PHP - Moved: How To Select Unique From Multiple Tables

This topic is now in MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=357554.0

Below is a page which is supposed to output the name, blog contribution and picture of contributing members of a website.
<div id="blog_content" class="" style="height:90%; width:97%; border:5px solid #c0c0c0; background-color: #FFFFFF;"> <!--opens blog content--> 



                             
<?php


//address error handling

ini_set ('display_errors', 1);
error_reporting (E_ALL & ~E_NOTICE);



//include the config file

require_once("config.php");



//Define the query. Select all rows from firstname column in members table, title column in blogs table,and entry column in blogs table, sorting in ascneding order by the title entry, knowing that the id column in mebers table is the same as the id column in blogs table.


$sql = "SELECT


    blogs.title,blogs.entry,members.firstname,images.image
FROM
    blogs
LEFT JOIN
    members
ON
    blogs.member_id = members.member_id
LEFT JOIN
    images
ON
    blogs.member_id = images.member_id

ORDER BY
     blogs.title ASC

"; 

$query = mysql_query($sql);

                 if($query !== false && mysql_num_rows($query) > 0)

                 {

         while(($row = mysql_fetch_assoc($query)) !== false)

         {

 echo

                
                              '<div id="blog_content1" style="float:left; position:relative;bottom:18px;left:13px; background-color: #FFFFFF; height:16.7%; width:100%; border:0px none none;"                              
                              <!--opens blog_content1  same as main center top 1 and 2 from index page everything scaled down by a factor of 3, heightwise--> 
        
 
                                   <div class="red_bar" style="height:3%; width:100%; border:1px solid #959595;"> <!--a--> 
 
                                       <div class="shade1" style="height:5px; width:100%; border:0px none none;"> </div>                                      
                                       <div class="shade2" style="height:5px; width:100%; border:0px none none"> </div> 
                                       <div class="shade3" style="height:5px%; width:100%; border:0px none none"> </div>

 
                                   </div> <!-- closes red bar--> 
 
 
 
                                   <div class="content" style="height:28.3%; width:100%; border:0px none none;"> <!----> 
 
                                       
                                           <div class="slideshow" id="keylin" style="float:left; width:20%;  border:0px none none;"> <!--a-->
 
                                                  
                                                  
 
                                                 <div><img header("Content-type: image/jpeg"); name="" alt="" id="" height="105" width="105" src="$row[image]" /></div>                              
 
 
                                       
                                           </div> <!-- closes pic--> 
 
 
 
                                           <div class="content_text"  style="float:right;  position:relative;top:7px;left:0px; max-height:150px; width:78.5%; border-width:4.5px; border-bottom-style:solid; border-right-style:solid; border-color:#c0c0c0; "> <!--a-->'; 
 
                                           

                                               
                                                echo "<h3>".$row['title']."</h3>";

echo "<p>" .$row['entry']."<br />".$row['firstname']."</p>";

         
                                             
                                                                                           
                                           echo                                         
                                           '</div> <!-- closes content text--> 
 
  
                                   </div> <!-- closes content--> 
 
                                   
                                                                                                                                                                                                                            
                            </div> <!-- closes blog_content1-->';



                                                 }

                 }

                 else if($query == false)

                 {

               

 echo "<p>Query was not successful because:<strong>".mysql_error()."</strong></p>";

         echo "<p>The query being run was \"".$sql."\"</p>";

                 }

                 else if($query !== false && mysql_num_rows($query) == 0)

                 {

         echo "<p>The query returned 0 results.</p>";

                 }


                                                 mysql_close(); //Close the database connection.





                                                 ?> 

                      
                        </div> <!-- closes blog content-->


The select query is designed to retrieve all the blog contributions(represented by the fields blogs.title and blogs.entry) from the database, alongside the contributing member (member.firstname) and the member's picture(images.image), using the member_id column to join the 3 tables involved, and outputs them on the webpage.   The title, entry and firstname values are successfully displayed on the resulting page.  However, I can't seem to figure out how to get the picture to be displayed.  Note that the picture was successfully stored in the database and I was able to view it on a separate page using a simple select query.  It is now just a question of how to get it to display on this particularly crowded page.  Anyone knows how I can output the picture in the img tag?  I tried placing the header("Content-type: image/jpeg"); statement at the top of the php segment, then just right below the select query and finally just right above the img tag, but in every case, I just got a big white blank page starring at me.  How and where should I place the header statement? And what else am I to do to get this picture displayed?  Any help is appreciated.

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=305902.0

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=312377.0

firstly, apologies on my TOPIC TITLE.  i couldnt think of how better to write it.   anywho, i am inserting a new row of data into a table. immediately after inserting it, i want to select the unique value in the 'id' row.  two questions.    1. how can i reference this newly inserted row if the only unique value is the id (primary auto-increment)? 2. is there a way to insert this new row AND select that id value in one query?

I have searched for a solution to a code that I wrote, with unique numbers in the SQL statement of LIMIT at the end and using execute().  I have also set

PDO::ATTR_EMULATE_PREPARES, false

I know that there is ways to use bindValue() or bindParam() instead of execute() for this. However, the way I have it set up works, but is there a security flaw with the way I am using LIMIT and should I be using bindParam() instead of execute()?

<?php
if ($numbered_row == 0) {
	$limitation = '';
} else {
	$started_page = ($page_number - 1) * $items_on_each_page;
	$limitation = ' LIMIT '. $started_page . ',' . $items_on_each_page;
}
$sql_query = "SELECT * FROM `myTable` WHERE `id` = :id AND `group` = :group AND `name` LIKE :name AND `country` = :country ORDER BY `date` DESC" . $limitation;
$query_result = $pdo_connecting->prepare($sql_query);
$query_result->execute(array(':id' => '73', ':group' => 'Furniture', ':name' => '%'.$name.'%', ':country' => $country));
?>

 

Edited November 21, 2018 by Cobra23

Im doing a search system and Im having some problems. I need to search in two tables (news and pages), I already had sucess doing my search system for just one table, but for two tables its not easy to do. I already use a select statment with two tables using UNION because I want to show number of search results, that is number of returned rows of my first sql statment. But now I need to do a select statment that allows me to acess all fields of my news table and all fields of my pages table. I need to acess in my news table this fields: id, title, content, link, date, nViews I need to acess in my pages table this fields: id, title, content, link Im trying to do this also with UNION, but in this case Im not having any row returning. Do you see what I have wrong in my code?   <?php
//first I get my $search keyword
$search = $url[1];

$pdo = connecting();
//then I want to show number of returned rows for keyword searched
$readALL = $pdo->prepare("SELECT title,content FROM news WHERE title LIKE ? OR content LIKE ?
UNION SELECT title,content FROM pages WHERE title LIKE ? OR content like ?");
$readALL->bindValue(1,"%$search%", PDO::PARAM_STR);
$readALL->bindValue(2,"%$search%", PDO::PARAM_STR);
$readALL->bindValue(3,"%$search%", PDO::PARAM_STR);
$readALL->bindValue(4,"%$search%", PDO::PARAM_STR);
$readALL->execute();
//I show number of returned rows
echo '<p>Your search keyword returned <strong>'.$readALL->rowCount().'</strong> results!</p>';
//If dont return any rows I show a error message
if($readALL->rowCount() <=0){
echo 'Sorry but we didnt found any result for your keyword search.';
}
else{
//If return rows I want to show, if it is a page result I want to show title and link that I have in my page table
//if it is a news result I want to show title and link that I have in my news table and also date of news
echo '<ul class="searchlist">';
$readALL2 = $pdo->prepare("SELECT * FROM news WHERE status = ? AND title LIKE ? OR content LIKE ? LIMIT 0,4
UNION SELECT * FROM pages where title LIKE ? OR content LIKE ? LIMIT 0,4");
$readALL2->bindValue(1, '1');
$readALL2->bindValue(2, "%$search%", PDO::PARAM_STR);
$readALL2->bindValue(3, "%$search%", PDO::PARAM_STR);
$readALL2->bindValue(4, "%$search%", PDO::PARAM_STR);
$readALL2->execute();

while ($result = $readALL2->fetch(PDO::FETCH_ASSOC)){
echo '<li>';
echo '<img src="'.BASE.'/uploads/news/'.$result['thumb'].'"/>';
echo '<a href="'.BASE.'/news/'.$result['id_news'].'">'.$result['title'].'</a>';
//if it is a news result I also want to show date on my list
//echo '<span id="date">'.$result['date'].'</span>';
echo '</li>';
}
echo ' </ul>';
//but how can I do my select statement to have access to my news table fields and my page table fields??
}
?>

This topic has been moved to MySQL Help.

http://www.phpfreaks.com/forums/index.php?topic=349293.0

This seems to be a bit of a challenge but I am creating a multiple page form and on one of the pages I have a select field. I would like the user to have the ability to select multiple options but I am using some functions to move the data in hidden fields from page to page. I don't think my functions are jiving with my my foreach loop cause I keep getting an invalid argument error.

Thanks in advance for any help.

Here is my function:

    function setSelected($fieldName, $fieldValue) {
        if(isset($_POST[$fieldName]) && $_POST[$fieldName] == $fieldValue) {
            echo 'selected="selected"';
        }
    }

And here is my loop:

    $selections = "";
   
    if(isset($_POST["selections"])) {
        foreach ($_POST["selections"] as $selection) {
            $selections .= $selection . ", ";
        }
    }

I have 2 queries that I want to join together to make one row  

I have a search where I want to be able to search a string of words. The search is going to be looking in 2 different table joined by a left outer join. The tables are "quotes" and "categories".

$sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')";
   
The above mysql statement works and returns values..BUT if say, I search "john" and "funny", and a quote is posted by the user "john", but has a category of "funny" it will output the same quote twice. I was wondering if there was a way to see if a quote has either 1 term or both terms, if so display that quote but only display it once. Below is what the query is outputting.


[100] => Array
        (
            [id] => 100
            [username] => John
            [quote] => new test quote blah blah
            [by] => John
            [voteup] => 0
            [votedown] => 0
            [servtime] => 2010-12-02 @ 16:27:03
            [label] => Array
                (
                    [0] => Historic
                    [1] => Serious
                    [2] => Funny
                )

        )


Here is the code in full.


////
$sword = explode(" ",$search);
foreach($sword as $sterm){
$srch="%".$sterm."%";
echo"$srch<br />";
$sql="SELECT q.id, q.username, q.quote, q.by, q.voteup, q.votedown, q.servtime, c.quote_id, c.label FROM quotes q LEFT OUTER JOIN categories c ON q.id = c.quote_id WHERE ( q.username LIKE '$srch' OR q.quote LIKE '$srch' OR q.`by` LIKE '$srch' OR c.label LIKE '$srch')";
$result=mysql_query($sql);
while($row=mysql_fetch_object($result)){
$quote[$row->id]['id'] = $row->id;
$quote[$row->id]['username'] = $row->username;
$quote[$row->id]['quote'] = $row->quote;
$quote[$row->id]['by'] = $row->by;
$quote[$row->id]['voteup'] = $row->voteup;
$quote[$row->id]['votedown'] = $row->votedown;
$quote[$row->id]['servtime'] = $row->servtime;
$quote[$row->id]['label'][] = $row->label;
}
echo"<pre>";
print_r($quote);
echo"</pre>";


I don't think this is the fastest way of doing this, as it loops for each item in the db, per each keyword that is search.

Any help would be great!!
-BaSk

I have a form where a user can duplicate part of a form like below:


I've named the fields with the HTML arrays (ie. "fieldName[]") and came up with this:

//--> CONTROLLERS
$system_controllers_qty = $_POST['system_controllers_qty'];
$system_controllers_make = $_POST['system_controllers_make'];
$system_controllers_model = $_POST['system_controllers_model'];
$system_controllers_serial_no         = $_POST['system_controllers_serial_no'];
for ($i = 0; $i < count($system_controllers_qty); $i++)
{
echo "qty " . clean($system_controllers_qty[$i]) . "<br/>";
echo "make " . clean($system_controllers_make[$i]) . "<br/>";
echo "model " . clean($system_controllers_model[$i]) . "<br/>";
echo "serial_no " . clean($system_controllers_serial_no[$i]) . "<br/>";
}

//--> CPUS
$system_cpus_qty = $_POST['system_cpus_qty'];
$system_cpus_model = $_POST['system_cpus_model'];
$system_cpus_serial_no = $_POST['system_cpus_serial_no'];
$system_cpus_speed = $_POST['system_cpus_speed'];
for ($i = 0; $i < count($system_cpus_qty); $i++)
{
echo "qty " . clean($system_cpus_qty[$i]) . "<br/>";
echo "model " . clean($system_cpus_model[$i]) . "<br/>";
echo "serial_no " . clean($system_cpus_serial_no[$i]) . "<br/>";
echo "speed " . clean($system_cpus_speed[$i]) . "<br/>";
}

//--> DISKS
$system_disks_qty = $_POST['system_disks_qty'];
$system_disks_make = $_POST['system_disks_make'];
$system_disks_model_no = $_POST['system_disks_model_no'];
$system_disks_size = $_POST['system_disks_size'];
$system_disks_serial_no = $_POST['system_disks_serial_no'];
for ($i = 0; $i < count($system_disks_qty); $i++)
{
echo "qty " . clean($system_disks_qty[$i]) . "<br/>";
echo "make " . clean($system_disks_make[$i]) . "<br/>";
echo "model_no " . clean($system_disks_model_no[$i]) . "<br/>";
echo "size " . clean($system_disks_size[$i]) . "<br/>";
echo "serial_no " . clean($system_disks_serial_no[$i]) . "<br/>";
}

//--> MEMORY
$system_memory_qty = $_POST['system_memory_qty'];
$system_memory_serial_no = $_POST['system_memory_serial_no'];
$system_memory_manf = $_POST['system_memory_manf'];
$system_memory_part_no = $_POST['system_memory_part_no'];
$system_memory_size = $_POST['system_memory_size'];
for ($i = 0; $i < count($system_memory_qty); $i++)
{
echo "qty " . clean($system_memory_qty[$i]) . "<br/>";
echo "serial " . clean($system_memory_serial_no[$i]) . "<br/>";
echo "manf " . clean($system_memory_manf[$i]) . "<br/>";
echo "part_no " . clean($system_memory_part_no[$i]) . "<br/>";
echo "size " . clean($system_memory_size[$i]) . "<br/>";
}


This just outputs all the fields I post at the moment. Say I have 3 different disk types, it's going to loop 3 times. Is it possible to make this all into 1 giant query or am I better off doing each query separately? Each section is a different table.

I am trying to export multiple csv files to download from 2 separate tables in my database.

Some background:
I have a web app that links to a phpmyadmin database. There are 2 tables in the database (entering and exiting). These tables hold the phone inventory information of employees currently entering or exiting the organization.

The fields in my tables a

location, firstname, lastname, username, extension, mac, type

What I am trying to do is export the data in these 2 tables to CSV (which I have working now) but I need to have multiple CSVs for each.

For example, for my exiting table, I need to have one CSV export all the fields in the table and I also need another CSV to export just the location and username field. I have a simple html form with a submit button which is currently working now:

<form action="exportexiting.php" method="POST" style="width: 456px; height: 157px">
   <div>
   <fieldset>
   <legend style="width: 102px; height: 25px"><strong>Entering CSV:</strong></legend>
   <input name="Export" type="submit" id="Export" value="Export">
   </fieldset><br/>
   </div>
</form>


This links to my exportexiting.php file:

<?php
$host = 'localhost';
$user = 'root';
$pass = 'xxxx';
$db = 'PhoneInventory';
$table = 'exiting';


 
// Connect to the database
$link = mysql_connect($host, $user, $pass);
mysql_select_db($db);
 
require 'exportcsv.inc.php';

 
exportMysqlToCsv($table);
 
 
 
?>

Then to exportcsv.inc.php:

<?php
 
function exportMysqlToCsv($table,$filename = 'export.csv')
{
    $csv_terminated = "\n";
    $csv_separator = ",";
    $csv_enclosed = '';
    $csv_escaped = "\\";
    $sql_query = "select * from $table";
 
    // Gets the data from the database
    $result = mysql_query($sql_query);
    $fields_cnt = mysql_num_fields($result);
 
 
    $schema_insert = '';
 
    for ($i = 0; $i < $fields_cnt; $i++)
    {
        $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
            stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
        $schema_insert .= $l;
        $schema_insert .= $csv_separator;
    } // end for
 
    $out = trim(substr($schema_insert, 0, -1));
    $out .= $csv_terminated;
 
    // Format the data
    while ($row = mysql_fetch_array($result))
    {
        $schema_insert = '';
        for ($j = 0; $j < $fields_cnt; $j++)
        {
            if ($row[$j] == '0' || $row[$j] != '')
            {
 
                if ($csv_enclosed == '')
                {
                    $schema_insert .= $row[$j];
                } else
                {
                    $schema_insert .= $csv_enclosed .
               str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed;
                }
            } else
            {
                $schema_insert .= '';
            }
 
            if ($j < $fields_cnt - 1)
            {
                $schema_insert .= $csv_separator;
            }
        } // end for
 
        $out .= $schema_insert;
        $out .= $csv_terminated;
    } // end while
 
    header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
    header("Content-Length: " . strlen($out));
    // Output to browser with appropriate mime type, you choose
    header("Content-type: text/x-csv");
    //header("Content-type: text/csv");
    //header("Content-type: application/csv");
    header("Content-Disposition: attachment; filename=$filename");
    echo $out;
    exit;
 
}
 
?>



Again, this is working perfectly for only exporting all the data from the exiting table into one CSV file. My question is, how can I make my one submit button export the 2 CSV files that I need?


Thanks for the help...

I have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. 
I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`.

What I would very much appreciate assistance with is;

a) Generating a 5 digit alphanumeric code, ie: 5ABH6 
b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again 
c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. 
d) display the code on screen.

What code must I put and where?


**My current php is as follows:**

Code: [Select]
    require "includes/connect.php";
   
    $msg = '';
   
    if($_POST['email']){
   
    // Requested with AJAX:
    $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH']  == 'XMLHttpRequest');
   
    try{
    if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){
    throw new Exception('Invalid Email!');
    }
   
    $mysqli->query("INSERT INTO coming_soon_emails
    SET email='".$mysqli->real_escape_string($_POST['email'])."'");
   
    if($mysqli->affected_rows != 1){
    throw new Exception('You are already on the notification list.');
    }
   
    if($ajax){
    die('{"status":1}');
    }
   
    $msg = "Thank you!";
   
    }
    catch (Exception $e){
   
    if($ajax){
    die(json_encode(array('error'=>$e->getMessage())));
    }
   
    $msg = $e->getMessage();
    }
    }

This topic has been moved to MySQL Help.

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