PHP - Not Pulling Data From Table, Just Field Names

This is my first real jump into PHP, I created a small script a few years ago but have not touched it since (or any other programming for that matter), so I'm not sure how to start this.

I need a script that I can run once a day through cron and take the date from one table/filed and insert it into a different table/field, converting the human readable date to a Unix date.

Table Name: Ads
Field: endtime_value (human readable date)

to

Table Name: Node
Field: auto_expire (Converted to Unix time)

Both use a field named "nid" as the key field, so the fields should match each nid field from one table to the next.  Following a tutorial I have been able to insert into a field certain data, but I don't know how to do it so the nid's match and how to convert the human readable date to Unix time.  Thanks in advance!.

Hi all.  I've got a little function to generate a simple form depending on the input.  What I'd like to do is alias the field names that get output to make them a little more human readable.  However, I'm not entirely sure how to do that with the output that I get.

The function....
function build_form($table_name){
$result=mysql_query("SELECT * FROM $table_name");
$num=mysql_num_rows($result);
$i=1;
echo "<table>";
while ($i < mysql_num_fields($result)) {
$fields=mysql_fetch_field($result,$i);
echo "<tr><td>" . $fields->name . "</td><td><input type=\"text\" size=\"30\" name=\"" . $fields->name . "\" /></td></tr>";
$i++;
};
echo "</table>";
};

Q:  Where would I have to modify the output from mysql_fetch_field?

My modified function...
function build_form($table_name){
$result=mysql_query("SELECT * FROM $table_name");
$num=mysql_num_rows($result);
$i=1;
echo "<table>";
while ($i < mysql_num_fields($result)) {
$fields=mysql_fetch_field($result,$i);
                $field_name=str_replace("_"," ",$fields->name);
echo "<tr><td>" . $field_name . "</td><td><input type=\"text\" size=\"30\" name=\"" . $field_name . "\" /></td></tr>";
$i++;
};
echo "</table>";
};

Not sure if that will work, but am I heading in the right direction?  Any help is much appreciated!

Hi.

The idea:

I want to pull a client record and simply place all the row columns into editable form field text boxes. Once the user reviews and edits a submit button will update the record.

What I have:

Code: [Select]
$Query01 = "SELECT * FROM `CustomerSignups`
WHERE `Id` = '$_GET[Id]'";
$Result01 = mysql_query($Query01) or die("Error 01: " . mysql_error());

while ($get_info = mysql_fetch_row($Result01))
{
foreach ($get_info as $field)
echo "<p>$field</p>";

It displays as expected, a line for each field.

How can I get this to pull the field names also and then I can use those as text box input fields...?

I need to update a particular table and there be a whole lot of field names. I'd like to do it without having to use them the same way you can access then like $row[12] after a "select" query. The standard for updating (at least how I write it) goes like this ...
Code: [Select]
$query = "UPDATE linguistics SET welcome1='$var3', welcome2='$var4' WHERE language = '$lengua'";
Well, I'd like to do it where I don't have to name welcome1 and welcome2, but instead refer to their numerical position within the database. On a "select" query we can do this. Can this be done on an update? Something perhaps like ...
Code: [Select]
$query = "UPDATE linguistics SET 3='$var3', 4='$var4' WHERE language = '$lengua'";
... where 3 and 4 represent the 4th and 5th fields respectively. I know that this particular phrasing doesn't work because I've tried it, but surely there has to be something. This will save me LOTS of time. Thanks!!

I have the following mysql query:
Code: [Select]
        $lead_query=$this->db->query("
   SELECT `first_name`, `last_name` , `state` FROM leads WHERE `lead_id`='$lead_id'
   ");
   $this->view->lead_query=$lead_query->fetchALL();
Now when I retrieve the above details  I need to return the first_name last_name together(separated as space) and the name of the key as client_name in the array.

I need it that way because when i return a json_encode($lead_query), I want to return the first_name.last_name as client_name.

I currently have php code that outputs information from my database, but how do i make it also display the name of the fields beside each entry of the database?

heres my PHP code:
Code: [Select]
<?php

$server = "";      // Enter your MYSQL server name/address between quotes
$username = "";    // Your MYSQL username between quotes
$password = "";    // Your MYSQL password between quotes
$database = "";    // Your MYSQL database between quotes

$con = mysql_connect($server, $username, $password);       // Connect to the database
if(!$con) { die('Could not connect: ' . mysql_error()); }  // If connection failed, stop and display error
mysql_select_db($database, $con);  // Select database to use
// Query database
$result = mysql_query("SELECT * FROM Properties");

if (!$result)
{
    echo "Error running query:<br>";
    trigger_error(mysql_error());
}
elseif(!mysql_num_rows($result))
{
    // no records found by query.
    echo "No records found";
}
else
{
    $i = 0;
    echo '<div style="font-family:helvetica; font-size:15px; padding-left:15px; padding-top:20px;">';
    while($row = mysql_fetch_array($result)) {     // Loop through results
        $i++;
         echo '<img class="image1" src="'. $row['images'] .'" />';   //image
        echo "Displaying record $i<br>\n";
        echo "<b>" . $row['id'] . "</b><br>\n";      // Where 'id' is the column/field title in the database
        echo $row['Location'] . "<br>\n";            // Where 'location' is the column/field title in the database
        echo $row['Property_type'] . "<br>\n";       // as above
        echo $row['Number_of_bedrooms'] . "<br>\n";  // ..
        echo $row['Purchase_type'] . "<br>\n";       // ..
        echo $row['Price_range'] . "<br>\n";         // ..
    }
echo '</div>';
}

mysql_close($con);  // Close the connection to the database after results, not before.
?>



thanks in advance

Hi all.

The title pretty much says it all.  I really have no idea if this is even possible or where to start.  A recent dilemma caused me to have to change a field name with some spaces in it.  I have a database with ~65 tables, a majority of which were converted from Access.  So I'm curious as to how many others have bad field names.  Is there a way to use PHP to go through all the field names in a database and remove spaces?

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=318312.0

Good evening,

This has been bugging me for 24 hours now. I have created 2 web applications. The first one is the dummy, and the second one is the final. Basically, this two web applications does the same, just a few modifications made on the final one. I have a process of pulling out of information from the database should the user would want to modify a field. I have a problem though, the dummy one works perfectly, but the new one don't. In fact, if I use the dummy php file together with the new files, the dummy won't be working. But if I use it together with the old files, it works perfectly fine.

This is the error I am getting:


Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\xampp\htdocs\invent-asia\edit_client.php on line 46

<?php
include("dbconnection.php");

if(isset($_POST["btnSubmit"]))
{
$id = $_POST["id"];
$territory = $_POST["territory"];
$job_title = $_POST["job_title"];
$area_of_work = $_POST["area_of_work"];
$employer = $_POST["employer"];
$location = $_POST["location"];
$job_title = $_POST["job_title"];
$date_posted = $_POST["date_posted"];
$closing_date = $_POST["closing_date"];
$department = $_POST["department"];
$gender = $_POST["gender"];
$first_name = $_POST["first_name"];
$last_name = $_POST["last_name"];
$title = $_POST["title"];
$telephone = $_POST["telephone"];
$address_1 = $_POST["address_1"];
$address_2 = $_POST["address_2"];
$address_3 = $_POST["address_3"];
$country = $_POST["country"];
$city = $_POST["city"];
$postal_code = $_POST["postal_code"];
$website = $_POST["website"];
$email_address = $_POST["email_address"];
$comment_by_cg = $_POST["comment_by_cg"];
$date_emailed = $_POST["date_emailed"];
$mailing_comments = $_POST["mailing_comments"];
$telesales_comments = $_POST["telesales_comments"];

$query = "UPDATE contacts SET territory= '".$territory."', job_title = '".$job_title."', area_of_work = '".$area_of_work."', employer = '".$employer."', location = '".$location."', job_title = '".$job_title."', employer = '".$employer."', date_posted = '".$date_posted."', department = '".$department."', closing_date = '".$closing_date."', gender = '".$gender."', first_name = '".$first_name."', last_name = '".$last_name."', title = '".$title."', telephone = '".$telephone."', address_1 = '".$address_1."', address_2 = '".$address_2."', address_3 = '".$address_3."', country = '".$country."', city = '".$city."', postal_code = '".$postal_code."', website = '".$website."', email_address = '".$email_address."', comment_by_cg = '".$comment_by_cg."', date_emailed = '".$date_emailed."', mailing_comments = '".$mailing_comments."', telesales_comments = '".$telesales_comments."' WHERE id = '".$id."'";
mysql_query($query) or die(mysql_error());

echo "<script>
alert('You have successfully updated a record');
window.location = 'view.php';
</script>";
}

$query = "SELECT * FROM contacts WHERE id = '".$_GET["id"]."'";
$result = mysql_query($query, $connection);

if(mysql_num_rows($result) > 0) - THIS IS THE 46th LINE IN THE CODE
{
$territory = mysql_result($result,0, "territory");
$job_title = mysql_result($result, 0, "job_title");
$area_of_work = mysql_result($result, 0, "area_of_work");
$employer = mysql_result($result, 0, "employer");
$status = mysql_result($result, 0, "status");
$location = mysql_result($result,0, "location");
$department = mysql_result($result,0, "department");
$date_posted = mysql_result($result,0, "date_posted");
$closing_date = mysql_result($result,0, "closing_date");
$gender = mysql_result($result,0, "gender");
$first_name = mysql_result($result,0, "first_name");
$last_name = mysql_result($result,0, "last_name");
$title = mysql_result($result,0, "title");
$telephone = mysql_result($result,0, "telephone");
$address_1 = mysql_result($result,0, "address_1");
$address_2 = mysql_result($result,0, "address_2");
$address_3 = mysql_result($result,0, "address_3");
$city = mysql_result($result,0, "city");
$country = mysql_result($result,0, "country");
$postal_code = mysql_result($result,0, "postal_code");
$website = mysql_result($result,0, "website");
$email_address = mysql_result($result,0, "email_address");
$comment_by_cg = mysql_result($result,0, "comment_by_cg");
$date_emailed = mysql_result($result,0, "date_emailed");
$mailing_comments = mysql_result($result,0, "mailing_comments");
$telesales_comments = mysql_result($result,0, "telesales_comments");
}
?>

Can anyone help me solve this issue? This is the only feature in my project that is left bugged

Your quick response is well appreciated. Thank you very much

Code: [Select]
id: 20 Reason: this is a test
id: 21 Reason: Tests
id: 22 Reason: Lolcatz
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: Reason:
id: 36 Reason: Test
As you can see on the 2nd code box there are id's 20,21,22 and 36 in the database the rest are not active in the database.

i am using using Code: [Select]
for to pull out the id that starts with the lowest value in the database, and only have it run until it gets to the maximum value.
Code: [Select]
for ($id=$set_min; $set_max<=7; $id++)
{
                // $id=$set_min is pulling the smallest value and $set_max is pulling the maximum value so it stops  after it gets to 36
$query=mysql_query("SELECT * FROM posted WHERE id = $id");
$query_row=mysql_fetch_array($query);

$reason = $query_row[reason];
$pulled_id = $query_row[id];
$pulled_pic22 = $query_row[picture];
$href_pull = "<a href=" . "search.php?id=" . "$id" .">";

echo "<td>" . $href_pull . "<img src=$pulled_pic22 height=200 width=150 />" . "</td>";
}

how would i make it so i do not pull the values 23-35 which are not in the active database.

Example: http://dev.hackmuch.com/of-the-day/search.php?id=36

FOr some reason i cant pull data from an XML file to insert into the database, it works without error just adds a blank value in the database?

i have this code at the moment, i guess arrayValue[71] is the value i need to pull and add to the "TABLE2" table, but when i run the script it just adds a blank value in the database?


<?php
include "connect.php";

//Price check Isle 9001! Query EVE-Central API. Example XML file is: http://api.eve-central.com/api/marketstat?typeid=35&regionlimit=10000002
$queryItemList = mysql_query("SELECT * FROM TABLE2;") or die(mysql_error());
$rowCount = mysql_num_rows($queryItemList);
$s=0;
$typeArray = array();
$region = "regionlimit=10000002";
while($s<$rowCount){

$typeID = mysql_result($queryItemList,$s,"typeID");

echo $typeID."<br />";

//echo "start<br />";

$reader = new XMLReader();

//echo "initialized XMLReader<br />";

$url = "http://api.eve-central.com/api/marketstat?typeid=".$typeID;

echo $url.$region."<br />";

$reader->open($url.'&'.$region);

$t=0;

$arrayName = array();

$arrayValue

 = array();

while ($reader->read()) {

//echo $reader->name;

$name = $reader->name;

$arrayName[$t] = $name;

if ($reader->hasValue) {

//echo ": " . $reader->value."<br />";

$value = $reader->value;

$arrayValue[$t] = $value;

}

$t++;

}

echo $arrayValue[71];

$import="UPDATE TABLE2 SET marketPrice='$arrayValue[71]' WHERE typeID='$typeID';";

mysql_query($import) or die(mysql_error());

$s++;;
}
print_r($typeArray);

/*print_r($arrayName);
echo "<br />";
echo "<br />";
echo "<br />";
print_r($arrayValue);*/

?>


an example XML file would be:
Code: [Select]
<!--
 Automatically generated data from EVE-Central.com
-->
<!-- This is the new API :-) -->
−
<evec_api version="2.0" method="marketstat_xml">
−
<marketstat>
−
<type id="24692">
−
<all>
<volume>4.00</volume>
<avg>152500000.00</avg>
<max>152500000.00</max>
<min>152500000.00</min>
<stddev>0.00</stddev>
<median>152500000.00</median>
<percentile>0.00</percentile>
</all>
−
<buy>
<volume>0.00</volume>
<avg>0.00</avg>
<max>0.00</max>
<min>0.00</min>
<stddev>0.00</stddev>
<median>0.00</median>
<percentile>0.00</percentile>
</buy>
−
<sell>
<volume>4.00</volume>
<avg>152500000.00</avg>
<max>152500000.00</max>
<min>152500000.00</min>
<stddev>0.00</stddev>
<median>152500000.00</median>
<percentile>152500000.00</percentile>
</sell>
</type>
</marketstat>
</evec_api>

im looking at pulling the following value from the <sell> section:
Code: [Select]
<median>152500000.00</median>
i am guessing the above should be arrayValue[71] but for some reason its not picking it up.

any help on this would be greatly appreciated as im lost in this script.

I am pulling records from a mysql db.   

Example Output:

Team A=  Our Team
Team b = An opponent team
Team A score = 7
Team B score = 8

Team A = Our Team
Team b = Another Opponent
Team A score = 3
Team B score = 1


What I need now is to add ONE more output, which is whether this is a "WIN" or a "LOSS".

Should I add a field into the table that calc's this?    If so, how?   Please be specific.

Or, should I use php to compare Team A score vs Team B score PER every record and then insert this new variable into the output.    If so, how do I create a new variable value for every single output in the table?


I know ultimately that this is a IF THEN type of calc, but can't quite figure out how specifically.   

Please be specific.

Thanks

Hi all,

I have the following MySQL insert query:
Code: [Select]
$insert= mysql_query   ("INSERT INTO tablename (column1,`".$EXPfields."`) VALUES ('$something','".$EXPvalues."')");
where $EXPfields is an array of table-field-names and $EXPvalues is an array of table-field-values.

Now I want to write an equivalent query, but using UPDATE instead of INSERT INTO, but I don't want to write out all the field names/values separately, but again want to use $EXPfields and $EXPvalues.

So something like this:
Code: [Select]
$update = mysql_query ("UPDATE tablename
                     SET (column1,`".$EXPfields."`) = ('$something','".$EXPvalues."')
                     WHERE ....
                  ");

Is this possible? If so, what is the proper syntax? Thanks!

Ok I have a fairly straight forward question. I am designing a baseball website and I am trying to add in a schedule, here is what I have:

Data Bases
1) Teams DB - Each team has a unique team ID, location, logo, and owner
2) Schedule DB - Each game has a unique game ID, and the schedule is set up like this: AWAY = Team ID, HOME = Team ID....

So I assume I am using the JOIN command to pull the schedule from both databases, any idea how the SQL command would look?