PHP - Multiple Inserts In A Table

If I am running a query like this:

INSERT INTO `cam_locations` (`id`, `datacenter`, `address1`, `address2`, `city`, `state`, `zip`, `country`, `phone`) VALUES
(1, 'Austin Data Center', '', '', 'Austin', 'Texas', '', 'United States', ''),
(2, 'Sunnyvale Date Center', '', '', 'Sunnvale', 'California', '', 'United States', ''),
(4, 'BoxBorough Data Center', '', '', 'Boston', 'Massachusetts', '', 'United States', '')


It it possible to use mysql_insert_id() and get all the id's inserted? Maybe like an array of them or something? Thanks

Hi all.

Im trying to insert from one form 3 items of data into to different tables.  I will post the code as most of my notes are in there but first.......

What is happening is the form is filled in then the first part of the form where it updates my clubs table with category ID's works fine. Nothing in the
if ($result) {   }
seems to run.
I have create some fake groups so the drop down is populated with groups already created and I have tried to select one of these groups so it can be entered into the clubs table and nothing.  No errors just no answers.  Does anybody no what I am doing wrong?


first Ill post the form and the querys that make fields in the form... 

Querys

//gets
$validation = $_GET['new_club'];
//Querys
    $qGetClub = "SELECT * FROM clubs WHERE validationID = '$validation'"; 
$rGetClub = mysql_query($qGetClub);
$Club = mysql_fetch_array($rGetClub);
//Query for category by name
$qGetCat = "SELECT * FROM club_category WHERE catID = ".$Club['cat']."";
$rGetCat = mysql_query($qGetCat);
$CatName = mysql_fetch_array($rGetCat);
//query for related sub categorys.
$qGetSub = "SELECT * FROM sub_categorys WHERE catID =".$Club['cat']."";
$rSubCat = mysql_query($qGetSub);
// query for groups created
$Groupq = mysql_query("SELECT * FROM groups WHERE memberID = '".$User['memberID']."'");



  then we have the form


<form action="" method="post"  id="insert_clubfrm">
  
                        <tr valign="baseline">
                                <td colspan="2"  valign="top"><br/><p>Your Chosen category was <strong><?php echo $CatName['categorys'];?></strong> Please select a sub category.</p><br></td>
                              </tr>
                              
                              <tr valign="baseline">
                                <td width="132"  valign="top" >Club Sub Category:</td>
                                <td width="256"  valign="top"  ><select name='subcat'>
                            <option value="None">Please Select One</option>
<?php while ($New_SubCat = mysql_fetch_assoc($rSubCat)) { ?>

                                <option value="<?php echo $New_SubCat['subID']; ?>"><?php echo $New_SubCat['sub_categorys']; ?></option>"<?php  }  ?>

</select>
  </td>
                              </tr>
                              <tr valign="baseline">
                                 <td colspan="2"  valign="top" ><br/><p>If your sub category does not exist in the list please select "none" above and enter your new sub categroy below.</p><br></td>
                              </tr>
                              <tr valign="baseline">
                                <td  valign="top" class="left_padding">New Sub Category</td>
                                <td valign="top" class="left_padding"><input type="text" name="newSubCat" id="new_cat" value="" /></td>
                              </tr>
                              <tr valign="baseline">
                                <td colspan="2"  valign="top" class="left_padding"><br/>
                                 If you had/have more than one site and you had to give your group of companies a name what would that name be?
                                <br/></td>
                              </tr>
                              <tr valign="baseline">
                                <td  valign="top" class="left_padding">Group Name:</td>
                                <td  valign="top" class="left_padding"><label for="other_groups"></label>
                                  <select name="other_groups" id="other_groups">
                                  <option>None</option>
                                  <?php while ($group = mysql_fetch_assoc($Groupq)) { ?>
                                    <option value="<?php echo $group['groupID']; ?>"><?php echo $group['group']; ?></option>"<?php  }  ?>  
                                </select></td>
                              </tr>
                              <tr valign="baseline">
                                <td  valign="top" class="left_padding">Group Name:</td>
                                <td  valign="top" class="left_padding"><label for="new_groups"></label>
                                 <input type="text" name="new_group" value="">

  
</td>
                              </tr>
                                                        <tr valign="baseline">
                                <td valign="top" nowrap="nowrap">&nbsp;</td>
                                <td valign="top"><div align="left">
                                  <input type="submit" id="insert_clubbtn1" name="insert_clubbtn1" value="Insert record" />
                                </div></td>
                              </tr>
                            </table>
                            </form>






now the code to make the form work...



if(isset($_POST['insert_clubbtn1'])){ 
//Process data for validation     
$subcat     = trim($_POST['subcat']);  
$NewSubCat = trim($_POST['NewSubCat']); 

$otherg = trim($_POST['other_groups']);
$newg = trim($_POST['new_groups']);     
//Prepare data for db insertion      
$newg = mysql_real_escape_string($newg);  
$subcat = mysql_real_escape_string($subcat); 
//find the new category 
//insert
$result = mysql_query("UPDATE clubs  SET 
`sub_category` = '$subcat'
WHERE validationID ='$validation'") or die(mysql_error());
if ($result) {
//if an item other than none from the list is selected then update the club with an ID relating to the group it belongs to
if ($otherg !=='None') { $groupsq = mysql_query("UPDATE `clubs` SET groupID ='$otherg' WHERE validationID ='$validation')") or die (mysql_error()); }
// If none is selected then $newg must have a value so create a new group in the groups table and then on the next page I will add the group in the club table 
if ($otherg == 'None') {
$groupsq = mysql_query("INSERT INTO `groups` (memberID, group, clubID) VALUES ('".$User['memberID']."', '$newg', ''".$Club['clubID']."')");
} }


if ($NewSubCat !="") { mail("email","New Sub Category Request","Dear Owner,
\n\nThe club in the name of $name with a validation code of $validationID would like a new sub category called $new_cat\n\n  
\nTeam Me\n\n\n\n"); }

$url = "/create/create_clubp3.php?new_club=$validation";  
header("Location: $url");     

how do i  stop multiple duplications in database on my PHP script?



ok i have attached a screenshot of what the database looks like after a few runs of my script. the script is designed to pull api information, input into 1 database and update another user table.
i have made it run as a cron job every 60 minutes.

here is my code:
<?php

/* You need multiple instances of this script. Each instance runs once every hour so 6 instances means one 
runs every 10 mins. Remember to change the API URL to reflect the different accounts or characters.*/
include "connect.php";

$columns = "`date` , `refID`, `refType`, `ownerName1`, `ownerName2`, `argName1`, `amount`, `balance`, `reason`";

//Live URL is 

//Assumeing that they are only donating at this time and no one is being paid to reduce the balance. Balance reduction can be done in the prize claim script so its not API delayed.
if ( ($data[2] == "Player Donation") && ($data[4] == "Ship Lotto")){
$reUsed = mysql_query("SELECT * FROM bank WHERE refID='$data[1]';");
if(!empty($reUsed)){
$import="INSERT into bank($columns) values('$data[0]','$data[1]','$data[2]','$data[3]','$data[4]','$data[5]','$data[6]','$data[7]','$data[8]')";
mysql_query($import) or die(mysql_error());
}

/*check to see if the player has already been credited. It checks the last recorded reference #
and checks to see if the new ref # is greater, else skips the processing. You need to check since 
the API gives you the last 1000 journal entries or 1 week, what ever is shorter. Not just what is 
new since last check. Check is performed by seeing if the record in the database for the user is 
less then or equal to the new once. This works only because CCP's reference #s are auto increasing 
so they only go up if they are newer, never down.*/
$name = $data[3];
//echo "Updating account of ".$name."<br />";
$queryLastRef = mysql_query("SELECT lastRef FROM users WHERE username='$name';") or die(mysql_error());
//echo $queryLastRef;
$arraylastRef = mysql_fetch_assoc($queryLastRef);
$lastRef = $arraylastRef["lastRef"];
//echo "The last reference # was: ".$lastRef."<br />";
$currentRef = $data[1];
//echo "The current reference # is: ".$currentRef."<br />";
if($lastRef<$currentRef){
$amount = $data[6];
//echo "Player deposited ISK in the amount of: ".$amount."<br />";
$queryBal = mysql_query("SELECT user_iskbalance FROM users WHERE username='$name';") or die(mysql_error());
//echo "Executing the SQL command to query balance ID#: ".$queryBal."<br />";
$getBal = mysql_fetch_assoc($queryBal);
//echo "Executing the SQL command to get balance amount: ".$getBal["user_iskbalance"]."<br />";
$deposit = $amount+$getBal["user_iskbalance"];
//echo "Depositing ISK in the ammount of: ".$deposit."<br />";
$importBal= "UPDATE users SET user_iskbalance=$deposit WHERE username='$name';";
//echo "Executing the SQL command to desposit: ".$importBal."<br />";
mysql_query($importBal) or die(mysql_error());
$importRefID= "UPDATE users SET lastRef='$currentRef' WHERE username='$name';";
//echo "Executing the SQL command to set the new reference: ".$currentRef."<br />";
mysql_query($importRefID) or die(mysql_error());
//echo "Success!"."<br />";

//For the sake of stats tracking update the total isk on deposit. The payout script will subtract.

$queryiskDeposit = mysql_query("SELECT iskDeposit FROM stats;") or die(mysql_error());
//echo "Executing the SQL command to query the ISK deposited : ".$queryiskDeposit."<br />";
$arrayiskDeposit = mysql_fetch_assoc($queryiskDeposit);
$getiskDeposit = $arrayiskDeposit["iskDeposit"];
//echo "Got total isk on deposit of: ".$getiskDeposit."<br />";
$iskDeposit = $getiskDeposit+$deposit;
//echo "Inserting: ".$iskDeposit." ISK"."<br />";
$importiskDeposit= "UPDATE stats SET iskDeposit='$iskDeposit';";
//echo "Executing the SQL command to desposit: ".$importBal."<br />";
mysql_query($importiskDeposit) or die(mysql_error());
//echo "<br />";
//echo "<br />";
//echo "NEXT!<br />";
//echo "<br />";
}
else{
//echo "There is no update for ".$name." because ".$lastRef." is not less then or equal to ".$currentRef."<br />";
//echo "<br />";
//echo "<br />";
//echo "NEXT!<br />";
//echo "<br />";
}
//echo "DEBUG for ".$name." lastRef ".$lastRef." and currentRef ".$currentRef."<br />";

//update the time that last update ran
$today = date("Ymd G:i");
mysql_query("UPDATE stats SET iskLastUpdate='$today';") or die(mysql_error());
//echo "Updating Date to: ".$today;
//echo "<br />";
//echo "<br />";
//echo "NEXT!<br />";
//echo "<br />";
}
}
?>


can anyone help me stop it duplicating the entries in the database please?

If one inserts acute letters, grave letters, ampersands and accented letters in xhtml they show perfectly on the page.
However if one uses insert or rss feed they show as � or a square.

How does one make them show correctly.

Is it possible - and reasonable - to have one Form which allows Users to create a new record (i.e. do an INSERT) and which also allows Users to modify an existing record (i.e. do an UPDATE)?   

When a User registers at my website, not only do they create a record in the "member" table, but one of the required fields is "First Name". 

What that means is that when I allow Users to edit details in their Profile - most of which were not included in registration to streamline the process - I don't have to worry about doing an INSERT, because I already created a "member" record and on the "Edit Details" page the first field is "First Name" so that is a hook so to speak where they can enter more info about themselves like...
Code: [Select]
- Location
- Date of Birth
- Interests
- Bio
and so on...


So here is my problem which I just discovered...

Also in my User Profile, I allow Users to answer several open-ended questions like...
Code: [Select]
1.) Why did you decide to start your own business?

2.) What advice would you share with others on what NOT to do?

The problem is that these questions exist in the "bio_question" table and the answers that I am trying to get from Users will be stored in the "bio_answer" table but no record currently exists?!

So do I need both an "INSERT Answers Form" *and* an "UPDATE Answers Form", or can I combine things into one form?!

Hope that all makes sense?!


Debbie