PHP - Quick Rundonw On Windows Command Prompt To Run Php Program

Does anyone know what the source code for the PHP MyAdmin login prompt (the pop out box) looks like?

I can determine which radio button is selected for each file upload prompt because I have a name and a value. So the array name=image can have one of three values for each file upload prompt.

Is there a way to determine which of the three file upload prompts was loaded (clicking browse & select image) with an image and which was not? There doesn't seem to be a value like there is with radio buttons. I want to be able to replace an already uploaded image with another.

Thanks.

<input type='radio' name='image[image0]' value='keep' checked='checked'/>
<input type='radio' name='image[image0]' value='delete' />
<input type='radio' name='image[image0]' value='replace' />
<input type="file" name="image[]" />

<input type='radio' name='image[image1]' value='keep' checked='checked'/>
<input type='radio' name='image[image1]' value='delete' />
<input type='radio' name='image[image1]' value='replace' />
<input type="file" name="image[]" />

<input type='radio' name='image[image2]' value='keep' checked='checked'/>
<input type='radio' name='image[image2]' value='delete' />
<input type='radio' name='image[image2]' value='replace' />
<input type="file" name="image[]" />

if (isset($_POST['submitted']) && 
($image = $_POST['image'])) {

foreach($image as $imageKey => $imageValue) {
if ($imageValue == 'keep') {
do this
}
}
}

Hello! This bit of code actually does work, I just want to check that this is the best/proper/most efficiant way of doing it. Basically i'm calling a PHP function that uses the javascripts prompt function, then returning the value that the user types in back to PHP. Most probably easier to show you.

Code: [Select]
<?php

//prompt function
function prompt($prompt_msg){
echo("<script type='text/javascript'> var answer = prompt('".$prompt_msg."'); </script>");

$answer = "<script type='text/javascript'> document.write(answer); </script>";
return($answer);
}

//program
$prompt_msg = "Please type your name.";
$name = prompt($prompt_msg);

$output_msg = "Hello there ".$name."!";
echo($output_msg);

?>

That is the entire code, I just want to know if this is the proper way to do something like this (using javascript and PHP together) thanks guys!

Need help urgent.
the website sudden prompt out error below:

Warning: require_once() [function.require-once]: open_basedir restriction in effect. File(/var/www/vhosts/db2020.co.uk/application/application/config/admin/config.live.php) is not within the allowed path(s): (/var/www/vhosts/db2020.co.uk/subdomains/admin/httpdocs:/tmp) in /var/www/vhosts/db2020.co.uk/subdomains/admin/httpdocs/index.php on line 11

Warning: require_once(/var/www/vhosts/db2020.co.uk/application/application/config/admin/config.live.php) [function.require-once]: failed to open stream: Operation not permitted in /var/www/vhosts/db2020.co.uk/subdomains/admin/httpdocs/index.php on line 11

Fatal error: require_once() [function.require]: Failed opening required '/var/www/vhosts/db2020.co.uk/application/application/config/admin/config.live.php' (include_path='.:') in /var/www/vhosts/db2020.co.uk/subdomains/admin/httpdocs/index.php on line 11

and also after this problem occur, trafic of this domain go overlimit.

how can i solve this problem? urgent.... website = https://db2020.co.uk/

thanks.

I have a shoutbox my friend made, and I'm just adding onto it.

I have command that are like @prune, @prunelogs, @logout, etc.. I am tying to make it so you can type @ban username, @unban username, etc..

Here is my command that my friend came up with.
if($_POST['text'] == '@ban'.$username.'') {
$unn=$idk['username'];
mysql_query("UPDATE users SET banned = '1' WHERE usernane='$unn'") or die(mysql_error());
mysql_query("INSERT INTO chat (`log`, `date` ,`username` ,`text`) VALUES (1, NOW( ) , '".stripslashes($_SESSION['user'])."', 'has banned '$unn'.');") or die(mysql_error());

I've created a login page in Dreamweaver and there is a redirect page for login success and login fail. What I want to have is a selection of screens based on a data field held in the user security table.
Each security record will have up to 5 different security codes e.g. code1, code2 etc. If a code e.g. TA40, appears in any of the 5 code fields then I want the user directed to one page, if code TA41 appears in any of the 5 code fields then I want them directed to another page.
The user code will only appear in one of the fields, but can appear in any of the 5 code fields.. How can I incorporate this in to the login screen logic, as currently it will just show the follwoing

if (isset($_POST['opno'])) {
  $loginUsername=$_POST['opno'];
  $password=$_POST['pass_word'];
  $MM_fldUserAuthorization = "";
  $MM_redirectLoginSuccess = "/menu.php";
  $MM_redirectLoginFailed = "/loginform.php";
  $MM_redirecttoReferrer = false;
  mysql_select_db($database_Hanson, $Hanson);

I have created a tar file with my site backup and I assume it is the full backup.  Not sure becasue I can't "un"-tar the file.

I have tried several ways to "unzip" or untar the file but can not come up with anything.


here is how I had created the tar file:
Code: [Select]
$date = date("m-d-Y");

// repeat this command for multiple backups, changing the path - e.g. you can have a backup for email, another for files, etc.
shell_exec("tar cvfz file_backup_$date.tar.gz mydir/ ");

now how do extract it?

Hi..

I have a php file where i have only one line which says header('Location: index.php');

How do i run this php file in the terminal on fedora 14?

Thanks,
Rohit

Hi,

I'm having a weird issue when I try to run PHP scripts from the command line on my server.  I'm trying to just run a very simple script to test it out:

#!/usr/bin/php-cgi -q
echo "Hello terminal\n"; 

And I get the following error in the terminal..

Code: [Select]
Error in argument 1, char 3: option not found
Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f <file>]
       php-cgi <file> [args...]
When I try taking out the quiet (-q) parameter, I get the following error..

Code: [Select]
-bash: ./socket_server.php: /usr/bin/php-cgi^M: bad interpreterNo such file or directory
As you can see, in the second example, a rogue "^M" was appended to the end of the first line of my socket_server.php file.  What does ^M correlate to?  I realize it is a character code for something that can't be represented with an actual character, but I don't know what it is, and I'm not sure why it is being appended to the end of my first line.

My assumption is that this is happening in the first example too, which is why I get the "error in argument 1" message, since undoubtedly -q^M is an invalid argument...

Any help is greatly appreciated!

nethnet

hello, i was wondering if there is a way to have a link do a command, but not to goto a page.   my reason being is that the music player software i use has a built in web server and if you goto a certain page, it will process that command.  so right now, i have an iframe that i do a target to.  its pretty mickey mouse, but its what i knew how to do.

thanks

Is there anything in php that let's me SWAP  2 arrays?

like let's say I have

3,2,1  in a array,

is there a way I can swap the 2 and 1 if a statement is true?

This topic has been moved to mod_rewrite.

http://www.phpfreaks.com/forums/index.php?topic=326238.0

It was suggested that I add a ‘report’ parameter to the code, after revising with the ‘scale2ref’ code which appears to prevent the video from uploading/proceeding:

$ffmpegCommand =''.$ffmpeg_b.' -y -i '.$video_file_full_path.' -i '.$watermark_image_full_path.' -filter_complex "[0]scale=426:-2[vid];[1][vid]scale2ref='oh*mdar':'ih/10'[wm][vid];[vid][wm]overlay=5:5:format=rgb,format=yuv420p" -vcodec libx264 -preset '.$pt->config->convert_speed.' -crf 26 -report'.$video_output_full_path_240.' 2>&1';
$shell = shell_exec($ffmpegCommand); 

I couldn’t see where the -report parameter was supposed to output (error.log has a filesize of 0). So I was asked to “run command from the shell and check”?

But, I’m not sure what command and where/how to do that.

I tried adding this to the php code, and attempted to upload again, same result

echo shell_exec("/usr/local/bin/ffmpeg -report log.txt 2>&1");

 

any additional help is appreciated

 

 

Any guidance with that is appreciated.

Edited June 4, 2019 by Chrisj

I am having difficulty working out how to grab from a URL within a URL a link to an image and display this image on a webpage.
example:

http://domainA.com/page1.php?file_image=http://domainB.com/image.jpg

I know little of this the code below but this is not working:

<?php echo $_GET['file_image']; ?>

this just copies the url, whereas I want to display this image.jpg from domainB using image source by grabing it.
<img src=" ">

I hope you understand me.

I know that php has a function that can execute ping command but i'm not sure how it works.
I am trying to get the result of the ping command to determine:
IP address has a reply (PC/device is turned on) IP address has no reply (ip address is vacant and not assigned to any pc/device IP address has a response (PC/device is turned off)
is this "do-able" in php??

this is my script:
Code: [Select]
function ping($ip){
// #5882FA blue color indicates Fiber Module
// #FACC2E orange color indicates cascade/uplink cable
  // #81F781 Green color indicates connected/turned on
// #FE2E2E Red color indicates disconnected/turned off
// #585858 dark gray color indicates connected patch panel port is vacant at user side

if($ip=="Cascade" OR $ip=="Uplink"){
return $status="style=\"background-color:#FACC2E;cursor:pointer;\""; /* orange */
}elseif ($ip=="Fibre Module"){
return $status="style=\"background-color:#5882FA;cursor:pointer;\""; /* blue */
}elseif ($ip==null or $ip==""){
return $status="style=\"cursor:pointer;background-image:url(images/x.gif);\""; /* dark gray */
}else{
$str = exec("ping -n 1 -w 1 $ip", $input, $result);
if ($result == 0){
return $status="style=\"background-color:#81F781;cursor:pointer;\""; /* green */
//return "on";
}else{
return $status="style=\"background-color:#FE2E2E;cursor:pointer;\""; /* red */
//return "off";
} 
}
}

i can get it display on or off and i've tested it working. but i just can't figure out if i could use this command to determine if the IP address is vacant or unassigned. I'm using this for a IP list inventory system built in PHP. I have careted a page where the the 3com switch is drawn in tabulated format with each port assigned (via PHP) to the corresponding IP address of the device/PC and indicates the port color as described in the above function. Surprisingly it works well for this switch inventory. I just want to create another page for IP address inventory using the same function. To put is simple i want to have the same function as the sofware "Advance IP-Scanner" which does the same thing as well only thing is my resources are limited to PHP (WAMP).

any help guys?