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PHP - Shortcut Back To The Web Public Folder?
../ tells the php program to go up a level.
Code: [Select] require_once '../directory/somefile.php'; Is there a shortcut to go to the public web folder? For example. The following file is placed 3 folders deep: "var/www/deep/deeper/verydeep/index.php" and it requires a file with location: "var/www/thisfile.php" I there a short cut/ quicker method to?? Code: [Select] require_once '../../../thisfile.php'; Similar TutorialsI have searched around and found this code that suggests that I should be able to read an image file and echo it directly in to the page without hyperlinking to the file that is outside the public folder, but i get the error message that it is not there even though the file is. Warning: getimagesize() [function.getimagesize]: Unable to access "/home/****/upload/AAABBBCCC.JPG" in /home/****/public_html/client.php on line 40 Code: [Select] $image = "AAABBBCCC.JPG"; $path= "/home/****/upload/"; $details = getimagesize($path . $image); header ('Content-Type: ' . $details['mime']); echo file_get_contents($path . $image); edited: please note all wmv files are not more than 10 or 20 seconds long. also their size is no more than 500kb. I have this following code that works for photos, but wish to alter this slightly so it will work for video files (wmv) getFtpImage.php Code: [Select] <? header('Content-Type: image/jpg'); $imgdir = '/home/mysite/ftpfolder'; readfile($imgdir . '/' . $_GET['file']); ?> index.php Code: [Select] $imgdir = '/home/mysite/ftpfolder'; // the directory, where your images are stored $allowed_types = array('png','jpg','jpeg','gif'); // list of filetypes you want to show $dimg = opendir($imgdir); while($imgfile = readdir($dimg)) { if(in_array(strtolower(substr($imgfile,-3)),$allowed_types)) { $a_img[] = $imgfile; sort($a_img); reset ($a_img); } } $totimg = count($a_img); // total image number for($x=0; $x < $totimg; $x++) { $size = getimagesize($imgdir.'/'.$a_img[$x]); // do whatever $halfwidth = ceil($size[0]/2); $halfheight = ceil($size[1]/2); ?><img src="getFtpImage.php?file=<? echo ($a_img[$x]); ?>" height="180"><? // echo 'name: '.$a_img[$x].' width: '.$size[0].' height: '.$size[1].'<br />'; } i have the images show to fill the screen and wish for the video page to do the same and with the videos you click the [play] in the center of the video image to play it like most videos play, not like the flash. Hi.. I've seen code for back up database but when I run the code the database was backup outside the folder. I want to put the back up database inside the folder here is the code: Code: [Select] <?php include 'config.php'; backup_tables('localhost','root','','payroll'); /* backup the db OR just a table */ function backup_tables($host,$user,$pass,$name,$tables = '*') { $link = mysql_connect($host,$user,$pass); mysql_select_db($name,$link); //get all of the tables if($tables == '*') { $tables = array(); $result = mysql_query('SHOW TABLES'); while($row = mysql_fetch_row($result)) { $tables[] = $row[0]; } } else { $tables = is_array($tables) ? $tables : explode(',',$tables); } //cycle through foreach($tables as $table) { $result = mysql_query('SELECT * FROM '.$table); $num_fields = mysql_num_fields($result); $return.= 'DROP TABLE '.$table.';'; $row2 = mysql_fetch_row(mysql_query('SHOW CREATE TABLE '.$table)); $return.= "\n\n".$row2[1].";\n\n"; for ($i = 0; $i < $num_fields; $i++) { while($row = mysql_fetch_row($result)) { $return.= 'INSERT INTO '.$table.' VALUES('; for($j=0; $j<$num_fields; $j++) { $row[$j] = addslashes($row[$j]); $row[$j] = ereg_replace("\n","\\n",$row[$j]); if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; } if ($j<($num_fields-1)) { $return.= ','; } } $return.= ");\n"; } } $return.="\n\n\n"; } //save file $myfoldername = "backup_DBPayroll";//your folders name $handle = fopen(getcwd().$myfoldername.'db-backup-'.time().'-'.(md5(implode(',',$tables))).'.sql','w+'); // $handle = fopen('db-backup-'.date('m-d-Y').'-'.(md5(implode(',',$tables))).'.sql','w+'); fwrite($handle,$return); fclose($handle); } $smarty->display('header_cat.tpl'); $smarty->display('backup.tpl'); $smarty->display('footer.tpl'); ?> Thank you in advance How can I call a public function inside of another public function? The get_primary_edge() says it's undefined, but it's just another public function in the class so shouldn't this work? Code: [Select] public function get_dynamic_edge($uid) { $uid = (int)$uid; $sql = "( SELECT `users`.`id` FROM partners INNER JOIN `users` ON `partners`.`user_id` = `users`.`id` WHERE partners.friend_id = '${uid}' AND `approved` = 1 ) UNION ALL ( SELECT `users`.`id` FROM `partners` INNER JOIN `users` ON `partners`.`friend_id` = `users`.`id` WHERE `partners`.`user_id` = '${uid}' AND `approved` = 1 )"; $result = mysql_query($sql) or die(mysql_error()); $i = 0; while (($row = mysql_fetch_assoc($result)) !== false) { $dynamic[$i] = array( 'uid' => $row['id'], 'score' => get_primary_edge($row['id']), ); $i++; } print_array($dynamic); } This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=334031.0 I got this script: But it give me error, file_get_contents cannot open stream. I need to add the FTP connection with user/pass paramaters. then look in set http url, to get the file contents(images) and transfer to ftp server location. Can Anyone take alook and tell me if I am going down the right path and how to get there. Please Code: [Select] function postToHost($host, $port, $path, $postdata = array(), $filedata = array()) { $data = ""; $boundary = "---------------------".substr(md5(rand(0,32000)),0,10); $fp = fsockopen($host, $port); fputs($fp, "POST $path HTTP/1.0\n"); fputs($fp, "Host: $host\n"); fputs($fp, "Content-type: multipart/form-data; boundary=".$boundary."\n"); // Ab dieser Stelle sammeln wir erstmal alle Daten in einem String // Sammeln der POST Daten foreach($postdata as $key => $val){ $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n"; } // Sammeln der FILE Daten if($filedata) { $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$filedata['name']."\"; filename=\"".$filedata['name']."\"\n"; $data .= "Content-Type: ".$filedata['type']."\n"; $data .= "Content-Transfer-Encoding: binary\n\n"; $data .= $filedata['data']."\n"; $data .= "--$boundary--\n"; } // Senden aller Informationen fputs($fp, "Content-length: ".strlen($data)."\n\n"); fputs($fp, $data); // Auslesen der Antwort while(!feof($fp)) { $res .= fread($fp, 1); } fclose($fp); return $res; } $postdata = array('var1'=>'today', 'var2'=>'yesterday'); $filedata = array( 'type' => 'image/png', 'data' => file_get_contents('http://xxx/tdr-images/images/mapping/dynamic/deals/spot_map') ); echo '<pre>'.postToHost ("localhost", 80, "/test3.php", $postdata, $filedata).'</pre>'; Please, take a look to the following code.After clicking Next it goes to overview.php.Why when I click back on my browser to return to this page again, it is not returning back? When I click back I receive "Confirm Form Resubmission" message. After refreshing page it loads page. I guess problem is in "session_start();" part. Something to do with cookies. Please, help me it is very urgent for me. <?php session_start(); echo "<html> <head> <title>Hello World</title> <meta http-equiv='Content-Type' content='text/html; charset=Windows-1252'/> </head>"; require_once ('functions.inc'); if(!isset($_POST['userid'])) { echo "<script type='text/javascript'>"; echo "window.location = 'index.php'"; echo "</script>"; exit; }else{ session_register("userid", "userpassword"); $username = auth_user($_POST['userid'], $_POST['userpassword']); if(!$username) { $PHP_SELF = $_SERVER['PHP_SELF']; session_unregister("userid"); session_unregister("userpassword"); echo "Authentication failed " . "Please, write correct username or password. " . "try again "; echo "<A HREF=\"index.php\">Login</A><BR>"; exit; } } function auth_user($userid, $userpassword){ global $default_dbname, $user_tablename; $user_tablename = 'user'; $link_id = db_connect($default_dbname); mysql_select_db("d12826", $link_id); $query = "SELECT username FROM $user_tablename WHERE username = '$userid' AND password = '$userpassword'"; $result = mysql_query($query) or die(mysql_error()); if(!mysql_num_rows($result)){ return 0; }else{ $query_data = mysql_fetch_row($result); return $query_data[0]; } } echo "hello"; echo "<form method='POST' name='myform' action='overview.php'>"; echo "<input type='submit' value='Next'>"; echo "</form>"; ?> I'm learning MVC and getting a bit confused with the accessibility of variables in classes... Code: [Select] class Load { public $load2; } Does this mean that the variable $load2 will be accessible just by all functions within the class Load? or: Does that mean that the variable $load2 will be accessible by all other classes, eg model, controller...etc inc all the functions within? Hi i created a website where you cam view ip webcams via php. I want to make it so people can make the camera private and public. I made two fields in mysql called "Username" and "Puborprivate" I tried to make the "Puborprivate" have two numbers "0" would be private and "1" would be public. How could I do this? My site is cwuforum.com/live/ Hi folks, I had a working, editable profile but it wasn't visible to other users. So I'm trying to make that conversion now. Here's the current 'myprofile' code: <?php session_start(); include('config.php'); include('date.php'); $id = $_GET['id']; $sql = mysql_query("SELECT * FROM members WHERE id = '$id' LIMIT 1"); $check = mysql_num_rows($sql); $check = mysql_query($sql_user_verify) or die('Cannot Execute:'. mysql_error()); if ($check > 1) { echo "No one matches that id number!"; exit(); } if($check == 1) { while($row = mysql_fetch_array($sql)) { $user = $id; echo "<h2>Profile</h2> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name: </th><td>".$row['callname']."</td></tr> <tr><th>Email: </th><td>".$row['email']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr> <tr><th>Registered: </th><td>".$row['registered']."</td></tr> <tr><th>Last Login: </th><td>".$row['lastlogin']."</td></tr>"; echo "</table><br />"; } if($id = $_SESSION['id']) { echo "<h2>Profile</h2> <form method='post' action='editprofile.php'> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name: </th><td>".$row['callname']."</td></tr> <tr><th>Email: </th><td>".$row['email']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr> <tr><th>Registered: </th><td>".$row['registered']."</td></tr> <tr><th>Last Login: </th><td>".$row['lastlogin']."</td></tr>"; echo "</table><br /> <input type='submit' value='edit profile' /> </form>"; } } else { die (); } ?> <?php include('footer.php'); ?> Here's the link to the user's own profile: <a href=myprofile.php?id='.$id.'>Profile</a> And here's the edit profile link, which works fine: <?php include('config.php'); include('date.php'); if(isset($_POST['btnedit'])){ $callname = $_POST['callname']; $email = $_POST['email']; $password = $_POST['password']; $sql = mysql_query( "UPDATE users SET callname='".$callname."', email='".$email."', password='".$password."' WHERE id='".$_SESSION['id']."'" ); if($sql){ echo "<script>alert('profile updated');window.location='myprofile.php'</script>"; }else{ echo "<script>alert('updating profile failed!');</script>"; } } $sql = mysql_query( "SELECT * FROM users WHERE id='".$_SESSION['id']."'" ); $row = mysql_fetch_array($sql); $userfinal = $_SESSION['id']; $user = $userfinal; echo "<h2>Edit profile</h2> <form method='post'> <table><tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name:</th><td><input type='text' name='callname' value='".$row['callname']."'/></td></tr> <tr><th>Email:</th><td><input type='text' name='email' value='".$row['email']."'/></td></tr> <tr><th>Password:</th><td><input type='password' name='password' value='".$row['password']."'/></td></tr> <tr><th>Registered:</th><td>".$row['registered']."</td></tr> <tr><th>Last Login:</th><td>".$row['lastlogin']."</td></tr> </table><br /> <input type='submit' name='btnedit' value='update' /> </form>"; ?> <?php include('footer.php'); ?> It fails, it says the query was empty, even though there are user accounts created and information is being stored (as it worked fine before I tried editing the code to make it public. What am I doing wrong? I have the following static method: public static function query($query){ self::$num_queries++; return mysql_query($query)or die(mysql_error()); } I then call it like this: $oql = Mysql::query("SELECT first FROM members WHERE member_id = '{$this->owner}'"); $rql = mysql_fetch_assoc($oql); I then get the following error: Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /incl/php/classes/Photo.php on line 13 Why am I getting this error? I am modifying someones existing coldfusion web app. I am adding php processing pages to do various tasks. Up to this point I have just been calling the php pages, and interacting with the web app by passing variables via the url. Current usage: Code: [Select] public.cfm calls processing.php?id=69 Then processing will do what it has too, then ultimately: Code: [Select] header("Location: $publichome?id=$id&importantstuff=$stuff"); exit(); And the webapp will pick up where it has too. But now one of my scripts has to send a JSON object back instead of simple variables. I don't know how to get this done. I tried doing a post with cURL but that wasn't working because I need the public facing coldfusion page to take over and curl returns to the php script (I know I can echo the body of the curl result but this keeps me on the php script domain which I dont want). Is there a way to do the above header location and send an object because thats what I need - the php script to stop and the coldfusion page to be served up with the object to work with. Do I have to create some sort of JSON service in php, that the coldfusion page will call an retrieve the result? If so how? <? for ($i = 1; $i <= $first_day_of_month-1; $i++) { $days_so_far = $days_so_far + 1; $count_boxes = $count_boxes + 1; echo "<td width=\"125\" height=\"100\" class=\"beforedayboxes\"></td>\n"; } for ($i = 1; $i <= $days_in_month; $i++) { $days_so_far = $days_so_far + 1; $count_boxes = $count_boxes + 1; IF($_GET['month'] == $todays_month+1){ IF($todays_date == $day){ $class = "publicholidayhighlightedboxes"; } ELSE { $class = "dayboxes"; } } ELSE { IF($i == $todays_date){ $class = "highlighteddayboxes"; } ELSE { $class = "dayboxes"; } } The problem is I can only display one highlighted box in one month. For example, in November, there are two public holidays, but only 1 public holiday box is highlighted. Would appreciate if someone can help me out asap. Thank you This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=316783.0 I am writing a script which will be dependent on the client's public ip address. e.g.
if the client is using ip address 203.122.55.124 script A should run and if else then script B should run. Now I know that the If and else will be used but cant guess how will the public ip be captured.
Please help
I tried these below, Code: [Select] class Site extends Controller { function Site() { public $data = Array(); } } but it fail? Thanks in advanced. Hi, I am making a dating site where I have made the user profile edit page visible to the user when they log in, and I think I can get away with not showing the user their "public" profile view. But I definitely need to show other users on the site the "public" non editing profile page view. But I don't know how to do this. I have yet to create the search, search results, thumbnails with optional descriptions of the possible dating results. But I first want to just get 2 versions of the user profile page view. One that the user sees that I have already done. (The editable one). And the other I need to make which is the page the other users will see, (The public profile) Please if anyone has any idea how to do this I would greatly appreciate it, especially if you have any pseudocode ideas. thank you. Hi, I want to create a simple online buying site. I have an admin site with login where admin can add items to the database table, and change other fields such as price and description of product and I want to make a public html page to display the updates made in my admin page. I appreciate it if someone give me some suggestions on how to get started. My admin php scripts is working fine (so SQL queries for UPDATE, DELETE, INSERT) but I don't know how to 'sync' it with the an nice html table of products the user can checkbox off to purchase on the public website. Let me know, thanks. I want to copy everything in templates/blue to the folder code/ However: shell_exec("cp -r 'templates/blue' 'code'"); Creates a folder called blue inside code. I tried cp -r 'templates/blue/*' 'code', but that didn't do anything. Any ideas? <?php
class Post{
private $user_obj;
private $con;
public function __construct($con, $user){
$this->con = $con;
$this->user_obj = new User($con,$user);
}
public function submitPost($body,$user_to){
$body = strip_tags($body);////Removing HTML TAGS
$body = mysqli_real_escape_string($this->con,$body);
$check_empty = preg_replace('/\s+/', '', $body);//delte all spaces
if($check_empty != ""){
//Current Date and time
$date_added = date("Y-m-d H:i:s");
//get username
$added_by = $this->user_obj->getUsername();
//if user have not a profile send to the none
if($user_to == $added_by){
$user_to = "none";
}
////insert query
$query = mysqli_query($this->con,"INSERT INTO posts VALUES('','$body','$added_by','$user_to','$date_added','no','no','0')");
$retured_id = mysqli_insert_id($this->con);
//insert notification
//Update post count for user
$num_post = $this->user_obj->getNumPosts();
$num_post++;
$update_query = mysqli_query($this->con,"UPDATE users SET num_post = '$num_post' WHERE username = '$added_by'" );
}
public function loadPostsFriends(){
$str = ""; //string to return
$data = mysqli_query($this->con,"SELECT * FROM posts where deleted = 'no' ORDER by id DESC");
while($row = mysqli_fetch_array($data))
{
$id = $row['id'];
$body = $row['body'];
$added_by = $row['added_by'];
$date_time = $row['date_added'];
/// Creating user post on other user profile
if($row['user_to'] == "none"){
user_to = "";
else {
$user_to_obj = new User($con,$row['user_to']);
$user_to_name = $user_to_obj->getFirstandLastname();
$user_to = "to <a href='" . $row['user_to'] . "'>" .$user_to_name . "</a>";
}
// check if user account was closed
$added_by_obj = new User($this->con,$added_by);
if($added_by_obj ->isClosed()){
continue;
}
$user_details_query = mysqli_query($this->con,"SELECT first_name,last_name,profile_pic FROM users where username = '$added_by'");
$user_row = mysqli_fetch_array($user_details_query);
$first_name = $user_row['first_name'];
$last_name = $user_row['last_name'];
$profile_pic= $user_row['profile_pic'];
///time stamp
$date_time_now = date("Y-m-d H:i:s");
$start_date = new Date_Time($date_time);////Time_of_post
$end_date = new Date_Time($date_time_now);///Current_time
$intervel = $start_date->diff($end_date);
if($intervel->y >< 1 ){
if($intervel ==1 )
$time_message = $intervel->y . " year ago";/// 1 Year Ago
else
$time_message = $intervel->y . " years ago"; //1+ year ago
}
else if($intervel-> m >= 1 ){
if($intervel->d == 0){
$days = " ago";
}
else if($intervel->d == 1){
$days = $intervel->d."day ago";
}
else
{
$days = $intervel->d."day ago";
}
if($intervel->m == 1){
$time_message = $intervel->m." month".$days;
}
else
$time_message = $intervel->m." months".$days;
}
}
else if($intervel->d >= 1){
if($intervel->d == 1){
$days = "Yesterday";
}
else
{
$days = $intervel->d."days ago";
}
}
else if($intervel->h >= 1){
if($intervel->h == 1){
$time_message = $intervel->h." hour ago";
}
else
{
$time_message = $intervel->h." hours ago";
}
}
else if($intervel->i >= 1){
if($intervel->i == 1){
$time_message = $intervel->i." minute ago";
}
else
{
$time_message = $intervel->i." minutes ago";
}
}
else{
if($intervel->s < 30){
$time_message = "Just Now";
}
else
{
$time_message = $intervel->s." seconds ago";
}
}
$str .= "<div class='status_post'>
<div calss='post_profile_pic'>
<img src='$profile_pic' width='50'>
</div>
<div calss='posted_by' style='color#ACACAC;'>
<a href = '$added_by'> $first_name $last_name </a> $user_to ; ; $time_message
</div>
<div id = 'post_body'$body<br></div>
</div>
"
}
echo $str;
}
}
?>
When i run this code this show me the error Parse error: syntax error, unexpected 'public' (T_PUBLIC) in C:\xampp\htdocs\social\Classes\Post.php on line 39 the line 39 is public function loadPostsFriends() I check the code again and again but i cant find the error please help in this error |
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