PHP - If Statement + Numbers In A Range With Decimals

Code: [Select]
$_POST['amount'] = intval($_POST['amount']);
if ($_POST['amount'] < 0){
message($lang_common['Bad request']);
}
if (!is_numeric($_POST['amount'])){
message($lang_common['Bad request']);
}
echo $pun_user['gold'];
echo '<br>';
echo $_POST['amount'];
exit;
if I enter 0.05
 in my gold input textbox and submit it, it reads 0, it doesn't read the decimal values, i need it to read them, but I also need it to be secure and use intval.. help

Hi guys,

I've got a line of code that asks for a column called "distance_completed" to be displayed as part of a string.

This column tells users how far people have run in a running race.

I set up this field in my database to 11,3 so all distances appear with a decimal at the end, and then 3 digits after the decimal place.

How would I alter the code so that the numbers that don't have any information in the places section just appear as integers Eg: 42 instead of 42.000 (for someone who ran exaclty 42km) and those that do have information in the decimal places appear correctly (eg: if a person ran 42km and 195m, it would appear as 42.195).

I think this is probably the only line of code that would need modification:

Code: [Select]

echo ($row['time'] != null)?$row["time"]:"dnf at ".$row["distance_completed"]."km.";

Hi,
I need to sort variables in groups of up to 15 and put it in an array. For example:
$exstract['center_tabOpBody_0'] =5
$exstract['center_tabOpBody_1'] =6
$exstract['center_tabOpBody_2'] =8
$exstract['center_tabOpBody_3'] =1


Should yield:
ARRAY(
          = center_tabOpBody_1,center_tabOpBody_2,center_tabOpBody_3 // <-----15 [1] = center_tabOpBody_0 //<----5
)

Is there some simple function do do the "efficiency" sort?

Thanks,
Vadim

I want to find the first sentence in a string without counting decimals. Here is the code I have, but I still want it to display the decimals, but I don't want it to count as the end of a sentence.

$content = "This is my test string which is 3.5% of what I'm trying to do. This is only a test.";

Code: [Select]
function first_sentence($content)
 {
if(preg_match('/[0-9]+\.[0-9]/', $content, $num)) {
$number = "$num[0]";
$content = ereg_replace("$number","", $content);
}
preg_match('/^.*[^\s](\.|\?|\!)/U', $content, $match);
$string = $match[0];

$title_count = strlen($match[0]);
if($title_count > "6"){
return "$match[0]";
}
else {
$content2 = ereg_replace("$match[0]","", $content);
preg_match('/^.*[^\s](\.|\?|\!)/U', $content2, $step);
return "$match[0] $step[0]";
}}
Currently this is what it displays: This is my test string which is % of what I'm trying to do.
This is what I want it to display: This is my test string which is 3.5% of what I'm trying to do.

Hi - To me, this doesn't make sense.   My Order form uploads product weights in an array . If I echo out those weights they are fine ie 25.25

However, when I try to update the DB for some reason, the for loop strips out all but the first digit, so 25.25 becomes '2' or indeed if I had entered 9999999 it just '9' is entered in to the DB.

I have tried using number_format to pre-process the decimals, - but I get an error saying you can not use it in a write format.

Many Thanks to anyone who can help with this  !!


PS - I have abbreviated the below code for clarity:

Code: [Select]
$weight = $_POST['weight'];

        for ($i = 0; $i < $numloops ; $i++)

      {
       $sql ="
UPDATE `confirmedorder`
SET orderid = '$orderid[$i]', weight='$weight[$i]',status='finished', ordervalue='$ordervalue'
WHERE customerid = $customerid
";
$this->db->query($sql);
}

Hi there.

I am trying to display numbers if they have the numbers like:

number_format($price,2)

This gives us two decimal places i.e 7.23

Now thats fine, I would like to round the last two decimal places. I would like to make it 7.25, (rounding it from 7.23 to 7.25)

Similarly making:

12.44 to 12.45
33.18 to 33.20
52.13 to 52.15

So actually rounding the last two places. Coz obviously customers won't be able to pay 52 dollars 13 cents. So therefore rounding the last cent's (decimal part) making it to 52.15

Thank you.

All comments and feedback are welcomed.


(d

Ok so say I have php do some calculations for me

Code: [Select]

$Value1 = 300;
$Value2 = 100000;
$FirstRatio = $Value1 / $Value2;

$Value3 = 8000;
$Value4 = 6000000;
$SecondRatio = $Value3 / $Value4;


$FirstRatio = 0.003
$SecondRatio = 0.0013

How would I go about doing these calculations and then sorting $FirstRatio and $SecondRatio and then it would take the highest ratio ($FirstRatio) and it would echo the value?

I am currently working on a date range script and wondering if anybody think of an easier way to do this, doing up to next 8 weeks?  This one starts on a Sunday. I also need to do one starting on a Monday (will figure that one later)

$thisweek = date("Y-m-d");
$week = date('w', strtotime($thisweek));
$date = new DateTime($thisweek);
$firstWeek = $date->modify("-".$week." day")->format("M d");
$endWeek = $date->modify("+6 day")->format("M d");
echo $firstWeek." - ";
echo $endWeek;

$nextweek = date(("Y-m-d"), strtotime("+7 Days"));
$week1 = date('w', strtotime($nextweek));
$date1 = new DateTime($nextweek);
$firstWeek1 = $date1->modify("-".$week1." day")->format("M d");
$endWeek1 = $date1->modify("+6 day")->format("M d");
echo $firstWeek1." - ";
echo $endWeek1;

 

This works if say I do 192.168.0.1 - 192.168.1.254 it will work. However doing 192.168.0.1 - 192.168.1.10 will only generate up to .10 on both IP schemes. I see why, but I cannot figure out a way around this...

Thanks!

$start = explode('.', '192.168.10.1');
$end = explode('.', '192.168.11.10');

/**
 * Final output...
 */
$a = 0;
$b = 0;
$c = 0;
$d = 0;

// First segment
for ($a = $start[0]; $a < 1 + $end[0]; $a++)
{
// Second segment
for ($b = $start[1]; $b < 1 + $end[1]; $b++)
{
// Third segment
for ($c = $start[2]; $c < 1 + $end[2]; $c++)
{
// Fourth segment
for ($d = $start[3]; $d < 1 + $end[3]; $d++)
{
echo "{$a}.{$b}.{$c}.{$d}<br />";
}
}
}
}

Why is this not working?
Code: [Select]
$result = mysql_query("SELECT * FROM contacts WHERE type = 'consumer' AND sent BETWEEN '".date("Y-m-d")."' AND '".date("Y-m-d", strtotime("-7 days"))."'")
or die(mysql_error());
$numrows = mysql_num_rows($result);
if($numrows < 0 ){
echo "No records found";
}

The record that is stored in the sent column is like this "2011-11-03 14:42:12", so there is a record in there, but nothing is showing up.

Can anyone see why?

thanks in advance

I have range of categories from 1 to 999

With this is piece of code:

foreach (range(96,204) as $number)
if (Tools::getValue('id_category') == $number)
return;
$this->filterResults();
return $this->display( __FILE__, 'block-center-filter.tpl');

iw managed to avoid display of 'block-center-filter.tpl' in that range but it shows in every other categories.

What i need is opposite... i would like to dont show except in that range...
how to do that?

Hello,

I'm very disapointed because I don't know how do it this.
I'm explain.
I have a database with one input date_arrival and second date_departure.
Two dates are saved in SQL format : 2014-03-02.

After my SQL request to select all dates in database I'd like to add dates between date_arrival and date_departure and for each line.
For example I have
date_arrival date_departure
line 1 : 2014-02-01 2014-02-05
line 2 : 2014-02-10 2014-02-15

In fact at the end, I have to send the result like this (with JSON) :

["2014-02-01","2014-02-02","2014-02-03","2014-02-04","2014-02-05","2014-02-10","2014-02-11","2014-02-12","2014-02-13","2014-02-14","2014-02-15"] 

Can you give me some help to add intermediates values in an array ?
Thx

if i want find included a word in the a range how can i do it?

example : Quote

array("problem is an obstacle, impediment, difficulty or challenge, or any situation that invites resolution; the resolution of which is recognized as a solutionquestion raised for inquiry, consideration, or solution proposition in mathematics or physics stating something to be done");



how can i find only start 20 charecter and my found word after 20 character by end

example :if my word be inquiry

i want find :...soluti

Quote

onquestion raised for inquiryconsideration, or solution proposition...



[/size]

Hi,

I am trying to come up with the best way to create a range voting form.
Each candidate will have a "confidence" value associated with the choice.(using a pulldown menu?)
So for March Madness it would be:
Team .......
Confidence Value.....

each team could only be voted to finish the tournament in a particular place, and a value would be associated with that choice. The total choices possible determines the range of confidence value possible.
So....if there are 16 teams to vote on....the confidence value would range from 1-16. The voter would assign his highest available value to the team he was most confident in landing in that particular position.
Example: 16 teams - 16 conf vals -

if certain Duke will end up at #1 - then vote :
#1 = Duke, conf val 16

next, if almost as certain that NC will end up last - then vote:
#16 = NC, conf val 15

next most certain
"", conf val 14
and so on....

the tricky part is making sure that the form code validates each conf val so that it is used, but used on ly once....

ideally the form could return values that could then be imported into excel and comopared.


has this been done somewhere?
Can you help ?

hope so....

thanks!!

Okay we are using a javascript, but the javascript that the site comes from has bans all irans ips... and it loads slow for those people, how would I place a if statement saying dont load this javascript if in Iran, thanks... I know how to do it, but I can't find a real set number, and I would use just 1 ip but the guy has dynamic... thanks ahead of time