PHP - Php & Mysql Hierachical Order

Hello,

I would like to order by date that contains day and month, like this: 14-3
Is this possible?

Quote

$sql = mysql_query("SELECT * FROM date WHERE online='1'");

Im displaying scores from my database from highest to lowest but 10 always comes out first. Why?

Hi guys,  Having problems sorting mysql results. I can easily order/sort table columns but would like to order the results by a variable.(Distance in Miles).
Havent much experience in PHP and really struggling with this. Basically a query echoing out car make and models and how far they are located from a postcode. Can get it to work no porblem, but not to order/sort by least distance.

Heres what i'm working with:
Code: [Select]
$res=mysql_query("SELECT * FROM cars");
while ($row = mysql_fetch_assoc($res)){

echo $row['Make'];
echo $row['Model'];

//variable will be determimed by user input form
$postcode="W12 3SR";

$start=$postcode;
$ends = array();

//finds value from database field
{
$ends[]=$row['Location'];
}

// Postcode entered by user via input form
$result=mysql_query("SELECT * FROM postcodes WHERE Pcode='$start'");
while($row=mysql_fetch_array($result)){
$gridn[0]=$row['Grid_N'];
$gride[0]=$row['Grid_E'];
}

foreach($ends as $fin){
// Postcodes within mysql table
$result=mysql_query("SELECT * FROM postcodes WHERE Pcode='$fin'");
while($row=mysql_fetch_array($result)){
$gridn[1]=$row['Grid_N'];
$gride[1]=$row['Grid_E'];
}

// TAKE GRID REFS FROM EACH OTHER TO WORK OUT DISTANCE.
$distance_n=$gridn[0]-$gridn[1];
$distance_e=$gride[0]-$gride[1];

// CALCULATE THE DISTANCE BETWEEN THE TWO POSTCODES AND DIVIDE BY 1.6 TO CONVERT KM TO MILES
$hypot=sqrt(($distance_n*$distance_n)+($distance_e*$distance_e))/1.609;

//VARIABLE FOR DISTANCE AND ROUNDED OF TO NEAREST WHOLE NUMBER.
$distance=''.round($hypot/1000,0).'';


  echo " $distance miles";
  echo "<br>";
}
}
?>
I wish i could just do something like this but isnt possible, is it ?
Code: [Select]
"Select * FROM cars ORDER BY $distance";
Thanks!

How can i select the last 3 rows in a table and order it by ASC. When i use DESC it displays the results in the wrong order.

$query24 = mysql_query("SELECT * FROM notifications WHERE to_id='$session' AND state='1' ORDER BY id DESC LIMIT 3 ");

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Hello..
I'm a somewhat beginner in php, but i decided to create my own basic forums system with a content managing system. Right now I'm trying to figure out how to make a thread link be at the top of the list for the forum display page, when someone posts a response or creates a new thread. HELP MUCH APPRECIATED 

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What is the best function to use to ensure an order is not re-entered when the user selects reload page? I can link code if you'd like but I'm only looking for a direction to go in and search google with. 'reload current page inserts extra' that google search hasn't been fruitful.

I am loading notifications from a database table called "notifications" and I am having a little trouble getting them to order in the correct way.

my query I'm using right now:

Code: [Select]
$query = mysql_query("SELECT B.* FROM (SELECT A.* FROM notifications A WHERE A.user_id='$session' AND A.from_id!='$session' ORDER BY A.id ASC ) AS B ORDER BY B.state ASC LIMIT 7");

this works well as far as showing the unread notifications on top, then the read notifications below, however it's not ordering the two sets by ID (which the id auto increments so the higher id number is the newest) from newest on top to the oldest on bottom, still keeping them separated by the unread on top, read on bottom (column name is state for showing whether they're read or not).
The order the notifications are displaying by their ID is:

3
5
2
4
1

when it should be:

5
3
2
4
1

Hello   I have a mysql table like this: id | user | car
1 | 1 | fiat 500
2 | 2 | vw polo
3 | 2 | vw golf
4 | 3 | renault clio
5 | 2 | fiat panda 6 | 3 | seat ibiza

From this table how can i get a query that the result be like:   user 2 - 3 cars user 3 - 2 cars user 1 - 1 cars   Thanks

okay I am using a jquery plugin to re-arrange images which are in mysql and they have their own "order_number" ... when i re-arrange stuff the new order is put into a hidden field in a form and i have it along with another hidden field with their current order... when submitted I combine these two fields in an array so the key is the original order and the value is the new order ....i have 12 images...
Array ( [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 [6] => 6 [7] => 7 [8] => 8 [9] => 9 [10] => 10 [11] => 11 [12] => 12 ) 

this is what is what the array looks like... i have a foreach loop with a mysql query but things get kind of weird when you try to do it this way

$num = $_POST['old_num'];
$num = unserialize($num);
$sort = $_POST['sortOrder'];
$sort = explode(',', $sort);

if ($_POST){


$combine = array_combine($num, $sort);

foreach($combine as $key => $value){


mysql_query("UPDATE shirts SET order_number='$value' WHERE order_number='$key' ")
or die(mysql_error());


}


when you do this lets say for example we have the image with order number "1" get switched with the image order number "2"..... the database first updates with number 1 which becomes 2... then when it goes to number "2"... at this point... the first image gets switched back to number 1.... so  1 becomes 2 then the new 2 becomes 1 again and the other 2 becomes 1 also.

I can not think of another way I could update mysql with the correct order numbers... If anyone has any ideas or other solutions I am open to all suggestions... thank you!

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