PHP - Passing Variable Value To External Site That Uses A Javascript "onclick" Trigger
I'm trying to send a submission to the following Craigslist form that uses javascript to trigger an auto submit.
The user selects "For Sale" on my form and it will pass the data in a hidden div to the proper selection on the craigslist page. Heres the page it would be passing to. I know I will have to pass it in the URL. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <base href="https://post.craigslist.org"> <title>houston craigslist | choose type</title> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <link type="text/css" rel="stylesheet" media="all" href="/styles/craigslist.css?v=9"> </head> <body id="pp"> <table width="100%" id="header" summary="header"> <tr valign="top"> <td><a href="http://houston.craigslist.org/"><b>houston craigslist</b></a> > choose type<br></td> <td width="10%" class="highlight" style="text-align: right; white-space: nowrap;"> <font size="2" face="sans-serif" color="#7a7a7a">[ logged in as <a href="https://accounts.craigslist.org/login"><b>kennymahaffey@gmail.com</b></a> ] [ <a href="https://accounts.craigslist.org/logout">logout</a> ]</font> <br></td> </tr> </table> <hr> <blockquote> <div class="highlight"> <i>Please post to a single geographic area and category only -- cross-posting to multiple cities or categories is not allowed</i> </div> <h4>What type of posting is this:</h4> <form action="https://post.craigslist.org/k/kInfxI4M4RGIA7PWTF5SWg/HjdlJ" method="POST"> <blockquote> <label> <input type="radio" name="id" value="jo" onclick="form.submit(); return false;">job offered </label> <br> <label> <input type="radio" name="id" value="jw" onclick="form.submit(); return false;">resume / job wanted </label> <br> <br> <label> <input type="radio" name="id" value="ho" onclick="form.submit(); return false;">housing offered </label> <br> <label> <input type="radio" name="id" value="hw" onclick="form.submit(); return false;">housing wanted </label> <br> <br> <label> <input type="radio" name="id" value="fs" onclick="form.submit(); return false;">for sale </label> <i>(please do not post prohibited <sup><a target="_blank" href="http://www.craigslist.org/about/prohibited.items">[?]</a></sup> or recalled <sup><a target="_blank" href="http://www.craigslist.org/about/recalled_items">[?]</a></sup> items)</i> <br> <label> <input type="radio" name="id" value="iw" onclick="form.submit(); return false;">item wanted </label> <br> <br> <label> <input type="radio" name="id" value="go" onclick="form.submit(); return false;">gig offered </label> <i>(I'm hiring for a short-term, small or odd job)</i> <br> <label> <input type="radio" name="id" value="so" onclick="form.submit(); return false;">service offered </label> <br> <br> <label> <input type="radio" name="id" value="p" onclick="form.submit(); return false;">personal / romance </label> <br> <br> <label> <input type="radio" name="id" value="c" onclick="form.submit(); return false;">community </label> <br> <label> <input type="radio" name="id" value="e" onclick="form.submit(); return false;">event </label> <br> <br> </blockquote> <input type="hidden" name="U2FsdGVkX:18yNDg2NDI0O:A8dZroeLa8K5Y677RwK4hzBe2OPdD3XxLUDb5lS9LllELhxNpMqXZIwAWDxJ.7Wo4A" value="U2FsdGVkX18yNDg2NDI0OFjS1qgWn_NKgmgnh5qCZ9aK2m7eOmS-uAAM_Pwu8VHN"> <button type="submit" name="go" value="Continue">Continue</button> </form> </blockquote> Similar TutorialsHow can i make echo "<b>Site:</b> ".$req_user_info['site']."<br>"; linkable The site raw fron the db contains an site url. Regards Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hello! I am executing an external command from a PHP script, using the exec function. Since this program can take more than 1-2 minutes to run, I thought I should use a "Loading page...please wait". What I need is to be able to get the process id from the external program that is being run and, when this finishes, I'll start outputting the results. Is there a way to do this? Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! So I wanted to create stickers on my forum where people type in say ":Blobby-Tired" and then instead of the comment showing ":Blobby-Tired" it shows an html image tag displaying a picture of Blobby in the comment box So I created the following page CommentUpload.php However my sql fails to insert it despite the fact when I "echo $new" it shows the image on the page correctly And it can't be my sql insert code as if I change $new variable for "$BodyText" int he SQL query it it inserts ":Blobby-Tired" OK?
<?php include 'dbconnect.php'; session_start(); if(isset($_POST["submit"]) && !empty($_POST["CommentText"])){ $id = intval($_SESSION['id']); echo $_SESSION['id'] . '<p> </p>' ; $BodyText = $conn -> real_escape_string($_POST['CommentText']) ; $User = $_SESSION['username']; //Replace flairs with <img> tags /*not working currently) */ $new = str_replace(":Blobby-Tired","<img src='flairs/Blobby-Tired.jpg'> </img>","'$BodyText'"); echo "$new"; /************************/ $sql = "INSERT INTO Posts (User, CommentText, IdOfThread) VALUES ('$User','$new','$id')"; if (mysqli_query($conn, $sql)) { echo "New record has been added successfully !"; } else { echo "Error: " . $sql . ":-" . mysqli_error($conn); } mysqli_close($conn); } ?> Edited April 28 by Fishcakes hello how do i pass a foreach loop through "Passing by Reference" say i have a foreach loop in a function like this: Code: [Select] function findText(&$output){ $word = Text::find_all(); foreach ($word as $words){ $output = $words->text; } } then one the page i put Code: [Select] findText($output); echo $output; that will just give me the last word in the database. so how do i get it to echo out the array on the page ? thanks Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 This is what I have $eeee = $_POST['forum_reply']; $eeee = strip_tags($eeee, '<p>'); echo $eeee; this is what prints out Quote Untitled document testinggg this is a print_r of $_Post Quote Array ( [forum_reply] => testinggg [form_reply_submit] => Reply ) Please someone tell me what in binary's name is going on! I get the following error when I try to pass a value to a methiod in a loop: Warning: Attempt to assign property of non-object in /Users/staceyschaller/Sites/dev_zone/ckwv2/classes/class.php on line 670 This one has me very baffled. It will work the first time, and seems to work every other time, so I have no clue what is wrong. Here is the code: This code is part of my "display" class: function display_partner ($type,$loc,$rand=0,$narrow=0) { $this->partners = new partner($this->cxn); $display = ' <div id="cont_info" class="partner-list"> <div> <h3 class="settings">'.ucfirst($loc).' '.ucfirst($type).last_letter($type).'s</h3> </div> <div class="settings-value" style="height:12px;padding:0;margin:0;text-align:right;padding-right:10px;"> <a href="" class="trunc">Add your organization to this list</a></p> </div> <div style="height:2px;padding:0;margin:0;"> <hr class="account" /> </div> '; $ids = $this->partners->get_partners_list($type,$loc,$rand); for ($b=0;$b<sizeof($ids->id);$b++) { $this->partnerID = $ids->id[$b]; $display .= ($narrow)? $this->card_partner_narr():$this->card_partner(); if ($b!=(sizeof($ids->id)-1)) { $display .= '<hr class="account" />'; } } if (sizeof($ids->id)==0) { $display .= '<div style="color:#999999;display:line;text-align:center;height:20px;">No Partners found for '.ucfirst($loc).' '.ucfirst($type).'</div>'; } $display .= ' </div>'; return $display; } function card_partner () { $this->partners->set_partner_id($this->partnerID); $part_info = $this->partners->get_partner_info(); if ($part_info) { $display .= ' <table class="settings"> <tr> '.$this->show_if($part_info['partLogo']['val'],'<td class="settings-value" rowspan="2"><img src="'.LOGO_FOLDER.$part_info['partLogo']['val'].'" '.resize_img(LOGO_FOLDER.$part_info['partLogo']['val'],175).'alt="'.$part_info['partName']['val'].'" /></td>').' <td class="settings-value" colspan="2"><h5>'.$part_info['partName']['val'].'</h5></td> </tr> <tr> <td class="settings-value"> <span style="color:999999;">'.$part_info['partAddress']['val'].'<br /> '.$part_info['partCity']['val'].', '.$part_info['partST']['val'].' '.$part_info['partZIP']['val'].'<br /> '.$part_info['partPhone']['val'].'</span><br /> <a href="'.$this->form->show_href($part_info['partWeb']['val']).'" target="_blank">'.$part_info['partWeb']['val'].'</a> </td> <td class="settings-value">'.$part_info['partInfo']['val'].'</td> </tr> </table> '; } return $display; } This code is part of my "partners" class: function set_partner_id($partID) { echo '<p>partID: '.$partID.' '.gettype($partID).'<br> $this->partner->id: '.$this->partner->id.'</p>'; $this->partner->id = $partID; ///*** ERROR HAPPENS HERE ***/ echo '<p>id set: '.$this->partner->id.'<br> $this->partner->id: '.$this->partner->id.'</p><hr>'; } function get_partner_id() { return $this->partner->id; } // gets user info at login function get_partner_info() { $this->partner = $this->cxn->proc_info('partner','partID',$this->partner->id);//$this->partner->id return $this->partner; } The following is the output generated: partID: 24 string $this->partner->id: id set: 24 $this->partner->id: 24 partID: 26 string $this->partner->id: Warning: Attempt to assign property of non-object in /Users/staceyschaller/Sites/dev_zone/ckwv2/classes/class.php on line 670 id set: $this->partner->id: partID: 17 string $this->partner->id: id set: 17 $this->partner->id: 17 partID: 25 string $this->partner->id: Warning: Attempt to assign property of non-object in /Users/staceyschaller/Sites/dev_zone/ckwv2/classes/class.php on line 670 id set: $this->partner->id: As you can see, the value passes to $this->set_partner_id($partID) each time. It is formatted as a string. When it assigns the value to $this->partner->id, however, sometimes it works, and sometimes it doesn't. It's probably something obvious, but I've racked my brain to see what it is. Any ideas? preg_replace() asks that "Delimiter must not be alphanumeric or backslash" in the pattern. So I changed $new_text = preg_replace($_POST['withthis'] ,$_POST['withthis'],$_POST['text']); to this $replacethis = $_POST['replacethis']; $new_text = preg_replace("/$replacethis/",$_POST['withthis'],$_POST['text']); It works fine, but out of curiosity, is there any way to have the POST variable as a parameter directly, and why does it not work? Just to try it, I attempted: "/$_POST['withthis']/" and $_POST["/'withthis'/"] and both do not work. str_replace is a better option I think, but I am just trying to get a better understanding of this delimiter rule. Thanks for your time! Code: [Select] <?php session_start(); $index="1"; $_SESSION[$index]=2; echo "$_SESSION[$index]"; ?> Hi good day check how to have a variable "$index" inside session.. Hey, I wanted to know if there is any difference between catching a return value and assigning into a variable, and just catching the value when when you just simply call the function on its own. Here is what I mean below In the first example I called the return by simple calling the function. In the second example I catched the return value through a variable, and then echoed it out. Code: [Select] <?php // Example 1 function text (){ $string = "this is a string </br>"; return $string;} echo text(); // Example 2 function text (){ $string = "this is a string </br>"; return $string; } $new_value = text(); echo $new_value; } ?> Hi Guys Ever had the feeling your being a spoon and can't see the wood for the trees? Well, that's how I feel today. All I am trying to to is implement a variable in a "foreach" loop that increments by one through each iteration of the loop. I know how to do it in a "for" loop but can't for the life of me get it to work here. Here is the code: foreach ($cart as $prodcode => $qty) { $item = get_product_details($prodcode); echo '<input type="hidden" name="item_name_'.[b]$needavariablehere[/b].'" value="'.$item['description'].$_SESSION['finish'][$prodcode].$_SESSION['handles'][$prodcode].'" />' . "\n"; } Where I have highlighted $needavariablehere is where I want a number to appear i.e. if there is one item available and the foreach loop iterates once I want the number 1 here. If there are two items and the foreach loop iterates twice I want the output to have number 1 in the first line and number 2 the second time around and so on. How many times the foreach loop iterates is based on the $cart array which contains items in a shopping cart. Thanks for any help you can give guys. Hi. I installed xampp to practice php scripting. Until today, it has worked fine, but now it says: Notice: Undefined variable: text in E:\xampp\htdocs\Experiments\Tutorial\HelloWorld.php on line 6 What can I do to fix this? I'm told that variable don't need to be defined before being initialized, but that doesn't really mean much to me! Please help Hello, I want to buy some traffic on "trafficholder". This site have a large network of sellers and you paid for traffic niche, country, etc... so just to know if they send me the correct amount of traffic I though on give they an URL like this: www.mysite.com/?ref=traffic so all traffic sent there will be counted. whit this method I can I can differentiate that traffic is normal and what is from trafficholder (they send traffic from many many sites so it's difficult to track it whit google-analytics for example) do you know guys how to do it? if you can do a script for me (I think it's simple but my php knowledge is 0) I'll appreciate!!! Thanks in advance For some reason, this include function is putting a "1" on my website, why? <?php $link ='index.php?sent'; if (!isset($_GET['sent'])) echo include('contact.php'); ?> Thanks! |