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PHP - If Is File Print All Others
Hello guys and gals, I am pretty green to PHP! I have an empty array that that I am trying to put images into. The thing is I have a certain file name in the folder, I want to exclude that file. This is what I have tried, any advice would be appreciated!
Code: [Select] $thumbImg[] = array(); foreach (glob($DImg) as $PImg) { if (!is_file("thumbnail.jpg")) { $thumbImg[] = "<img src=\"pathtoimage\">"; } } Later on the page I am printing it out with this. It is still including the thumbnail.jpg image. Thank you in advance!! Code: [Select] for ($i=0; $i<count($thumbImg); $i++) print $thumbImg[$i]; Similar TutorialsAnyone know how I can print a file (specifically a PDF) that is stored on the server to the clients computer with a button? I don't want them to be able to view it, just print it. I've done some research and understand that there is no way to print directly without popping up the Windows Print dialog. And that is fine. I just want them to print this file, but not no where it is or be able to type in a URL to access it. Thanks Mike Hello, What im trying to do is create a file with the name "triangular_10.txt" where the number in the file name is the number the user entered. From there I want the text file to have the triangular series of numbers. So if the user enters 10, it'll display the first 10 numbers of the triangular series. So far the file name change is working. The algorithm is here that I used for PHP:http://www.codecodex.com/wiki/Calculate_a_triangle_number eg . user enters 10. Result in txt file is first 10 numbers in the triangular series = [1, 3, 6, 10, 15, 21, 28, 36, 45] This is what I have so far but Im not having any luck! At the moment its only writing the number I entered on to the txt file and nothing else! Any ideas?
$number = $_POST['number-entered'];
foreach ( range(1, 1000) as $i ) {
$triangle_numbers[] = $i * ( $i + 1 ) / 2;
}
//make a file
$contents = fopen('gs://a1-task22020.appspot.com/triangular_' .$number. ".txt", "w");
fwrite($contents, $number);
//open the file
$contents = fopen('gs://a1-task22020.appspot.com/' . $contents, 'w');
// re-open the document if you put something in it
fwrite($contents, $number);
fclose($contents);
}
}
hi, whats the best way to print labels. I have already tried the script from fpdf.de but i can not get my dot matrix printer (dot matrix is needed for this purpose) the correct layout. Its continuous paper, with size 110 height x 62mm width (for each label). I am not able to select a self-adjustable paper-size. so i hope to solve this with PHP / PDF if possible. anyone have experience with this? cheerz!! is there a way to print the file as it appears. I want to print the HTML and PHP within a file rather than just the output. Example: File contains: <?php echo "Hello World"; ?> i would like to echo: <?php echo "Hello World"; ?> instead of just hello world which is what i get with file_get_contents() Hello, I have the following code writting IP,session, and date to a text file (it works) but I want to add a white space after the IP address. fwrite($fp, $_SERVER['REMOTE_ADDR']. $_SESSION["sess_name"]. " $dateTime\r\n"); At the moment it prints like this 16.17.51.41SESSION_ID 2011/01/23 12:53:32 thanks in advance. Hello, How to customize print page in php ? I had a page, but I need to print it like an invoice look page. Thanks in advance Hello.
i am totally new to php and just started to learn now. i just dont understand why the following code is not printing the username that i enter on the page.
Please note that the code itself is saved with the name "basicForm.php".
Thanks.
<html> Code: [Select] $query ="SELECT oneID FROM table WHERE table.PersonID = 'game.PlayerA'" ; $result = mysql_query($query); $row = mysql_fetch_array($result); $oneID = $row[0]; [code] If I then echo "$oneID" why does it not print anything? $result echos resource7 I currently have a search page on my site that prints the products but it prints the products more than once if its in more than one category I have tried getting distinct item in my SQL. But this doesnt work so im trying an if statement that if there is more than one specific result then to just print this once. I was wondering if anyone had any ideas of how to do this using an if statement I just dont know how to go about just printing the result just once if its greater than 1. The code is below to make it clearer. $searchterm = $_POST['searchterm']; trim ($searchterm); /*check if search term was entered*/ if (!$searchterm){ echo 'Please enter a search term.'; echo $searchterm; } /*add slashes to search term*/ if (!get_magic_quotes_gpc()) { $searchterm = addslashes($searchterm); } /*query the database*/ $query = "SELECT * from (products LEFT JOIN categories_products_link ON products.prod_id = categories_products_link.prod_id) LEFT JOIN categories ON categories_products_link.cat_id = categories.cat_id WHERE prod_title LIKE '%" . $searchterm . "%' ORDER BY cat_title, prod_title"; $result = mysql_query($query); /*number of rows found*/ $num_results = mysql_num_rows($result); echo '<p><h1>Search Results: '.$num_results.'</h1></p><br />'; /*loops through results*/ for ($i=0; $i <$num_results; $i++) { $num_found = $i + 1; $row = mysql_fetch_assoc($result); echo "$num_found. "?><a href="store-<?php echo $row['cat_id'];?>-<?php echo $row['prod_id']; ?>/<?php echo seo_makeSafeURI($row['prod_title']); ?>.html"><strong><?php echo $row['prod_title']; ?></strong></a> <br /> This topic has been moved to Installation in Windows. http://www.phpfreaks.com/forums/index.php?topic=351150.0 Hi I have this code to echo th econtents of a table, which contains 100 rows. I want to be able to display all 100 rows. The problem is that it displays 99 (it excludes the first). I've tried to backtrack to reconstruct the code to find out where the error is but no joy. Any ideas? Thanks in advance! Code: [Select] .... // get all entries from table $sql = "SELECT * FROM 100words ORDER BY word_id"; $result = mysqli_query($dbc, $sql); $r = mysqli_fetch_row($result); //print table entries to screen in columns echo '<div id="container">'; // results presented in html table 5 columns, 20 rows per page echo '<div id="outerbox">'; echo '<div class="innerbox">'; echo '<table class="centerresults" border="0">' . "\n"; echo '<td>'; $i = 0; $max_columns = 5; while ($list = mysqli_fetch_assoc($result)) { extract($list); // open row if counter is zero if($i == 0) echo '<tr>' . "\n"; echo '<td width="150px"><a href="word.php?w=' . $list['word'] . '">' . $list['word'] . "</a></td> \n "; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo '</td>' . "\n"; $i=0; } // END if(++$i == $max_columns) { } // END while (!empty($myArray)) { //} END while ($list = mysql_fetch_array($result)) { //END if($i < $max_columns) { echo '</tr>' . "\n"; echo '</table>' . "\n"; echo '</div>'; echo '</div>'; I'm working on a site where I've implemented a simple back end wysiwyg editor for content on a page. Then on the public page I run a php query to pull that content and display it. But doing this cancels out the css I have been using to split content into two columns. Is there a way to do this in php, or is there a way to circumvent the problem? ( also tried echoing the entire css style along with the query result - that didn't work either) The <p id='container_sub'> is what is split into two columns. I tried it outside of the query, and inside the query around where I echo results. Neither worked. Here's the basic php code, and further down the css that makes two columns: Code: [Select] <?php $pageid = '2'; // Formulate Query // This is the best way to perform an SQL query // For more examples, see mysql_real_escape_string() $query = sprintf("SELECT content FROM tbl_pages WHERE page_id='%s'", mysql_real_escape_string($pageid)); // Perform Query $result = mysql_query($query); // Check result // This shows the actual query sent to MySQL, and the error. Useful for debugging. if (!$result) { $message = 'Invalid query: ' . mysql_error() . "\n"; $message .= 'Whole query: ' . $query; die($message); } // Use result // Attempting to print $result won't allow access to information in the resource // One of the mysql result functions must be used // See also mysql_result(), mysql_fetch_array(), mysql_fetch_row(), etc. while ($row = mysql_fetch_assoc($result)) { echo "<p id='container_sub'>".$row['content']."</p>"; } // Free the resources associated with the result set // This is done automatically at the end of the script mysql_free_result($result); ?> The css.... Code: [Select] #container_sub {-moz-column-count: 2; -moz-column-gap: 25px; -webkit-column-count: 2; -webkit-column-gap: 20px; column-count: 2; column-gap: 20px;} #container_sub2 {-moz-column-count: 2; -moz-column-gap: 25px; -webkit-column-count: 2; -webkit-column-gap: 20px; column-count: 2; column-gap: 20px;} Probably a simple solution, just one I'm not sure how to do it. I need the array to print out like this Code: [Select] array( 'name'=>'Store 1', 'address'=>'LA1' ), Right now, I got it to look like this Thanks in advance Code: [Select] Array ( [name] => 'Albertville Farmers Market', [address] => '116 Main Street Albertville, Alabama 35950' ) , Array ( [name] => 'Alexander City Downtown Market', [address] => 'Braod Street Alexander City, Alabama 35010' ) , How can I go about accomplishing this? Here is my code Code: [Select] $stores = array('name'=>"'$MktName',",'address'=>"'$address'"); echo "<pre>"; print_r($stores); echo "</pre>"; Hi, I am trying to get the form field to echo a php variable. The problem is that the form is 'Printed' via php. print "<td width=\"300\" valign=\"top\"><input type=\"text\" name=\"usr\" value=\"i.e. JBloggs \" onfocus=\"if(!this._haschanged){this.value=''};this._haschanged=true;\" tabindex=\"1\"></td>"; Instead of the value being i.e. JBloggs have it echo the $name variable. Any input would be appreciated. Hi all this might be a bit of a novice question, but if anyone knows the following i would be pleased and my eyes will too I am looking for a way to print on paper or pdf (en print the pdf in the end) all the stringfunctions on php.net (http://www.php.net/manual/en/ref.strings.php) If anyone knows a way to do so i would love to hear it, because after a few days behind a computer my eyes are about to go on strike. Hi, What is the best way to print the local date and time, my website have customers from 4 or 5 countries. Saudi - UTC+3 Dubai - UTC+4 India - UTC+5.30 how to print the local time for them Thanks, print("<form name='form1' method='post' action='create-b.php' enctype='application/x-www-form-urlencoded' style='margin:0px'> <input type='hidden' name='time' value='werwRG/443gooa22a04c0c2d46c802cc7e3b262398852$glg/WE?F'> <input name='name' value='Anonymous' type='text' MAXLENGTH='15' style='position:absolute;width:650px;left:67px;top:142px;z-index:11'> <input name='subject' value='(No subject)' MAXLENGTH='15' type='text' style='position:absolute;width:650px;left:67px;top:166px;z-index:11'> <textarea name='body' MAXLENGTH='255' type='text' style='position:absolute;left:67px;top:191px;width:650px;height:98px;z-index:11'></textarea> <input name='submit' type='submit' value='Create thread' style='position:absolute;left:614px;top:291px;z-index:11'> <div id='captcha' style='position:absolute; overflow:hidden; left:10px; top:296px; z-index:10'> require_once('captc/recaptchalib.php'); $publickey = '*******************************************'; echo recaptcha_get_html($publickey); </form> </div>"); How can I make the highlighted text be read as PHP and not just text? It has to be in the form tags... before you reply saying you forgot the php tags, no i didn't. I can't use php tags inside php tags... Im trying to print several image url's and names from an sql database into 3 columns, Aiming to get it to go 1,2,3 4,5,6 7,8,9 etc etc. but for some reason myne is going 1,3,5 2,4,6 etc. Dont bother mentioning that my loops do nothing, i realised that about 10 minutes ago, Any help would be appreciated. <?php include 'config.php'; mysql_connect($host, $user, $pass) or die(mysql_error()); mysql_select_db($database) or die(mysql_error()); $result = mysql_query("SELECT * FROM tracks"); echo '<div id="left_wrapper">'; for ($i=0;$i<mysql_num_rows($result);$i+=3) { $row = mysql_fetch_array($result); $id = $row['id'] + 1; echo "<img src='Thumbnails/" . $id .".gif'></img><br>"; echo $row['name']. "<br>"; } echo "</div>"; echo '<div id="middle_wrapper">'; for ($i=1;$i<mysql_num_rows($result);$i+=3) { $row = mysql_fetch_array($result); $id = $row['id'] + 1; echo "<img src='Thumbnails/" . $id .".gif'></img><br>"; echo $row['name']. "<br>"; } echo "</div>"; echo '<div id="right_wrapper">'; for ($i=2;$i<mysql_num_rows($result);$i+=3) { $row = mysql_fetch_array($result); $id = $row['id'] + 1; echo "<img src='Thumbnails/" . $id .".gif'></img><br>"; echo $row['name']. "<br>"; } echo "</div>"; ?> i know each of those loops does nothing, But you can see where they are meant to do, Each div is aligned to different positions, first loop is left, 2nd is center, 3rd is right. Hi Guys I want to knw if its possible to send job to print with php. example, in my database I have a table called Letters which stores letters, while I loop through the table, I want to print each letter off, any examples available? Thank you |
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