PHP - Dynamic Drop Down - Multiple Colums

I am a beginner. 

How do you capture the selected value in dynamic dropdown and submit it to a different table in mysql

Holy smoke, it has been a looooooong time since I have been here. Love the new look of the site btw. Well I am working on a new project for my church. The idea is an email to SMS program. So one use of this would be that if there is a youth activity I could send a message to the entire youth group with one message. I am trying to figure out something specific with it. I need to create a form that grabs info from the database. So more specifically what I need is one drop down that will have "Youth Group", "Parents", "Deacons", etc. now based on what I select I need the second drop down to populate with the corresponding people in that group. Now I want an "All" to be in the drop down to which would let me send the message I type to ALL people in the desired group but to also have the individual names come up just in case I need to do a specific person.

How would I go about doing something like this? I have done much research and cant quite find what I would need to do. Any help would be GREATLY appreciated.

I really can't get my head around this dynamic drop box. What I want is for a drop box to be populated with values in my database.

I have this that connects to my SQL and picks out the table required:

function displayUsers(){
   global $database;
   $q = "SELECT username,"
       ."FROM ".TBL_USERS." ORDER BY userlevel DESC,username";
   $result = $database->query($q);    ...

I then have this to pick out any errors, and also using the num_rows to get the number of rows (values) there a

$num_rows = mysql_numrows($result);
   if(!$result || ($num_rows < 0)){
      echo "Error displaying info";
      return;
   }
   if($num_rows == 0){
      echo "Database table empty";
      return;
   }

From here, I guess I want the num_rows to keep 'adding on' the number of <option value=""> in my selection box according the number of values I have in my database.

At this point, I can pull out the values into a dynamic table ... but I want it into a drop box -- but I'll but up the code for the dynamic table so you can get an idea:


/* Display table contents */
   echo "<table align=\"left\" border=\"1\" cellspacing=\"0\" cellpadding=\"3\">\n";
   echo "<tr><td><b>Username</b></td></tr>\n";
   for($i=0; $i<$num_rows; $i++){
      $uname  = mysql_result($result,$i,"username");
      echo "<tr><td>$uname</td></tr>\n";
   }
   echo "</table><br>\n";
}

I hope you can use the code above to help me develop this darn drop box!

Thanks, Ollie!

Hi,

Can anyone point me in the right direction please? I want to have a drop down box which when a user clicks on a category the results on the page have changed to show only the data which is relative to the category chosen by the user. I also need a way so that when they click view all they are able to see all the results again.

Not really sure what to look for or even how hard this might be.

Lee   

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=306771.0

i have created a seating system.
based on the number of seats booked that value is passed to a page that dynamicly produces a drop down box for each seat booked so the type of seat price can be assigned.

this part works fine.
the problem i have is how do i code the recieving page not knowing how many values are going to be passed?

this is the drop down menu page

Thanks

Code: [Select]
<form action="payment.php?seatco=<?php echo $s_count; ?>" method="post" name="f1">
<div id="tick_select">
<?php
for($i=1; $i<=$s_count; $i++){
$tick= mysql_query("select * from ticket_list"); 
?>
<select name="tick_com<?php echo $i; ?>" id="tick_com" onChange="" title="Choose A Ticket">
<option value="">Select Ticket type</option>
<?php 
while($result= mysql_fetch_assoc($tick))
{ 
?>
<?php echo '<option value="'.$result[ticket_id].'" name="'.$result[price].'">'.$result[type].'</option>';?>
<?php }}?>
</select>
</div>
<INPUT TYPE="submit" VALUE="Select">
</form>

Hey Guys,

I'm building a site and I need a drop down menu created dynamicly....

This is the flat html code
Code: [Select]
<div class="art-nav">
            <div class="l"></div>
            <div class="r"></div>
            <ul class="art-menu">
<li><a href="URL 1"><span class="l"></span><span class="r"></span><span class="t">TOP LEVEL</span></a>
<ul>
<li><a href="URL 1">SUB CAT 1</a></li>
<li><a href="URL 2">SUB CAT 2</a></li>
<li><a href="URL 3">SUB CAT 3</a></li>
</ul>
</li>

<li class="art-menu-li-separator"><span class="art-menu-separator"></span></li>
<li><a href="URL 5"><span class="l"></span><span class="r"></span><span class="t">Contact Us</span></a></li>
            </ul>
            </div>

This is the code that shows a dyamic code, but not in the menu...


<?php wpsc_start_category_query(array('category_group'=> get_option('wpsc_default_category'), 'show_thumbnails'=> get_option('show_category_thumbnails'))); ?>

<a href="<?php wpsc_print_category_url();?>" class="wpsc_category_link"><?php wpsc_print_category_name();?></a> |

<?php wpsc_print_subcategory(); ?>
<?php wpsc_end_category_query(); ?>

Hi guys, I'm still not having any luck with coming up with an idea of how to make my multi-level drop down menu work with items from a database. I don't necessarily need code, but an idea of how to make it work, so any ideas are welcome.

The table:

Column Descriptions:
id       - The unique id
label    - The text to display
link     - The link to be used
relation - I cannot remember why I wanted that... just disregard it
parent   - The parent item's id (0 for no parent)
sort     - A sort number for the item (ascending)
active   - 0 for false, 1 for true (not implemented yet, will add a WHERE `active` = 1 into the sql later)
depth    - How many parent items there are

Now, here's what it has to do (the class):
Grab items from the database (sorted by depth, parent, and sort) Place the children in a child array of the parents (or however it can be sorted) Implode the array and turn it into an html menu with the below structure
Menu HTML Structure
Code: [Select]
<div id="menu">
  <ul>
    <li><h2>Level 1 A</h2>
      <ul>
        <li><a href="?r=level2/a">Level 2 A</a>
          <ul>
            <li><a href="?r=level3/a">Level 3 A</a></li>
            <li><a href="?r=level3/b">Level 3 B</a></li>
          </ul>
        </li>
      </ul>
    </li>
    <li><a href="?r=level1/b"><h2>Level 1 B</h2></a></li>
  </ul>
</div>
And here is the code I have so far, but I can't figure out how to get the children into the parent array, or at least sort it so that I can achieve the above HTML structure.

Thank you in advance for your help, and as I said above, I don't necessarily need code, but an idea of how to make it work, so any ideas are welcome.

I am having a lot of trouble with this code, and I have no clue how to fix it.  Right now, I have a GUI for a fictitious car dealership that has 5 populated drop down menus called Make, Model, Year, Color, and Mileage.  What I want the code to do is read the selections made by the user with the drop down menus once the user hits the submit button and then filter the tables that I have in a mysql database to meets the choice requirements of the user.

The code will bring up the GUI, but once I hit the submit button, I get the following errors

Please if anyone can help me that would be fantastic.  I really have no clue

Hello,, I have looked for numerous examples, and have only got part of the answer.
I have successfully populated a drop down list by reading the database.
It populates with a list of quest titles. Once the user selects the quest.
I want a textbox to populate with the Quest Description.

I found an example that uses AJAX/PHP to do this, but it doesn't access a db to read/populate.
The main code is in index.html
The original example you select a country, and it populates a text field with the currency code.
It passes a variable called $country to another file called find_ccode.php.
I changed the first case in find_ccode.php to access my database, and populate the text box with quest description.
Ideally I will like to make this case dynamic based off QuestID, would populate textbox with corresponding Quest Description (QDescrip).
I then tried the other way in index.php
I dynamically populated the dropdown list, and gave the option values the QuestIDs to be passed to $country, but something isn't working.
I have a write files command to let me know what the $country variable is passing, and it never writes. It works in index.html though.
I apologize in advance for my amateurish coding. I still have a lot to learn. I have included the code below, but if you know a more elegant way of doing it. I am creating a role-playing game, as you probably have figured out by now. I hope to one day put it on the web, but right now using it as a way of learning html, and PHP.

I really want to know how to catch the value of the dropdown box. I would like to know what it is before sending over.
also what is this.value. I assume this is what the value of the dropdown box is when you have selected something.

I have been beating my head for days trying to figure this out. Any help is very much appreciated!

Index.html
<html>
<head>
<title>Changing textbox value based on dropdown list using Ajax and PHP</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<script>
//  Developed by Roshan Bhattarai
//  Visit http://roshanbh.com.np for this script and more.
//  This notice MUST stay intact for legal use

//fuction to return the xml http object
function getXMLHTTP() {
      var xmlhttp=false;   
      try{
         xmlhttp=new XMLHttpRequest();
      }
      catch(e)   {      
         try{         
            xmlhttp= new ActiveXObject("Microsoft.XMLHTTP");
         }
         catch(e){
            try{
            xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
            }
            catch(e1){
               xmlhttp=false;
            }
         }
      }
          
      return xmlhttp;
   }
   
   
   
function getCurrencyCode(strURL)
{      
   var req = getXMLHTTP();      
   if (req)
   {
      //function to be called when state is changed
      req.onreadystatechange = function()
      {
         //when state is completed i.e 4
         if (req.readyState == 4)
         {         
            // only if http status is "OK"
            if (req.status == 200)
            {                  
               document.getElementById('cur_code').value=req.responseText;                  
            }
            else
            {
               alert("There was a problem while using XMLHTTP:\n" + req.statusText);
            }
         }            
       }         
       req.open("GET", strURL, true);
       req.send(null);
   }         
}
</script>




</head>

<body style="font: 12px Verdana, Arial, Helvetica, sans-serif;">

<form style="text-align:center" method="post" action="" name="form1">
<p style="color:#000099 ">When you change the dropdown list, the respective currency code of the country will be displayed in the textbox which is fetched from PHP using Ajax. </p>
<p>Country : <select name="country" onChange="getCurrencyCode('find_ccode.php?country='+this.value)"

<?php

mysql_connect('localhost', '$user', '$password');

mysql_select_db('sok');

$result = mysql_query('select QuestID,QTitle, QDescrip from QuestList');

$options="";

while ($row=mysql_fetch_array($result)) {

    $QuestID=$row["QuestID"];
    $QTitle=$row["QTitle"];
    $options.="<OPTION VALUE=\"$QuestID\">".$QTitle;
}
?>
   <option value="">Select Country</option>
   <option value="1">USA</option>
   <option value="2">UK</option>
   <option value="3">Nepal</option>   
        </select><br/><br/>
 Currency :   <input type="text" name="cur_code" id="cur_code" ></p>
</form>
</body>
</html>

Index.php
<html>
<head>
<title>Changing textbox value based on dropdown list using Ajax and PHP</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<script>
//  Developed by Roshan Bhattarai
//  Visit http://roshanbh.com.np for this script and more.
//  This notice MUST stay intact for legal use

//fuction to return the xml http object
function getXMLHTTP() {
      var xmlhttp=false;   
      try{
         xmlhttp=new XMLHttpRequest();
      }
      catch(e)   {      
         try{         
            xmlhttp= new ActiveXObject("Microsoft.XMLHTTP");
         }
         catch(e){
            try{
            xmlhttp = new ActiveXObject("Msxml2.XMLHTTP");
            }
            catch(e1){
               xmlhttp=false;
            }
         }
      }
          
      return xmlhttp;
   }
   
   
   
function getCurrencyCode(strURL)
{      
   var req = getXMLHTTP();      
   if (req)
   {
      //function to be called when state is changed
      req.onreadystatechange = function()
      {
         //when state is completed i.e 4
         if (req.readyState == 4)
         {         
            // only if http status is "OK"
            if (req.status == 200)
            {                  
               document.getElementById('cur_code').value=req.responseText;                  
            }
            else
            {
               alert("There was a problem while using XMLHTTP:\n" + req.statusText);
            }
         }            
       }         
       req.open("GET", strURL, true);
       req.send(null);
   }         
}
</script>

</head>

<body style="font: 12px Verdana, Arial, Helvetica, sans-serif;">

<form style="text-align:center" method="post" action="" name="form1">
<p style="color:#000099 ">When you change the dropdown list, the respective currency code of the country will be displayed in the textbox which is fetched from PHP using Ajax. </p>
<p>Quest : <select name="country" getCurrencyCode('find_ccode.php?country='+this.value)">'

<?php

mysql_connect('localhost', '$user', '$password');

mysql_select_db('sok');

$result = mysql_query('select QuestID,QTitle, QDescrip from QuestList');

$options="";

while ($row=mysql_fetch_array($result)) {

    $QuestID=$row["QuestID"];
    $QTitle=$row["QTitle"];
    $options.="<OPTION VALUE=\"$QuestID\">".$QTitle;
   
}

$myFile = "test_catchoption.txt";
$fh = fopen($myFile, 'w') or die("can't open file");   
fwrite($fh, $options);
fclose($fh);
?>

Choose your Quest
<?=$options?>
</SELECT>
 <br/><br/>
 Quest Description :   <input type="text" name="cur_code" id="cur_code" ></p>
</form>
</body>
</html>


find_ccode.php
<?php
// Developed by Roshan Bhattarai
// Visit http://roshanbh.com.np for this script and more.
// This notice MUST stay intact for legal use
$country=$_REQUEST['country'];
$myFile = "testFilefindcc.txt";
$fh = fopen($myFile, 'w') or die("can't open file");   
fwrite($fh, $country);
fclose($fh);
switch($country)
{
   case "1" :
   mysql_connect('localhost', '$user', '$password');
    mysql_select_db('sok');

$result = mysql_query("select * from QuestList where QuestID = '1'");
$row = mysql_fetch_assoc($result);
        echo $row['QDescrip'];
      break;
   case "2" :   
      echo "GBP";
      break;
   case "3" :   
      echo "NPR";
      break;
}
?>

Hi there.

Im a noob to sql and php not sure if this is right place to post,

Im trying to get a dynamic drop down menu to show the 1st column in my sql database the column is called cat and holds category info ie audio, internet, music ect. ( i have no idea how to do lol )

it has taken me 2 days to find and edit this  the bold and underline'd bit is what im trying to change with the dropdown menu.

Or thinking bout it is there a way to do it with the URL. IE.. page name.php?cat=audio ?
would that be easer ? is there any security issues with doing it that way ?


Code==================================
$db_host = '*******';
$db_user = '******';
$db_pwd = '*****;

$database = 'nbbcj_co_uk';
$table = 'penapps';

if (!mysql_connect($db_host, $db_user, $db_pwd))
    die("Can't connect to database");

if (!mysql_select_db($database))
    die("Can't select database");

// sending query
$result = mysql_query("SELECT * FROM {$table} WHERE `cat` = 'audio' LIMIT 10 ");
if (!$result) {
    die("Query to show fields from table failed");
}

$fields_num = mysql_num_fields($result);

//echo "<h1>Table: {$table}</h1>";
echo "<table border='1' width='100%'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
    $field = mysql_fetch_field($result);
    //echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
    echo "<tr>";

    // $row is array... foreach( .. ) puts every element
    // of $row to $cell variable
    foreach($row as $cell)
        echo "<td>$cell</td>";

    echo "</tr>\n";
}
mysql_free_result($result);
?>
code end ======================

the test page can been seen here http://www.nbbcj.co.uk/testd/1/test1.php

Any more questions let me know

Thanks for any help you can give, a we all have to start some ware lol

thanks kaine.

Hey all,

This question is coming forth of another topic, but since that topic is not really about this issue, I posted this new topic.

Okay, so I made a table, and each row is generated with a WHILE loop.
In this while loop, there's also a form generated for each row/record, for updating them seperately.

I'm having trouble with naming those forms to process them seperately.
I could name them like name="form20110001", with the number being the record's id.
But since there can be gaps between id's, how can I retreive them efficiently?
And I want them to process all on a single process page, obviously.

How can I do this easily?
Can someone give me a concise example?
Would appreciate it a lot.
Thanks

Hello Friends!.... here is the big idea. I am trying to make a form in which there will be 2 drop down lists which will be populating directly from MySQL DB ....
Actually i am developing a student management system as my first PHP project... here i want to have 2 drop down lists first is roll number and second is student name. i want that when some one select the roll number in the first drop down the student name against it is automatically populated in the next drop down.


please help me friends i am new to php and dont know soo much.! any help PLZZZZZZZZZZ

I am trying to get the output for a mysql query to be displayed in colums. I have it where it does this but it goes from left to right. I would rather it go from top to bottem, it would look better this way. I will also need it to brake into sevral pages when there are a certain amout of entrys shown. If you know of a  good how to on that let me know please.  The other problom that I am having is to make the output a link. I was able to do this before I attemped to devide everything but if I add in what I had before it comes back with no data.

Here's what I have now that put shows the data from left to right in 2 colums.

Code: [Select]
<?php
include"scripts/connect.php" ;

mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM movies WHERE type LIKE 'movie' ORDER BY title";

if(mysql_query($query))
{
$result=mysql_query($query);

$num=mysql_numrows($result);

}


for($i=0; $i<$num; $i++)
{
if($i%2==0){
echo "<tr><td>";
} 
else{
echo "<td>";
}

print mysql_result($result,$i,"title");

if ($i%2==0){
echo "</td>";
}
else{
echo "</td>";
}
}
echo "</tr>";
?>
Thanks in advance