PHP - Help Me On Calendar And Time Scheduling?

Basically I have recently been playing around with parsing a csv file. What I am looking to do at this point is simply take the date/timestamp (part of the csv file), which is in the following format:DD/MM HH:MM:SS.100th/s
For the sake of argument, lets say I have this in an array string called $csv[0] and the file has several lines that span the course of a couple hours. I wouldn't mind having to use explode() to breakup/remove the date or 100th/s IF that would make things a lot simpler.

So where would I start in trying to achieve this?. The result I am looking for will simply return "X Seconds". Storing this in a string variable would be a bonus, as I plan to use this to divide a separate piece of information.

Any examples or ideas would be great. Thank you.

ps:
Here is an example time from the csv file itself:
Code: [Select]
11/19 22:23:18.143

Hello,

I tried to implement some PHP code to enable a web page to show "Dinner" specials versus "Lunch" specials based on the time.

The business is located in the Eastern Time Zone, so I only need to routine to work based on Eastern Time (New York).

What I am noticing is that the server is processing the lines of code so fast that the command to establish the correct time for the remaining code is not always being acknowledged.

This line of code appears to be processing too fast for the remaining lines of code:
date_default_timezone_set ( "America/New_York" );

Is there some additional code I can put in place to make sure the correct time is always ascertained?

I need the $hourmin variable to always return a combination of hour + minute based on 24-hour time and Eastern Time zone.

My code is as follows:


 <?php
   $name8 = file_get_contents("test/special8name.txt");
date_default_timezone_set ( "America/New_York" );
$gethour = date("H");
$getminutes = $gettimedate["minutes"];
$gettimedate = date();
$hourmin = $gethour . $getminutes;
$currentday = date("l", time());
$currentdate = date("M j, Y");
if ($hourmin < 1500 && $currentday <> "Saturday" && $currentday <> "Sunday") {
   echo "<span class=\"namesred\">$name8 </span>";
}
  else if ( $hourmin > 1500 && $hourmin < 2300 && $currentday <> "Saturday" && $currentday <> "Sunday") {
   echo "<span class=\"namesblue\">$name8 </span>";
  }
  else if ( $currentday == "Saturday" or $currentday == "Sunday") {
   echo "<span class=\"namesblue\">$name8 </span>";
  }
?>

PHP 5.2.6

We rent PHP server space on a server in California. Several of my pages generated by PHP show the current date and time, so when the page is printed, the user knows when the data was printed. Our users could be anywhere in the US, I am in Michigan. How do I convert the server time (PDT) into local time, regardless of where the user is?

Thanks.

This topic has been moved to Application Design.

http://www.phpfreaks.com/forums/index.php?topic=316461.0

What are the differences and implications of UTC time and Zulu time?
  

<?php
function getArr(string $time):array
{
    $dateTime = new \DateTime($time);
    return [
        'time'=>$time,
        'timestamp'=> $dateTime->getTimestamp(),
        'dateTime' => $dateTime
    ];
}
$arr = getArr('2020-08-05');  
$arr_z = getArr('2020-08-05T00:00:00Z');  

print_r($arr);
print_r($arr_z);

echo('equal timestamps: '.($arr['timestamp'] === $arr['timestamp']?'true':'false'));

 

Array
(
    [time] => 2020-08-05
    [timestamp] => 1596585600
    [dateTime] => DateTime Object
        (
            [date] => 2020-08-05 00:00:00.000000
            [timezone_type] => 3
            [timezone] => UTC
        )

)
Array
(
    [time] => 2020-08-05T00:00:00Z
    [timestamp] => 1596585600
    [dateTime] => DateTime Object
        (
            [date] => 2020-08-05 00:00:00.000000
            [timezone_type] => 2
            [timezone] => Z
        )

)
equal timestamps: true

 

OK So I've got a datepicker that sends a date in d/m/y format. My DB stores the data in Unix Timestamp Which I can convert the date to with strtotime however this does the exact date & time.

All I want is the actual day. I've spent hours trying to convert this with just the day with mixed results...

Thanks.

I am having a problem with PHP displaying the correct date and time. It updates as it should, but is fast by 4min and is always displaying a date in 2004. I ran a basic php script to make sure the application im using itself is not wrong. go to lunenburgledger.com/time.php

Anybody had any ideas on where to check? The system time on the Windows Server 2003 is correct. The only thing I can think of is that it was converted to a virtual machine on vmware esxi, but the system time stayed right. Any ideas?

Thanks!

Hi,

The hosting provider for my domain confirm me that the server time is in EST (UTC-5). They also sent me a grab supporting that
Code: [Select]
server time is now:
----------------------
Sun Nov 7 02:20:01 EST 2010
-------------------

But when I use the following code, the output I get is has 1 hr difference (UTC-6)
echo date("d M, Y h:i:s A",time());

Output==> 07 Nov, 2010 01:20:01 AM

But it suppose to give the same time as the server, ryt? Can anybody please explain?

Thanks,

Let's say I am buying a share for $10.

If I sell the share on the same day BEFORE 3:30PM, it will be sold for $10, but if I keep the share past 3:30PM, I want the code to automatically add $1 (Taxes and such) once in the the price of the share in database, after that no matter how many days pass by, the price will remain the same.

 

I've thought about CRON jobs, but I have no idea how to make/use them or set them up.

 

Any direction or help is appreciated.

 

 

I am making a time clock, and I was wondering what is the best way to calculate the number of hours an employee worked?

I have a table called "statuses" it holds names of punch types:
- id = the auto_inc
- status = "in/out/break/lunch" text statuses
- paid = whether or not the punch is paid or not (true/false)

I have another table called "logging" This table holds the information about the punch type:
- id = the auto_inc
- owner = the member id
- ip = members ip
- inout = the punch type from the statuses table
- location = the city/state of where the punch took place
- date = the time the member punched

Maybe I am over thinking this, but what is the best way to calculate the hours a person has worked?

Right now I am getting all the punches for for a particular member between a date range. then loop through the data to display it and passing it to a method in a class called Calc. I want to then add the times from punch in to punch out, then the next punch in to punch out.

Any suggestions?

I have this:

    $sql = mysqli_query($conn, "SELECT ip
                                     , page
                                     , CASE WHEN referrer = ''
                                            THEN 'N/A'
                                            ELSE referrer
                                       END as referrer     
                                     , DATE_FORMAT(date, '%m/%d/%y') as date
                                     , TIME_FORMAT(time, '%T') as time
                                FROM tblTraffic 
                                ORDER BY date DESC, time DESC");

most of my traffic report contains the correct times, my time, which is CST in the USA.  but some records are off by a lot.  Does the time() function capture the time of the actual location from which the visitor is coming from?  if so, what could I do to return my timezone for any visitor?  w3 schools and php.net don't mention this.

 

    Good Evening ! 
little help or a lot please ?

I have coded a calendar on my site and am now trying to input the data info from MySQL into the 
calendar by PHP for each corresponding date...the calendar code works but I cant figure out how to 
get the info that's submitted in to the specified/corresponding date in the calendar :/ but I can get 
it to the bottom of the page.

I've been at this 3 days and a million searches to find an example to follow but now I am at my wits 
end ! been about 15 years since I've done this. PLEASE help :) and thank you so much
The HTML is good I can add to it if needed but the problem area is the calendar portion and putting 
it all in the right place without an error or code issue.

I'm not sure how much more information i can provide. Like I said I am still trying to remember all 
of this stuff and trying to teach myself again and im not having much luck but i am a fast learner 
and 
can pickup by seeing how the code is written usually

Here is my code: or at least the PHP portion of it. I hope this helps.

<?php
/*MAKES THE CONNECTION*/
include 'config.php';
$conn = mysqli_connect($servername, $username, $password, $dbname);
// CHECK CONNECTION
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
/*DRAWS CALENDAR*//
function draw_calendar($month,$year){

$calendar = '<table cellpadding="0" cellspacing="0" class="calendar">';

$headings = array('Sunday','Monday','Tuesday','Wednesday','Thursday','Friday','Saturday');
$calendar.= '<tr class="calendar-row"><td class="calendar-day-head">'.implode('</td><td 
class="calendar-day-head">',$headings).'</td></tr>';

$running_day = date('w',mktime(0,0,0,$month,1,$year));
$days_in_month = date('t',mktime(0,0,0,$month,1,$year));
$days_in_this_week = 1;
$day_counter = 0;
$dates_array = array();
$start_day = 

$calendar.= '<tr class="calendar-row">';

for($x = 0; $x < $running_day; $x++):
    $calendar.= '<td class="calendar-day-np"> </td>';
    $days_in_this_week++;
endfor;

for($list_day = 1; $list_day <= $days_in_month; $list_day++):
    $calendar.= '<td class="calendar-day">';
        /* add in the day number */
        $calendar.= '<div class="day-number">'.$list_day.'</div>';

        /** QUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !!  IF MATCHES FOUND, PRINT THEM !! **/
        $sql = "SELECT * FROM $tablename WHERE $current_epoch BETWEEN $start_day AND $end_day";
        /** NEED TOQUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !!  IF MATCHES FOUND, PRINT THEM !! 
**/
$calendar.= str_repeat('<p>'.$start_day.'</p>',2);

     $calendar.= '</td>';
    if($running_day == 6):
        $calendar.= '</tr>';
        if(($day_counter+1) != $days_in_month):
            $calendar.= '<tr class="calendar-row">';
        endif;
        $running_day = -1;
        $days_in_this_week = 0;
    endif;
    $days_in_this_week++; $running_day++; $day_counter++;
endfor;

if($days_in_this_week < 8):
    for($x = 1; $x <= (8 - $days_in_this_week); $x++):
        $calendar.= '<td class="calendar-day-np"> </td>';
    endfor;
endif;

/* final row */
$calendar.= '</tr>';

/* end the table */
$calendar.= '</table>';

return $calendar;
}
$sql = "SELECT id, name, phone, item, start_day, end_day, start_time, end_time FROM $tablename";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $calendar. "id: " . $row["id"]. " - Name: " . $row["name"]. " - Phone: " . $row["phone"]. " - 
Item: " . $row["item"]. " - Start Day: " . $row["start_day"]. " - End Day:  " . $row["end_day"]. " - 
Start Time:  " . $row["start_time"]. " - End Time:  " . $row["end_time"]. "<br>";
}
} else {
echo "0 results";
}

	
	/*END OF SHOWINGCALENDAR_________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
*/	
	
	
$sql = "SELECT id, name, phone, item, start_day, end_day, start_time, end_time FROM $tablename";
$result = $conn->query($sql);
	
/*GETS THE RESULTS OF THE CALENDAR FROM DATABASE TABLE*/
if ($result->num_rows > 0) {
  // output data of each row
  while($row = $result->fetch_assoc()) {
    echo $calendar. "id: " . $row["id"]. " - Name: " . $row["name"]. " - Phone: " . $row["phone"]. " - Item: " . $row["item"]. " - Start Day: " . $row["start_day"]. " - End Day:  " . $row["end_day"]. " - Start Time:  " . $row["start_time"]. " - End Time:  " . $row["end_time"]. "<br>";
  }
} else {
  echo "0 results";
}

 

Edited January 18 by Isfun42ofus

hi,

i have implemented a calendar in php and added contols to display the previous and next months. How will I enhance my code to add links to display the previous and next year calendars?

My code is as follows:
Code: [Select]
<?php
 session_start();
 $_SESSION['username'];
 $_SESSION['unique_id'];
 $username = $_SESSION['username'];
 $unique_id = $_SESSION['unique_id'];
 ?>

<?php
    $host = "localhost";
    $user=""; 
    $password=""; 
    $db_name=""; 
    $tbl_name=""; 
    
    $con = mysql_connect("localhost","","");
    if (!$con)
      {
          die('Could not connect: ' . mysql_error());
      }
    mysql_select_db("$db_name", $con);
    
    // Now we need to define "A DAY", which will be used later in the script:
    define("ADAY", (60*60*24));
     
    // The rest of the script will stay the same until about line 82
     
    if ((!isset($_GET['month'])) || (!isset($_GET['year']))) {
        $nowArray = getdate();
        $month = $nowArray['mon'];  //mon - Numeric representation of a month
    $year = $nowArray['year'];
    } else {
        $month = $_GET['month'];
    $year = $_GET['year'];
    }
    $start = mktime(12,0,0,$month,1,$year);
    $firstDayArray = getdate($start);
    ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title><?php echo "Calendar: ".$firstDayArray['month']."" . $firstDayArray['year']; ?></title>
<link type="text/css" href="css/style_inner.css" rel="stylesheet" />
</head>

<body>
    <form method="get" action="<?php echo $_SERVER['PHP_SELF']; ?>" style="padding-top:50px">
    <?php
        /* "next month" control */
$next_month = '<a href="?month='.($month != 12 ? $month + 1 : 1).'&year='.($month != 12 ? $year : $year + 1).'" class="control" style="text-decoration:none; padding-left:50px;">Next Month&nbsp;&nbsp;></a>';

/* "previous month" control */
$previous_month = '<a href="?month='.($month != 1 ? $month - 1 : 12).'&year='.($month != 1 ? $year : $year - 1).'" class="control" style="text-decoration:none; padding-left:200px; padding-right:50px;"><&nbsp;&nbsp;Previous Month</a>';


/*$next_year = '<a href="?year='.($year != 2050 ? $year + 1 : 1).'&year='.($year != 2050 ? $year : $year + 1).'" class="control" style="text-decoration:none; padding-left:10px;">Next Year&nbsp;&nbsp;>></a>';

$previous_year = '<a href="?month='.($year != 2011 ? $year - 1 : 2050).'&year='.($year != 2011 ? $year : $year - 1).'" class="control" style="text-decoration:none; padding-left:150px;"><<&nbsp;&nbsp;Previous Year</a>';

echo $previous_year;*/
echo $previous_month;
    ?>
    <select name="month"><br/>
    <?php
    $months = Array("January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December");
     
    for ($x=1; $x<=count($months); $x++){
        echo "<option value=\"$x\"";
    if ($x == $month){
            echo " selected";
        }
        echo ">".$months[$x-1]."</option>";
    }
    ?>
    </select>
    <select name="year">
    <?php
    for ($x=2011; $x<=2050; $x++){
    echo "<option";
        if ($x == $year){
        echo " selected";
        }
        echo ">$x</option>";
    }
    ?>
    </select>
<input type="submit" name="submit" value="Go!">
<?php
    echo $next_month;
    /*echo $next_year;*/
?>
    </form>
    <br />
    <?php
    $days = Array("Sun", "Mon", "Tue", "Wed", "Thu", "Fri", "Sat");
    echo "<table border=\"1\" style=\"padding-left:100px;\"><tr>\n";
    foreach ($days as $day) {
        echo "<td style=\"background-color: #000000; width: 100px\" align=\"center\">
              <strong style=\"color:#FFFFFF;\">$day</strong></td>\n";
    }
     
    for ($count=0; $count < (6*7); $count++) {
        $dayArray = getdate($start);
        if (($count % 7) == 0) {
        if ($dayArray["mon"] != $month) {
            break;
        } else {
                echo "</tr><tr>\n";
        }
        }
        if ($count < $firstDayArray["wday"] || $dayArray["mon"] != $month) { //wday - Numeric representation of the day of the week
        echo "<td height=\"110px\"> </td>\n";
        } else { //mday - Numeric representation of the day of the month
            $chkEvent_sql = "SELECT event_title, event_shortdesc FROM calendar_events WHERE month(event_start) = '".$month."' AND dayofmonth(event_start) = '".$dayArray["mday"]."' AND year(event_start) = '".$year."' ORDER BY event_start";
       $chkEvent_res = mysql_query($chkEvent_sql, $con) or die(mysql_error($con));
 
        if (mysql_num_rows($chkEvent_res) > 0) {
            $event_title = "<br/>";
            while ($ev = mysql_fetch_array($chkEvent_res)) {
                    $event_title .= "<font color=\"#006600\">" . stripslashes($ev["event_title"])."</font><br/>";
                    //$event_shortdesc .= stripslashes($ev["event_shortdesc"])."<br/>";
            }
                mysql_free_result($chkEvent_res);
            } else {
            $event_title = "";
            $event_shortdesc = "";
            }
 
        echo "<td height=\"110px\" style=\"color : #0000CC;\">".$dayArray["mday"]."<a href=\"event.php?m=".$month."&d=".$dayArray["mday"]."&y=".$year."\" style=\"text-decoration:none;\"><img src=\"images/Add Event.jpg\" alt=\"Add Event\" title=\"Add Event\" height=\"20px\" width=\"20px\" style=\"padding-left:20px;\"/></a><br/>".$event_title."</td>\n";
         unset($event_title);
     
            $start += ADAY;
        }
    }
    echo "</tr></table>";
    mysql_close($con);
    ?>

</body>
</html>

Please help me out its urgent..


Thank you in advance...

Hello there!

I've been at this for too long! I've got a normal calendar at the side of my website that works fine, however i would like one that shows the next 7 days starting at today. I have an image here that kind of shows what i want...



So it will show the next 7 days starting with today, and going into the next month if todays date is the 30th etc.

Could anybody please help me? :\

Hello Guys,
My goal is to make a Php and SQL calendar. I started learning php and sql a while ago, and basically got distracted. I'm now back, with a new project in the unhelpful position of having forgotten most of what I had learnt!

I am making a project where I want to make a booking system. I have 3 rooms that are available to be booked Room 1, Room 2 and Room 3. I want to make a table that displays the current year in the top row, with the option to be able to click on a '<' or a '>' to change years. I want the same option for months and weeks. I think I am happy with how I would do this. The next bit is more tricky. I want a column for each of the days of the week. directly under this I want to display the correct date, under the correct day, starting with the current week we are on. for example it might look like this:

               -------------------------------------------
               |             <     2012      >                    |
               -------------------------------------------
               |             <      March     >                   |
               -------------------------------------------
               |             <      2     >                          |
               -------------------------------------------
               |mon | tues | wed| thur | fri  | sat | sun |
              | 5th  |  6th |  7th|  8th |9th |10th| 11th |
               ---------------------------------------------
Room 1   | yes    |        |       |       |      |     |        |
               ----------------------------------------------
Room 2   |         |        | yes  |       |      |     |        |
               ----------------------------------------------
Room 3   |         |        |       |       |yes  |     |        |
               ----------------------------------------------

Although at the moment I'm struggling with the whole flippin' thing, the main issue is getting the correct dates to line up under the correct days of the week. I'm not asking for you to do this for me- but a bit of gentle help in this, and maybe some general advice in what I'm trying to achieve would be really useful!

Regards,

AJLX