PHP - Display Current Username First From Array

i get this error Warning: current() [function.current]: Passed variable is not an array or object..

for this
Code: [Select]
$lastblock = current( ${"s".$row} );
print_r($lastblock);
when i change to this it works..
Code: [Select]
$lastblock = current( $s0 );
print_r($lastblock);
The problem is i won't know the $row seeing as it is in a while loop.  Solution?

Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code.

$sql="select * from Profile where username = '$username';
$result = mysql_query( $sql, $conn )
      or die( "ERR: SQL 1" );
if(mysql_num_rows($result)!=0)
{
process form
}
else
{
echo "That username already exist!";
}


the current code of the form


<?PHP
//session_start();
require_once "formvalidator.php";
$show_form=true;

if (!isset($_POST['Submit'])) {



$human_number1 = rand(1, 12);



$human_number2 = rand(1, 38);



$human_answer = $human_number1 + $human_number2;



$_SESSION['check_answer'] = $human_answer;
}

if(isset($_POST['Submit']))
{





if (!isset($_SESSION['check_answer'])) {
echo "<p>Error: Answer session not set</p>";
}


if($_POST['math'] != $_SESSION['check_answer']) {
echo "<p>You did not pass the human check.</p>";
exit();
}


   $validator = new FormValidator();
    $validator->addValidation("FirstName","req","Please fill in FirstName");







$validator->addValidation("LastName","req","Please fill in LastName");
$validator->addValidation("UserName","req","Please fill in UserName");
$validator->addValidation("Password","req","Please fill in a Password");
$validator->addValidation("Password2","req","Please re-enter your password");
$validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!");
$validator->addValidation("email","email","The input for Email should be a valid email value");
$validator->addValidation("email","req","Please fill in Email");
$validator->addValidation("Zip","req","Please fill in your Zip Code");
$validator->addValidation("Security","req","Please fill in your Security Question");
$validator->addValidation("Security2","req","Please fill in your Security Answer");
    if($validator->ValidateForm())
    {
        $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error());
        mysql_select_db("beatthis_beatthis") or die(mysql_error());
$FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file
$LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file
$UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file
$Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file
$Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file
$email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file
$Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file
$Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file
$Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file
$Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file



$sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')"; 
//echo $sql;
if (!mysql_query($sql,$con)) {

 die('Error: ' . mysql_error());

} else{



mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body);

echo "<h3>Your profile information has been submitted successfully.</h3>";
}

mysql_close($con);
        $show_form=false;
    }
    else
    {
        echo "<h3 class='ErrorTitle'>Validation Errors:</h3>";

        $error_hash = $validator->GetErrors();
        foreach($error_hash as $inpname => $inp_err)
        {
            echo "<p class='errors'>$inpname : $inp_err</p>\n";
        }        
    }
}

if(true == $show_form)
{
?>

Hi,

iam pretty new and have made a forum style page for intern project display. ATM i use a standard php loginscript, just so i can add the author of the text.

But as you can imagine thats pretty inconvinient.

Is their a way to get the username from my roaming profil or from the current AD user (dont need to auth, just so i can add my nameunder post, like i login on windows with username "Heinz", and write a post on my side, so he can take the username "Heinz" and display it beneth the post?

iam pretty clueless where to start looking, would you be so nice and provide me some topic/hints to give me a push in the right direction.

 

Sry if my english is..... a bit rubbish.

i greatfull for all your time

sincerly

Nasten

Hello my problem here is to have a drop down menu which gathers usernames from the database. Then with a click of a button the information for that specific user selected is shown. I'm close code wise but right now it's just showing me all users. I'm displaying the info in text box's to allow an admin to change the info. 

<form action="edit.php" method="post">

	 <select name="username" id="username">
	 	  <?php 
	  
 // Connects to your Database 
  $con=mysqli_connect('localhost', 'root', '');

/* check connection */

if (mysqli_connect_errno($con)) {
    trigger_error('Database connection failed: '  . mysqli_connect_error(), E_USER_ERROR);
}

$query = "SELECT `username` FROM `bencobricks` . `users`";

$result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR);

if($result) {
	while($row = mysqli_fetch_assoc($result)) {
		//printf ("%s\n %s\n ",
		echo	"<label for='username'>Username: </label> <option value='$row[username]'>$row[username] </option><br/>";
			
		echo "<br/><br/> ";
		
	}
} 

mysqli_close($con);

?>
	 </select>
<br />
  <input name="send" id="send" type="submit" value="Edit User" />
</form>

Then in the edit.php file i have this code: 

<?php 

// Connects to your Database
$con=mysqli_connect('localhost', 'root', '');

/* check connection */

if (mysqli_connect_errno($con)) {
	trigger_error('Database connection failed: '  . mysqli_connect_error(), E_USER_ERROR);
}

if (isset($_POST['send'])) {
 $username = $_POST['username'];
 
 $query = "SELECT * FROM `bencobricks` . `users` ";
 $result = mysqli_query($con, $query) or trigger_error("Query Failed! SQL: $query - Error: ". mysqli_error($con), E_USER_ERROR); 
// Print the result

 if($result) {
while ($row = mysqli_fetch_assoc($result)) {
//	$query = "SELECT * FROM `bencobricks` . `users` WHERE `username` = username = $row[username]";
 printf ("%s\n %s\n %s\n %s\n %s\n %s\n %s\n %s\n %s\n %s\n %s\n",
			"<label for='username'>Username: </label> <input type='text' name='username' value='$row[username]'>" . "</input><br/>",
			"<label for='email'>Email: </label> <input type='text' name='email' value='$row[email]'>" . "</input><br/>",
			"<label for='membership'>Membership: </label> <input type='text' name='membership' value='$row[membership]'>" . "</input><br/>",
			"<label for='firstName'>First name: </label> <input type='text' name='firstName' value='$row[firstName]'>" . "</input><br/>",
			"<label for='lastName'>Last name: </label> <input type='text' name='lastName' value='$row[lastName]'>" . "</input><br/>",
			"<label for='gender'>Gender: </label> <input type='text' name='gender' value='$row[gender]'>" . "</input><br/>",
			"<label for='dateOfBirth'>Birthdate: </label> <input type='text' name='dateOfBirth' value='$row[dateOfBirth]'>" . "</input><br/>",
			"<label for='date'>Date: </label> <input type='text' name='date' value='$row[date]'>" . "</input><br/>",
			"<label for='sets'>Sets: </label> <input type='text' name='sets' value='$row[sets]'>" . "</input><br/>",
			"<label for='checkbox'>Checkbox: </label> <input type='text' name='checkbox' value='$row[checkbox]'>" . "</input><br/>",
			"<label for='admin'>Admin? </label> <input type='text' name='admin' value='$row[adminFlag]'>" . "</input><BR>",
			
		"<br/><br/> ");
}
}
} 
mysqli_close($con);
?>

Any help is greatly appreciated. 

hi,

i have a password array system and i want to be able to make a php to add a username, password and a homepage, the same as the username just at the end of a URL:

The array file code looks like this:
Code: [Select]
<?php

//My Login Page
//u

//u
//u


//Users and Settings
$domain_code = 'blogger123';   //Alpha Numeric and no space
$random_num_1 = 213;      //Pick a random number between 1 to 500
$random_num_2 = 754;      //Pick a random number between 500 to 1000
$random_num_3 = 2;         //Pick a random number between 1 to 3

//Usernames can contain alphabets, numbers, hyphens and underscore only
//Set users below - Just add '' => '' with the first '' being
//the username and the second '' after the => being the password.
//Its an array so add an , after every password except for the
//last one in the list. As shown below
//Eg. $users = array(
//      'user1' => 'password',
//      'user2' => 'password'
//   );

$users = array(
      array('user1', 'test', '/users/1/'),
      array('user2', 'test', '/users/2/')
                array('user2', 'test', 'tusers/2/')
array('user2', 'test', '/users/4/')
array('user2', 'test', '/users/5/')
array('user2', 'test', '/users/6/')
array('user2', 'test', '/users/7/')
array('user2', 'test', '/users/8/')
array('user2', 'test', '/users/9/')
array('user2', 'test', '/users/10/')
array('user2', 'test', '/users/11/')
array('user2', 'test', '/users/12/')
array('user2', 'test', '/users/13/')
array('user2', 'test', '/users/14/')

   );


?>
thanks in advance