PHP - Order By Day?

Currently i have a query which at the end has this
Code: [Select]
order by (value/counter) desc");

which works fine, however i was wondering, if in the case that 2 rows have the same, is it possible to set a second value to order by?

I have a database of assorted.  Each row contains defined QUANTITIES for each column item.
Example: columns for shirt, tie, pants, socks.
A row would indicate a purchase of 2 shirts, 1 tie, 0 pants, 3 socks for customer A.
Followed by a row indicate a purchase of 1 shirts, 1 tie, 4 pants, 2 socks for customer B, etc.

Now I want to sort EACH item, group them by quantity, and get an ordered list by quantity, that provides me with something like this:

1 shirt customer B
2 shirt customer C
3 shirt customer F
3 shirt customer H
4 shirt customer D, etc.

I am using this code for my query:
$query = "SELECT brisket, COUNT(brisket) FROM pass GROUP BY brisket ORDER BY brisket ASC";

but it is not organizing the info in a correlated manner.

Help?

Hi All,

I have a 'Newspaper' in a game I'm coding. My plan was to have an edition every week and on average 15 articles a week. I would set this out like so. .

Code: [Select]
<?
$select_paper=mysql_query("SELECT * FROM paper WHERE id=1");
while($the=mysql_fetch_object($select_paper)){
?>
<table width=100% class=table>

<tr>
<td>
<td width=50% style=border: none; background-color: transparent; valign=top>


<table border=1 cellpadding=0 cellspacing=0 bordercolor=#000000 class='main' align=center>
<tr>
  <td width=500 class='tableheading'><?php echo "$the->title"; ?><center>
  </center></td>
  </tr>
<tr >
<td class="profilerow" align=left><center><?php echo "$the->news"; ?>
</td>
  </tr>
<tr >
<td  class="subtableheader" align=left><center><?php echo "Article By $the->by - $the->date"; ?>
</td>
  </tr>
  </table>
<br>
</td>
<? } ?>
With that repeated for 15 articles per edition.

BUT! To save time, space and complication, I would rather do it using something like this. .  Code: [Select]
$select = mysql_query("SELECT * FROM paper WHERE edition=1 ORDER by id ASC");
$num = mysql_num_rows($select);
Could someone tell me how to intergrate this with the layout tables as show in code #1?

Thanks!

Hello,
Am trying to get my records in ascending order from the database using 'ORDER BY' but they come randomly.
What might be the problem?

Is it possible to use the PDO with a statement that has ORDER BY tablename.

The program works fine but when I added the ORDER BY clause it outputted an error.

Is it maybe because I set the fetch mode to PDO::FETCH_OBJ? Or is that irrelevant?

This is the error that outputs:
Code: [Select]
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'BY task_position' at line 1' in /tasks.php(38): PDO->query('SELECT * FROM t...') #1 tasks.php(57): tasks->grab_tasks('2') #2 {main} thrown in tasks.php on line 38
It normally worked without the ORDER BY.

Here is my MYSQL call:

$grabber = $this->pdo->query('SELECT * FROM tasks WHERE user_id = ' . $userid . "ORDER BY 'task_position'");
$grabber->setFetchMode(PDO::FETCH_OBJ);



 

I'm working on a simple ad server and would like to display the ads in order (not random).

I'm fairly certain I can do something like this:

Code: [Select]
// Get the last ad id, or becomes 0 if not available
$lastid = ($_GET['lastid'] == '') ? '0' : $_GET['lastid'];

// Get the next ad in order, or get the first one available
mysql_query("SELECT adcode FROM ads WHERE zone='$zoneid' AND id > $lastid ORDER BY id ASC LIMIT 1");

The above code would get the first ad or the next ad in order.. How do I go back to the beginning when I run out of ads to show?

I'm pulling a list from a DB and inserting it in a drop down menu. Each item on the list has a numerical id associated called marketid in the DB. It works, but it orders the list alphabetically. I need it to order by marketid which is the column name. What code do I need to add? Here is what I have now....

<option value="<?=$market['marketid']?>"><?=$market['name']?></option>

Thanks in advance all!!

Tony

I'm just trying to see if the order of my logic is correct or if there's something I can do differently.  I'm also curious to know at what point I should get the 2 passwords that exists in the database for the user. These are two different passwords.

Code: [Select]
function login_submit()
    {
        $this->form_validation->set_rules('username', 'Username', 'trim|required|xss_clean');
$this->form_validation->set_rules('password', 'Password', 'trim|required|xss_clean');
$this->form_validation->set_rules('remember', 'Remember me', 'integer');
       
        $user_id = $this->users->get_user_id_by_username($this->input->post('username'));
       
        if ($user_id !== 0)
        {
            if ($this->kow_auth->is_max_login_attempts_exceeded($user_id))
            {
                echo json_encode(array('error' => 'yes', 'message' => 'Your account is currently locked, we appologize for the inconvienence. You must wait 10 minutes before you can login again!'));
            }
            else
            {
                $user_status = $this->users->get_user_status($user_id);
               
                if ($user_status == 1)
                {
                    echo json_encode(array('error' => 'yes', 'message' => 'Sorry you must verify your account before logging in!'));                   
                }
                elseif ($user_status == 3)
                {
                    echo json_encode(array('error' => 'yes', 'message' => 'Your account has been suspended!'));         
                }
                elseif ($user_status == 4)
                {
                    echo json_encode(array('error' => 'yes', 'message' => 'Your account is currently banned!'));         
                }
                elseif ($user_status == 5)
                {
                    echo json_encode(array('error' => 'yes', 'message' => 'Your account has been deleted!'));     
                }
                else
                {
                    if ($this->form_validation->run()) {
                        if ($this->kow_auth->login($this->form_validation->set_value('username'), $this->form_validation->set_value('password'), $this->form_validation->set_value('remember')))
                        {
                            redirect('');
        }
                        else
                        {
                            echo json_encode(array('error' => 'yes', 'message' => 'Incorrect username and password combination!'));
                        }
                    }
                }                                             
            }               
        }
        else
        {
            echo json_encode(array('error' => 'yes', 'message' => 'Incorrect username and password combination!'));
        }           
       
    }

Hi all,

I have a script that is essentially a log file of all preious versions of an article (versioning)

You can see the script I am talking about in action at:

http://danielrhyshardy.com/AWT/forumadmin.php

What I would like to do is, instead of displaying the title of each instance (you will see there are two instances named "apple", as they are two previous versions of an article), I would like to display that title once, and then all of the instances of that title be displayed below.

I hope that makes sense.

Here is the code Code: [Select]
<?

$sql = "SELECT id,title,message,date_added FROM messages2 ORDER BY id "; 
 
 
 
 
   $result = mysql_query($sql) or trigger_error(mysql_error(),E_USER_ERROR);
   
   



   while(list($id,$title,$message,$date_added)=mysql_fetch_row($result)){





     
echo '<div style="color:#bb0000;width:250px;text-align:center;float:left;margin-left:15px;margin-bottom:15px;padding-bottom:20px;"><b>'.$title.'<br>'.$date_added.'</b>
 
<input id="'.$message.'" type="radio" name="admin[]" value="'.$id.'"  onclick="javascript:document.form22.car.value=this.id"
  >


</font></div>'."\n";
   
   

   

 
}



?>

I would use something like
Code: [Select]
if ($title = "apple") {

but this would obviously not work for new posts, unless I wanted to constantly update my code.

I am sure there is a simple way to achieve this.

Perhaps someone can tell me!?

Thanks in advance

Dan

Currently I have where the User can search for records, then the records are displayed on a page. I then have a drop down box to where the user can Order by 2 different categories to make it easier for the user to see things but for some reason it is not working. Here is my code.

Oh and the error I get is mysql_num_rows(): supplied argument is not a valid MySQL result resource in

<?php
$qry_str="SELECT * FROM timeslip WHERE 1 ";  

if($_POST['Initials']) 
{ 
   $Initials=$_POST['Initials'];  
   $qry_str.="and Initials='$Initials' "; 
} 

if($_POST['Identifier']) 
{ 
   $Identifier=$_POST['Identifier'];  
   $qry_str.="and Identifier LIKE '%$Identifier%' "; 
} 

if($_POST['Type']) 
{ 
   $Type=$_POST['Type'];  
   $qry_str.="and Type LIKE '%$Type%' "; 
} 
if($_POST['Terms']) 
{ 
   $Terms=$_POST['Terms'];  
   $qry_str.="and Terms LIKE '%$Terms%' "; 
} 
if($_POST['Memo']) 
{ 
   $Memo=$_POST['Memo'];  
   $qry_str.="and Memo LIKE '%$Memo%' "; 
}
if($_POST['date1']) 
{  
   $date1=$_POST['date1'];
   $date2=$_POST['date2'];
   $start=date('Y-m-d', strtotime($date1));
   $end=date('Y-m-d', strtotime($date2));
   $qry_str.="and Date >= '$start' and Date <= '$end' "; 
}
if($_POST['order1'] && $_POST['order2'])
{
$order1=$_POST['order1'];
$order2=$_POST['order2'];
$qry=$_POST['qry'];
$qry_str="$qry ORDER BY $order1 ASC, $order2 ASC ";
}
if($_POST['order1'])
{
$order1=$_POST['order1'];
$qry=$_POST['qry'];
$qry_str="$qry ORDER BY $order1 ASC";
}
if($_POST['order2'])
{
$order2=$_POST['order2'];
$qry=$_POST['qry'];
$qry_str="$qry ORDER BY $order2' ASC ";
}
$result=mysql_query($qry_str); 
$count=mysql_num_rows($result); 
if ($count>0){

?>

<form action="" method="post">
<input type="hidden" value="<?=$qry_str?>" name="qry"/>
Order Results By
<select name="order1" >
<OPTION value="<?=$order1?>"><?=$order1?></OPTION>
<OPTION value="Identifier">Identifier</OPTION>
                <OPTION value="Type">Type</OPTION>
             <OPTION value="Terms">Terms</OPTION>
                <OPTION value="Date">Date</OPTION>
             <OPTION value="Cost">Cost</OPTION>
              
</select> 
Then
<select name="order2" >
<OPTION value="<?=$order2?>"><?=$order2?></OPTION>
<OPTION value="Identifier">Identifier</OPTION>
                <OPTION value="Type">Type</OPTION>
             <OPTION value="Terms">Terms</OPTION>
                <OPTION value="Date">Date</OPTION>
             <OPTION value="Cost">Cost</OPTION>
              
</select> 
<input type="submit" name="submit">
</form>

Greetings! I am really stock on this situation.

1. I have a variable $uc_order_created.
2. I have a code like this:

<b><?php echo t('Due Date:'); ?></b>
             </td>
                <td width="98%">
             <?php $duedate = mktime(0,0,0,date("m"),date("d")+30,date("Y"));
        echo "".date("F jS Y", $duedate);?>

3. How do I code if I want the result of $uc_order_created get displayed as Due Date using the code above? Or other modifications?
4. The situation now, the code is working when printing the invoice but its not based on $uc_order_created. So, every time I will edit the Order because of the change of items among others the Due Date will also update. All I want that when Order is edited the value of Due Date will still remain based on the $uc_order_created.

Thank you so much in advance for your help.

Hey everybody, i'm building a website for the softball league i play in.... so far the website is pretty good... with all the stats and profiles.... i'm having a little problem with the ORDER of the leaders in the categories i have to calculate the result...

for example... avg. is the result of the total hits divided by the total number of at bats... both numbers are coming from the database... the problem comes when i have to order the leaders from first to last...

this is my php:

Code: [Select]
$sql = "select profile_id, SUM(total_hits) AS hitstotal, SUM(ab) AS abtotal from batters WHERE year = '2010' GROUP BY profile_id";

$cons = mysql_query($sql);
while ($result = mysql_fetch_array($cons)) {
$sumaab = $resultad['abtotal'];
$sumahits = $resultad['hitstotal'];
$p_id = $resultad['profile_id'];
$prom = round(($sumahits."") / ($sumaab.""),3);

that gives me all the batting averages for the players.

and here is my question:
how can i order that $prom result from first to last?

I posted this in mysql as well but maybe someone would know the php/mysql syntax to do this:

How to re order records after a delete or move?

I have table of navigational items. lets say under "about us" i have 5 sub links and i order them by a field called theorder. How can a re order them properly if one is deleted?  orders are 1,2,3,4,5 and if i delete the record that is 3 then the order is 1,2,4,5 but i want it to now become 1,2,3,4.  How do i do this properly?

Thanks

Hi guys, i'm having trouble with making a order form for my school assignment, i'm trying to get it so that it gets the product number from one of the tables to show in a drop down box thingy any help would be greatly appricated. the code is below:

<form name="Place an Order" method="post" action="order2.php "></center>
    <center><p>Enter the Product ID of the product you wish to purchase <a href="product.php" target="content">(cant remember? click here)</a>:  <input name="ProductID" type="select" value="$query=mysql_query("SELECT ProductID FROM Products ORDER BY ProductName ASC") or die(mysql_error());
print("<select name=\"productid\">\n");
while ($row = mysql_fetch_row($query)) {
   printf("<option value=\"*" selected>*</option>\n", $row[0], $row[1]);
}
print("</select><br>");">"</p>
    <p>Customer ID <a href="Customer.php" target="content">(If you are not already a customer click here)</a>:  <input name="CustomerID" type="text" value="Customer ID"></p>
    <p>Quantity:  <input name="Quantity" type="text" value="99"></p>
    <input name="Place Order" type="submit" value="Place Order">
   </center>
</form>

Hi, I've been trying to re-order an array and I can't seem to even do it let alone neatly. I've ran out of time and would appreciate any help!


$array = array(
  '0' => array(
    'filepath' => 'files/image_site1.png',
    'title' => 'Website',
  ),
  '1' => array(
    'filepath' => 'files/image_id.png',
    'title' => 'Identitity',
  ),
  '2' => array(
    'filepath' => 'files/image_site2.png',
    'title' => 'Website',
  )
)

I'm looking to re-order the arrays within the parent array depending on whether the 'filepath's contain a sub string of '_id' or '_site'.

I've been using:
$type = '_site';
foreach ($array as $item){
  if (preg_match("/$type/i", $item['filename'])){
    //add this $item to the top of array, somehow...
  }
}

So with $type set to '_site', I'd like to re-arrange the array so both arrays containing _site1.png and _site2.png appear at the top of the parent array. I.e:
$array('0' = array(...), '2' => array(...), '1' => array(...));

I hope I've explained it well enough.

Thanks,