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PHP - Validating A Date In Php
I have the following code below to validate a date that the user types in. But I am getting the following error: "Warning preg_match() [function.preg-match]: Unknown modifier '('"
Code: [Select] if(!empty($_POST['exp_date'])) { $pattern = '(^[0-9]{1,2})' // 1 or 2 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,2})' // 1 or 2 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,4}$)'; // 1 to 4 digits $exp_date = trim($_POST['exp_date']); if(preg_match($pattern, $exp_date)){ $pattern = '(^[0-9]{1,2})' // 1 or 2 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([a-zA-Z]{1,})' // 1 or more alpha .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,4}$)'; // 1 to 4 digits if (preg_match($pattern, $exp_date)){ $pattern = '(^[a-zA-Z]{1,})' // 1 or more alpha .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,2})' // 1 or 2 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,4}$)'; // 1 to 4 digits if (preg_match($pattern, $exp_date)){ $pattern = '(^[a-zA-Z]{1,})' // 1 or more alpha .'([0-9]{2})' // 2 digits .'([0-9]{4}$)'; // 4 digits if (preg_match($pattern, $exp_date)){ $pattern = '(^[0-9]{4})' // 4 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,2})' // 1 or 2 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,2}$)'; // 1 to 2 digits if (preg_match($pattern, $exp_date)){ $pattern = '(^[0-9]{2})' // 2 digits .'([0-9]{2})' // 2 digits .'([0-9]{4}$)'; // 4 digits if (preg_match($pattern, $exp_date)){ $pattern = '(^[0-9]{4})' // 4 digits .'([^0-9a-zA-Z])' // not alpha or numeric .'([a-zA-Z]{1,})' // 1 or more alpha .'([^0-9a-zA-Z])' // not alpha or numeric .'([0-9]{1,2}$)'; // 1 to 2 digits } else { $errors[]= 'Please enter a valid expiration date.'; } } else { $errors[]= 'Please enter a valid expiration date.'; } } else { $errors[]= 'Please enter a valid expiration date.'; } } else { $errors[]= 'Please enter a valid expiration date.'; } } else { $errors[]= 'Please enter a valid expiration date.'; } } else { $errors[]= 'Please enter a valid expiration date.'; } } else { $errors[]= 'Please input an expiration date.'; } Similar TutorialsHey, I'm using a script which allows you to click on a calendar to select the date to submit to the database. The date is submitted like this: 2014-02-08 Is there a really simple way to prevent rows showing if the date is in the past? Something like this: if($currentdate < 2014-02-08 || $currentdate == 2014-02-08) { } Thanks very much, Jack Hello. I'm new to pHp and I would like to know how to get my $date_posted to read as March 12, 2012, instead of 2012-12-03. Here is the code: Code: [Select] <?php $sql = " SELECT id, title, date_posted, summary FROM blog_posts ORDER BY date_posted ASC LIMIT 10 "; $result = mysql_query($sql); while($row = mysql_fetch_assoc($result)) { $id = $row['id']; $title = $row['title']; $date_posted = $row['date_posted']; $summary = $row['summary']; echo "<h3>$title</h3>\n"; echo "<p>$date_posted</p>\n"; echo "<p>$summary</p>\n"; echo "<p><a href=\"post.php?id=$id\" title=\"Read More\">Read More...</a></p>\n"; } ?> I have tried the date() function but it always updates with the current time & date so I'm a little confused on how I get this to work. I have tried a large number of "solutions" to this but everytime I use them I see 0000-00-00 in my date field instead of the date even though I echoed and can see that the date looks correct. Here's where I'm at: I have a drop down for the month (1-12) and date fields (1-31) as well as a text input field for the year. Using the POST array, I have combined them into the xxxx-xx-xx format that I am using in my field as a date field in mysql. <code> $date_value =$_POST['year'].'-'.$_POST['month'].'-'.$_POST['day']; echo $date_value; </code> This outputs 2012-5-7 in my test echo but 0000-00-00 in the database. I have tried unsuccessfully to use in a numberof suggested versions of: strtotime() mktime Any help would be extremely appreciated. I am aware that I need to validate this data and insure that it is a valid date. That I'm okay with. I would like some help on getting it into the database. Alright, I have a Datetime field in my database which I'm trying to store information in. Here is my code to get my Datetime, however it's returning to me the wrong date. It's returning: 1969-12-31 19:00:00 $mysqldate = date( 'Y-m-d H:i:s', $phpdate ); $phpdate = strtotime( $mysqldate ); echo $mysqldate; Is there something wrong with it? (continuing from topic title) So if I set a date of July 7 2011 into my script, hard coded in, I would like the current date to be checked against the hard coded date, and return true if the current date is within a week leading up to the hard coded date. How could I go about doing this easily? I've been researching dates in php but I can't seem to work out the best way to achieve what I'm after. Cheers Denno Hi, I have a job listing website which displays the closing date of applications using: $expired_date (This displays a date such as 31st December 2019) I am trying to show a countdown/number of days left until the closing date. I have put this together, but I can't get it to show the number of days.
<?php
$expired_date = get_post_meta( $post->ID, '_job_expires', true );
$hide_expiration = get_post_meta( $post->ID, '_hide_expiration', true );
if(empty($hide_expiration )) {
if(!empty($expired_date)) { ?>
<span><?php echo date_i18n( get_option( 'date_format' ), strtotime( get_post_meta( $post->ID, '_job_expires', true ) ) ) ?></span>
<?php
$datetime1 = new DateTime($expired_date);
$datetime2 = date('d');
$interval = $datetime1->diff($datetime2);
echo $interval->d;
?>
<?php }
}
?>
Can anyone help me with what I have wrong? Many thanks How much should you validate a First Name? This is my code... // Validate First Name. if (empty($trimmed['firstName'])){ $errors['firstName'] = 'Please enter your First Name.'; }else{ if (preg_match('#^[A-Z \'.-]{2,20}$#i', $trimmed['firstName'])){ $firstName = $trimmed['firstName']; }else{ $errors['firstName'] = 'First Name must be 2-20 characters (A-Z \' . -)'; } } I did this for fear if I left things wide-open it would be a security risk. And in the U.S. at least, the above would really cover all valid First Names. Thoughts? Debbie Hello all, I need your help again. I have this page where the user inputs data: <?php include "include/dbc.php"; include "include/header.inc"; #error checking will go here ?> <style type="text/css"> .mydate{ color:#00F; text-decoration:underline; cursor:pointer; } </style> <script type="text/javascript"> function displayDate(d){ var date=new Date(); var D=date.getDate(); date.setDate(D+d); var YYYY=date.getFullYear(); var MM=date.getMonth()+1; MM<10?MM='0'+MM:null; var DD=date.getDate(); DD<10?DD='0'+DD:null; var span=document.getElementById('date'); span.innerHTML= 'Entries for '+MM+'/'+DD+'/'+YYYY; } onload=function(){displayDate(0)}; </script> <h1>Food Diary</h1> <div class="full"> <center><div><span class="mydate" onclick="displayDate(-1)"><img src="images/left_arrow.png" border="0">Yesterday</span> <span id="date" style="font-size:2em;"></span> <span class="mydate" onclick="displayDate(1)">Tomorrow<img src="images/right_arrow.png" border="0"></span></div><br /> <a href="#" onclick="displayDate(0);return false;">Today</a> </center> <div class="full"> <form name="exercise" id="exercise" method="GET" action=""> <center><table> <tr> <td><h3>Add an Activity</h3></td> </tr> <tr> <td><input name="NewSearchString" style="width: 100px" type="text"/> <input type="submit" value="Search" /> </td> </tr> <tr> <td> <select name="activity"> <option value="_">Activity Browse...</option> <option value="all">All Activities</option> <option value="biking">Biking</option> <option value="condition">Conditioning</option> <option value="dancing">Dancing</option> <option value="fish">Fishing & Hunting</option> <option value="Home">Home Activities</option> <option value="misc">Miscellaneous</option> <option value="music">Music Playing</option> <option value="occupation">Occupation</option> <option value="running">Running</option> <option value="sports">Sports</option> <option value="walking">Walking</option> <option value="water">Water Activities</option> <option value="winter">Winter Activities</option> </select> <input type="submit" value="Submit" /></td></tr></table></center></form> </td> </tr> </table> </center> <table width="100%"> <tr bgcolor="#66CC33"> <td><div>Activity</div></td> <td><div>Specific Activity</div></td> <td><div>Time (hh:mm)</div></td> <td><div>Distance</div></td> <td><div>Units</div></td> </tr> <tr bgcolor="#66CC33"> <td><div></div></td> <td><div></div></td> <td><div></div></td> <td><div class="Float"></div></td> <td class="cp_Distance"><div></div></td> </tr> <?php if(isset($_GET[activity])) { $category=$_GET[activity]; $result = mysql_query("SELECT * FROM exercise WHERE type='$category'"); ?> <form action="add_activity.php" method="POST"> <?php while($row = mysql_fetch_array($result)) { echo '<tr><td><div>'.$row[Type].'</div></td>'; echo '<td><div>'.$row[Name].'<input type="hidden" name="exerciseid[]" value="'.$row[Name].'"></div></td>'; echo '<td><div><input type="text" name="duration['.$row['Name'].']"></div></td>'; echo '<td><div><input type="text" name="distance['.$row['Name'].']"></div></td>'; echo '<td><div><select name="metric[]"> <option value=""></option> <option value="mile">mile</option> <option value="Km">km</option> <option value="M">m</option>; <option value="Yard">yrd</option> <option value="Feet">ft</option> </select></div></td></tr>'; echo'<input type="hidden" name="submitted" value="1">'; } mysql_close(); ?> <tr><td colspan="6" align="center"><input type="submit" name="submit" value="Add Activities" onClick="return confirm( 'Are you sure you want to submit the activities?');"></td></tr> </form> <?php } ?> <tr bgcolor="#66CC33"> <td><div></div></td> <td><div></div></td> <td><div></div></td> <td><div class="Float"></div></td> <td class="cp_Distance"><div></div></td> </tr></table> <div></div> <?php include "include/footer.inc"; ?> I want to validate that the user enters data for at least one of all the fields provided (distance, duration, metric). If someone could help me get started I'd greatly appreciate it. Hi, I have a user system where people login to my site with their emails. The thing I am after is when a person is registering I want to validate that they have entered a valid email with @.com in the string and not just some repetitive characters e.g. wwwwwww. Could some one guide me what is the best way to check for a valid email and for repetive characters in any given field examle firstname. One last thing I would also like to check that a person only enters Alphabets for name and stuff. This topic has been moved to Other Programming Languages. http://www.phpfreaks.com/forums/index.php?topic=347582.0 Hello.. I have Two HTML form and one is a Check boxes form that enable users to select their category. Then I need to display second form according to the categories they selected in first form. I use this code in first form to validate form submission.. if ( isset( $_POST['category']) && sizeof( $_POST['category']) <= 3) { $category = $_POST['category']; } else { $errors[] = 'Please select atleast 1, not more than 3 categories'; } If errors array is empty I did this.. if ( empty( $errors )) { // If everything's OK $_SESSION = $category; $url = 'http://localhost/lanka_institute/tutorsignup/select_subjects.php? // Define the URL. ob_end_clean(); // Delete the buffer. header("Location: $url"); exit(); // Quit the script. } Can I know and is this correct? I display category list from mysql category table, it has category name and category id this is my html part from first page echo '<td width="50%"><input type="checkbox" name="category[]" vlaue="' . $info['category_id'] . '" /> ' . $info['category_name'] . '</td>'; any help appreciated. Thanks in advance.. Hi all, Hi have a bit of a problem that I am completely stuck on. I have a form on a website that needs checkboxes to be processed by PHP, but i have no idea how to implement them. I have found examples, but my knowledge of php is exactly zero, so its confusing the hell out of me. The website is: http://www.geelongnannies.com.au/test/employment.html http://www.geelongnannies.com.au/test/freecontactformprocess3.php http://www.geelongnannies.com.au/test/freecontactformsettings.php if anyone can have a look and give me an example of how to change the php to process the checkboxes when submitted, I will be very grateful cheers! Hi Guys.. How can I change a date on the fly ? Everything is UTC on my server. How can I change a date to something else on the fly? Ie: $timezone = "cet"; $datetime = "2011-09-04 19:53:00"; echo $datetime($timezone); So I can give it a datetime and have it echo the datetime as if it were in the other timezone? Thanks Graham i have a table that shows payments made but want to the payments only showing from a set date(06/12/14) and before this date i dont want to show
this is my sql that doesnt seem to work and is showing dates before the specified date.
.
"SELECT * FROM payments2014, signup2014, editprop2014 WHERE signup2014.userid = payments2014.payment_userid AND editprop2014.prop_id = signup2014.prop_id AND signup2014.userid !='page1' AND signup2014.userid !='page6' AND signup2014.userid !='page4' AND payments2014.payment_transaction_status !='none' AND payments2014.payment_transaction_status !='CANCELLEDa' AND payments2014.payment_type !='deposit' AND payments2014.payment_paid_timestamp NOT LIKE '%2012%' AND payments2014.payment_paid_timestamp NOT LIKE '%2011%' AND payments2014.payment_paid_timestamp >= '06/12/14' ORDER BY payments2014.payment_id DESC"i have some other parts in the statment but this one that should be filtering is host_payments2014.payment_paid_timestamp >= '06/12/14'thanks in advance Hi, I am trying to convert a String date into numeric date using PHP function's, but haven't found such function. Had a look at date(), strtotime(), getdate(); e.g. Apr 1 2011 -> 04-01-2011 Could someone please shed some light on this? Regards, Abhishek Hi there, I have a string '12/04/1990', that's in the format dd/mm/yyyy. I'm attempting to convert that string to a Date, and then insert that date into a MySQL DATE field. The problem is, every time I try to do so, I keep getting values like this in the database: 1970-01-01. Any ideas? Much appreciated. I'm getting this Time Zone error. Perhaps it's a compatibility issue with PHP 5.3. Looked all over for an answer without finding one. Here is the error message Warning: date() [function.date]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/New_York' for 'EST/-5.0/no DST' instead in /blocked.php on line 41 12/02/12 Here is the code. Line 41 is near the bottom, the one with the d,m,y. Perhaps the echo date (d/m/y") needs to be changed. Appreciate any help! Code: [Select] <table border="3" width="16%" align="center" cellspacing="0" bgcolor="#FF6600" bordercolor="red" bordercolordark="red" bordercolorlight="red"> <tr> <td width="176"> <p align="center"><?php // shows IP Number on Page echo $ip; ?> </p> </td> </tr> </table> <p align="center"><?php // Show the user agent echo 'Your user agent is: <b>'.$_SERVER['HTTP_USER_AGENT'].'</b><br />';?></p> [b]<h1 align="center"><?php echo date("d/m/y");?></h1>[/b] </td> </tr> </table [,code] Hi, Currently I am making a module for joomla. every article has an publish date, if the article was published in 7 days ago, it will displayed as "article in last week", My idea is to use today's date - publish date, if the result is greater than 7 and smaller than 14, the article will be displayed as "article in last week. Any one know how to write this code? Here is what I have got, but not working. <?php $todays_date = date("Y-m-d"); $result = mysql_query("select * from jos_content where $test between $todays_date-14 and $todays_date-7"); while($row = mysql_fetch_array($result)) { echo "$todays_date - $row[title]"; } ?> Hi guys, I'm putting together a small event system where I want the user to add his own date and time into a textfield (I'll probably make this a series of drop-downs/a date picker later). This is then stored as a timestamp - "0000-00-00 00:00:00" which displays fine until I try to echo it out as a UK date in this format - jS F Y, which just gives today's date but not the inputted date. Here's the code I have right now: Code: [Select] $result = mysql_query("SELECT * FROM stuff.events ORDER BY eventdate ASC"); echo "<br />"; echo mysql_result($result, $i, 'eventvenue'); echo ", "; $dt = new DateTime($eventdate); echo $dt->format("jS F Y"); In my mysql table eventdate is set up as follows: field - eventdate type - timestamp length/values - blank default - current_timestamp collation - blank attributes - on update CURRENT_TIMESTAMP null - blank auto_increment - blank Any help as to why this could be happening would be much appreciated, thanks. |
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