PHP - Moved: Php Mysql Query Select

$var = @$_GET['q'] ;
$trimmed = trim($var);
$table = @$_GET['field'];
$query="SELECT * FROM contacts WHERE @'table' contains @'trimmed' order by id";
$result=mysql_query($query);
$num=mysql_numrows($result);


Why wont this work?

Zacron

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=322629.0

Hi there,

I'm having a problem with updating a record with an UPDATE mysql query and then following that query with a SELECT query to get those values just updated.

This is what I'm trying to do...I'd like a member to be able to complete a recommended task and upon doing so, go to a page in their back office where they can check off that task as "Completed".  This completed task would be recorded in their member record in our database so that when they return to this list, it will remain as "Completed".  I'm providing the member with a submit button that will call the same page and then update depending on which task is clicked as complete.

Here is my code:
Code: [Select]
$memberid = $_SESSION['member'];

// Check if form has been submitted
if(isset($_POST['task_done']) && $_POST['task_submit'] == 'submitted')
{
  $taskvalue = $_POST['task_value'];
  $query = "UPDATE membertable SET $taskvalue = 'done' WHERE id = $memberid";
  $result = mysqli_query($dbc, $query);
}

$query ="SELECT task1, task2, task3 FROM membertable WHERE id = $memberid";
$result = mysqli_query($dbc, $query);
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);

$_SESSION['task1'] = $row['task1'];
$_SESSION['task2'] = $row['task2'];
$_SESSION['task3'] = $row['task3'];
?>
<h4>Task List</h4>
<table>

  <form action="" method="post">
    <tr>
      <td>Task 1</td>
      <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
    </tr>
    <input type="hidden" name="task_value" value="task1" />
    <input type="hidden" name="task_submit" value="submitted" />
  </form>

  <form action="" method="post">
    <tr>
      <td>Task 1</td>
      <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
    </tr>
    <input type="hidden" name="task_value" value="task2" />
    <input type="hidden" name="task_submit" value="submitted" />
  </form>

  <form action="" method="post">
    <tr>
      <td>Task 1</td>
      <td><?php if($_SESSION['task1'] == 'done') {echo '<div>Completed</div>';} else{ echo '<input type="submit" name="task_done" value="Mark As Completed" />';} ?></td>
    </tr>
    <input type="hidden" name="task_value" value="task3" />
    <input type="hidden" name="task_submit" value="submitted" />
  </form>

</table>

The problem that I am having is that the database is not updated with the value "done" but after submission, the screen displays "Completed" instead of "Mark As Completed".  So the value is being picked up as "done", but that is why I have the SELECT after the UPDATES, so that there is always a current value for whether a task is done or not.  Then I refresh and the screen returns the button to Mark As Complete.  Also, when I try marking all three tasks as, sometimes all three are updated, sometimes only one or two and again, I leave the page or refresh and the "Marked As Completed" buttons come back.  Bizarre.  If anyone can tell me where my logic is going wrong, I would appreciate it.

I have a photo album style gallery to build
and
i'm finding it dificult to list all the table names (these are names of photo albums) and then enter the data into a seperate query for each album name (these will change often so i cant keep updating the file as normal. this will then post all the data to the xml file and show the set of photos in the individual albums in a flash file.
can anyone help me where im going wrong at all?



<?php
$dbname = 'cablard';

if (!mysql_connect('localhost', 'cablard', '')) {
    echo 'Could not connect to mysql';
    exit;
}

$sql = "SHOW TABLES FROM $dbname";
$result = mysql_query($sql);

if (!$result) {
    echo "DB Error, could not list tables\n";
    echo 'MySQL Error: ' . mysql_error();
    exit;
}

while ($row = mysql_fetch_row($result)) {
    echo "Table: {$row[0]}\n";
}

mysql_free_result($result);



$query = "SELECT * FROM photo ORDER BY id DESC"; 
$result2 = mysql_query ($query)  or die ("Error in query: $query. ".mysql_error());

   
   while ($row = mysql_fetch_array($result2))  
   {                                       
         echo  "
<image>
<date>".$row['date']."</date>
<title>".$row['title']."</title>
<desc>".$row['description']."</desc>
<thumb>".$row['thumb']."</thumb>
<img>".$row['image']."</img>
</image>

";


   }                      
?>


Thanks
James

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=350716.0