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PHP - Help With Php (str & Replace Code)
Hello, I need help with this, I need a code that removes double occurrences of \\ only, but not if followed \n. for example Hello\\n should display Hello\ + new line Hello\\\n should display Hello + new line Hello\\ should display Hello Hello\\x should display Hellox Similar TutorialsHi, I am trying to take a string from a database and replace everything within {} with code... similar to how posting in a forum works. so say I have "...Lorem ipsom {gallery:1} sit imet..." it will take that string (from a DB) and replace "{gallery:1}" with "<?php gallery('1'); ?>". How can this be done? Or is there keywords I can search on to find the answer? Thank you in advance. The situation is that I have a large string with some identifiers to say "replace me" with something else. My goal is to replace the values, but if one replacement includes one of the other keys, I don't want to replace it.
For example:
<?php $str = 'some blob ~abc~ followed by ~def~'; $arr_orig = array( '~abc~', '~def~' ); $arr_new = array( 'value~def~', 'blah' ); echo str_replace( $arr_orig, $arr_new, $str ); ?>This will echo: some blob valueblah followed by blah But that's not what I'm trying to accomplish. Basically, I want ~abc~ to be replaced with the literal: value~def~ and for the ~def~ that happens to be part of that string to NOT be replaced. I hope what I'm asking is clear. Basically, preg_replace/str_replace with arrays seems no different than just doing a FOR loop and replacing ~abc~ and then ~def~. But that's not what I need. I'm hoping that if ~abc~ is replaced with text that happens to be another identifier -- ~def~, ~xyz~, whatever -- that this already replaced text is not again replaced. Is there a built-in function to do something like this? If not, should I just parse the whole string and count characters or something? Seems like a pain (and slow!) I have a website that has definitions and articles. I need a code that craws the php content pulled from my database, finds a specified word and replaced that word with a link. For example If "car" appears replace with <a href="http://www.website.com/car.php">car</a> Thanks Todd Hi i wrote a find and replace code but my code replace last value of array and skip the first, second.... values in the array. Please give me an idea because i stack with this code. Regards $KeyWord = explode("\n", $RowGetWords['KEYWORDS']); $Replace = explode("\n", $RowGetWords['ReplaceTo']); for($i=0; $i<count($KeyWord); $i++){ $pattern = $KeyWord[$i]; $replace = "<a href=\"" .$URL. "\" target=\"_blank\" >" .$Replace[$i]. "</a>"; $html = str_replace($pattern, $replace, $Row['MessageBody']); } Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob I have multiple \n in a string, and I need to replace it with <br />. How do I go about doing this? Preg replace? alright, is this the correct format for a REPLACE INTO? if not what do i need to change.......it isn't working...... Code: [Select] $sql = "REPLACE INTO Events (name, event, eventid, userid, title1, title2, title3, title4, title5, title6, title7, title8, email) VALUES('$name','$event','$eventid','$userid','$title1','$title2','$title3','$title4','$title5','$title6','$title7','$title8', '$email')"; $rs = mysql_query($sql) or die ("Problem with the query: $sql<br>" . mysql_error()); ok so I have an string with data that I need to be replaced with contents from an array. I need the occurance position replace with the index of the array. example Code: [Select] //here is the setup $string = "testing %s one %d %s"; array('this',1,'three'); //here is the result testing this one 2 three the problem I am having is because the %s can occur more than once I cant use str_replace. I am working on a solution with substr_replace but was wondering if anyone had any suggestions on how to do this. When I replace it I also need to run the value through a function so keep that in mind. Also the replace's are stored in an array so they need to be looped through as well. Code: [Select] $replaces = array('%s'=>'func_one','%d'=>'func_two'); Any help is appreciated. Hi, I'm pretty new to PHP, and I'm trying to write my own encoding/decoding script (not with base_64). I'd like to replace like all A's with B's, all B's with C's, C's with D's, and so on. How would I do this? Here's an example: String #1: "ABCDEFG" string #1 goes through my encryption string #2 (output): "BCDEFGH". How would I go about doing this? Thanks. User can edit a post. I need to replace the html '<br/>' element to newline character ('\n') . When a user will edit a post he/she will not see the '<br/>'. How can i do this with php ? How does wordpress and other similar CMS/applications replace their div elements? For example, if you view the source code of a wordpress site, you will only see: Quote <div id="header"></div> Where, the above code is clearing being switched out for "header.php". How is this done? I believe it's php and jquery, but I would be wrong. Thanks! Hello, I'm trying to convert a paragraph of text which is already html formatted. I wish to find keywords, such as, 'PHP', which are contained in the paragraph, and replace them with a link, for example <a href="http:/www...">PHP</a> str_replace('PHP', '<A href=""....">PHP</a>', $content); My problem arises when some of these keywords are already contained in a link, so say, visit PHP website, is all one link, so str_replace would simply convert the PHP in this string, to two links for one single word. Code: [Select] <a href="">visit <A href=""....">PHP</a> website</a>How could this problem be resolved? Thanks I retrieve urls that have the following path $url=http://cdn.test1.com $url=http://cdn.test2.com and so on... i want to to do a string replace such that it displays http://test.com,http://test2.com and son without the cdn part. Will the following work for all cases? Code: [Select] $url=str_replace("cdn.","",$url); Hello: I have a quick question. I am currently using the following code to replace an apostrophe and quote marks when inserting and updating a database record: Code: [Select] $myPageContent = mysql_real_escape_string(str_replace("'", "'", $_POST['myPageContent'])); $myPageContent = mysql_real_escape_string(str_replace("", """, $_POST['myPageContent'])); My question is - how can I modify it so I only need to use one line. Like (but this does not work): Code: [Select] $myPageContent = mysql_real_escape_string(str_replace("'", "'", "", """, $_POST['myPageContent'])); It seems to me that the way I am currently doing it might be POSTing the data twice? Thanks! I've managed to insert an image in my database, but when i upload a second picture it replaces the first!What should i do? The output of the array1 is looks as below. Code: [Select] Array ( [num_found] => 60 [articles] => Array ( [0] => Array ( [aut] => Array ( [0] => ANI ) [by] => ANI [Id] => 278 [key] => Array ( [0] => trans fats [1] => junk food [2] => food labels [3] => miscarriage [4] => hydrogenated ) [norm] => true [body] => Gorging [cat] => Array ( [0] => food & drink ) [pm] => ANI|P#M#D| [pm] => Beware! [seo] => junk [pmT] => Array ( [0] => trans fats [1] => junk food [2] => food labels [3] => miscarriage [4] => hydrogenated ) [pid] => 72 [Date] => 2011-06-02T00:00:00Z [section] => Health [sd] => 3506926 [ti] => Beware! Junk food can cause miscarriage [ur] => riage [kick] => [subtitle] => [image] => [Tag] => ) [1] => Array ( [aut] => Array ( [0] => URVASHI ASHER ) [by] => URVASHI [Id] => 277 [key] => Array ( [0] => film [1] => design [2] => biography [3] => amitabh bachchan [4] => cinema ) [norm] => true [body] => division. [cat] => Array ( [0] => entertainment ) [pm] => URVASHI ASHER|P#M#D|TNN [pm] => booked [seo] => film [pmT] => Array ( [0] => film [1] => design [2] => biography [3] => amitabh bachchan [4] => cinema ) [pid] => 72 [Date] => 2011-06-02T00:00:00Z [section] => News & Interviews [sd] => 3921796 [ti] => Amitabh booked [uri] => film [kick] => [subtitle] => [image] => [Tag] => ) I have a array2 similar to this. Code: [Select] Array ( [num_found] => 70 [articles] => Array ( [0] => Array ( [aut] => Array ( [0] => ANI ) [by] => RNI [Id] => 643 [key] => Array ( [0] => trans fats [1] => junk food [2] => food labels [3] => miscarriage [4] => hy ) [norm] => true [body] => Test [cat] => Array ( [0] => drink ) [pm] => ANI|P#M#D| [pm] => Beware! [seo] => junk [pmT] => Array ( [0] => trans fats [1] => junk food [2] => food labels [3] => miscarriage [4] => hydrogenated ) [pid] => 73 [Date] => 2011-06-02T00:00:00Z [section] => Health [sd] => 8434 [ti] => Beware [ur] => riage [kick] => [subtitle] => [image] => [Tag] => ) [1] => Array ( [aut] => Array ( [0] => URVASHI ASHER ) [by] => URVASHI [Id] => 345 [key] => Array ( [0] => film [1] => design [2] => biography [3] => bachchan [4] => cinema ) [norm] => true [body] => division. [cat] => Array ( [0] => entertainment ) [pm] => URVASHI|P#M#D|TNN [pm] => booked [seo] => film [pmT] => Array ( [0] => film [1] => design [2] => biography [3] => amitabh bachchan [4] => cinema ) [pid] => 72 [Date] => 2011-06-02T00:00:00Z [section] => News & Interviews [sd] => 43543543 [ti] => booked [uri] => film [kick] => [subtitle] => [image] => [Tag] => ) Please tell me how to add the 1st value from array2 and replace in array1. The output should look like Code: [Select] Array ( [num_found] => 60 [articles] => Array ( [0] => Array ( [aut] => Array ( [0] => ANI ) [by] => RNI [Id] => 643 [key] => Array ( [0] => trans fats [1] => junk food [2] => food labels [3] => miscarriage [4] => hy ) [norm] => true [body] => Test [cat] => Array ( [0] => drink ) [pm] => ANI|P#M#D| [pm] => Beware! [seo] => junk [pmT] => Array ( [0] => trans fats [1] => junk food [2] => food labels [3] => miscarriage [4] => hydrogenated ) [pid] => 73 [Date] => 2011-06-02T00:00:00Z [section] => Health [sd] => 8434 [ti] => Beware [ur] => riage [kick] => [subtitle] => [image] => [Tag] => ) [1] => Array ( [aut] => Array ( [0] => URVASHI ASHER ) [by] => URVASHI [Id] => 277 [key] => Array ( [0] => film [1] => design [2] => biography [3] => amitabh bachchan [4] => cinema ) [norm] => true [body] => division. [cat] => Array ( [0] => entertainment ) [pm] => URVASHI ASHER|P#M#D|TNN [pm] => booked [seo] => film [pmT] => Array ( [0] => film [1] => design [2] => biography [3] => amitabh bachchan [4] => cinema ) [pid] => 72 [Date] => 2011-06-02T00:00:00Z [section] => News & Interviews [sd] => 3921796 [ti] => Amitabh booked [uri] => film [kick] => [subtitle] => [image] => [Tag] => ) where array[0] is the value from array2. basically what i am trying to do is replace the <a href="whatever.com"> with <a href="whatever.com" onclick = "if (! confirm("Continue?")) return false;"> so that when the user clicks the url in a message the box pops up first then redirects them to the url if they click confirm. However i am getting the following error: Code: [Select] Warning: preg_replace() [function.preg-replace]: Compilation failed: reference to non-existent subpattern at offset 11 here is the code i used. $message_content = $content_info['message_content']; $pattern='<a href="\\1">'; $replace='<a href="\\1" onclick = "if (! confirm("Continue?")) return false;">'; $message_content = preg_replace($pattern, $replace, $message_content); echo $message_content; Anyone know where i went wrong? So i have this script that outputs Listed Files inside a folder echo '<option value="'.$fileName.'">'.$fileName.'</option>';} like this : <option value="Fonts/28 Days Later.ttf">Fonts/28 Days Later.ttf</option> etc files .... i would like to know how may i remove " Fonts/ " And the .ttf extension from the second part that repeats (the name) using something like preg_replace and to make the first letter uppercase using ucfirst() And if someone is familiar with preg_replace could you please give me a tutorial on how it works to replace some text ? Thanks In Advance how can i find reference to something like this "navigationID=3" or "navigationID=44" within a string and then re write it to become something like this "/en/content/3/Link_Name"? there could be more than one reference within the string and the integer val (ie 3 and or 44) will not be known. Any help with this would be greatly appreciated. hi, im trying to replace an arrays key with its value. this is so i can display the html on the pages. eg: index.html <title>{BOARD_TITLE}</title> index.php $template->replace(array( '{BOARD_TITLE}' => $settings['board_name'] )); template.php(template class) function replace($array) { foreach ($array as $key => $val) { echo $key = $val; } return; } however {BOARD_TITLE} does not get replaced with the value. where am i going wrong? Thanks |
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