo: <input name="e" value="" type="text" size="15" maxlength="30" /><p>
<input name="Submit" type="Submit"/>
</form>   and the form's result: <?

$e =$_POST['e'];

if(!empty($e)) {
echo '<img src="http://www.gbamedica...ebayimg/logos/'.$e.'">';
};

?>   Here is a link to the example: http://www.gbamedica...ension_test.php Use "olympus.jpg" for test. I am looking for code that can determine the file type and dynamically add the extension. Can it be done?

Folks,

I am building a membership script for 21 months now!!! That long!!!
Anyway, I need members to say infront of their cams a few things and then upload the vid file to the site (from the confirm_id.php page) where the member's sponsor (recruiter) will get the video copy to check if it's the real person with the real personal details or not. If true details, then sponsor verifies the member account. Else, unverifies it.
Now, I been testing my code. I uploaded an mp4 file. That should be ok but I get echoed:
"There was a problem uploading your video file $file_name! Make sure your file is an MP4 or a WAV file. You may try again now." 
Why ?

Not pasting the whole script as really long. Would do your head in.
Only pasting relevant part:

if($_SERVER["REQUEST_METHOD"] == "POST") 
    { 
        if(!isset($_FILES["id_verification_video_file"]))  //REtype
        { 
            echo "no isset";
        }
        else 
        { 
            $id_verification_video_file = $_FILES['id_verification_video_file']; //REtype
            //Feed Id Video Verification File Upload Directory Path. 
            $directory_path = "uploads/videos/id_verifications/"; 
            //Make Directory under $user in 'uploads/videos/id_verifications' Folder. 
            if(!is_dir("$directory_path" . "$user")) 
            { 
                $mode = "0777"; 
                mkdir("$directory_path" . "$user", "$mode", TRUE); //Thanks Requinix for my "$mode" typo hint.
            } 
            
            //Grab Uploading File details. 
            $Errors = Array(); //SHOULD I KEEP THIS LINE OR NOT ?
            $file_name = $_FILES["id_verification_video_file"]["name"]; 
            $file_tmp = $_FILES["id_verification_video_file"]["tmp_name"]; 
            $file_type = $_FILES["id_verification_video_file"]["type"]; 
            $file_size = $_FILES["id_verification_video_file"]["size"]; 
            $file_error = $_FILES['id_verification_video_file']['error']; 
            
            //Grab File Extension details. 
            $file_extension = pathinfo($file_name, PATHINFO_EXTENSION); 
            if(file_exists('$directory_path' . '$user/' . '$file_name')) 
            { 
                $Errors[] = "Error: You have already uploaded a video file to verify your ID!"; 
                exit(); 
            } 
            else 
            { 
                //Feed allowed File Extension(s). 
                $allowed_file_extensions = array("mp4" => "video/mp4","wmv" => "video/wmv"); 
                //Feed allowed file size. 
                $max_file_size_allowed_in_bytes = 1024*1024*100; //Allowed limit: 100MB. 
                $max_file_size_allowed_in_kilobytes = 1024*100; 
                $max_file_size_allowed_in_megabytes = 100; 
                
                $max_file_size_allowed = "$max_file_size_allowed_in_bytes"; //RETYPE
                
                //Verify File Extension. 
                if(!array_key_exists($file_extension,$allowed_file_extensions)) die("Error: Select a valid video file format. Select an MP4 or WAV file."); 
                //Verify MIME Type of the file. 
                elseif(!in_array($file_type,$allowed_file_extensions)) 
                { 
                    echo "Error:<font size ='5' font color ='red'><b>There was a problem uploading your video file $file_name! Make sure your file is an MP4 or a WAV file. You may try again now.</b></color></size>"; //THANKS TO REQUINIX FOR BRINNGING IT TO MY ATTENTION I AM STILL PROCESSING THE SCRIPT AFTER THIS LINE WHEN I SHOULD NOT. 
                    exit(); 
                } 
                //Verify File Size. Allowed Max Limit: 100MB. 
                elseif($file_size>$max_file_size_allowed) die("Error: Your Video File Size is larger than the allowed limit of: $max_file_size_allowed_in_megabytes."); //Fixed variable name typo. Thanks to Requinix & Simon JM. 
                //Move uploaded File to newly created directory on the server. 
                move_uploaded_file("file_tmp","$directory_path" . "$user/" . "$file_name"); 
                //Notify user their File was uploaded successfully. 
                echo "<font size ='5' font color ='red'><b>Your Video File \"$file_name\" has been uploaded successfully! You will get notified once your Id has been verified successfully.</b></color></size>"; 
                

Can you spot my coding error ?
Any other errors ?
How-about you show me code sample how you'd do it better and simpler with as much less lines of codes as possible ?

Hi guys,
I am using a MySQL table to store if a user has access permisisons to a file.

The files are stored outside the webdirectory in drive F:\

So I have this code I have been playing around with in order to display the file I access and check permissions for:
<?php
$file = $_GET['file'];

$myfile = 'F:\files\/'.$file.'.jpg';

echo "<img src='$myfile' />";
?>


So a sample case would be say on index.php
<img src="http://somedomain.com/files?file=abcdefghijkl" />
and only if the current user had permissions to view that file would they see it.

Any help on how I can do this is greatly appreciated.

I do understand all my above code is probably totally wrong.

Cheers

I almost have it but can't figure why the code below only shows one file per folder.

I think it is showing the last file.

I need $ul somehow looping to show all the files in $file.


<?php
$year = date('Y');

if ($handle = opendir("results/$year/Boys")) {

while (false !== ($file = readdir($handle))) {

if ($file != "." && $file != "..") {

if ($handle2 = opendir("results/$year/Boys/$file")) {

while (false !== ($file2 = readdir($handle2))) {

if ($file2 != "." && $file2 != "..") {
$ul = "<li><a href=\"#\">$file2</a></li>";

$li =  "<li><a target=\"_blank\" href=\"javascript:void(0)\">$file</a>
<ul>
$ul
</ul>
</li>";

} // close if file2
}echo $li;
}
}
}
}closedir($handle);closedir($handle2);
?>

hey all,
i have an issue, i have a directory site called hackingtoolz.tk and if you go to it, you will see a list of folders as it is just a directory the problem is how to i stop the banner from apearing in the directory.
i have tried changing the chmod to 4000 and that just made the jpeg stay their and the banner screw up
if you go to the site you will understand what i mean better
hope you can help
cheers nick

I have a variable that holds the name of a File...
Code: [Select]
$origFileName = $_FILES['userPhoto']['name'];

What is the best way to just get the File Name from this?


Debbie

Hello everyone.
I am having trouble trying to write some script that will unlink all files in a directory. Can anyone help me? I am not sure of the best way to do this? Thankyou. 

Hey guys, I've written a script that is suppose to Display the files within a specified directory /documents/ with check boxes to the right of them..  This worked out great.

Then I wanted to devise a method to remove or unlink the selected files (via check box) when the user pressed a Submit button..

File Permissions on the server are 777 and I have hardcoded an unlink to test to see if it works and it does..  So the bug lies within my code..

Before I post the code let me explain my method in doing this.
I created a for loop to name each check box after the corresponding file to the left and created a variable with the file name (to use later)

Then on button press I made a for loop (it goes up to 50 because I wasn't sure how to make it the exact number of files and I didn't want to overload the server with say 1000000 :?) that goes through and checks the check box's values and if they equal 1, unlink the file in /documents/

Here's the code:
Code: [Select]
<html>
<body>

<form action="" method="post" class="delete">
<?php
$dir = "documents/";
if ($handle = opendir($dir))
{
echo '<h2>List of Files in '.$dir.'</h2>';
echo '<table>';
for ($i = -2; false !== ($file = readdir($handle)); $i++)
{
if ($file != "." && $file != "..")
{
echo '<tr><td><a href="'.$dir.''.$file.'">'.$file.'</a></td><td><input type="checkbox" name="Del['.$i.']" /></td</tr>';
$DelFile[$i] = $file;
}
}
echo '</table>';
closedir($handle);
}

?>
<br />
<input type="submit" name="submit" value="Delete Checked Files" />
</form>

<?php
for ($i = 0; $i <= 50; $i++)
if ('Del['.$i.']' == 1)
unlink("'.$dir.''.$DelFile[$i].'");
?>

</body>
</html>
Help is extremely appreciated, and Thanks in advance guys!

I have a function that reads all the picture files in a folder and displays them as thumbnails. It also displays a large version of the first image in the folder and clicking the thumbnail changes the large picture. I'm trying to use pictures of arrows as a button to allow users to click and have the next picture displayed large rather than having to click each individual thumbnail but don't really know how to get started. Can anyone suggest a method or give me a hint?

This is my code so far if that helps:


function displayPhotos(){

global $columns,$dir,$album;

generateThumbnails();

$act = 0;
$keyid = 0;

$thumb_selected = (isset($_GET['thumb']) ? $_GET['thumb']:'');

if ($thumb_selected !==""){

$dirName  = substr($thumb_selected,0,strpos($thumb_selected,basename($thumb_selected)));
       $thumbName = basename($thumb_selected);
$thumbFile = $dirName.$thumbName;
$large = str_replace('_th.jpg','.jpg',$thumbFile);
}

else{

$picture_array = glob("$dir*");

$large = $picture_array[$keyid];
}

echo "<tr><td colspan='3' height='300' width='400' align='center'><img src='$large' alt=''></td></tr>
<tr><td><img src='gallery/icons/arrow-blue-rounded-left.jpg' alt='Previous'></td><td></td><td align='right'><img src='gallery/icons/arrow-blue-rounded-right.jpg' alt='Next'>
        </td></tr><tr><td height='50'></td></tr>";

if ($handle = opendir("$dir")) {

while (false !== ($file = readdir($handle)))  {

$file=$dir.$file;

if (is_file($file)){

       if (strpos($file,'_th.jpg')){

++$act;

if ($act > $columns) {

echo "</tr><tr><td width='160' height='120' align='center'><a href='?album=$album&amp;thumb=$file'><img src='".$file."' alt='".$file."'/></a></td>";

$act = 1;

} else {

echo "<td width='160' height='120' align='center'><a href='?album=$album&amp;thumb=$file'><img src='".$file."' alt='".$file."'/></a></td>";

}    

       }

       }

}

}

}


Thanks very much to anyone having a look at this!

I am trying to find a script that will show just the file names of files in a specific directory.
I tried this code posted previously on this forum and it works but shows the directory name.
Code: [Select]
<?php
filesInDir('attachments');
function filesInDir($tdir)
{
        $dirs = scandir($tdir);
        foreach($dirs as $file)
        {
                if (($file == '.')||($file == '..'))
                {
                }
                elseif (is_dir($tdir.'/'.$file))
                {
                        filesInDir($tdir.'/'.$file);
                }
                else
                {
                        echo $tdir.'/'.$file."<br>";
                }
        }
}
?>
Result is: attachments/Sedona_and_Slot_Canyon_links.docx
Thanks for the help.

I am using the following code to list mp3 files from a directory and find out if there is a file for it in mysql if so not to include it in the list. The code below is listing each file twice I only would like them to be listed once.



if($_POST['submit'] != 'select') {
echo'Choose an mp3 to add information.<p><select name="file">';
$dir = "/uploads/";

$result = mysql_query("SELECT * FROM dj_pool") or die(mysql_error());
$num_rows = mysql_num_rows($result);

// Open a known directory, and proceed to read its contents
if (is_dir($dir)) {
    if ($dh = opendir($dir)) {
        while (($file = readdir($dh)) !== false) {
            $info = explode(".", $file);
            if($info[1] == "mp3") {
            $i = 0; 
            while ($i < $num_rows)
              {
        $file2 = mysql_result($result,$i,mp3);
                if ($file != $file2) { echo "<option value='$info[0]'>$info[0]</option>"; }
            $i++; 
              }
                              }
        }closedir($dh);}
        
    }

print "</select><p><input type=submit value=select name=submit>";

Dear sirs,

I need to upload files to FTP and To waste less time, I zip the files, but the problem that since it is Automation it zips with directory - like this  C:/DIR.zip 
in zip file I have a DIR/files....    How to unzip all files to main directory on the server.  Right now if the main dir is  /main/html/  it unzips to /main/html/dir/files
But I need /main/html/files

Thank you.

I have a directory full of pictures that I would like to display in a gallery.

Originally I was going to write HTML like this...

	<li>
	    <img src=/photos/img_001.jpg">
	</li>
	

And then simply copy and paste that for the number of photos I have, and then tweak the code to: img_002.jpg, img_003.jpg, and so on.

I guess that is silly considering that I have over 500 photos to display!

How could I use PHP to go to my /photos/ directory, scan all of the files in that directory, and then grab the file name so I could automate this process?

Sorry, but I haven't written PHP in several years so all of this escapes me!  ☹️

Hi, how do I extract just file extension?

eg:
$file="hello.xml";

$fileExt=???

print $fileExt;

Any help much appreciated!

Hi Guys,

I am having some issues in trying to return a file extension in a php upload script, here is what I am trying to do, no extension is added when a file is uploaded.



$p_id = $row['p_id'];

$tempFile = $_FILES['Filedata']['tmp_name'];
$targetPath = $_SERVER['DOCUMENT_ROOT'] . $_REQUEST['folder'] . '/';
$filename = $HTTP_POST_FILES['Filedata']['name'];
$ext = end(explode('.', $filename));
$nfilename = $p_id . $ext;


$targetFile =  str_replace('//','/',$targetPath) . $nfilename;