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PHP - Post Data Help
im trying to understand this Post Data script it's not posting, no errors:
postdata.php Code: [Select] <?php //create array of data to be posted //$post_data['firstName'] = 'Name'; $post_data['item_name'] = '12345'; //traverse array and prepare data for posting (key1=value1) foreach ( $post_data as $key => $value) { $post_items[] = $key . '=' . $value; } //create the final string to be posted using implode() $post_string = implode ('&', $post_items); //we also need to add a question mark at the beginning of the string $post_string = '?' . $post_string; //we are going to need the length of the data string $data_length = strlen($post_string); //let's open the connection $connection = fsockopen('www.example.com', 80); //sending the data fputs($connection, "POST /i.php HTTP/1.1\r\n"); fputs($connection, "Host: www.example.com \r\n"); fputs($connection, "Content-Type: application/x-www-form-urlencoded\r\n"); fputs($connection, "Content-Length: $data_length\r\n"); fputs($connection, "Connection: close\r\n\r\n"); fputs($connection, $post_string); //closing the connection fclose($connection); ?> reuslt should be posted here i.php Code: [Select] <?php require('database_connection.php');?> <?php if(isset($post_items[0])) { //$Subscription_id = mysql_real_escape_string($md5c); //$PropertyID = mysql_real_escape_string($rowData['ID']); //$User_ID = mysql_real_escape_string($rowData['User_ID']); $item_name=mysql_real_escape_string($post_items[0]); $query = 'INSERT INTO SP_subscriptions(id,) values("'.$item_name.'")'; //$query = 'INSERT INTO SP_subscriptions(id,PropertyID,User_ID) values("'.$item_name.'","'.$PropertyID.'","'.$User_ID.'")'; $success = mysql_query($query); } else { $item_name=54321; $query = 'INSERT INTO SP_subscriptions(id) values('.$item_name.')'; //$query = 'INSERT INTO SP_subscriptions(id,PropertyID,User_ID) values("'.$item_name.'","'.$PropertyID.'","'.$User_ID.'")'; $success = mysql_query($query);} //var_dump($_POST); //var_dump($query); echo $query; ?> Similar Tutorials
$post='{"cart_items":[{"configuration":{"price":100,"recharge_number":"9999999999"},"product_id":"999","qty":1}]}';
i try this n reslut was :There are no valid items in cart: help me plz
Edited by ShivaGupta, 30 November 2014 - 01:11 AM. Hi guys, I think I may be losing my marbles over this form I've put together. I'm trying to get my code to post the following to a database but my MySQL and PHP isn't that good, so wondering if any one could possibly suggest what I could do? Here is my code: Code: [Select] <?php // we check if everything is filled in if(empty($_POST['fname']) || empty($_POST['lname']) || empty($_POST['email'])) { die(msg(0,"All the fields are required")); } // is the sex selected? if(!(int)$_POST['sex-select']) { die(msg(0,"You have to select your sex")); } // is the birthday selected? if(!(int)$_POST['day'] || !(int)$_POST['month'] || !(int)$_POST['year']) { die(msg(0,"You have to fill in your birthday")); } // is the email valid? if(!(preg_match("/^[\.A-z0-9_\-\+]+[@][A-z0-9_\-]+([.][A-z0-9_\-]+)+[A-z]{1,4}$/", $_POST['email']))) die(msg(0,"You haven't provided a valid email")); // I think here is where I need to put something to get the data into a table! echo msg(1,"registered.html"); function msg($status,$txt) { return '{"status":'.$status.',"txt":"'.$txt.'"}'; } ?> How do I get the $_POST['day'] and $_POST['month'], $_POST['year'] etc into a table? It should be so easy but my head is hurting from trying lots of things and tutorials online. Any thoughts my PHP Freaks? Hi I have a little strange problem. I cannot get the post data from my form. It works fine if there is 10 or 15 user but reaching 40 or more than form values not posting. This is output of size: echo (int) $_SERVER['CONTENT_LENGTH']; ===== 22164 Code: [Select] if(isset($_POST['hiddenField'])) { // do some work; } $sql = mysql_query("SELECT id, name FROM user WHERE shop_id = '" .$_SESSION['id']. "' ORDER BY name ASC"); while($row = mysql_fetch_array($sql)) { echo ' <div style="width:100%; border:solid 1px #CCC; background-color:#f1e7e7; margin-bottom:5px;"> <table class="tableSmall"> <tr><th width="81">' .$row['name']. '</th><th width="71">'; echo $grl_pic .' </th> <td width="622"><table width="100%"> <tr>'; for($j=0; $j<7; $j++) { $sql2 = mysql_query("SELECT user_master_id, user_start, user_end FROM work_master WHERE user_master_id = '" .$row['id']. "' AND date = '" .$days_no_kanji[$j]. "'"); $row2 = mysql_fetch_array($sql2); if(mysql_num_rows($sql2) == 0) { $start = "00:00"; $end = "00:00"; $m = 0; } else { $start = $row2['user_start']; $end = $row2['user_end']; $m = 1; } echo ' <th><input type="hidden" name="userData[]" value="' .$row['id']. '_' .$j .'_' .$m. '" /> <select name="' .$row['id']. '_' .$j .'_' .$m. '_start">' .ShopHour($start). '</select><br />～<br /> <select name="' .$row['id']. '_' .$j .'_' .$m. '_end">' .ShopHour($end). '</select> </th>'; } echo ' </tr> </table></td> </tr> </table> </div>'; } Is there someone has any idea why php is not posting? Hi guys, I am creating a quiz system for my personal site, I am done with all the quiz questions creating part, but I am stuck with something like... user taking a random sql generated quiz and submitting it.. Here's randomly generated sql quiz, even the answers are in random order: <form method="post"> <b>1. What is color or sky</b> <ol> <li><input name="question_3_answer" type="radio" value="6" /> sky</li> <li><input name="question_3_answer" type="radio" value="8" />blue</li> <-- true <li><input name="question_3_answer" type="radio" value="3" />red</li> </ol> <b>2. What is name of my cat</b> <ol> <li><input name="question_6_answer" type="radio" value="9" />brat</li> <--true <li><input name="question_6_answer" type="radio" value="7" />rat</li> </ol> <b>3. What is name of my pet</b> <ol> <li><input name="question_18_answer" type="radio" value="9" />cat</li> <--true <li><input name="question_18_answer" type="radio" value="7" />dog</li> </ol> </form> Now this is tricky part for me is.. receiving these data in another page.. since it's randomly generated questions, how do I know which question it is? here's example I've tried : $list_all_quiz_questions = $db->get_row("SELECT question_id, its_true_ans_id FROM question_table WHERE quiz_group = 'ef23fsdfers3e' "); $i = 1; foreach ($list_all_quiz_questions as $myquestion) { $answer.$i == $_POST["question_".$myquestion->question_id."_answer"]; //?????????? not working lol ;(( $i++ } Hi All, Not sure if this is a silly question so here we go. I have some divs that have data attributes (data-value). When i submit and post the form, can i use these values as part of the submission and put their data-value into the db? Thanks as always in advance. Hello
I have a nusoap web service running, which is fine, but I need to send a new variable in the parameters which decides what database to use...
This is how I call the function:
$params = array(
'region' => '1'
);
$response1 = $client->call('function1', array ($params)); // response will be in JSON
So basically I'm using PHP to solve a math problem for me. The user puts in a few parameters and the program runs those numbers through the algorithm and spits out a bunch of xy coordinates. I'm using the PHP SELF method to retrieve the user input. This all works fine, but it's afterwords that I run into problems. I create a drop down menu of all the x values and I want the user to be able to choose any x value they wish and to have the corresponding y value be displayed. The problem is that I have to use another POST command for this and when I do, it wipes out all the computed data. Of course the y-value is never displayed, and there lies the problem. I'm sure there are many ways to get around this, but I could not find one out myself. Anyone have any ideas? i am trying to fit this php code to so when ever i upload a video link to the database it prints in the divs from left to right. ( i have made blank boxes for where the videos should be, so you guys can see what i mean. i will give you the code here. Code: [Select] <?php $query = mysql_query("SELECT * FROM `G4V_Videos` ORDER BY `id` DESC") or die(mysql_error()); while ($data = mysql_fetch_array($query)) { ?> ID-nummer: <?php print $data['id']; ?> - Name: <?php print $data['navn']; ?> - <a href="/Video.php?id=<?php print $data['id']; ?>"><img src="http://i.ytimg.com/vi/<?php print $data['link'];?>/hqdefault.jpg" width="200" height="160" /></a><br /> <a href="/Video.php?=<?php print $data['id']; ?>"> <?php } ?> and the website is here, http://www.game4vids.com/index.php and i also want it so once i have used up all the boxes it posts the new video in box one and overwrites the old one if you get what i mean. This website is a great example of what i mean. http://www.retardo.dk Hello, I need to post plenty of data to a file with a java file with a .do extension using a php program. How do I get to auto-post mass data in php from a database straight to this java file? Put in mind that each mysql record is posted as its own form as in: <form ...>mysql record</form> Thanks in advance I'm doing an ajax call from javascript using jquery library: Code: [Select] ajaxCall: function(process, obj, type){ $.post("registration-post.php", type + "=" + process, function(data){ if(data==""){ $(obj).css(registration.errorNotificationType, registration.validatedColour); }else{ $('.error').append($.trim(data) + "<br />"); $(obj).css(registration.errorNotificationType, registration.errorColour); registration.progress = false; } } ); } When the ajax calls the php page, I want the php page to know what post information the javascript has sent, rather than pre-defining what the PHP should be trying to retrive from the POST data. Something like // pseudo $_POST["whateverwassentfromajax"] I want to do this because I want to have one function doing everything. So in my javascript I am saying, check if the username and email have already been used... But i dont want to call two different php functions. //pseudo function 1(){ $_POST["username"]; } function 2(){ $_POST["email"]; } Is there a special way to know which post data has been sent. Or do i need to do a few if statements in php. Hey I have checkbox and when the user tick one or more box these should be stored as 0 or 1 but since its while loop, I am not sure how to work that out. So far I have <html> <?php session_start(); include '../Database/connection.php'; $Value24 = mysql_real_escape_string(trim($_POST['myselect'])); $_SESSION['smodule'] = $Value24; ?> <body> <form action="Test_Completed.php" method="post"> <?php $query = mysql_query(" SELECT * FROM Test WHERE Tes_ID = '{$_SESSION['smodule']}' "); while( $query1 = mysql_fetch_array($query) ) { echo "Test Name: {$query1['Tes_Name']}"; } ?> <br> <?php $query = mysql_query(" SELECT * FROM User WHERE Use_ID = '{$_SESSION['ssubject']}' "); while( $query1 = mysql_fetch_array($query) ) { echo "User Name: {$query1['Use_Name']}"; } ?> <br> <?PHP include '../Database/take_an_exam.php'; $intNumber = 1; while($info = mysql_fetch_array( $sql )) { echo "$intNumber, {$info['Que_Question']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice1[]\" value=\"{$info['Que_Choice1']}\" /> "; echo "{$info['Que_Choice1']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice2[]\" value=\"{$info['Que_Choice2']}\" /> "; echo "{$info['Que_Choice2']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice3[]\" value=\"{$info['Que_Choice3']}\" /> "; echo "{$info['Que_Choice3']} <br />\n"; echo "<input type=\"checkbox\" name=\"choice4[]\" value=\"{$info['Que_Choice4']}\" /> "; echo "{$info['Que_Choice4']} <br />\n"; $intNumber++; } ?> <input type="submit" value="submit"/> </body> </html> </body> </html> <?PHP $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Examination", $con); //Get & clean value from POST data $choice1 = mysql_real_escape_string(trim($_POST['choice1'])); $choice2 = mysql_real_escape_string(trim($_POST['choice2'])); $choice3 = mysql_real_escape_string(trim($_POST['choice3'])); $choice4 = mysql_real_escape_string(trim($_POST['choice4'])); $user = mysql_real_escape_string(trim($_SESSION['username1'])); //Create and run INSERT query $query = "INSERT INTO Answer (`Ans_Answer1`, `Ans_Answer2`, `Ans_Answer3`, `Ans_Answer4`, `Que_ID`, `Use_ID`) VALUES ('{$choice1}', '{$choice2}', '{$choice3}', '{$choice4}', '{$query1}', '{$user}')"; $result = mysql_query($query) or die (mysql_error()); $_SESSION['Ans_ID'] = mysql_insert_id(); header("location:check.php"); ?> I needed a server side PHP validation script for my form to use on top of client side Javascript as a backup. I found a nice package where I just include the validator and set a few options then it does the rest. However it doesn't seem to work with the action="whateveraction.php" for the form. It will skip all the validation and immediately go to the action script. So I left that blank as you can see in the form below and figured I would send the post data somehow to the script using PHP when the validation is successful. However I am stumped on how to do that can I get some coding help? This is the small validation script. I will attach the formvalidator.php in this post. Code: [Select] <?php require_once "formvalidator.php"; if(isset($_POST['submit'])) { $validator = new FormValidator(); $validator->addValidation("age","req","Please fill in your Age"); $validator->addValidation("mcid","req","Please fill in your Minecraft Username"); $validator->addValidation("description","req","Please fill in a Description"); if($validator->ValidateForm()) { //need something here to have it send the post data to /mcbuildapp/form_submit.php } else { echo "<div class=blockrow><b><font size=5>Form Errors:</font><b></div>"; $error_hash = $validator->GetErrors(); foreach($error_hash as $inpname => $inp_err) { echo "<div class=blockrow><p><font color=red>$inp_err</font></p>\n</div>"; } } } Then the form if it matters.... Code: [Select] <div class="blockrow"> <font size=4><b>Minecraft Building Rights Application</b></font> <br /> <br /> <b>Failing to fill in any of these fields sufficiently will result in an automatic denial of your application!</b><br /> <b>Think of it this way, being lazy and applying wrong is only wasting your time. Take the time to do it correctly the first time.</b> <br /> <br /> <b><font color=red>To ensure proper user authentication and security you must first join the server at least once before applying for your building rights to work!</font></b> <br /> <br /> <form action="" id="mcbuilderapp" name="mcbuilderapp" method="post"> <label><b>Your Minecraft Username (required)</b><br /> Use exact capitalization and punctuation that matches your Minecraft.net account!</label> <br /> <br /> <input type="text" name="mcid" id="mcid" maxlength="25"/> <br /> <br /> <label><b>Your Age (required)</b></label> <br /> <br /> <input type="text" name="age" id="age" maxlength="3"/> <br /> <br /> <label><b>Describe Yourself (required)</b><br /> Describe yourself in <b>no less</b> than 3 sentences using <b>correct grammar</b>.</label> <br /> <br /> <textarea name="description" id="description" minlength="10" maxlength="1000" cols=60 rows=5 wrap="physical"> </textarea> <br /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </div> MOD EDIT: PHP manual tags changed to code tags . . . [attachment deleted by admin] How can I encrypt POST data from a form? Basically, I want to ensure that the data on the form is not in plain text ever. Is this possible? <form method="post"> <input type="text" name="email" size="40"> <input type="password" name="password"/> ... Basically, when this posts, I want to do a foreach on $_POST and see something like: password = 1f3870be274f6c49b3e31a0c6728957f and not password = stringTheUserTyped I hope what I'm asking for is clear. (PHP 5.2.14) Thanks! I'm trying to send a HTTPS POST request with XML data to a server using PHP. Anything sends to the server requires authentication therefore I'll use cURL. Some background info.: the XML data is to request the server to upload a file from a specific URL to its local storage. One rule of using this API is I MUST set the content type for each request to application/xml. This is what I've done but isn't working... <?php $fields = array( 'data'=>'<n1:asset xmlns:n1="http://.....com/"><title>AAAA</title><fileName>http://192.168.11.30:8080/xxx.html</fileName><description>AAAA_desc</description><fileType>HTML</fileType></n1:asset>' ); $fields_string = ""; foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); $url = "https://192.168.11.41:8443/"; $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_POST, count($fields)); curl_setopt($ch, CURLOPT_POSTFIELDS, $fields_string); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, false); curl_setopt($ch, CURLOPT_HEADER, true); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch, CURLOPT_USERPWD, "admin:12345678"); curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-type: application/xml', 'Content-length: '. strlen($fields_string)) ); $result = curl_exec( $ch ); curl_close($ch); echo $result; ?> I am expected to get an XML reply of either upload successful or upload failed. But instead I am getting this error message. HTTP/1.1 415 Unsupported Media Type Server: Apache-Coyote/1.1 Content-Type: text/xml;charset=UTF-8 Content-Length: 0 Date: Thu, 02 Dec 2010 03:02:33 GMT I'm sure the file type is correct, the XML format is correct. I've tried urlencode the fields but it didn't work. What else I might have done wrong? Hello guys. I have a form with 20 images. My user have to write a description for each image and when submitting the form the user will get an HTML code which will display an album. My problem is that my users want to choose a sequence of the images in the album. How do I solve that? I tried with making a select with 20 options (number 1-20) for each image and a desription for the user to place them in a correct sequence but I don't know how to do it. And another problem is when a user chooses the same number for more than one image. Thanks I have a form with lots of fields. How would I run a loop to get each field name and data into an array, so i can then send it off to a function to process each field name / data differently. Instead of typing all the variables in the main function name for each post. Would a foreach statement work? Hello all, I have this issue: I have a form with several fields. I need to save to a session variable (in submit page) all of the fields upon submit and then post some of the fields to a https site using a POST request (i.e., doing a header('Location: https://mynewdomain.com/page.cfm?'.$data) won't cut it). Now, I can do it with javascript... a whole bunch of hidden fields in the between page and then auto submit the form to the mynewdomain.com domain using the post method. I am wondering whether there would be a better way for that. I know that Curl does it, with one glitch. When I set the parameter CURLOPT_FOLLOWLOCATION to true it redirects the user BUT it doesn't load any css or javascript from the new page. People say on the web to do a request for each file but I haven't figured out how to do it. Can anyone post an elegant/concrete solution to this problem or should I resort to Javascript? Thanks menwn I've looked at various cURL tutorials and the PHP manual, but I don't see what I'm doing wrong here. My goal is to be able to send data to test.php and then have that page run a MySQL query to insert the TITLE and MESSAGE into the database. Any comments? :/ post.php <?php if(isset($_GET['title']) && isset($_GET['message']) && isset($_GET['times'])) { $array = array('title' => urlencode($_GET['title']), 'message' => urlencode($_GET['message'])); foreach($array as $key => $value) { $fields = $key.'='. $value .'&'; } rtrims($felds); //set our init handle $curl_init = curl_init(); //set our URL curl_setopt($curl_init, CURLOPT_URL, 'some url'); //set the number of fields we're sending curl_setopt($curl_init ,CURLOPT_POST, count($array)); for($i = 0; $i < $_GET['times']; $i++) { //send the POST data curl_setopt($curl_init, CURLOPT_POSTFIELDS, $fields); curl_exec($curl_init); echo 'post #'.$i. ' sent<br/>'; } //complete echo '<b>COMPLETE</b>'; //close session curl_close($curl_init); } else { ?> <form action="post.php" method="GET"> <table> <tr><td>Title</td><td><input type="text" name="title" maxlength="30"></td></tr> <tr><td>Content</td><td><textarea name="message" rows="20" cols="45" maxlength="2000"></textarea></td></tr> <tr><td>Process Amount</td><td><input type="text" name="times" size="5" maxlength="3"></td></tr> <tr><td>START</td><td><input type="submit" value="Initiate Posting"></td></tr> </table> </form> <?php } ?> test.php <?php mysql_connect('host', 'user', 'pass'); mysql_select_db('somedb'); if($_POST['title'] && $_POST['message']) { mysql_insert("INSERT INTO tests VALUES (null, '{$_POST['title']}', '{$_POST['message']}')"); } echo '<hr><br/>'; //query $query = mysql_query("SELECT * FROM tests ORDER BY id DESC"); while($row = mysql_fetch_assoc($query)) { echo $row['id'].'TITLE: '. $row['title'] .'<br/>MESSAGE: '. $row['message'] .'<br/><br/>'; } ?> Iv tried asking a lot of people and have had no luck resolving this issue, so I will try here. I have created a Form which gathers its information from a Database. The first form is a Dropdown Option, which when submitted takes you to another page. The new page is Supposed to use the value from the Dropdown to search the database and return the proper rows to populate a few text areas to edit the values. This is where I am stuck. Compared to what most of you create this is probably sloppy and not too well structured, but I am new to this. Anyways, I will provide more information below now. The following is the initial page with the first form. This is where you would select what page you wish to edit. (I believe this may be where the issue resides) - (I included the 'num' value before the 'name' value so that I could see it is getting the value from the database, which it is) <form method="post" action="pageedit.php"><br /> <?php include "config.php"; echo "<select name=\"page\">\n"; $conn = mysql_connect("localhost", "$username", "$password"); if (!$conn) { echo "Unable to connect to DB: " . mysql_error(); exit; } if (!mysql_select_db("$database")) { echo "Unable to select $database: " . mysql_error(); exit; } $sql = "SELECT * FROM sitePages"; $result = mysql_query($sql); if (!$result) { echo "Could not successfully run query ($sql) from DB: " . mysql_error(); exit; } if (mysql_num_rows($result) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($result)) { echo "<option value='"; echo $row['num']; echo "'>"; echo $row['num']; echo " - "; echo $row['name']; echo "</option>"; } echo "</select>"; ?> <br /> <input type="submit" /> </form> And then the following is the page that the form is sent to when submitted: (I have attempted to Echo the 'num' value sent so that I could verify that it is indeed sent, but it is not. I will post the message I receive after the PHP snippet <form method="post" action="pageeditinsert.php"><br /> <?php include "config.php"; echo $_POST['num']; $num=$_POST['num']; $conn = mysql_connect("localhost", "$username", "$password"); if (!$conn) { echo "Unable to connect to DB: " . mysql_error(); exit; } if (!mysql_select_db("$database")) { echo "Unable to select $database: " . mysql_error(); exit; } $sql = "SELECT * FROM sitepages WHERE num = '$num'"; $result = mysql_query($sql); if (!$result) { echo "Could not successfully run query ($sql) from DB: " . mysql_error(); exit; } if (mysql_num_rows($result) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($result)) { echo "<input name'num' type='hidden' class='form1' value='"; echo $num; echo "' maxlength='10' id='cat' /><br /><br /><br />"; echo "<input name='name' type='text' class='form1' value='"; echo $row['name']; echo "' maxlength='20' id='name' /><br /><br />"; echo "<input name='desc' type='text' class='form1' value='"; echo $row['desc']; echo "' maxlength='100' id='desc' /><br /><br /><br />"; echo "<input name='title' type='text' class='form1' value='"; echo $row['title']; echo "' maxlength='100' id='title' /><br /><br /><br />"; echo "<input name'cat' type='hidden' class='form1' value='cat' maxlength='3' id='cat' /><br /><br /><br />"; } ?> <br /><br /><br /> <center><input type="submit" /><input type="reset" /></center> </form> Below is the message I receive when attempting to echo the POSTed 'num' value: Quote Notice: Undefined index: num in C:\wamp\www\gondieCOM\editor\edit\pageedit.php on line 16 Call Stack # Time Memory Function Location 1 0.0025 687600 {main}( ) ..\pageedit.php:0 (I am running the latest WAMP release on my personal PC for testing purposes until I have finished this and upload it to my hosting server) Anyways thanks for your time. Hopefully someone has an idea for me. II am new to jscript and AJAX and have a problem that I need to solve.
I have a form on which I need to input the RGB values of a color that will be used in the next PHP file.
I have choosen a color chooser written in jscript called JS-Color.
There are a number of pre-written scripts for choosing the color, of which I have used the following:
<script type="text/javascript" src="jscolor/jscolor.js"></script>
R<input id="red" size="5"> G<input id="grn" size="5"> B<input id="blu" size="5"> - - -
H<input id="hue" size="5"> S<input id="sat" size="5"> V<input id="val" size="5">
<p> Choose any color: <input class="color" id="myColor" onchange="
document.getElementById('red').value = this.color.rgb[0]*100 + '%';
document.getElementById('grn').value = this.color.rgb[1]*100 + '%';
document.getElementById('blu').value = this.color.rgb[2]*100 + '%';
document.getElementById('hue').value = this.color.hsv[0]* 60 + '°';
document.getElementById('sat').value = this.color.hsv[1]*100 + '%';
document.getElementById('val').value = this.color.hsv[2]*100 + '%';">
I am trying to work out how to use this to get the 3 values that I can post in a form.
Looking at the internet, I have found that AJAX is the easiest way to POST from jscript.
I have attempted to write some script, but I'm sure I'm way off the mark.
Here is my attempt:
<!--DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
Design by Free CSS Templates
http://www.freecsstemplates.org
Released for free under a Creative Commons Attribution 2.5 License
Name : Yosemite
Description: A two-column, fixed-width design with dark color scheme.
Version : 1.0
Released : 20091106
-->
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta name="keywords" content="" />
<meta name="description" content="" />
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<title></title>
<link rel="stylesheet" href="style.css" />
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
</head>
<body>
<div id="wrapper"><!-- start #wrapper -->
<div id="menu"><!-- start #menu -->
<ul>
<li class="current_page_item"><a href="index.php">Home</a></li>
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<h1>Page Title</h1>
<script type="text/javscript">
$(function (){
$('#form_id').on('submit', function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "/test_input.php",
data: $(this).color.rgb[0]*255, $(this).color.rgb[1]*255, $(this).color.rgb[2]*255,
success: function() {
alert('success');
}
});
});
});
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<script type="text/javascript" src="jscolor/jscolor.js?refresh=adsl"></script>
<script type="text/javascript">
jscolor.dir = "jscolor/";
</script>
<script type="text/javascript" src="jscolor/jscolor.js"></script>
R<input id="red" size="5"> G<input id="grn" size="5"> B<input id="blu" size="5">
H<input id="hue" size="5"> S<input id="sat" size="5"> V<input id="val" size="5">
<p> Choose any color: <input class="color" id="myColor" onchange="
document.getElementById('red').value = this.color.rgb[0]*255;
document.getElementById('grn').value = this.color.rgb[1]*255;
document.getElementById('blu').value = this.color.rgb[2]*255;
document.getElementById('hue').value = this.color.hsv[0]* 60 + '°';
document.getElementById('sat').value = this.color.hsv[1]*100 + '%';
document.getElementById('val').value = this.color.hsv[2]*100 + '%';">
<input type="submit" id="submit" name="submit" value="Send">
</form>
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Which is the variable that I can use?
Is it this.color.rgb[0]*255; for example?
I have created a variable $red etc, but it does not even open the test_input.php file.
None of the examples I have seen on the internet relate to the task I am trying to figure out.
Can anyone advise me?
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