PHP - How To Get Content From First Row Of Db Table
Hi, I am building function to convert the db table to an XML file. But I want to retrieve the root node value from the FIRST row in that db table before I build a for loop to traverse that db table.
Let's say I have this table NodeInfo: node_Id source target ====== ===== ===== 1 email to 2 to toFirstName pseudocode for what I want: 1) store root (the source field of table NodeInfo 2)for each entry in table NodeInfo, do: build XML END FOR-EACH Any help much appreciated! Similar TutorialsHi all, 1) I realised after applying php's codes, the contents in 'panel 2' doesn't stay within 'panel 2', apparently the contents went outside of 'panel 2 <div>'. Attached is the picture example. Is there anything amiss which I have done? 2) Another thing, I realised the <td> is very far apart from the next <td>, example... Code: [Select] if (!empty($row1['uni2'])) { echo '<tr><td class="label">Faculty or Course:</td><td>' . $row1['uni2'] . '</td></tr>'; } <td class="label">Faculty or Course:</td> is apparently very far apart from <td>' . $row1['uni2'] . '</td> As you can see it in the attachment. How do i close up the wide gap? Thanks Code: [Select] echo '<div id="panel2">'; /***University***/ echo '<table>'; if (!empty($row1['uni1'])) { echo '<br/><tr><td class="row_header">' . $row1['uni1'] . '</td></tr>'; if (!empty($row1['uni2'])) { echo '<tr><td class="label">Faculty or Course:</td><td>' . $row1['uni2'] . '</td></tr>'; } if (!empty($row1['uni3'])) { echo '<tr><td class="label">Results:</td><td>' . $row1['uni3'] . '</td></tr>'; } } echo '</table>'; echo '</div>'; //End of Panel 2 Name says it all. I have a form and 2 tables that are going to have to be linked with each other. Although what I'm trying to do now is very basic and I'm struggling haha Though this is my first php project Basicly I got a form with a drop down menu, which I want to display the contents of my table (course) which the user then selects from and submits to another table (student) Here is my code for this part <?php Code: [Select] <?php $q = "SELECT cname FROM course "; $result = mysql_query($q); $course = mysql_fetch_array($result); ?> <div id="apdiv3"> <FORM action = "demo.php" method ="post"> <p>Course name:</p> <select name="cname"> <OPTION> <?php echo $course['cname']; ?> </option> </SELECT>?> It only displays 1 item from my course table. What am I doing wrong? And also please explain so I can learn from my mistakes I am wanting HTML to render within a table and sourcing the data from another file. In an attempt to do this, I tried: Code: [Select] <TABLE class="main"> <TR> <TD> <?php readfile('./1/index.html'); ?> </TD> </TR> </TABLE> This does not work and I am wondering if anyone knows how it can be done - or even if it can be done? Hi. Maybe a tricky question? How do I reflect the content of a column from a database table in a roll down select menu in the browser? Let's say that the content of the table column is: Anna Michael These names should be reflected in this select menu like this: <select name="friends"> <option value="Choose a name">Choose a name</option> <option value="Anna">Anna</option> <option value="Michael">Michael</option> So visitors can choose a name, and thereby turn it into a variable, for reuse in the database. Best regards Morris Hi, I will start off trying to explain what I am trying to make the best I can. What I want to create is a script that gets the gold value from this website: http://www.lbma.org.uk/pages/index.cfm?page_id=46&title=current_statistics and then save it to a variable which I will use to calculate values of different gold karats. Here is the content in bold I need on the website I linked: Quote LONDON GOLD FIXING USD GBP EUR AM 1588.00 1005.127 1251.083 PM 1589.50 1004.741 1249.803 So what help do I need? Well, I don't expect you to figure out the calculating part for me but some help how to get that content pointed out above and save it to a variable is what I would appreciate getting some help with. I don't know much PHP, only some and I have been trying to figure this out for a day now without any success. I suppose php get contents and/or curl should be used here but I don't know how really. I would very much appreciate the help I can get on this. Thank you! This is the Code i am using. This is show error: Fatal error: Call to a member function item() on a non-object in /home/domain/public_html/forum/file/Test.php on line 35 Code: [Select] <?php $xml=("http://www.vn-zoom.com/external.php?type=RSS2&forumids=77"); $xmlDoc = new DOMDocument(); $xmlDoc->load($xml); //get elements from "<channel>" $channel=$xmlDoc->getElementsByTagName('channel')->item(0); $channel_title = $channel->getElementsByTagName('title') ->item(0)->childNodes->item(0)->nodeValue; $channel_link = $channel->getElementsByTagName('link') ->item(0)->childNodes->item(0)->nodeValue; $channel_desc = $channel->getElementsByTagName('description') ->item(0)->childNodes->item(0)->nodeValue; //output elements from "<channel>" echo("<p><a href='" . $channel_link . "'>" . $channel_title . "</a>"); echo("<br />"); echo($channel_desc . "</p>"); //get and output "<item>" elements $x=$xmlDoc->getElementsByTagName('item'); $i=1; // $i = 1 to n (I use For here). { $item_title=$x->item($i)->getElementsByTagName('title') ->item(0)->childNodes->item(0)->nodeValue; $item_link=$x->item($i)->getElementsByTagName('link') ->item(0)->childNodes->item(0)->nodeValue; $item_desc=$x->item($i)->getElementsByTagName('description') ->item(0)->childNodes->item(0)->nodeValue; // If i remove this, it will work....//////////// $item_content=$x->item($i)->getElementsByTagName('content') ->item(0)->childNodes->item(0)->nodeValue; ///////////////////////////////////////////////////// echo ("<p><a href='" . $item_link . "'>" . $item_title . "</a>"); echo ("<br />"); echo ($item_desc . "</p>"); echo ("<br />"); echo ($item_content . "</p>"); } ?> Please help me Fix this Code to Get content of Tag Name <content:encoded> Thanks Hi All,
I want to copy into a table values from another table that partially match a given value, case-insensitively. So far I do as follows but I wonder whether there is a quicker way.
$input_table=array('1'=>'toto','2'=>'tota','3'=>'hello','4'=>'TOTO','5'=>'toto'); $input_table_2 = array_map('strtolower', $input_table); $value_to_look_for='Tot'; $value_to_look_for_2=strtolower($value_to_look_for); $output_table=array(); foreach ($input_table_2 as $k=>$v) { if(false !== strpos($v, $value_to_look_for_2)) { $output_table[]=$input_table[$k]; } }One drawback is that $input_table_2 is 'foreached' whereas there might be no occurrences, which would lead to a loss of time/resources for big arrays. Thanks. Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero hi... i have a table ... i add and remove data in the table...when i add new record , information add to center of the table ! whats problem? i want add data in first of table. please guide me.thanks
Hi All ,
I have a small table with 4 fields namely Day_ID, Dues, Last_Visit, Points. where Day_ID is an auto-increment field. The table would be as follows:
Day_ID -- Dues --- Last_Visit --- Points.
1 --------- 900 -------- 1/12 -------- 6
2 --------- 700 -------- 4/12 -------- 7
3 --------- 600 -------- 7/12 -------- 5
4 --------- 600 -------- 9/12 -------- 6
5 --------- 600 -------- 10/12 ------- 6
6 --------- 600 -------- 14/12 ------- 6
So this is the record of a person's visit to say a club. The last row indicates the last date of his visit to the club. His points on this date are 6. Based on this point value of 6 in the last row I want to retrieve all the previous BUT adjoining all records that have the same Points i.e. 6.
So my query should retrieve for me, based on the column value of Points of the last row (i.e. Day_ID - 6 ), as follows:
4 --------- 600 -------- 9/12 -------- 6
5 --------- 600 -------- 10/12 ------- 6
6 --------- 600 -------- 14/12 ------- 6
This problem stated above had been completely resolved, thanks to a lot of help from Guru Barand by this following query :-
$query = "SELECT cv.day_id, cv.dues, cv.last_visit, cv.points FROM clubvisit cv WHERE last_visit >= ( SELECT MAX(last_visit) FROM clubvisit WHERE points <> ( SELECT points as lastpoints FROM clubvisit JOIN ( SELECT MAX(last_visit) as last_visit FROM clubvisit ) as latest USING (last_visit) ) )";I am using this and it works perfectly except that now there is a slight change in the table because the criteria for points is now dependent on more than one column cv.points and is more like cv.points1, cv.points2, cv.points3 etc. So now I need to make a selection based on each of these cv.points columns. As of now I can still get the results by running the query multiple times for each of the cv.points columns ( seperately for cv.points1, cv.points2, cv.points3) and it works correctly. However I am wondering if there is a better way to do this in just one go. This not only makes the code repetitive but also since the queries are interconnected, involves the use of transactions which I wish to avoid if possible. The values that I require for each of the cv.point columns is 1. day_id of the previous / old day on which the cv.points value changed from the current day value, and 2. cv.points on that old/ previous day. So for example if the table is as below: Day_ID -- Dues --- Last_Visit --- Points1 --- Points2. 1 --------- 900 -------- 1/12 ----------- 9 ------------ 5 2 --------- 600 -------- 4/12 ----------- 6 ------------ 6 3 --------- 400 -------- 7/12 ----------- 4 ------------ 7 4 --------- 500 -------- 9/12 ----------- 5 ------------ 8 5 --------- 600 -------- 10/12 ---------- 6 ------------ 8 6 --------- 600 -------- 11/12 ---------- 6 ------------ 8 7 --------- 600 -------- 13/12 ---------- 6 ------------ 7 8 --------- 500 -------- 15/12 ---------- 5 ------------ 7 9 --------- 500 -------- 19/12 ---------- 5 ------------ 7 Then I need the following set of values : 1. day_id1 -- Day 7, points1 ---- 6, days_diff1 -- (9-7 = 2) . // Difference between the latest day and day_id1 2. day_id2 -- Day 6, points2 ---- 8, days_diff2 -- (9-6 = 3) 3. day_id3 -- .... and so on for other points. Thanks all ! Hi
I am very new to PHP & Mysql.
I am trying to insert values into two tables at the same time. One table will insert a single row and the other table will insert multiple records based on user insertion.
Everything is working well, but in my second table, 1st Table ID simply insert one time and rest of the values are inserting from 2nd table itself.
Now I want to insert the first table's ID Field value (auto-incrementing) to a specific column in the second table (only all last inserted rows).
Ripon.
Below is my Code:
<?php $con = mysql_connect("localhost","root","aaa"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("ccc", $con); $PI_No = $_POST['PI_No']; $PO_No = $_POST['PO_No']; $qry = "INSERT INTO wm_order_entry ( Order_No, PI_No, PO_No) VALUES( NULL, '$PI_No', '$PO_No')"; $result = @mysql_query($qry); $val1=$_POST['Size']; $val2=$_POST['Style']; $val3=$_POST['Colour']; $val4=$_POST['Season_Code']; $val5=$_POST['Dept']; $val6=$_POST['Sub_Item']; $val7=$_POST['Item_Desc']; $val8=$_POST['UPC']; $val9=$_POST['Qty']; $N = count($val1); for($i=0; $i < $N; $i++) { $profile_query = "INSERT INTO order_entry(Size, Style, Colour, Season_Code, Dept, Sub_Item, Item_Desc, UPC, Qty, Order_No ) VALUES( '$val1[$i]','$val2[$i]','$val3[$i]','$val4[$i]','$val5[$i]','$val6[$i]','$val7[$i]','$val8[$i]','$val9[$i]',LAST_INSERT_ID())"; $t_query=mysql_query($profile_query); } header("location: WMView.php"); mysql_close($con); ?>Output is attached. Hello everyone. I need help with the following PHP APP. I am running on (Version PHP 7.2.10) I am trying to have a page table form on table.php pass the input variable of “5-Numbers” to another page called table_results.php I want that variable string of “5-Numbers” to be compared against 4 arrays and output any duplicates found within each of those 4 lists. If nothing is found, I still want some visual output that reads “None found”.
Lets pretend I have the following example .. On table.php, I typed inside my table form the 5-Numbers .. INPUT: 2,15,37,13,28 On table_results.php, the 4 arrays to be compared against my input numbers “ 2,15,37,13,28” are ..
$array_A = array(2,6,8,11,14,18,24); $array_B = array(1,2,9,10,13,14,25,28,); $array_C = array(1,3,7,9,13,15,20,21,24); $array_D = array(4,5,12,22,23,27,28,29);
So my output should read as follows below .. OUTPUT:
TABLE COLUMN 1 COLUMN 2 ROW 1 Matches Found Results .. ROW 2 GROUP A: 2 ROW 3 GROUP B: 2,13,28 ROW 4 GROUP ? 13,15 ROW 5 GROUP ? 28 ROW 6 5#s Input: 2,15,37,13,28
Please let me know if anyone has any suggestions on how to go about it. Thanks. Edited January 1, 2019 by Jayfromsandiego Wanted to include image example I know I'm doing it something right, but can someone tell me why only one table is showing up? Can you help me fix the issue? Heres my code: function showcoords() { echo"J3st3r's CoordVision"; $result=dbquery("SELECT alliance, region, coordx, coordy FROM ".DB_COORDFUSION.""); dbarray($result); $fields_num = mysql_num_fields($result); echo "<table border='1'>"; // printing table headers echo "<td>Alliance</td>"; echo "<td>Region</td>"; echo "<td>Coord</td>"; // printing table rows while($row = mysql_fetch_array($result)) { // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row AS $Cell) echo "<tr>"; echo "<td>".$row['alliance']."</td>\n"; echo "<td>".$row['region']."</td>\n"; echo "<td>".$row['coordx'].",".$row['coordy']."</td>\n"; echo "</tr>\n"; } echo "</table>"; mysql_free_result($result); } I have 2 rows inserted into my coords table. Just frustrated and ignorant to php. This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=317025.0 Not sure how to do this at all... I'm creating a page with a form to edit existing info in two tables in the database. I need to pre-check some checkboxes and I don't know how. The first query query_selectguest below puts data into the form just fine. query_checked looks in the second table for any rows that match the discount id. Then further down in the form, I have a php snippet that pulls all the classes from a third database. As I'm echoing these out to the page, I want them to be pre-checked if they match a result found in $result_checked here's what I have right now... Code: [Select] $query_selectguest = 'SELECT * FROM tbl_discount WHERE discount_id='.$passedID; $result_guest = mysql_query($query_selectguest); $g_row = mysql_fetch_array($result_guest); $query_checked = 'SELECT * FROM active_discounts WHERE disc_id='.$passedID; $result_checked = mysql_query($query_checked); $h_row = mysql_fetch_array($result_checked); ?> <form name="form1" method="post" action="update_discount.php" onSubmit="return validate_form()"> <input name="discount_name" type="text" class="input" id="subject" size="50" maxlength="100" value="<? print $g_row['discount_name'] ?>"> <input name="discount_amount" type="text" class="input" id="subject" size="5" maxlength="3" value="<? print $g_row['discount_amount'] ?>"> <!-- here's what I'm concerned with --> This discount applies to these classes:<br> <?php $quer4=mysql_query("SELECT workshop_id, workshop_title FROM tbl_workshops order by workshop_title"); while($row4 = mysql_fetch_array($quer4)) { echo "<input type='checkbox' name='workshop_link_1[]' value='".$row4[workshop_id]."'>".$row4[workshop_title]."<BR>"; } ?> hello friends I'm dealing with this problem for two days. I put here the screenshot for easier understanding.Sorry about my bad english. Here is the ss http://i61.tinypic.com/2rz5q55.jpg I don't want to inner join or table join. All image links which same sku should displayed in single row where products.resimler colon I can join the tables but i want to one table.Because i can import single csv file for e-commerce script.How can I use a update query for list multiple images in table products. Edited by nogai, 10 October 2014 - 07:01 AM. How would you retrieve information from one table and enter that informatio to another and the same time get other details from form. Do you retrieve the data and use a form to post this and insert that to another table. Have I confused you??? I am new to php.i want to be able to link echoed out rows from a table to another row in another table so that when users clicked the first row i echoed out it will take them to that SPECIFIC row i linked it to in the second table..JUST LIKE FACEBOOK...Please do i make sense or is there another way to do it. Thanks in advance Simple question but I couldn't find any straight forward answers.
I have a customer details table with: customer ID, name, address, email.
I also have an delivery table with delivery ID, customer ID, order ID.
How can I link the customer ID column from the customer table to the delivery table so that when changes occur on the customer table they subsequently alter all other tables?
I know it might use foreign keys but I couldn't find any online resource that explained how to use them properly.
Cheers
Hi I have two tables Employer and Job. Emp_ID as PK of Employer and Job_id as PK of Job. I want to put Emp_ID as Foreign key for jobs. and when the employer logs in his empid is being stored as a session and when he creates a job his empid will be entered in the job table. |