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PHP - How To Display 2 Query Results Not Just One
Hello all,
I have made the multi level marketing downline tree, but the problem with it now, it gives only the downline of one result, as the query gives 2 results what I want now is to make it give the downline of both results not just one, and it's always 2 results, not more here is my code Code: [Select] <?php $id = $_GET['id']; $result = mysql_query("SELECT id FROM users WHERE id = '".$id."' ORDER BY id"); $row = mysql_fetch_assoc($result); if ($row['id'] == 0) { echo" <table> <div id=\".piccenter\""; echo "<tr>"; echo "<img src=\"icon.gif\" border=0 align=\"center\">"; echo ""; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row['id']."'"; echo ""; echo "</div>"; } } $result2 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row['id']."'"); $rows2 = mysql_fetch_assoc($result2); foreach ($rows2 as $row2) { if ($row2['id'] == 0) { echo" <div id=\".picleft\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0 >"; echo "<br />"; echo "'".$row2['id']."'"; echo "</div>"; echo " <td>"; echo "</td> "; } } $result3 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows2['id']."'"); $row3 = mysql_fetch_assoc($result3); if ($row3['id'] == 0) { echo"<div id=\".picright\"> <img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$row3['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result4 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$row3['id']."'"); $rows4 = mysql_fetch_assoc($result4); if ($rows4['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows4['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result5 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows4['id']."'"); $rows5 = mysql_fetch_assoc($result5); if ($rows5['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows5['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result6 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows5['id']."'"); $rows6 = mysql_fetch_assoc($result6); if ($rows6['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows6['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result7 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows6['id']."'"); $rows7 = mysql_fetch_assoc($result7); if ($rows7['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows7['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result8 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows7['id']."'"); $rows8 = mysql_fetch_assoc($result8); if ($rows8['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows8['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> "; } $result9 = mysql_query("SELECT id FROM users WHERE recruiteris = '".$rows8['id']."'"); $rows9 = mysql_fetch_assoc($result9); if ($rows9['id'] == 0) { echo"<img src=\"icon.gif\" border=0 align=\"center\">"; } else { echo "<img src=\"images.png\" border=0>"; echo "<br />"; echo "'".$rows9['id']."'"; echo ""; echo " <tr> <td>"; echo "</td> </tr> </tbody> </table> "; } ?> Similar TutorialsHey all. I have a query that selects data from a datbase based on a criteria. Easy enough. But now I am growing and the amount displaying is too much. How can you, via php, have a queries result be displayed only so many at a time and auto create links that show the rest? Like if query returns 82 results, I want it to display 25 immediately and create 3 links at the bottom. The next link would show 26-50. The next 51-75. And the final 76-82. etc Example: Code: [Select] $result = mysql_query("SELECT * FROM pay"); $num_rows = mysql_num_rows($result); while($row = mysql_fetch_array($result)) { echo $row['first_name']; echo $row['last_name']; echo $row['item_name']; echo $row['option_selection1']; echo $row['payment_date']; echo $row['stat']; } This is simple. But what happens when the results are 125? I want to limit it to displaying 25 at a time. Is the only way to manually create seperate pages and have each one show 1-25, then 26-50, etc? Or is there a way to have the script do it, itself? Any tutorials out there on this specifically? Hopefully I am making sense. Thanks! Hello, I know this should be pretty simple to figure out, but everything I try is giving me absolutely no results. I have a mysql query selecting columns from my database and returning results. I have the results printing out right now, so I can see that this part is working. All I want to do is take the results and put them into a table to display on my page. Basically, take what's in the database table and copy it to a table I can put on the web. FYI I am using sourcerer so the "connect" code is taken care of for me in the "JFactory" bit of code. Here is the first part of my code, selecting the information from the database. {source} <?php $db = JFactory::getDbo(); $query = $db -> getQuery(true); $query -> SELECT($db -> quoteName(array('first_dept_name', 'last_name', 'dept', 'position', 'phone_num'))); $query -> FROM ($db -> quoteName('#__custom_contacts')); $query -> ORDER ('first_dept_name DESC'); $query -> WHERE ($db -> quoteName('contact_category')."=".$db -> quote('YTown Employees')); $db -> setQuery($query); $results = $db -> loadObjectList(); print_r($results); Here is where I am trying to print the results into a table. I got this code directly from a PHP book, but I am getting nothing at all returned back to me. I get table headers, but no data. <?php echo "<table><tr><th>Name</th><th>Department</th></tr>"; while ($row = mysqli_fetch_array ($result)){ echo "<tr>"; echo "<td>".$row['last_name']."</td>"; echo "<td>".$row['dept']."</td>"; echo "</tr>"; } echo "</table>"; ?> {/source} Hello all. I'm using this code to go through the database and output certain user-defined numbers Code: [Select] <?php mysql_connect ("pdb1.awardspace.com", "anastasov_db","moscow1945") or die (mysql_error()); mysql_select_db ("anastasov_db"); $term = $_POST['term']; $sql = mysql_query("select * FROM countries WHERE cocode = '$term'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Code: '.$row['cocode']; echo '<br/> Country: '.$row['coname']; echo '<br/><br/>'; } ?> Now how would I go about making a page that appears if the script can't find any results in the database? Thank you in advance I have no clue about to go abt this one: I have form which has some: Code: [Select] <table> <tr> <td> <form> Title display info </form> </td> </tr> </table> I need to add an additional link next to title such that when someone clicks on the link the table expands and displays rsult of a query. Code: [Select] <table> <tr> <td> <form> Title LINK if( link is clicked ) { $query=select display query results } else { dont display query results display info } </form> </td> </tr> </table> Say a user puts in a support request, and for every request it generates a unqiue string, and enters it into the database. Ok, now say there is a text field, when the user enters their unique string and it finds a match, it displays the data along with it. How can I accomplish this? Im kind of new to mysql, but I know basic SQL. Would be great if somebody could point me in the right direction! Thanks First off, let me say that this will not be a public use site. We want to create a site that allows us to run queries in our database; this way we don't need to log into the MySQL server when ever we want to run a query. Basically, I am trying to create something as simple as a form with a text-input and a submit button. In this text-input, we will write a query (such as SELECT * FROM xxxx). When we hit submit, we would like to have the MySQL table printed out in a large textbox below. Our database has multiple tables, so something that works across the entire database seamlessly is key. Has anyone ever made anything like this? Is there another way to go about this? We really just want an easy way to run queries on the go. Thanks in advance to anyone who replies! In an .html, before : <!-- BEGIN myquery --> I need to stop output and check the content of "myquery" Is there a command for that ? Thank You. I have the following code that searches my database and displays results in a table: $fields = array("field1", "field2", "field3") $cols = implode (', ', $fields); $result= mysql_query (" SELECT $cols FROM tablename WHERE ................... "); if (!$result) {die('Could not search database: ' . mysql_error());} if($result) { if(mysql_num_rows($result) == 0) { return "Sorry. No records found in the database"; } else { $table = "<table border='1' cellpadding='5' cellspacing='5'>"; while($arr = mysql_fetch_array($result, MYSQL_ASSOC)) { $table .= "\t\t<tr>\n"; foreach ($arr as $val_col) { $table .= "\t\t\t".'<td>'.$val_col.'</td>'."\n"; } $table .= "\t\t</tr>\n"; } $table .= "</table>"; echo $table; } mysql_free_result($result); } As you can see each of the MySQL table fields specified by $fields is displayed in a new column in the html table. I want to change this so that e.g. "field3" is displayed in a new row instead. So, instead of the html table looking like: | "field1-result1" | "field2-result1" | "field3-result1" | | "field1-result2" | "field2-result2" | "field3-result2" | | "field1-result3" | "field2-result3" | "field3-result3" | I want it to look like: | "field1-result1" | "field2-result1" | | "field3-result1" | | | "field1-result2" | "field2-result2" | | "field3-result2" | | | "field1-result3" | "field2-result3" | | "field3-result3" | | I guess this is quite straightforward, but I can't work it out! Pls help! Thanks. Hello all,
Based on the suggestion of you wonderful folks here, I went away for a few days (to learn about PDO and Prepared Statements) in order to replace the MySQLi commands in my code. That's gone pretty well thus far...with me having learnt and successfully replaced most of my "bad" code with elegant, SQL-Injection-proof code (or so I hope).
The one-and-only problem I'm having (for now at least) is that I'm having trouble understanding how to execute an UPDATE query within the resultset of a SELECT query (using PDO and prepared statements, of course).
Let me explain (my scenario), and since a picture speaks a thousand words I've also inlcuded a screenshot to show you guys my setup:
In my table I have two columns (which are essentially flags i.e. Y/N), one for "items alreay purchased" and the other for "items to be purchased later". The first flag, if/when set ON (Y) will highlight row(s) in red...and the second flag will highlight row(s) in blue (when set ON).
I initially had four buttons, two each for setting the flags/columns to "Y", and another two to reverse the columns/flags to "N". That was when I had my delete functionality as a separate operation on a separate tab/list item, and that was fine.
Now that I've realized I can include both operations (update and delete) on just the one tab, I've also figured it would be better to pare down those four buttons (into just two), and set them up as a toggle feature i.e. if the value is currently "Y" then the button will set it to "N", and vice versa.
So, looking at my attached picture, if a person selects (using the checkboxes) the first four rows and clicks the first button (labeled "Toggle selected items as Purchased/Not Purchased") then the following must happen:
1. The purchased_flag for rows # 2 and 4 must be switched OFF (set to N)...so they will no longer be highlighted in red.
2. The purchased_flag for row # 3 must be switched ON (set to Y)...so that row will now be highlighted in red.
3. Nothing must be done to rows # 1 and 5 since: a) row 5 was not selected/checked to begin with, and b) row # 1 has its purchase_later_flag set ON (to Y), so it must be skipped over.
Looking at my code below, I'm guessing (and here's where I need the help) that there's something wrong in the code within the section that says "/*** loop through the results/collection of checked items ***/". I've probably made it more complex than it should be, and that's due to the fact that I have no idea what I'm doing (or rather, how I should be doing it), and this has driven me insane for the last 2 days...which prompted me to "throw in the towel" and seek the help of you very helpful and intellegent folks. BTW, I am a newbie at this, so if I could be provided the exact code, that would be most wonderful, and much highly appreciated.
Thanks to you folks, I'm feeling real good (with a great sense of achievement) after having come here and got the great advice to learn PDO and prepared statements.
Just this one nasty little hurdle is stopping me from getting to "end-of-job" on my very first WebApp. BTW, sorry about the long post...this is the best/only way I could clearly explaing my situation.
Cheers guys!
case "update-delete":
if(isset($_POST['highlight-purchased']))
{
// ****** Setup customized query to obtain only items that are checked ******
$sql = "SELECT * FROM shoplist WHERE";
for($i=0; $i < count($_POST['checkboxes']); $i++)
{
$sql=$sql . " idnumber=" . $_POST['checkboxes'][$i] . " or";
}
$sql= rtrim($sql, "or");
$statement = $conn->prepare($sql);
$statement->execute();
// *** fetch results for all checked items (1st query) *** //
$result = $statement->fetchAll();
$statement->closeCursor();
// Setup query that will change the purchased flag to "N", if it's currently set to "Y"
$sqlSetToN = "UPDATE shoplist SET purchased = 'N' WHERE purchased = 'Y'";
// Setup query that will change the purchased flag to "Y", if it's currently set to "N", "", or NULL
$sqlSetToY = "UPDATE shoplist SET purchased = 'Y' WHERE purchased = 'N' OR purchased = '' OR purchased IS NULL";
$statementSetToN = $conn->prepare($sqlSetToN);
$statementSetToY = $conn->prepare($sqlSetToY);
/*** loop through the results/collection of checked items ***/
foreach($result as $row)
{
if ($row["purchased"] != "Y")
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToY = $statementSetToY->fetch();
foreach($resultSetToY as $row)
{
$statementSetToY->execute();
}
}
else
{
// *** fetch one row at a time pertaining to the 2nd query *** //
$resultSetToN = $statementSetToN->fetch();
foreach($resultSetToN as $row)
{
$statementSetToN->execute();
}
}
}
break;
}
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What would be the correct way to close a mysql query? At current the second query below returns results from the 1st query AND the 2nd query The 3rd query returns results from the 1st, 2nd and 3rd query. etc etc. At the moment I get somthing returned along the lines of... QUERY 1 RESULTS Accommodation 1 Accommodation 2 Accommodation 3 QUERY 2 RESULTS Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 QUERY 3 RESULTS Takeaways 1 Takeaways 2 Takeaways 3 Restaurant 1 Restaurant 2 Restaurant 3 Accommodation 1 Accommodation 2 Accommodation 3 Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <?php include($_SERVER['DOCUMENT_ROOT'].'/include/db.php'); ?> <title>Untitled Document</title> <style type="text/css"> <!-- --> </style> <link href="a.css" rel="stylesheet" type="text/css" /> </head><body> <div id="listhold"> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Placestostay.html">Places To Stay</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Accommodation' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingout.html">Eating Out</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Restaurant' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------------------------------------------------------------------------------> <div class="list"><a href="Eatingin.html">Eating In</a><br /> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Takeaways' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> <!------------------------------------------------------------------------------SKILLED TRADES BELOW---------------------------------------------------> <div class="list"><a href="Skilledtrades.html">Skilled Trades</a><br/> <?php $title ="TITLE GOES HERE"; $query = mysql_query("SELECT DISTINCT subtype FROM business WHERE type ='Skilled Trades' AND confirmed ='Yes' ORDER BY name"); echo mysql_error(); while($ntx=mysql_fetch_row($query)) $nt[] = $ntx[0]; $i = -1; foreach($nt as $value) {$i++; $FileName = str_replace(' ','_',$nt[$i]) . ".php"; $FileUsed = str_replace('_',' ',$nt[$i]); echo "<a href='" . str_replace(' ','_',$nt[$i]) . ".php?title=$title&subtype=$FileUsed'>" . $nt[$i] . "</a>" . "<br/>"; $FileHandle = fopen($FileName, 'w') or die("cant open file"); $pageContents = file_get_contents("header.php"); fwrite($FileHandle,"$pageContents");} fclose($FileHandle); ?> </div> quick question, I have this code that returns over 100 buttons: Code: [Select] <?php // Query member data from the database and ready it for display $sql = mysql_query("SELECT * FROM products"); while($row = mysql_fetch_array($sql)){ $product = $row["product"]; $id =$row["id"]; $price =$row["price"]; ?> <div id="products"> <form action="" method="POST" name="myform<?php echo $id; ?>" class="myform<?php echo $id; ?>"> <input type="hidden" name="hiddenField" class="hiddenField" value="<?php echo $product; ?>" /> <input type="hidden" name="hiddenField2" class="hiddenField2" value="<?php echo $id; ?>" /> <input type="hidden" name="hiddenField1" class="hiddenField1" value="<?php echo $price; ?>" /> <input type="submit" name="submit" class="submit" value="<?php echo $product; ?>" style="background-color:lightgreen; height:50px; width:100px;"> </form> </div> <?php } ?> What I would like is for the buttons to form columns of nine. ie 9 buttons in a column then a new column form.... how do I do this? Can someone please give me some ideas as to what might be wrong with this query...I keep getting no result and am echoing $count for debugging (and usernames and passwords) but get nothing for $count (expecting a 0 or a 1) or $dbusername or $dbpassword $sql="SELECT * FROM `users` WHERE `User name` = '$fusername' and `Password` = '$fpassword'"; $result=mysql_query($sql); $dbusername=mysql_result($result,0,"User name"); $dbpassword=mysql_result($result,0,"Password"); echo $dbusername; echo $dbpassword; // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $fusername and $fpassword, table row must be 1 row echo $fusername; echo $fpassword; echo $count; if($count==1){ (This is where I keep going to the else) Hi, say I have a query like so: foreach($_REQUEST['r'] as $position => $row) { $row = implode("', '",$row); $result = mysql_query("Insert into player_stats (position,shirt_number,player_id,goals,cards,substituted,used_sub,injury,season,report_id) values('$position','$row','$currentSeason','$report_id')"); } How do I print the results of that query to my Browser for each time? Thanks Hello, This is query in MySQL Quote mysql> LOAD DATA LOCAL INFILE '/var/www/html/numbers.csv' INTO TABLE details FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n' (number); Query OK, 0 rows affected (0.00 sec) Records: 2200 Deleted: 0 Skipped: 1200 Warnings: 0 Now, I am trying to run the same query in PHP and display the same results.... (i.e. Records, Deleted, Skipped) Quote <?php $db=mysql_connect("localhost", "user", "1234") or die(mysql_error()); $dname="database"; mysql_select_db($dname)or die(mysql_error()); $sqlstatement="LOAD DATA LOCAL INFILE '/var/www/html/numbers.csv' INTO TABLE details FIELDS TERMINATED BY ',' LINES TERMINATED BY '\n' (number)" ; mysql_query($sqlstatement) or die(mysql_error());; echo "it is done!"; ?> Tried mysql_fetch_array, row but could not get it to work... please help guys I am able to run and display two queries I need for my program but having issues comparing the two result sets. If they are identical, means both tables are also identical (the query is for the table's schemas in MS-SQL) Here's the relevant part ... Code: [Select] //Variables $table_name=$_POST['table_name']; // Connect via Windows authentication $server = 'win1\i01'; //Connection info for PRO $connectionInfoPRO = array( 'Database' => 'adventureworks', 'CharacterSet' => 'UTF-8' ); $dbPRO = sqlsrv_connect($server, $connectionInfoPRO); if ($dbPRO === false) { exitWithSQLError('Database connection to PRO failed'); } //Connection info for ITG $connectionInfoITG = array( 'Database' => 'adventureworksCOPY', 'CharacterSet' => 'UTF-8' ); $dbITG = sqlsrv_connect($server, $connectionInfoITG); if ($dbITG === false) { exitWithSQLError('Database connection to ITG failed'); } /* Set up and execute the query. */ $query1 = "SELECT COLUMN_NAME, DATA_TYPE, ORDINAL_POSITION, COLUMN_DEFAULT, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='$table_name'"; // Run PRO query $qresult1 = sqlsrv_query($dbPRO, $query1); if ($qresult1 === false) { exitWithSQLError('Query of product data failed.'); } echo '<tr><th>NAME</th><th>TYPE</th><th>POSITION</th><th>DEFAULT</th><th>LENGHT</th><th>IS NULLABLE</th></tr>'; // Retrieve individual rows from the result while ($row1 = sqlsrv_fetch_array($qresult1)) { echo '<tr><td>', htmlspecialchars($row1['COLUMN_NAME']), '</td><td>', htmlspecialchars($row1['DATA_TYPE']), '</td><td>', htmlspecialchars($row1['ORDINAL_POSITION']), '</td><td>', htmlspecialchars($row1['COLUMN_DEFAULT']), '</td><td>', htmlspecialchars($row1['CHARACTER_MAXIMUM_LENGTH']), '</td><td>', htmlspecialchars($row1['IS_NULLABLE']), "</td></tr>\n"; } // null == no further rows, false == error if ($row1 === false) { exitWithSQLError('Retrieving schema failed.'); } //Run ITG query $query2 = "SELECT COLUMN_NAME, DATA_TYPE, ORDINAL_POSITION, COLUMN_DEFAULT, CHARACTER_MAXIMUM_LENGTH, IS_NULLABLE FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='$table_name'"; $qresult2 = sqlsrv_query($dbITG, $query2); if ($qresult2 === false) { exitWithSQLError('Query of product data failed.'); } echo '<tr><th>NAME</th><th>TYPE</th><th>POSITION</th><th>DEFAULT</th><th>LENGHT</th><th>IS NULLABLE</th></tr>'; // Retrieve individual rows from the result while ($row2 = sqlsrv_fetch_array($qresult2)) { echo '<tr><td>', htmlspecialchars($row2['COLUMN_NAME']), '</td><td>', htmlspecialchars($row2['DATA_TYPE']), '</td><td>', htmlspecialchars($row2['ORDINAL_POSITION']), '</td><td>', htmlspecialchars($row2['COLUMN_DEFAULT']), '</td><td>', htmlspecialchars($row2['CHARACTER_MAXIMUM_LENGTH']), '</td><td>', htmlspecialchars($row2['IS_NULLABLE']), "</td></tr>\n"; } // null == no further rows, false == error if ($row2 === false) { exitWithSQLError('Retrieving schema failed.'); } How can I compare $row1 and $row2 here (the query results for each one) and validate if they both have same results, each and all columns. Any help is highly appreciated! Hello all, I am new here so thank you in advance for all of your help. I am writing a pretty simple search script to display data from a table however have run into a snag. Things seem to get complicated all by themselves. I have a drop down to select the predetermined search criteria, because the data has either a 'Y'es or 'N'o. For example there are 50 or so products/brands with ingredients/categories in them. i.e. Brand X contains Sugar=Y, Salt=Y, Vinegar=N Brand Y contains Sugar=N, Salt=N, Vinegar=N Brand Z contains Sugar=Y, Salt=Y, Vinegar=Y Brand A contains Sugar=N, Salt=N, Vinegar=Y I want to display the brands that contain only the selected ingredients. I have added check boxes for the user to select. This runs ok however the return is more of a broader result and requires too much interpretation from the user. i.e. If I want to know which brands contain only salt and vinegar ??BRAND??= Sugar=N, Salt=Y, Vinegar=Y or ??BRAND??= Salt=Y, Vinegar=Y The return comes back: Brand X contains Sugar=Y, Salt=Y, Vinegar=N Brand Z contains Sugar=Y, Salt=Y, Vinegar=Y Brand A contains Sugar=N, Salt=N, Vinegar=Y Ideally the return Should only be: Brand Z contains Sugar=Y, Salt=Y, Vinegar=Y I believe the else if statement would work, I just have no knowledge of where to put it or how it would work. Any suggestions would be greatly appreciated. Hi I have a query where it returns a few fields based on the location. I created a class for the function and an index page. It does not return any values. Can someone please advise/ THE CLASS Code: [Select] <?php /**************************************** * * WIP Progress Class * * ****************************************/ class CHWIPProgress { var $conn; // Constructor, connect to the database public function __construct() { require_once "/var/www/reporting/settings.php"; define("DAY", 86400); if(!$this->conn = mysql_connect(DB_HOST, DB_USERNAME, DB_PASSWORD)) die(mysql_error()); if(!mysql_select_db(DB_DATABASE_NAME, $this->conn)) die(mysql_error()); } public function ListWIPOnLocation($location) { $sql = "SELECT `ProgressPoint.PPDescription` AS Description ,`Bundle.WorksOrder` AS WorksOrder, `Bundle.BundleNumber` AS Number, `Bundle.BundleReference` AS Reference,`TWOrder.DueDate` AS Duedate FROM `TWOrder`,`Bundle`,`ProgressPoint` WHERE `Bundle.CurrentProgressPoint`=`ProgressPoint.PPNumber` AND `TWOrder.Colour=Bundle.Colour` AND `TWOrder.Size=Bundle.Size` AND `TWOrder.WorksOrderNumber`=`Bundle.WorksOrder` AND `ProgressPoint.PPDescription` LIKE '" . $location . "%' ORDER BY TWOrder.DueDate DESC"; mysql_select_db(DB_DATABASE_NAME, $this->conn); $result = mysql_query($sql, $this->conn); echo $sql; while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $return[] = $row; } return $return; } } ?> The index page Code: [Select] <?php // First of all initialise the user and check for permissions require_once "/var/www/users/user.php"; $user = new CHUser(7); // Initialise the template require_once "/var/www/template/template.php"; $template = new CHTemplate(); // And create a cid object require_once "/var/www/WIPProgress/DisplayWIPOnLocation.php"; $WIPProgress= new CHWIPProgress(); $content = "Check WIP Status on Location <br>"; $content = "<form action='index.php' method='get' name ='location'> <select id='location' > <option>Skin Room</option> <option>Clicking</option> <option>Kettering</option> <option>Closing</option> <option>Rushden</option> <option>Assembly</option> <option>Lasting</option> <option>Making</option> <option>Finishing</option> <option>Shoe Room</option> </select> <input type='submit' /> </form>"; $wip = $WIPProgress->ListWIPOnLocation($_GET['location']); // Now show the details $content .= "<h2>Detail</h2> <table> <tr> <th>PPDescription</th> <th>Works Order</th> <th>Bundle Number</th> <th>Bundle Reference</th> <th>Due Date</th> </tr>"; foreach($wip as $x) { $content .= "<tr> <td>" . $x['Description'] . "</td> <td>" . $x['WorksOrder'] . "</td> <td>" . $x['Number'] . "</td> <td>" . $x['Reference'] . "</td> <td>" . $x['DueDate'] . "</td> </tr>"; } $template->SetTag("content", $content); echo $template->Display(); ?> thank you Code: [Select] $PlayerQuery = "SELECT FirstName, SurName FROM players p, rounds m, entrants e, games t WHERE p.PlayerID = e.PlayerID AND m.GameID = '$ID' AND e.EntrantID = m.Player"; $PlayerResult = mysql_query($PlayerQuery); $PlayerRow = mysql_num_rows($PlayerResult); Can someone suggest why this returns game*the number of results. For each new game it returns an extra duplicate result. For example for 2 games: j Smith j Smith t John t John etc There are no duplicate entry's! and results should be unique. Not in a loop (positive) I was just wondering if this is a way that you can exclude certain rows from a MySQL query. For example if I have 10 records each with a unique id, is there anyway I can get all of the records except record 5? Thanks for any help. Hi all, I'm new to php and I was trying to send the results of one query to another query. I need the results of both queries. Here are the queries $cui1 = mysql_query("SELECT DISTINCT CUI FROM MRSTY WHERE STY='ABC' "); $cui2 = mysql_query("SELECT DISTINCT CUI FROM MRSTY WHERE STY='XYZ' "); I want to know if this is possible $cuis = mysql_query("SELECT CUI1,CUI2,REL FROM MRREL WHERE CUI1 IN $cui1 OR CUI1 IN $cui2 "); Thanks. |
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