PHP - Forum Search Engin To Search Keywords In Database In Php

 The result pages is supposed to have  pagination like google  help me please

 

I require a page to be added to my website. This page will facilitate a refined search via Google, Bing and Yahoo search engine simultaneously , show the top 5 of each engine.

Is this possible using php ?

Thank's

Hello,

Does anyone know a tutorial I can follow to create my own search engine over the items I have in my SQL database?
I find a lot of tutorials but they are all 'one word searches' which means if you type two words you will get all results that contain either word (too many hits).

If the search engine tutorial displays result with AJAX even better.

Thanks for help.
df

Hi i am an absolute PHP/MYSQL Novice but i guess we all gotta start somewhere.

I have a table in my database with names and addresses, f_name, s_name, street, zip_code, city etc etc etc

What i want to do is display a drop down of all cities in my database then click on any city in the list to display all the details of people in that city, showing all fields.

So i have got this far ..
Code: [Select]
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');

$dbname = 'cities_wrdp1';
mysql_select_db($dbname);


$sql = "SELECT DISTINCT City FROM PBM";
$result = mysql_query($sql);

echo "<select name='City'>";
while ($row = mysql_fetch_array($result)) {
    echo "<option value='" . $row['City'] . "'>" . $row['City'] . "</option>";
}
echo "</select>";


This produces the nice drop down list of cities from the database ...

Now on click i would like to return results similar to this 

Code: [Select]
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql');

$dbname = 'cities_wrdp1';
mysql_select_db($dbname);


$query = sprintf("SELECT * FROM PBM");

$result = mysql_query($query);


if (!$result) {
$message = 'Invalid query: ' . mysql_error() . "\n";
$message .= 'Whole query: ' . $query;
die($message);
}

echo "<br />";
echo "<table border='0'>";


while ($row = mysql_fetch_assoc($result))
{
echo "<tr><td>";
echo "<a href=\"" .$row['profileURL'] . "\">
<img src=\"" . $row['faviconURL'] . "\" border=0 alt=\"" . $row["Thumbnail"] . "\">
</a>";
echo "</td><td align='center'>";
echo $row['f_name'];
echo "</td><td align='center'>";
echo $row['s_name'];
echo "</td><td align='center'>";
echo $row['number'];
echo "</td><td align='center'>";
echo $row['street'];
echo "</td><td align='center'>";
echo $row['zip'];
echo "</td><td align='center'>";
echo $row['city'];
echo "</td><td align='center'>";
echo $row['Country'];
echo "</td><td align='center'>";
echo $row['email_address'];
echo "</td><td align='center'>";
echo $row['fb'];
echo "</td><td align='center'>";
echo $row['web_site'];
echo "</td><td align='center'>";
echo $row['phone'];
echo "</td><td align='center'>";
echo $row['land'];
echo "</td><td align='center'>";
echo $row['age'];
echo "</td></tr>";
}

echo "</table>";


mysql_free_result($result);

So my question is .. how do i make the first piece of code selectable to produce similar results to the second piece of code based on the city selected ?
Thanks for any help .. and please excuse my ignorance ..

Hello all. First of all, if this isn't the right place for this topic, please excuse me and may the moderators/admins move it where it should belong.

Second, I'm trying to make a mysql search - Everything works, but if say, a user searches for 34 it displays all numbers that have the number 34 in them.

I want the results to be exact - if a user searches for 34, to display only 34, not 334, 5034 or 3401 (like it happens now).

Here's the code:

Code: [Select]
<?php
mysql_connect ("**************", "*******","*****")  or die (mysql_error());
mysql_select_db ("********");
 
$term = $_POST['term'];
 
$sql = mysql_query("select * FROM countries WHERE cocode LIKE '%$term%'");
 
while ($row = mysql_fetch_array($sql)){
    echo '<br/> Code: '.$row['cocode'];
    echo '<br/> Country: '.$row['coname'];
    echo '<br/><br/>';
    }
 
?>
If you have any questions, you're welcome to ask them in the thread. 

Thank you in advance  

Friends,

I want to extract the Search Keyword from the URL, a visitor came from. I am using a PHP CMS and want to show the Keyword on my Blog.

So if they search "abcd" from google, i want to extract "abcd" and echo on my blog.

Here is the coding i could got hold of, but its not working, not echoing anything

<?php

function pk_stt2_function_get_delimiter($ref) {
    $search_engines = array('google.com' => 'q',
'go.google.com' => 'q',
'images.google.com' => 'q',
'video.google.com' => 'q',
'news.google.com' => 'q',
'blogsearch.google.com' => 'q',
'maps.google.com' => 'q',
'local.google.com' => 'q',
'search.yahoo.com' => 'p',
'search.msn.com' => 'q',
'bing.com' => 'q',
'msxml.excite.com' => 'qkw',
'search.lycos.com' => 'query',
'alltheweb.com' => 'q',
'search.aol.com' => 'query',
'search.iwon.com' => 'searchfor',
'ask.com' => 'q',
'ask.co.uk' => 'ask',
'search.cometsystems.com' => 'qry',
'hotbot.com' => 'query',
'overture.com' => 'Keywords',
'metacrawler.com' => 'qkw',
'search.netscape.com' => 'query',
'looksmart.com' => 'key',
'dpxml.webcrawler.com' => 'qkw',
'search.earthlink.net' => 'q',
'search.viewpoint.com' => 'k',
'mamma.com' => 'query');
    $delim = false;
    if (isset($search_engines[$ref])) {
        $delim = $search_engines[$ref];
    } else {
        if (strpos('ref:'.$ref,'google'))
            $delim = "q";
elseif (strpos('ref:'.$ref,'search.atomz.'))
            $delim = "sp-q";
elseif (strpos('ref:'.$ref,'search.msn.'))
            $delim = "q";
elseif (strpos('ref:'.$ref,'search.yahoo.'))
            $delim = "p";
        elseif (preg_match('/home\.bellsouth\.net\/s\/s\.dll/i', $ref))
            $delim = "bellsouth";
    }
    return $delim;
}

/**
 * retrieve the search terms from search engine query
 * */ 
function pk_stt2_function_get_terms($d) {
    $terms       = null;
    $query_array = array();
    $query_terms = null;
    $query = explode($d.'=', $_SERVER['HTTP_REFERER']);
    $query = explode('&', $query[1]);
    $query = urldecode($query[0]);
    $query = str_replace("'", '', $query);
    $query = str_replace('"', '', $query);
    $query_array = preg_split('/[\s,\+\.]+/',$query);
    $query_terms = implode(' ', $query_array);
    $terms = htmlspecialchars(urldecode(trim($query_terms)));
    return $terms;
}

/**
 * get the referer
 * */ 
function pk_stt2_function_get_referer() {
    if (!isset($_SERVER['HTTP_REFERER']) || ($_SERVER['HTTP_REFERER'] == '')) return false;
    $referer_info = parse_url($_SERVER['HTTP_REFERER']);
    $referer = $referer_info['host'];
    if(substr($referer, 0, 4) == 'www.')
        $referer = substr($referer, 4);
    return $referer;
}



$referer = pk_stt2_function_get_referer();
if (!$referer) return false;
$delimiter = pk_stt2_function_get_delimiter($referer);
if( $delimiter ){
$term = pk_stt2_function_get_terms($delimiter);
}
echo $term;
?>


May someone help?

Natasha T

Hello,

I'm developing a website that asks the user to submit a keyword for a search. The results should display matches for this keyword, but also show matches for related keywords (in order of relevenace!).

I'm planning on building up a library of which search terms users use in the same sessions (e.g. if someone searches for "it jobs" and "php jobs", I'll know the terms are correlated), and I'll also measure the click-through rates of the items on the results list.

I've been spending all weekend trying to map out the design for this but it's proving incredibly complicated and I think the solution is likely to be on the internet somewhere already?!

Please could someone point me in the right direction if you've come accross this problem before?

Thanks a million,

Stu

Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search

I managed to get all the things working the way I wanted, except one important and crucial thing.
Let me explain.
My table consist of three columns, like this:

ID(bigint20)    title(text)        link (varchar255)
=============================
ID1                title1                link-1
ID2                title2                link-2
etc...

Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table.

Here is the code I used.

<?php

$dbHost = 'localhost'; // localhost will be used in most cases
// set these to your mysql database username and password.
$dbUser = 'user'; 
$dbPass = 'pass';
$dbDatabase = 'db'; // the database you put the table into.
$con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error());

mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error());
// Set up our error check and result check array
$error = array();
$results = array();
// First check if a form was submitted. 
// Since this is a search we will use $_GET
if (isset($_GET['search'])) {
   $searchTerms = trim($_GET['search']);
   $searchTerms = strip_tags($searchTerms); // remove any html/javascript.
   
   if (strlen($searchTerms) < 3) {
      $error[] = "Search terms must be longer than 3 characters.";
   }else {
      $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection.
   }
   
   // If there are no errors, lets get the search going.
   if (count($error) < 1) {
      $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'";

      $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}");
      
      if (mysql_num_rows($searchResult) < 1) {
         $error[] = "The search term provided {$searchTerms} yielded no results.";
      }else {
         $results = array(); // the result array
         $i = 1;
         while ($row = mysql_fetch_assoc($searchResult)) {
            $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> ";

    $i++;

       

   
         }
      
      }
   }
}

function removeEmpty($var) {
   return (!empty($var)); 


}
?>

      <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?>
      <form method="GET" action="search?" name="searchForm">
         Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" />
        
         <input type="submit" name="submit" value="Search" />
      </form>

    <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?>




 $results = array(); // the result array
         $i = 1;
         while ($row = mysql_fetch_assoc($searchResult)) {
            $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> ";

    $i++;

 
I would like the results to be displayed like this

Results for SearchItem:

Result 1
Download | Other link
Result 2
Download | Other link
etc.... or something like this.

So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ?
My first tries (fueled by my lack of knowledge) where things like

$results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> ";

but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions);
So there it is. I am really stuck and can't seem to find any workaround for this.
Any suggestions? (examples, documentation, anything would do, really)
Thanks,
Radu

Hi all

How do I modify the below code to search multiple tables in mySQL database?

$query = "select * from store_items where description like \"%$trimmed%\"  or title like \"%$trimmed%\" or dimensions like \"%$trimmed%\" order by id ASC";

 $numresults=mysql_query($query);
 $numrows=mysql_num_rows($numresults);

It is for a search function and I need it to search another table called 'about_text' and 'faq_text'

Thanks
Pete

Hey guys,

Could somebody help me with a little problem I am having, I havew spent the last two weeks trying different ways to search my database without success.

What I want to do is have an input field that I can search only one column of my database. (it is a game collection) for example I want to search the game 'Medal of Honor' i type this in the search field and click submit button and it should find all the entries with that name in the database.

I have tried a few online tutorials and nothing works.

 

here is some code that i tried.

<?php

$host = "localhost";
$user = "root";
$password ="";
$database = "csv_db";

$id = "";
$game = "";
$year = "";
$platform = "";

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);

// connect to mysql database
try{
    $connect = mysqli_connect($host, $user, $password, $database);
} catch (mysqli_sql_exception $ex) {
    echo 'Error';
}

// get values from the form
function getPosts()
{
    $posts = array();
    $posts[0] = $_POST['id'];
    $posts[1] = $_POST['game'];
    $posts[2] = $_POST['year'];
    $posts[3] = $_POST['platform'];
    return $posts;
}

// Search

if(isset($_POST['search']))
{
    $data = getPosts();
    
    $search_Query = "SELECT * FROM games WHERE id = $data[0]";
    
    $search_Result = mysqli_query($connect, $search_Query);
    
    if($search_Result)
    {
        if(mysqli_num_rows($search_Result))
        {
            while($row = mysqli_fetch_array($search_Result))
            {
                $id = $row['ID'];
                $game = $row['GAME'];
                $year = $row['YR'];
                $platform = $row['PLATFORM'];
            }
        }else{
            echo 'No Data For This Id';
        }
    }else{
        echo 'Result Error';
    }
}


// Insert
if(isset($_POST['insert']))
{
    $data = getPosts();
    $insert_Query = "INSERT INTO `games`(`Game`, `YR`, `PLATFORM`) VALUES ('$data[1]','$data[2]',$data[3])";
    try{
        $insert_Result = mysqli_query($connect, $insert_Query);
        
        if($insert_Result)
        {
            if(mysqli_affected_rows($connect) > 0)
            {
                echo 'Data Inserted';
            }else{
                echo 'Data Not Inserted';
            }
        }
    } catch (Exception $ex) {
        echo 'Error Insert '.$ex->getMessage();
    }
}

// Delete
if(isset($_POST['delete']))
{
    $data = getPosts();
    $delete_Query = "DELETE FROM `games` WHERE `ID` = $data[0]";
    try{
        $delete_Result = mysqli_query($connect, $delete_Query);
        
        if($delete_Result)
        {
            if(mysqli_affected_rows($connect) > 0)
            {
                echo 'Data Deleted';
            }else{
                echo 'Data Not Deleted';
            }
        }
    } catch (Exception $ex) {
        echo 'Error Delete '.$ex->getMessage();
    }
}

// Edit
if(isset($_POST['update']))
{
    $data = getPosts();
    $update_Query = "UPDATE `games` SET `GAMES`='$data[1]',`YR`='$data[2]',`PLATFORM`=$data[3] WHERE `ID` = $data[0]";
    try{
        $update_Result = mysqli_query($connect, $update_Query);
        
        if($update_Result)
        {
            if(mysqli_affected_rows($connect) > 0)
            {
                echo 'Data Updated';
            }else{
                echo 'Data Not Updated';
            }
        }
    } catch (Exception $ex) {
        echo 'Error Update '.$ex->getMessage();
    }
}



?>


<!DOCTYPE Html>
<html>
    <head>
        <title>PHP INSERT UPDATE DELETE SEARCH</title>
    </head>
    <body>
        <form action="php_insert_update_delete_search.php" method="post">
            <input type="number" name="id" placeholder="ID" value="<?php echo $id;?>"><br><br>
            <input type="text" name="game" placeholder="Game" value="<?php echo $game;?>"><br><br>
            <input type="text" name="year" placeholder="Year" value="<?php echo $year;?>"><br><br>
            <input type="number" name="platform" placeholder="Platform" value="<?php echo $platform;?>"><br><br>
            <div>
                <!-- Input For Add Values To Database-->
                <input type="submit" name="insert" value="Add">
                
                <!-- Input For Edit Values -->
                <input type="submit" name="update" value="Update">
                
                <!-- Input For Clear Values -->
                <input type="submit" name="delete" value="Delete">
                
                <!-- Input For Find Values With The given ID -->
                <input type="submit" name="search" value="Find">
            </div>
        </form>
    </body>
</html>

and here is the error i get.

Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '' at line 1 in H:\xampp\htdocs\php_insert_update_delete_search.php:41 Stack trace: #0 H:\xampp\htdocs\php_insert_update_delete_search.php(41): mysqli_query(Object(mysqli), 'SELECT * FROM g...') #1 {main} thrown in H:\xampp\htdocs\php_insert_update_delete_search.php on line 41

can anybody help me do I search engine for my database

i have enters some data using form which submit data in sql table1 like this,

Fields name in table -->>         id   First name     Lastname    Date   
data saved           -->>              1  user                1               2011-05-10
                                               2  user                2               2011-05-11
                                               3  user                3               2011-05-12

now i dont want to duplicate date in database let say while inserting data using form,

Firstname :  ____________
Lasename :  ____________
Date         :  ____________ (i dont want this date to b save if the date alredy exist in database,
                                          it should prompt user "Date already exist and to edit click here
                                         (this will be the link to that date which is already exist so that we can edit) " )

                                SAVE


i user  files ,       form.php ,   insert.php(so insert values in database) ,
so tell me what function should i use to solve my problem....
 

Hi all. This is the code I've been trying to execute.

<?php

  // Get the search variable from URL

  $var = @$_GET['q'] ;
  $trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=10; 

// check for an empty string and display a message.
if ($trimmed == "")
  {
  echo "<p>Please enter a search...</p>";
  exit;
  }

// check for a search parameter
if (!isset($var))
  {
  echo "<p>No search parameter</p>";
  exit;
  }

//connect to your database ** EDIT REQUIRED HERE **
mysql_connect("localhost","*","*"); //(host, username, password)

//specify database ** EDIT REQUIRED HERE **
mysql_select_db("my_db") or die("Can't select database//Does not exist."); //select which database we're using

// Build SQL Query  
$query = "select * from people \"%$trimmed%\"  
  order by FirstName"; // EDIT HERE and specify your table and field names for the SQL query

 $numresults=mysql_query($query);
 $numrows=mysql_num_rows($numresults);

// If we have no results, offer a google search as an alternative

if ($numrows == 0)
  {
  echo "<h4>Results</h4>";
  echo "<p>Sorry, your search: &quot;" . $trimmed . "&quot; returned zero results</p>";

// google
 echo "<p><a href=\"http://www.google.com/search?q=" 
  . $trimmed . "\" target=\"_blank\" title=\"Look up 
  " . $trimmed . " on Google\">Click here</a> to try the 
  search on Google</p>";
  }

// next determine if s has been passed to script, if not use 0
  if (empty($s)) {
  $s=0;
  }

// get results
  $query .= " limit $s,$limit";
  $result = mysql_query($query) or die("Couldn't execute query");

// display what the person searched for
echo "<p>You searched for: &quot;" . $var . "&quot;</p>";

// begin to show results set
echo "Results";
$count = 1 + $s ;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {
  $title = $row["FirstName"];

  echo "$count.)&nbsp;$title" ;
  $count++ ;
  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print "&nbsp;<a href=\"$PHP_SELF?s=$prevs&q=$var\">&lt;&lt; 
  Prev 10</a>&nbsp&nbsp;";
  }

// calculate number of pages needing links
  $pages=intval($numrows/$limit);

// $pages now contains int of pages needed unless there is a remainder from division

  if ($numrows%$limit) {
  // has remainder so add one page
  $pages++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {

  // not last page so give NEXT link
  $news=$s+$limit;

  echo "&nbsp;<a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 &gt;&gt;</a>";
  }

$a = $s + ($limit) ;
  if ($a > $numrows) { $a = $numrows ; }
  $b = $s + 1 ;
  echo "<p>Showing results $b to $a of $numrows</p>";
  
?>


As you can see, it's pretty simple and it's got very nice explanations of what everything does. But when I try it, I get this.

Quote

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in D:\Program Files\xampp\xampp\htdocs\search.php on line 36
Results

Sorry, your search: "Ella" returned zero results

Click here to try the search on Google
Couldn't execute query


I'm pretty much stuck. Any ideas what that error means? And yes, there is a entry with the name of Ella in the people table of the database.

Help? 

Hello, so i made table with Tags row which is Text(126).. and idea is to put text like "PHP, MySQL, Forum, Blog" etc etc... I have problem searching tags my search code:

$requestedtag = $con->real_escape_string($_GET['tag']);

$sql = "SELECT * FROM images WHERE tags = '$requestedtag' ORDER BY ID DESC LIMIT 12";
		$result = $con->query($sql);

		if ($result->num_rows > 0) 
		{
		    while($row = $result->fetch_assoc()) {
		    	$image_id = $row["ID"];
		    	$image_title = $row["Title"];
		    	$image_url = $row["ImgURL"];
		    	$image_tags = $row["Tags"];
		    	echo '<div class="col-3"><div class="thumb"><a href="/image.php?id='.$image_id.'" title="'.$image_title.'"><img src="'.$image_url.'"></img></a></div></div>';
			}
		}

But it doesnt return anything. I think the problem is that row["Tags"]; is divided by "," from tags and i should split it somehow but i dont really know what to do...

I am using ajax live search to retrieve data from MySQL table. It works fine. However I noticed that it only returns a single result that matches the entire word instead of multiple results that match only the first couple letters.

For e.g.

DB Table

----------------

1. Foot

2. Foot Path

3. Football

----------------

If I type "foo" in the ajax search field, it won't return any results. But if I type "foot", it'll return "Foot". It won't return the other two results that contain the letters "Foot".

Here's my query

$param_term = $_POST["term"] . '%';

$get_data = $db->prepare("SELECT name FROM table WHERE title LIKE :param");
$get_data->bindParam(':param', $param_term);
$get_data->execute();

 

I was wondering how can I improve the above query so that it looks for all potential results based on partial matching of letters?