PHP - Tool To Display The Localhost Website Files That Have Been Accessed
I'm working with a downloaded open-source CMS on localhost, and trying to learn.
Is there a tool that will list the files (php and otherwise) that are accessed (in order) as the CMS does various normal operations? I want to see the order and the repetition of files that are opened, even if it is something minor. Thanks. Similar TutorialsI tried searching on google but couldn't find any relevant information, please redirect me to relevant source or help me with the code. I want to pass a domain name in text field which will be scanned and then the script will display entire site map. Not external links or links on a page. Sorry it is not easy for me to explain. Eg. if i pass abc.com Script will display abc.com/12/adn.php abc.com/asd/asd/ etc Whatever their url format is. All the links on that domain. When I play a video (that is blocked from being downloaded as a file from a php web script player that I'm using) I can see the url address of the file from my PC in dev tools > networking > media, Is there a way to block or scramble the video's url from being available to be copied? If not, is there a way to have that url be available only if the potential viewer is 'logged-in' to the web site? Or some type of authentication based on checking for a user's PHP temp session file before allowing access from the video's url? Is there a way to run a PHP script every time a file is accessed in a certain folder? Thanks in advance. Hey Guys. I came across this code example below assigns array values to a private property. However the private property is not defined as an array. It was a bit confusing to me because I always thought you need to define the property as an array first. If someone can please help me understand this concept I would really appreciate it.
Below is the code.
<?php class Product { public $name; public $price; function __construct($name, $price){ $this->name = $name; $this->price = $price; } } class ProcessSale { private $callbacks; // This holds an array but is not defined as an array? function registerCallback($callback) { if(!is_callable($callback)) { throw new Exception("Callback Is Not Callable"); } $this->callbacks[] = $callback; } function sale($product) { print "{$product->name}: processing \n"; foreach ($this->callbacks as $callback) { call_user_func($callback, $product); } } } $logger = function($product) { print "logging ({$product->name})\n"; }; $processor = new ProcessSale(); $processor->registerCallback($logger); $processor->sale(new Product("shoes", 6)); echo "\n"; $processor->sale(new Product("coffee", 6)); I have a small family only website and I use this code on my login page to see if members are having trouble re logging in.
// routine writes to file when this page is accessed
<?php $logfile = '/home/xxxxxxx/public_html/temp/trouble.txt'; $date = date('j M Y H:i:s'); if (isset($_COOKIE["family_user"])) { $user = $_COOKIE["family_user"]; } if ($file = @fopen($logfile, 'a')) { fwrite($file, "\r\n$date $user "); fclose($file); } ?> How can I use the information gathered (fwrite($file, "\r\n$date $user ") that writes to my trouble.txt file be sent to me via email. And ideally only once per session. I found this code will send me an email every time the page is accessed but can not figure out how to get fwrite($file, "\r\n$date $user " into either the subject (preferred) or into the body. <?php mail('yourEmailAddress@yourDomain.com','Subject of the e-mail','This is the body of the e-mail!'); ?> Anyone able to help with the code Thank you for your time Here is my current code to display files from the end to beginning : Code: [Select] <?php function func() { $date = date("Y-m-d"); $picarray = array(); $userarray = array(); $handle = opendir ('pqimages/'.$date.'/'); while (false !==($file = readdir($handle))) { if($file != "." && $file != "..") { $picarray[] = "http://blah.com/pqimages/".$date."/".$file.""; $userarray[]= "pqimages/".$date."/".$file.""; } } sort($picarray); sort($userarray); closedir($handle); $json_array = json_encode($picarray); echo $json_array; } func(); ?> How could I change this from end to beginning for ($picarray)? Cheers, George I made this for my site and decided to share with the community. Depending on how you do the code and where, this can keep count of the views in different ways. Please read the somewhat directions have in the code, make a folder called counters, and be sure to include this below function file. I named the function file index.php and belongs in the counters folder you make. <?php /* name this file index.php and place it into a folder called counters the function will create a unique text file for each unique item, good for posts or pages and store all the files in the counters folder For the total website views,add this to your header file or top of your page <?php include('counters/index.php'); $website_view_url = "http://".$_SERVER['HTTP_HOST']; } $website_views = getViews("$website_view_url"); echo "<br />".$website_views."<br />"; ?> For the total pages or scripts views,add this to your header file or top of your page <?php include('counters/index.php'); $total_page_view_url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['SCRIPT_NAME']; } $total_page_views = getViews("$total_page_view_url"); echo "<br />".$total_page_views."<br />"; ?> For entire urls including queries,add this to your header file or top of your page <?php include('counters/index.php'); $page_queries_view_url = "http://".$_SERVER['HTTP_HOST'].$_SERVER['SCRIPT_NAME']; if (!empty($_SERVER["QUERY_STRING"])) { $page_queries_view_url .= "?".$_SERVER['QUERY_STRING']; } $page_queries_views = getViews("$page_queries_view_url"); echo "<br />".$page_views."<br />"; ?> for usage in posts like by id: if do not want the pages counted and did not do the above code,include the below somewhere near the beginning of your page <?php include('counters/index.php');?> Then in the posts loop, you can associate your $row['id']; or some other unique value <?php $post_views = $row['id']; $post_views = getViews("$post_views"); echo "<br />Post Views ".$post_views."<br />"; ?> if would like to combine any the above or use them all, just be sure to just include include('counters/index.php'); only one time */ function getViews($views_count_value) { $views_count_value = md5("$views_count_value"); $views_count_file_name = "counters/$views_count_value.txt"; if (!file_exists($views_count_file_name)) { $views_count =0; $file_handle = fopen($views_count_file_name, 'w') or die("can't open file"); fwrite($file_handle, "$views_count"); fclose($file_handle); } $file_handle = fopen($views_count_file_name, "r"); $views_count = fread($file_handle, filesize("$views_count_file_name")); fclose($file_handle); if ($views_count <= 0){ $views_count =1; } else { ++$views_count; } $file_handle = fopen($views_count_file_name, "w+"); fwrite($file_handle, "$views_count"); fclose($file_handle); return("$views_count"); } ?> Hi Basically I've built a CMS where by my clients can upload a number of images. On the success page I want to display the images they uploaded by file name. The issue is the number of images can vary. They may upload 2 or 10 or 50 etc. So far I've come up with this: Code: [Select] // number of files $UN = 3; //I've set this to 3 for now, but this is passed from the upload page! // server directories and directory names $dir = '../properties'; $images = glob($dir.'/*.{jpg}', GLOB_BRACE); //formats to look for $num_of_files = $UN; //number of images to display from number of uploaded files foreach($images as $image) { $num_of_files--; $newest_mtime = 0; $image = 'BROKEN'; if ($handle = @opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $image = "$file"; } } } } if($num_of_files > -1) //this made me laugh when I wrote it echo $trimmed = ltrim($image, "../properties").'<br />'; //display images else break; } Without this piece of code: Code: [Select] $newest_mtime = 0; $image = 'BROKEN'; if ($handle = @opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $image = "$file"; } } } } It shows the first 3 files alphabetically. I want to view the last number of images added. With the above code it simply shows the last image added 3 times! So I need to get the time each image was added and then order by the newest added and limit to the number of images uploaded. Any suggestions please? Kindest regards Glynn It's very possible, and I've seen a website that's done it (http://www.zybez.net/radio/) - They are able to include the recent songs played on there website. The information can be obtained from right he http://68.168.100.60:7942/played.html But I'm not sure if thats where they get it from. If I login to my Admin section, there will be an option that says get XML stats. But I'm not sure if that shows the recent songs played like it would at http://68.168.100.60:7942/played.html (Everytime I refresh the page, the stats/data/info in the XML change) Code: [Select] 1250001522Rockhttp://srbuckey.listen2myradio.comMusicPEAK - RockKings of Leon - Radioactive N/AN/AN/A226153140audio/mpeg1.9.86201901701119000000004013207.144.125.60NSPlayer/11.0.6001.7006 WMFSDK/11.0026101521287587284Kings of Leon - Radioactive 1287586919Three Days Grace - Riot 1287586542Alice In Chains - Here Comes The Rooster 1287586281Green Day - Boulevard of Broken Dreams 1287586277down 1287586075Green Day - American Idiot 1287586044Metallica - Enter Sandman 1287585836ACDC Highway To Hell.mp3 1287585449Metallica - 04 The Unforgiven I.MP3 1287585448[HTTP/1.1 200 OK] http://www.ventsi.com/Music/MetallicA/1991 - Black Album/Metallica - 04 The Unforgiven I.MP3 hello, I want to display the echo ''"; in the right place on my website in changepassword_form.html all messages are written in changepassword.php. how can i move these echo after entering the wrong password or username? changepassword.php <?php ........... //success //change password in db $querychange = mysql_query("UPDATE users SET password='$newpassword' WHERE username='$username'"); session_destroy(); echo 'Password Has Been Changed Successfully !'; //move these } else{ echo('new password doesnt match!'); //move these } } else { die('old password doesnt match!'); //move these } } else { echo ""; include 'changepassword_form.html'; exit(); } } else{ echo 'you must be logged '; } ?> move these echos somewhere to my html code how to do these??
I would like to pull in Facebook reviews from my Facebook page and display them on a page on my website but am new to doing that so just seeing if there is any sample code I can get from somewhere to have a look at please? Hi
I'm looking for some advice on how to parse an xml feed and display any odds on my site
Here is an example http://feed.youwincd...in_football.xml
and as you can see it is quite large so calling it every time would have an impact on the server.
I am looking at using many different feeds in the future so want to start this properly and in a scaleable way.
I want to use php but open to any ideas on the best way to do this
Many thanks
Sam
Hi,
I've got a "data.txt" file with the following content:
One1:One2:One3:One4:One5:One6 Two1:Two2:Two3:Two4:Two5:Two6 Three1:Three2:Three3:Three4:Three5:Three6Now I want to be able to take each data and put on a specific location of a htlm code. Each line for its own. So for the first line, it should look something like this: <html> <head> <title></title> <head> <body> <h1>One2</h1> <h2>One4 some other Text One5</h2> <img src="One6.jpg"> </body> </html>Unforturtunately I don't have a clue how to do that. Can anybody help me out or does someone know a good and easy tutorial? Thanks a lot Hello,
I try to get website speed of some website, but i can read only ''domain.com'' i can't read website files like css , js ... why ? i use proxies for this job.
here is the php code:
$options = array( 'useragent' => "Firefox (+http://www.firefox.org)", // who am i 'connecttimeout' => 120, // timeout on connect 'timeout' => 120, // timeout on response 'redirect' => 10, // stop after 10 redirects 'referer' => "http://www.google.com", 'proxyhost' =>'85.25.8.14:80' ); $response = http_get("http://solve-ict.com/wp-content/themes/ict%20theme/js/jquery-1.7.1.min.js", $options , $info);but it works fine with http://domain.com/ , but with files css or js it gives 404, using some free proxy servers available ? Thanks. does anyone know of a simple tutorial which will show me how to receive email sent via my localhost? i cant develop my script fully because of the email errors. thanks Hi, my school say not to use XAMPP, and I already have PHP installed, MySQL installed, Apache I am not sure, but assuming if I have it installed, how do I connect to localhost b/c beforer when I use XAMPP, the default for where to get php/mysql running was: C:\xampp\htdocs\ Please any help appreciated! I'm looking to connect to a MySQL localhost on my mac. I've been working for a few hours at this and I still can't figure it out. Below is my code. I've tried a number of different ways to connect to the database including using new mysqli, mysql_connect and PEAR MDB2. Any suggestions as to what I can do? Thanks in advance. <?php $first=$_POST['first']; $last=$_POST['last']; if (!$first || !$last) { echo 'Error: Enter the required data.'; exit; } if (!get_magic_quotes_gpc()) { $first = addslashes($first); $last = addslashes($last); } $hostname = 'localhost:8889'; $username = 'root'; $password = 'root'; $dbname = 'phonebook'; @ $db = new mysqli($hostname,$username.$password,$dbname); if (mysqli_connect_errno()) { echo 'Errer: Could not connect to database'; exit; } echo '.....Connected Successfuly'; $query = "insert into contact values ('null','".$first."','".$last."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." contact inserted into the database"; echo 'Contact Entered: '.$first.' '.$last.''; } else { echo 'Error: Contact not added.'; exit; } $db->close(); ?> This topic has been moved to Other. http://www.phpfreaks.com/forums/index.php?topic=327407.0 Hi, I still a noob in PHP programming I hope somebody in the forum can help me and give an ideas how to fixed to this problem, everytime I run localhost this message appear: ErrorException in Builder.php line 1023:count(): Parameter must be an array or an object that implements CountableBut if I type localhost/(anycharacter) the page appear but with error 404(kindly refer to image, all other buttons are working except the one indicated with the arrow( kindly refer on the last image, note: app_debug set to true), this problem keeps bugging me for a few weeks now that I still cannot find a way to fixed it. Thank you in advance. )
I have a Login Script with a Remember me Function. The Script works flawlessly on my local server but when I upload it doesn't work on my web server. From what I can tell its a Session issue, When I log in, I make a session with the user ID, in which is used to pull all there information on other pages. On my local host it makes the sessions and everything is dandy, but on the web server it doesn't seem to make the session. Can anyone shed any light on this, I'm clueless once again ^_^ |