PHP - Pass A Username Javascript Variable To Next Page As Hidden

I  have a menu that i want to be added to every page of  my coding using a hidden variable, but i cannot get it to work. I using this with a few if conditions. the index page should navigate every page. can anyone help?


I have attached the files to illustrate the coding i have done so far.

[attachment deleted by admin]

so I need some help passing these variable from this page to final.php.  how do I pass these arrays?  I know if it were singled....not arrayed, I could use hidden fields in a form and echo them out....but these are multiples....not singled.  The form way is prefered.....but it doesn't have to be.  I just need these passed to the page where I am going to process them.  I am not good at working with arrays.  Thanks in advance

Code: [Select]
<?php
include_once("connect.php");
session_start();

 
 




 
foreach($_POST["product"] AS $key => $val) {
$product = $val;
$month = $_POST['month'][$key];
$day = $_POST['day'][$key];
$year = $_POST['year'][$key];
$date = $_POST['date'][$key];
$price = $_POST['price'][$key];
$qty = $_POST['qty'][$key];
$id = $_POST['id'][$key];
$total = $_POST['total'][$key];
$academy = $_POST['academy'][$key];
$priceunit = $price * $qty;


}

?>

Hello

I'm using a form to collect user data (is a Cognito form) it is displayed on vacation rental properties pages, so it collects user´s email, in date, out date, etc.
However since my site https://www.bariloche.esp.br/hoteis/hosteria-no-centro-vista-ao-lago uses the same form for several properties, when someone submits, I get the information but I dont know if it comes from here https://www.bariloche.esp.br/hoteis/hosteria-no-centro-vista-ao-lago or https://www.bariloche.esp.br/hoteis/hotel-com-praia-de-lago-ha1 or any other property page.

in the cognito form I have one text hidden field called REF, 

I wonder how to do in order to use the same form and be able to identify where the info comes from. 

I thougt that if I could put the page url into the REF variable, the problem would be solved, but I'm not sure if that is possible and how to do it.

It is?

If not: is it possible to handle that ?

Hi guys,

I need your help, I have got a problem with the if statement. When I don't insert the pass function in the url like this:

Code: [Select]
http://www.mysite.com/myscript.php?image=myimagelocation&strings=mystrings&user=test

I will get this on my php page:

Code: [Select]
PASSWORD are missing

Code: [Select]
<?php
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbusername');
    define('DB_PASSWORD', 'mydbpass');
    define('DB_DATABASE', 'mydbname');
       
    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
    $image = clean($_GET['image']);
    $strings = clean($_GET['strings']);
    $username = clean($_GET['user']);
    $pass = clean($_GET['pass']);


    if($username == '' && $pass) {
  $errmsg_arr[] = 'username are missing';
  $errflag = true;
     }elseif($username && $pass =='') {
  $errmsg_arr[] = 'PASSWORD are missing';
  $errflag = true;
    }
    if($username == '' && $pass == '') {
  $errmsg_arr[] = 'username or password missing';
  $errflag = true;
    }

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {

 
$insert = array();
if(isset($_GET['image'])) {
    $insert[] = 'image = \'' . clean($_GET['image']) . '\'';
}
if(isset($_GET['strings'])) {
    $insert[] = 'strings = \'' . clean($_GET['strings']) . '\'';
}
if(isset($_GET['user'])) {
    $insert[] = 'user = \'' . clean($_GET['user']) .'\'';
}
if(isset($_GET['pass'])) {
    $insert[] = 'pass = \'' . clean($_GET['pass']) . '\'';
}



if (count($insert)>0) {
   $names = implode(',',$insert);

$required_fields = array('image', 'strings', 'user');

if($image && $strings && $username) {
  echo "working 1";
} elseif($username && $pass) {
  echo "working 2";
  }
 }
}
?>

Do anyone know how to fix this?

I have researched all over forums from past day. Not getting correct solution. I have 2 textboxes and a button. First box is to enter value and i will click button, i need to get the value.   Here is the code, that works without input box 1   In this code i want to modify my web address, at the end after ky= i want add my first textbox value, then click event and output in second textbox, let me know where i messed.  

<script type="text/javascript">
function Assign() 
{
<?php
$html = file_get_contents("http://geoportaal.maaamet.ee/url/xgis-ky.php?ky=79401:006:0812" );
preg_match_all('(<li.*?>.*?</li>)', $html, $matches);
$one=$matches[0][0];


?>
document.getElementById("OutputField").value = "<?=$one?>";
}
</script>




<input id="InputField" type="text" style="width:200px"/>
<input type="submit" value="Assign Value" onclick="Assign()"/>
<input id="OutputField" type="text" style="width:200px"/>

Here's my PHP form code:

Code: [Select]
<form method='POST' action="<?php basename($_SERVER['PHP_SELF']);?>" onSubmit="return stripInputBoxes(1)">
<?php
echo "<div id = 'purchaseOrderRow1' style = 'display:none;border: 1px solid black;'>";
echo $integrityBuildingProductsPDF;
echo '<input type = "hidden" id = "pdf1" value = "" name = "pdf1" />';
echo '<button name = "savePurchaseOrder" type = "submit">Save Purchase Order</button>';
echo "</div>";
?>


</form>
Here's my Javascript:
Code: [Select]
function stripInputBoxes(pdfNumber)
{
if (!document.getElementsByTagName) return;

for (i = 0; i < document.getElementById('tableBody').getElementsByTagName('tr').length - 3; i++)
{
document.getElementById(i).parentNode.innerHTML = document.getElementById(i).value;
}

document.getElementById("pdf" + pdfNumber).value = "ljkasdkljf";

return true;
}
Will this set the value of the hidden variable? I'm trying to echo the value of $_POST['pdf1'] but it comes out to nothing when the page reloads. How do I do this?
What I'm trying to do here is display a purchase order on the screen and the user can edit the quantities in the purchase order. They click SAVE to save the new updated quantities and it auto generates a PDF that's saved on the server with those new quantities. The problem is I need to run the stripInputBoxes function to take the <input> tags out of the HTML code before creating the PDF because the PDF generator doesn't recognize the tags.

Here's my search form:

    <form action="search" method="get" enctype="multipart/form-data">
      <input type="text" name="string" maxlength="100" /><br /><br />
      <input type="submit" value="Search" />
    </form>

When I submit it, the URL is search.php?string=Bleh

What I would like is for the URL to be search/string/Bleh

I'm already doing this with some other variables, like search/tag/Bleh and search/author/Bleh, instead of search.php?tag=Bleh and search.php?author=Bleh. However, those ones are passed via a link, not a form.

Any ideas?

Hi guys,

I have a trouble with my php snippet, when I insert the var function in the url bar something is like:

http://www.mysite.com/delete.php?favorites&id=0

or

http://www.mysite.com/delete.php?whateveritis&id=0

It doesn't get pass the favorites function to delete the id. It is the same things that it goes for each different function.

Here's the current code:

<?php
Code: [Select]
session_start();
    define('DB_HOST', 'localhost');
    define('DB_USER', 'mydbuser');
    define('DB_PASSWORD', 'mydbpass');
    define('DB_DATABASE', 'mydbtablename');

    $errmsg_arr = array();
    $errflag = false;

    $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
    if(!$link) {
  die('Failed to connect to server: ' . mysql_error());
    }

    $db = mysql_select_db(DB_DATABASE);
    if(!$db) {

die("Unable to select database");
    }

   function clean($var){

return mysql_real_escape_string(strip_tags($var));
    }
    $favorites = clean($_GET['favorites']);
    $id = clean($_GET['id']);

if($favorites && $id == ''){
   // both are empty
   $errmsg_arr[] = 'favorites id are missing.';
   $errflag = true;
}

    if($errflag) {
  $_SESSION['ERRMSG_ARR'] = $errmsg_arr;
  echo implode('<br />',$errmsg_arr);
   }
   else {
$insert = array();
if(isset($_GET['id'])) {
    $insert[] = 'id = \'' . clean($_GET['id']) .'\'';
}
if(isset($_GET['favorites'])) {
    $insert[] = 'favorites = \'' . clean($_GET['favorites']) . '\'';
}

if($favorites && $id) {
   mysql_query("DELETE FROM favorites WHERE id='$id'");
   $deleted = mysql_affected_rows();
   if($deleted > 0)
   {
  echo "favorites channels is deleted";
   }
   else
   {
  echo("favorites is already deleted");
   }
 }
}
?>
If you do know how to get pass the favorites function, then please say so as i need your help.

Any advice would be much appreicated.

Hi All,

I have a function that i want to pass a variable into so that i can do some SQL on it.

The information that i want to pass into it is a data-id on a button that is used to trigger the function.

The button that will be clicked is this

<div class='modaltrigger btn btn-primary' data-id='$itemId' data-toggle='modal'>Manage</div>

This button is being created by another function.

I would like to know either how i pass the variable from one function to another or how i pass it from the data-id to the function in php.

Thanks in advance.

When i execute the following code, it works and retrieves the record info i am looking for for the appropriate record, 2155015898:

  $adgrouppass = 2155015898;
  $selector->adGroupIds = array($adgrouppass);

However, when i try to get the adgroup variable from my url, which is where it is located, it doesn't work:

  $adgroup = trim($_GET['adgroup']);
  $adgrouppass = $adgroup;
  $selector->adGroupIds = array($adgrouppass);

yet, in trying to fix it, if i echo the above variable, it says it is correct, which is 2155015898.

Not sure if the $adgrouppass needs to be a string or variable to get it to pass it correctly.  Can anyone help?
 

Hi, I have this script, it all works fine apart from when I pass the variable on, it only passes the first word and not the whole variable

The form that actions to the samples page passes the $siteName as My Test Site, if I type echo $siteName in the sameples page, it will print My Test Site, however when I use this

Code: [Select]
createSample&siteName=$siteName
to pass the variable to the next page, it just echos 'My' instead of My Test Site. Even when I scroll over the link above it just shows My in the url.

Code: [Select]
case "samples":

// Get submitted data and assign to variables

$siteName = $_POST['siteName'];
$adminEmail = $_POST['adminEmail'];
$sendmailLoc = $_POST['sendmailLoc'];
$imgdir = $_POST['imgdir'];
$imgdirbase = $_POST['imgdirbase'];

// Write variable data to text file

$FileName = "data/server.txt";
$FileHandle = fopen($FileName, 'w') or die("can't open file");
$data = "<?php\n\$siteName = '$siteName';\n?>";
fwrite($FileHandle, $data);
$data = "<?php\n\$adminEmail = '$adminEmail';\n?>";
fwrite($FileHandle, $data);
$data = "<?php\n\$sendmailLoc = '$sendmailLoc';\n?>";
fwrite($FileHandle, $data);
$data = "<?php\n\$imgdir = '$imgdir';\n?>";
fwrite($FileHandle, $data);
$data = "<?php\n\$imgdirbase = '$imgdirbase';\n?>";
fwrite($FileHandle, $data);
fclose($FileHandle);

// Displays the create sample pages page

ECHO <<<SAMPLES

<table border=0 align=center bgcolor=#00CCFF>
  <tr>
    <td><span class=style1><b><center>Create Sample Pages</center></b></span></td>
  </tr>
  <tr>
    <td>Would you like Member Site Maker to create sample pages for:
<ul>
<li>index.html</li>
<li>login.html</li>
<li>search.html</li>
<li>register.html</li>
</ul>
</td>
</tr>
<tr>
<td><a href=installation.php?cmd=createSample&siteName=$siteName>Yes</a>
</td>
<td><a href=installation.php?cmd=mysql>No</a>

</td>
</tr>

</table>

SAMPLES;

break;
Can anybody tell me where I am going wrong please?

Thanks

Hi,

Im trying to pass a variable ($in_this_instance) into, and then back out of a function.  The variable goes into the function no problem, and is echo'ed out fine.  However the echo after the close of the function, does not give anything out. 

Code: [Select]
$in_this_instance = 'boo';

function in_this_instance($data) {
global $in_this_instance;

echo $in_this_instance;

$in_this_instance = 'hoo';


$rep_val = '[front banner]';

    $test = strpos($data, $rep_val);
    if ($test === false) {
return $data;
    } else {
    return $data;;
    }
}

add_filter('the_content', 'in_this_instance');
echo $in_this_instance;

Could any one give me a pointer please?  Many Thanks!

I have a table that has 5 columns

Quote

player_id
fname
lname
team
email


I'm trying to get all the values from that table using this sql command

Code: [Select]
include_once('../database_connection.php');

$player_id = addslashes($_REQUEST['edit_player']);

$sql_query = "Select * from nba_info where player_id = '$player_id'";
$result = MYSQL_QUERY($sql_query);
"edit_player" above is came from a different page.




They I'm fetching the data using while

Code: [Select]
while($row = mysql_fetch_array($result))
{
$row['player_id'];
    $row['fname'];
    $row['lname'];
    $row['team'];
    $row['email'];
}
Then I'm trying to pass that values to a variable here

Code: [Select]
$id = $row['player_id'];
$fname = $row['fname'];
$fname = $row['lname'];
$lname = $row['team'];
$email = $row['email'];

When I'm trying to put that variables in a textbox value, they are not showing up

Here

Code: [Select]
<table>
<form name="edit_player_form" method="post" action="">

<tr>
<td>Players ID</td>
<td><input type="text" name="playerid" size="20" value="<?php echo $id; ?>" /></td>
</tr>

<tr>
<td>First Name</td>
<td><input type="text" name="fname" size="20" value="<?php echo $fname; ?>" /></td>
</tr>

<tr>
<td>Last Name</td>
<td><input type="text" name="lname" size="20" value="<?php echo $lname; ?>" /></td>
</tr>

<tr>
<td>Team</td>
<td><input type="text" name="team" size="20" value="<?php echo $team; ?>" /></td>
</tr>

<tr>
<td>Email</td>
<td><input type="text" name="email" size="20" value="<?php echo $email; ?>" /></td>
</tr>


<tr>
         <td><div align="center">
         <input type="submit" name="Submit" value="Edit This Player">
         </div></td>
        </tr>



</form>
</table>


I wonder why it ain't showing up on the textbox value? tried almost everything... Anyone?

You guys are great, thanks again for the help last week.

Now I almost got this working but a small hiccup.

here is my code:
Code: [Select]

<?php 
include("config.php");
$my_t=getdate(date("U"));
$my_t1=$my_t[weekday];
$result = mysql_query("SELECT * FROM tourney where day_of_week = '$my_t1'") or die(mysql_error()); 
if ($result == '') echo "<br>Empty Set\n";
print_r ($my_t1); This prints correctly

Code: [Select]
while ($result = mysql_fetch_array($result,MYSQL_ASSOC)) { This is my error. "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /hermes/bosweb/web017/b172/ipg.dswdesignsnet/pp4c/charity1.php on line 8"

Code: [Select]
print "<b>Starting Time: <br></b>".$row{'start_time'}."<br><b>Tournament: </b><br>".$row{'tourney'}."<br><b>Buy-in: <br>".$row{'buy_in'}."<br><b>Starting Chips: <br>".$row{'start_chips'}."</font><p>";
This prints headers correctly, but no variables.

Code: [Select]
}
mysql_close($dbh);
?>
What did I forget to do or what did I do wrong.

I'm still learning mysql and php.