PHP - Controlling Search Variable
This may sound like an odd thought, but us beginners come up with weird ideas sometimes.
I'm trying to solve a "three letters or less" search. Basically if the user enters 4 words or more, my script does a fulltext search. If they do 3 letters or less, it does a basic search. But how can I write the script so that it only searches for those matching letters that have either a space in front or at the end... or that start with the three letters searched. so, if they type in "elm" I want to get "chinese elm" I want to get "Elmendorf's onion" I don't want to get "engelman's spruce"... or at the very least have results with no space on either side be at the end of the results? right now, I'm just doing a basic search and a basic search that concatenates two fields: Code: [Select] $data = mysql_query("SELECT * FROM plantae WHERE common_name_english LIKE '%$item%'"); Code: [Select] $data = mysql_query("SELECT * FROM plantae WHERE CONCAT(taxonomic_genus,' ',scientific_name) LIKE '%$item%'"); Similar TutorialsI have a PHP app that I wrote that requires a new IP address each time that it is run. Currently I use Tor on my desktop and the Vidalia app to change the Tor identity each time I run the script but I want to automate this. Can anyone help with switching Tor identities with PHP? Essentially after my script runs I need to call a function that switches to a new Tor identity. I have the following code but it doesn't seem to work, and I am not sure why. I am running this from XAMPP on OSX, Tor is running locally (client not server)... in my Tor settings I have 127.0.0.1 and port 9051, set to "no password"... Code: [Select] <?php function tor_new_identity($tor_ip='127.0.0.1', $control_port='9051', $auth_code='') { $fp = fsockopen($tor_ip, $control_port, $errno, $errstr, 30); if (!$fp) { return false; //can't connect to the control port } fputs($fp, "AUTHENTICATE $auth_code\r\n"); $response = fread($fp, 1024); list($code, $text) = explode(' ', $response, 2); if ($code != '250') { return false; //authentication failed } //send the request to for new identity fputs($fp, "signal NEWNYM\r\n"); $response = fread($fp, 1024); list($code, $text) = explode(' ', $response, 2); if ($code != '250') { return false; //signal failed } fclose($fp); return true; } tor_new_identity(); ?> Hey! Normally I'm very good with researching my problems, but I just can't think of what to search for, what I am wanting to do is design a script that sends a command to a batch file that is already open and running (or something to that effect), does anyone know how this would be possible, all help would be appreciated! Thank you for your time Regards GreenFanta Hello PHPFreaks, I'm sorry about the vague topic title, but allow me to explain: I got a PHP form with some fields, and it sends the input data to me, and a copy to the person that submits it. Only the receiver of the email sees the email it came from as: example.com@webhost-mailserver.com, rather than just "example.com" or "info@example.com". Is there a way to control this, so people dont see the root host? Coding: // send email $headers = "From: \"$naam\" <$email>\n"; $subject = "Contactformulier Kartalin"; $from = "Kartalin.nl"; $message = " blabla their input etc. "; mail ("$youremail", $subject, $message, "From: $from\nContent-Type: text/html; charset=iso-8859-1"); If you need more of the code let me know, but as far as I can tell this seems to be the part where it can be changed (coming from a PHP-dummy ) Thanks in advance! Dave Hi. how can I control a progress meter/bar to display errors when it failed to reach 100% or on getting to a point? thanks The result pages is supposed to have pagination like google help me please
I require a page to be added to my website. This page will facilitate a refined search via Google, Bing and Yahoo search engine simultaneously , show the top 5 of each engine. Is this possible using php ? Thank's Hello, Does anyone know a tutorial I can follow to create my own search engine over the items I have in my SQL database? I find a lot of tutorials but they are all 'one word searches' which means if you type two words you will get all results that contain either word (too many hits). If the search engine tutorial displays result with AJAX even better. Thanks for help. df Friends, I want to extract the Search Keyword from the URL, a visitor came from. I am using a PHP CMS and want to show the Keyword on my Blog. So if they search "abcd" from google, i want to extract "abcd" and echo on my blog. Here is the coding i could got hold of, but its not working, not echoing anything <?php function pk_stt2_function_get_delimiter($ref) { $search_engines = array('google.com' => 'q', 'go.google.com' => 'q', 'images.google.com' => 'q', 'video.google.com' => 'q', 'news.google.com' => 'q', 'blogsearch.google.com' => 'q', 'maps.google.com' => 'q', 'local.google.com' => 'q', 'search.yahoo.com' => 'p', 'search.msn.com' => 'q', 'bing.com' => 'q', 'msxml.excite.com' => 'qkw', 'search.lycos.com' => 'query', 'alltheweb.com' => 'q', 'search.aol.com' => 'query', 'search.iwon.com' => 'searchfor', 'ask.com' => 'q', 'ask.co.uk' => 'ask', 'search.cometsystems.com' => 'qry', 'hotbot.com' => 'query', 'overture.com' => 'Keywords', 'metacrawler.com' => 'qkw', 'search.netscape.com' => 'query', 'looksmart.com' => 'key', 'dpxml.webcrawler.com' => 'qkw', 'search.earthlink.net' => 'q', 'search.viewpoint.com' => 'k', 'mamma.com' => 'query'); $delim = false; if (isset($search_engines[$ref])) { $delim = $search_engines[$ref]; } else { if (strpos('ref:'.$ref,'google')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.atomz.')) $delim = "sp-q"; elseif (strpos('ref:'.$ref,'search.msn.')) $delim = "q"; elseif (strpos('ref:'.$ref,'search.yahoo.')) $delim = "p"; elseif (preg_match('/home\.bellsouth\.net\/s\/s\.dll/i', $ref)) $delim = "bellsouth"; } return $delim; } /** * retrieve the search terms from search engine query * */ function pk_stt2_function_get_terms($d) { $terms = null; $query_array = array(); $query_terms = null; $query = explode($d.'=', $_SERVER['HTTP_REFERER']); $query = explode('&', $query[1]); $query = urldecode($query[0]); $query = str_replace("'", '', $query); $query = str_replace('"', '', $query); $query_array = preg_split('/[\s,\+\.]+/',$query); $query_terms = implode(' ', $query_array); $terms = htmlspecialchars(urldecode(trim($query_terms))); return $terms; } /** * get the referer * */ function pk_stt2_function_get_referer() { if (!isset($_SERVER['HTTP_REFERER']) || ($_SERVER['HTTP_REFERER'] == '')) return false; $referer_info = parse_url($_SERVER['HTTP_REFERER']); $referer = $referer_info['host']; if(substr($referer, 0, 4) == 'www.') $referer = substr($referer, 4); return $referer; } $referer = pk_stt2_function_get_referer(); if (!$referer) return false; $delimiter = pk_stt2_function_get_delimiter($referer); if( $delimiter ){ $term = pk_stt2_function_get_terms($delimiter); } echo $term; ?> May someone help? Natasha T Hi all How do I modify the below code to search multiple tables in mySQL database? $query = "select * from store_items where description like \"%$trimmed%\" or title like \"%$trimmed%\" or dimensions like \"%$trimmed%\" order by id ASC"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); It is for a search function and I need it to search another table called 'about_text' and 'faq_text' Thanks Pete Hello. I am working on a php script for searching a database table. I am really new to this, so I used the this tutorial http://www.phpfreaks.com/tutorial/simple-sql-search I managed to get all the things working the way I wanted, except one important and crucial thing. Let me explain. My table consist of three columns, like this: ID(bigint20) title(text) link (varchar255) ============================= ID1 title1 link-1 ID2 title2 link-2 etc... Like I said, I managed to make the script display results for a search query based on the title. Want I want it to do more, but I can't seem to find the right resource to learn how, is to place a "Download" button under each search result with its corresponding link from the table. Here is the code I used. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'user'; $dbPass = 'pass'; $dbDatabase = 'db'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Search terms must be longer than 3 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT title, link FROM db WHERE title LIKE '%{$searchTermDB}%'"; $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="search?" name="searchForm"> Search for title: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /> <input type="submit" name="submit" value="Search" /> </form> <?php echo (count($results) > 0)?"Rezultate lucrari de licenta sau disertatie pentru {$searchTerms} :<br /><br />" . implode("", $results):""; ?> $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$row['title']}<br /> Download - this is the button I want to link to the title results - and maybe other links too - <br /> "; $i++; I would like the results to be displayed like this Results for SearchItem: Result 1 Download | Other link Result 2 Download | Other link etc.... or something like this. So, how do I add the data from the link row into a text(Dowload), within an <a href> tag (well, at least I guess it would go this way) ? My first tries (fueled by my lack of knowledge) where things like $results[] = "{$row['title']}<br /> <a href="{$row['link']}">Download</a> <br /> "; but I keep getting lots of errors, and then I don't know much about arrays and stuff (except basic notions); So there it is. I am really stuck and can't seem to find any workaround for this. Any suggestions? (examples, documentation, anything would do, really) Thanks, Radu I am developing a intranet forum in Php and MySQL and I am using ajax to display searched results on the same page but right now I am using query LIKE text% to search in database which is slower. but I want to make it fast search engin which can parse *,+ and show result. Since I am using ajax i am not able to use free search engin,so if possible pls provide a complete solution Hello, I'm developing a website that asks the user to submit a keyword for a search. The results should display matches for this keyword, but also show matches for related keywords (in order of relevenace!). I'm planning on building up a library of which search terms users use in the same sessions (e.g. if someone searches for "it jobs" and "php jobs", I'll know the terms are correlated), and I'll also measure the click-through rates of the items on the results list. I've been spending all weekend trying to map out the design for this but it's proving incredibly complicated and I think the solution is likely to be on the internet somewhere already?! Please could someone point me in the right direction if you've come accross this problem before? Thanks a million, Stu I have code to search a database of members, I can search by lastname but having a little problem. I want to be able to search by lastname starting with the first letter. (ie: a or b or c or d and so on). As it is right now I can only search by first letter of last name if I add % to the search (ie: a% b% c%) will give me all members with the last names starting with the approiate letter designation. I'm not sure how to handle this, any help would be appreciated. Thanks. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> </head> <body> <center><table cellspacing="10" cellpadding="10" width="750" border="0"> <h4>Search</h4> <form name="search" method="post" action="<?php $PHP_SELF?>"> Seach for: <input type="text" name="find" /> in <Select NAME="field"> <Option VALUE="lname">Last Name</option> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> <?php // check to see if anything is posted if (isset($_POST['find'])) {$find = $_POST['find'];} if (isset($_POST['searching'])) {$searching = $_POST['searching'];} if (isset($_POST['field'])) {$field = $_POST['field'];} //This is only displayed if they have submitted the form if (isset($searching) && $searching=="yes") { echo "<h4>Results</h4><p>"; // If they did not enter a search term we give them an error if (empty($find)) { echo "<p>You forgot to enter a search term"; exit; } // Otherwise we connect to our Database mysql_connect("localhost", "root", "1910") or die(mysql_error()); mysql_select_db("cmc_member") or die(mysql_error()); // We preform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); // Now we search for our search term, in the field the user specified $results = mysql_query("SELECT * FROM members WHERE upper($field) LIKE'$find'"); // And we display the results if($results && mysql_num_rows($results) > 0) { $i = 0; $max_columns = 3; while($row = mysql_fetch_array($results)) { // make the variables easy to deal with extract($row); // open row if counter is zero if($i == 0) echo "<tr>"; // make sure we have a valid product ALIGN='CENTER' if($fname != "" && $fname != null) echo "<td ALIGN='CENTER'><FONT COLOR='red'><b>$fname $lname</b></FONT><br> $address <br> $city $state $zip <br>$phone<br><a href=\"mailto: $email\">$email</a><br></td>"; // increment counter - if counter = max columns, reset counter and close row if(++$i == $max_columns) { echo "</tr>"; $i=0; } // end if } // end while } // end if results // clean up table - makes your code valid! if($i < $max_columns) { for($j=$i; $j<$max_columns;$j++) echo "<td> </td>"; } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches = mysql_num_rows($results); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> </tr> </table></center> </body> </html> Hello All, I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using: <?php session_start(); function verify() { //verify that the user is logged in via the login page. Session_start has already been called. if (!isset($_SESSION['loggedin'])) { header('Location: /index.html'); exit; } //if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. $user === $_SESSION['name']; //Connect to Databse $link = mysqli_connect("127.0.0.1", "database user", "password", "database"); if (!$link) { echo "Error: Unable to connect to MySQL." . PHP_EOL; echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL; echo "Debugging error: " . mysqli_connect_error() . PHP_EOL; exit; } //SQL Statement to lookup privlege information. if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) { //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv. while ($row = $result->fetch_assoc()) { $priv === $row["su"]; } } // close SQL connection. mysqli_close($link); // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special //accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. if ($priv !== 1) { echo $_SESSION['name']; echo "you have privlege level of $priv"; echo "<br>"; echo 'Your account does not have the privleges necessary to view this page'; exit; } } verify(); ?>
I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); Hello everyone, I can get Test 2 to successfully operate the if statement using a variable variable. But when I try the same method using a session variable (Test 1) the if statement is not executed. Please could you tell me why the if statement in Test 1 is not being executed? Code: [Select] <?php # TEST 1 $_SESSION[test_variable] = "abcd"; $session_variable_name = "_SESSION[test_variable]"; if ($$session_variable_name == "abcd") { echo "<br>line 373, abcd<br>"; } # TEST 2 $test_variable = "efgh"; $test_variable_name = "test_variable"; if ($$test_variable_name == "efgh") { echo "<br>line 379, efgh<br>"; } ?> Many thanks, Stu I have a script that adds points together based upon the placing. This is the actual script: Code: [Select] <? $points = 0; if($place === '1st') {$points = $points + 50;} elseif($place === '2nd') {$points = $points + 45;} elseif($place === '3rd') {$points = $points + 40;} elseif($place === '4th') {$points = $points + 35;} elseif($place === '5th') {$points = $points + 30;} elseif($place === '6th') {$points = $points + 25;} elseif($place === '7th') {$points = $points + 20;} elseif($place === '8th') {$points = $points + 10;} elseif($place === '9th') {$points = $points + 10;} elseif($place === '10th') {$points = $points + 10;} elseif($place === 'CH') {$points = $points + 50;} elseif($place === 'RCH') {$points = $points + 40;} elseif($place === 'TT') {$points = $points + 30;} elseif($place === 'T5') {$points = $points + 30;} elseif($place === 'Champion') {$points = $points + 50;} elseif($place === 'Reserve Champion') {$points = $points + 40;} echo "Total HF Points: $points"; ?>What it *should* do (my friend's script works the same way and it works) it starts at points = 0, than if there is a first place, it adds 50, and so forth until it reaches the end. It is included into a file, in this area: Code: [Select] <div class="tabbertab"> <h2>Records</h2> <? $query92 = "SELECT * FROM THISTABLE WHERE VARIABLE='$id' OR VARIABLE = '$name' ORDER BY ABS(VARIABLE), VARIABLE"; $result92 = mysql_query($query92) or die (mysql_error()); echo "<table class='record'> <tr><th>Show</th> <th>Class</th> <th>Place</th></tr> "; while($row92 = mysql_fetch_array($result92)) { $class = $row92['class']; $place = $row92['place']; $entries = $row92['entries']; $race = $row92['show']; $purse = number_format($row92['purse'],2); echo "<tr><td>$race</td> <td>$class</td> <td>$place</td></tr>"; } ?> <tr><td colspan='3'><div align='right'><? include('includes/points.php'); ?></div></td></tr> </table> </div> This is the code that is relevant. When ended here, it echoes the last place that appears in the results (such as a 5th place echoing 30 points). When I move it to be included in the while loop, it shows Total Points: 50 Total Points: 25 Total Points: 10 (depending on the results displayed on that page). What am I doing wrong? |