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PHP - Dynamic Php Page - Option Selected
Hi,
I wanted to make a dynamic php page. I want the user to choose an option you could select in an option box (html) and after that I wish that down the page some text would change. If I take option 1 -> text 1, option 2 -> text 2, ... But this doesn't work, do I need a button or something to made my code running, and how do I have to use it on the same page? Or is it possible to run it automaticly after a new choice? Thanx, Kevin My code: <?php /* Template Name: template voor Ieder1Trainer # */ get_header(); $Tacktiek = ""; $Tacktiek1 = "3-5-2"; $Tacktiek2 = "3-4-3"; $Tacktiek3 = "4-5-1"; $Tacktiek4 = "4-4-2"; $Tacktiek5 = "4-3-3"; $Tacktiek6 = "5-4-1"; $Tacktiek7 = "5-3-2"; $aantalDef; $aantalMid; $aantalAtt; ?> <div id="newsfeed"> <div class="banderol"> <div class="banderol_left"></div> <h1>Dynamic page</h1> </div> <?php if(is_user_logged_in()) { get_currentuserinfo(); //echo 'Username: ' . $current_user->user_login . "\n"; //echo 'User email: ' . $current_user->user_email . "\n"; ?> <!-- Here you choose a tactiek; 1,2,3, .. after that has been choosen I whise the next php-code would be run (the if-then-elseif-...) --> <tr> <td><p class="formulier">Kies je Tacktiek:</p></td> <td> <select size="1" name="$Tacktiek"> <option selected><?php echo $Tacktiek1;?></option> <option><?php echo $Tacktiek2;?></option> <option><?php echo $Tacktiek3;?></option> <option><?php echo $Tacktiek4;?></option> <option><?php echo $Tacktiek5;?></option> <option><?php echo $Tacktiek6;?></option> <option><?php echo $Tacktiek7;?></option> </select> </td> </tr> <!-- This must be run after choosen a tactiek. --> <?php if($Tacktiek == '3-5-2') { $aantalDef = 3; $aantalMid = 5; $aantalAtt = 2; } elseif($Tacktiek == '3-4-3') { $aantalDef = 3; $aantalMid = 4; $aantalAtt = 3; } elseif($Tacktiek == '4-5-1') { $aantalDef = 4; $aantalMid = 5; $aantalAtt = 1; } elseif($Tacktiek == '4-4-2') { $aantalDef = 4; $aantalMid = 4; $aantalAtt = 2; } elseif($Tacktiek == '4-3-3') { $aantalDef = 4; $aantalMid = 3; $aantalAtt = 3; } elseif($Tacktiek == '5-4-1') { $aantalDef = 5; $aantalMid = 4; $aantalAtt = 1; } elseif($Tacktiek == '5-3-2') { $aantalDef = 5; $aantalMid = 3; $aantalAtt = 2; } ?> <!-- After this run, the next code must be run and made a choose of text --> <tr> <td><p class="formulier"> <?php if($aantalDef == '3') { echo "3 defs"; //Choosen text if aantalDef == 3 } elseif($aantalDef == '4') { echo "4 defs"; //Choosen text if aantalDef == 4 } elseif($aantalDef == '5') { echo "5 defs"; //Choosen text if aantalDef == 5 } ?> </p></td> <!-- Other choose of options, but always the same options. --> <td> <select size="1" name="$Speler4"> <option selected><?php echo $NaamDef1;?></option> <option><?php echo $NaamDef2;?></option> <option><?php echo $NaamDefMid1;?></option> <option><?php echo $NaamDefMid2;?></option> <option><?php echo $NaamDefMid3;?></option> <option><?php echo $NaamDefMid4;?></option> <option><?php echo $NaamDefMid5;?></option> <option><?php echo $NaamDefMid6;?></option> <option><?php echo $NaamDefMid7;?></option> <option><?php echo $NaamDefMid8;?></option> <option><?php echo $NaamDefMidAtt1;?></option> <option><?php echo $NaamDefMidAtt2;?></option> <option><?php echo $NaamDefMidAtt3;?></option> </select> </td> </tr> <?php } else{ echo 'U dient in te loggen.'; } ?> </div> <?php get_footer(); ?> Similar TutorialsI'm trying to create a dynamic option menu with one alert selected based on the first query to the db. Any help would be greatly appreciated. Code: [Select] //function to get alerts and create select menu with current alerts pre-selected function getALERTS1($id){ require('db.php'); $alert = mysqli_query($conn, "SELECT alert1 FROM visit_data WEHERE patientid = $id AND discharged IS NULL"); $row = mysqli_fetch_array($alert); $selects=null; $query = mysqli_query($conn, "SELECT alertid, name FROM alerts"); while($row1 = mysqli_fetch_array($query)) { $selects .= "<option value=\"" . $row1['alertid'] . "\"> if($row1['alertid']==$row['alert1']) { echo ' selected'; } ".$row1['name']."</option>"; } return $selects; } I have the following which fils a combo box with years from 1950 to 2100. This is the year box for the date of birth. Year <select name="year_select"> <?php for( $i=1950; $i<=2100; $i++ ) { echo "<option value=\"{$i}\" class=\"year\">{$i}</option>"; } ?> </select> I want it to automatically display the year that is in the database so instead of automatically displaying 1950 i want their birth year displayed which is $tab_info->user_dob_year. How would i go about this? i dont know where to start since im using a for loop to populate it. Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete If I have a variable and a hard coded select dropdown, what is the easiest way to compare the variable with the value and set that particular option's selected attributed to selected? I'm just attempting to learn how PHP handles things and I can't quite wrap my head around how to apply Selected to the final Option and show the Traits for the Character based on the Selected Option. I understand this might need POST, if it does, I would appreciate a bit of help on how I would set this up as POST since I didn't think a drop down required a submit button. Code: [Select] $character= array (array(Name=>"Barry","Class"=>"Fighter",Level=>1,Str=>10,Dex=>10,"Int"=>10),array(Name=>"Lindehar","Class"=>"Ranger",Level=>1,Str=>10,Dex=>10,"Int"=>10),array(Name=>"Verelden","Class"=>"Mage",Level=>1,Str=>10,Dex=>10,"Int"=>10)); print "Select a Character:<br /><select>"; foreach($character as $array_num) { foreach($array_num as $char_trait=>$trait_value) { if($char_trait==Name) { $selected_value=""; $generated_chars="<option selected=".$selected_value." value='".$char_trait."'>".$char_trait.": ".$trait_value."</option>"; print $generated_chars; if($selected_value=/".$char_trait.": Barry"/") { foreach($char_trait=="Barry") { print "<h4>".$char_trait.": ".$trait_value."</h4>"; } } } } } print "</select><p />"; mysql.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("ckeditor",$con); ?> --------------------------------------------------------- add.php <?php include("mysql.php"); if(isset($_POST["button2"])) { $sql="INSERT INTO cktext (section) VALUES ('$_POST[select2]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } ?> ----------------------------------------------------------------- home.php <form id="form1" name="form1" method="post" action="add.php"> <tr> <td>Section:</td> <td><select name="select2" id="select2"> <option selected="selected" value="MALE">Male</option> <option selected="" value="FEMAIL">FEMAIL</option> </select></td> </tr> <input type="submit" name="button2" id="button2" value="Upload" /> </form> In DATABASE :- cktext table attribute "section" is varchar type. BUT IT RETURN ME BLANK OUTPUT.
<?php Not sure exactly where this problem is coming from, but php seems the most likely candidate to fix it. My php loads, from a MySQL database, a list of names (students in a class) and a drop-down for each student with attendance options. Based on the information in the database, the appropriate attendance option is selected (<option selected></option>). Everything works fine on the initial page load. Next, I want to update the status, so I select a new option from the drop-down list and click submit. The php code updates the database correctly, but the selected option (in HTML) is still the original one. If I change the option to something different and submit again, I get the previously selected option (that I selected the first time) - in essence, the HTML is always one step behind the database. I've attached the snippet of relevant code - again, I know that the code works when the page loads initially and that the database is getting updated correctly. Any help or comments are appreciated. I have a form that contains 3 text fields and 7 populated lists (that are dependent on the choice of the previous lists). When I post the information to MySQL and to my processing page, it posts the table "ids" instead of the selected option. Here's the php code for the form: <form action="gccsuccess_form.php" method="post" enctype="multipart/form-data" name="gcc" id="gcc"> <table width="700" border="0" align="center" cellpadding="3" cellspacing="3"> <tr> <td><label for="date">Today's Date:</label> <input type="text" name="date" id="date"></td> <td> </td> </tr> <tr> <td>Week Number: <select name="week" size="1" id="week"> <option value="0" selected>Week 0 - 3/26 - 4/1</option> <option value="1">Week 1 - 4/2 - 4/8</option> <option value="2">Week 2 - 4/9 - 4/15</option> <option value="3">Week 3 - 4/16 - 4/22</option> <option value="4">Week 4 - 4/23 - 4/29</option> <option value="5">Week 5 - 4/30 - 5/6</option> <option value="6">Week 6 - 5/7 - 5/13</option> </select></td> <td><label for="location"></label> </td> </tr> <tr> <td>Location: <select id='locations' name='location'> </select></td> <td> </td> </tr> <tr> <td><label for="label8">Team Name</label> <select id='team_names' name='team_name'> </select></td> <td> </td> </tr> <tr> <td><em>*Please enter each team member's first and last name:</em></td> <td> </td> </tr> <tr> <td><label for="mem_1"> Team <strong>Captain:</strong></label> <select id='team_members 1' name='capt'> </select></td> <td><label for="label4"><strong>Steps:</strong></label> <input type="text" name="steps_1" id="steps_1"></td> </tr> <tr> <td><label for="mem_2">Team Member #2 <strong>Name: <select id='team_members 2' name='mem_2'> </select> </strong></label></td> <td><label for="label5"><strong>Steps:</strong></label> <input type="text" name="steps_2" id="steps_2"></td> </tr> <tr> <td><label for="mem_3">Team Member #3 <strong>Name: <select id='team_members 3' name='mem_3'> </select> </strong></label></td> <td><label for="label6"><strong>Steps:</strong></label> <input type="text" name="steps_3" id="steps_3"></td> </tr> <tr> <td><label for="mem_4">Team Member #4<strong> Name</strong>: <select id='team_members 4' name='mem_4'> </select> </label></td> <td><label for="label7"><strong>Steps:</strong></label> <input type="text" name="steps_4" id="steps_4"></td> </tr> <tr> <td><label for="label">Team Member #5<strong> Name</strong>: <select id='team_members 5' name='mem_5'> </select> </label></td> <td><label for="label7"><strong>Steps:</strong></label> <input type="text" name="steps_5" id="steps_5"></td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td> </td> <td><em>* Maximum steps for each team member per week is <strong>105,000. </strong></em></td> </tr> <tr> <td> </td> <td><input type="submit" name="Submit Form" id="Submit Form" value="Submit"></td> </tr> </table> <label></label> <div align="center"><br> If you have questions about the competition or reporting please contact KC WELLNESS, INC toll free at <SPAN id="lw_1237248942_0">877-634-1412.</SPAN><br> <br> </div> </form> And here's the code for the page it is posted in: <?php $date = $_POST['date']; $week = $_POST['week']; $location = $_POST['location']; $team_name = $_POST['team_name']; $capt = $_POST['capt']; $mem_2 = $_POST['mem_2']; $mem_3 = $_POST['mem_3']; $mem_4 = $_POST['mem_4']; $mem_5 = $_POST['mem_5']; $steps_1= $_POST['steps_1']; $steps_2= $_POST['steps_2']; $steps_3= $_POST['steps_3']; $steps_4 = $_POST['steps_4']; $steps_5 = $_POST['steps_5']; mysql_connect("mysql1.myregisteredsite.com", "49200_kandace", "Leonardo56") or die(mysql_error()); mysql_select_db("49200_GCC") or die(mysql_error()); mysql_query("INSERT INTO `walkathon` VALUES ('$date', '$week', '$location', '$team_name', '$capt','$mem_2','$mem_3', '$mem_4', '$mem_5', '$steps_1','$steps_2', '$steps_3','$steps_4', '$steps_5' )"); Print "Thank you for your entry. <br> Report summary: <br/><br/>"; echo "<strong> Date: </strong> {$date} <br/> <br/><strong> Week: </strong> {$week} <br/> <br/><strong> Location: </strong> {$location} <br/> <br/><strong> Team Name: </strong> {$team_name} <br/> <br/><strong> Team Captain: </strong> {$capt} / <strong> Steps: </strong> {$steps_1} <br /> <br/><strong> Team Member 2 Name: </strong> {$mem_2} / <strong> Steps: </strong> {$steps_2} <br /> <br/><strong> Team Member 3 Name: </strong> {$mem_3} / <strong> Steps: </strong> {$steps_3} <br /> <br/><strong> Team Member 4 Name: </strong> {$mem_4} / <strong> Steps: </strong> {$steps_4} <br /> <br/><strong> Team Member 5 Name: </strong> {$mem_5} / <strong> Steps: </strong> {$steps_5}" ?> How do I get the processing page to echo the selected option instead of the id? Hi, I have an html form in "send.htm" that sends data to "retrieve.php" with the following structu send.htm: Code: [Select] <html> <body> <form method="post" action="retrieve.php" <select id='select' name='select' > <option>option1</option> <option>option2</option> <option>option3</option> <option>etc...</option> </select> <input type="submit"> </form> </body> </html> retrieve.php: Code: [Select] <?php $selectedoption = $_POST['select']; print" <html> <body> <select id='select' name='select' > <option>option1</option> <option>option2</option> <option>option3</option> <option>etc...</option> </select> </body> </html> "; ?> How do I specify that the select menu in retrieve.php should have the option selected that was chosen from the select menu in send.htm? I'm guessing this is probably quite straightforward, but I can't quite work it out. Please help! Thanks. Hi I have a list of states using the array method in a form. The drop down menu works fine. I want to save the user choice,if the form is re-displayed due to a blank field or pattern mismatch. I know I can use the selected=selected, but don't know wher to put the statement: My array is: state_province = array ("list of states", "provinces") Var in my labels array is "state"=>"state" Here is my code for the select/option statement: { if($field == "state") { echo "<div class='province_state'><label for='state' size='10'>* Province/State</label><select>"; foreach($state_province as $state) { echo "\n<option value='$state_province' /> "; echo $state ; echo "</option>"; } echo "</select></div>\n"; } ?Is this the correct code to add and where would I add it? if(@$_POST['state'] == $value) { echo "selected='selected' "; } The rest of my coding works however this part does not and I'm trying to figure out why. I'm sure my syntax isn't right so I hope someone can correct my mistake. $contentpageID = $_GET['id']; $query = "SELECT contentpages.contentpage, contentpages.shortname, contentpages.contentcode, contentpages.linebreaks, contentpages.backlink, contentpages.showheading, contentpages.visible, contentpages.template_id FROM contentpages WHERE contentpages.id = '" . $contentpageID . "'"; <label for="template">Template</label> <select class="dropdown" name="template" id="template" title="Template"> <option value="0">- Select -</option> <?php $query = 'SELECT * FROM templates'; $result = mysql_query ( $query ); while ( $template_row = mysql_fetch_assoc ( $result ) ) { print "<option value=\"".$template_row['id']."\" "; if($template_row['id'] == $row['template_id']) { print " SELECTED"; } print ">".$template_row['templatename']."</option>\r"; } ?> </select> This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=333152.0 Hi all, I have a html drop down menu and want to show the initially selected value as the one stored in the mysql database that a member selected. I have 180+ rows in mysql that a member could have selected and would like to basically do this: IF (value of option == $row['value'] ) { echo "selected=\"selected\"; } I could put this in every one of the rows it would be much better to have an if statement. As there are so many values I do not know where to begin. Can someone point me in the right direction? Thanks So, it's me again. Hope you dont mind I try to fetch data from mysql and list it to select option like this Code: [Select] <td>Category</td> <td>: <select name="category"> <?php $query = "SELECT DISTINCT category FROM dress"; $sql = mysql_query($query); while($result = mysql_fetch_array($sql)){ echo "<option value='".$result['category']."'>".$result['category']."</option>"; } ?> <option value="other">New Category --></option> </select><input type="text" name="categoryOther"></td> </tr> ...and success. BUT, when I try to echo submitted value it return nothing this is the code to process above form Code: [Select] if(isset($_POST['categoryOther'])){ $category = $_POST['categoryOther']; } else { $category = $_POST['category']; } if(isset($_POST['subcategoryOther'])){ $subcategory = $_POST['subcategoryOther']; } else { $subcategory = $_POST['subcategory']; } echo "category : ".$category."<br>"; What did I do wrong here? Hello I want product filter groups by category. There will be different options. Ex: http://prntscr.com/sr00ay Product Table : http://prntscr.com/sr00rm Option Groups Table : http://prntscr.com/sr013r Options Table : http://prntscr.com/sr01fk Product Option Table : http://prntscr.com/sr01r3 How can I build this structure? And how should it be sql for filtering? Is the structure correct? I'm waiting for your help. Edited May 31, 2020 by AtakanI have this function where i want to pass the month and year according to the date drop down that is chosen by the user. But can't seem to get the selected month and year. But instead, i got the month and year for now (which is April 2020). Can any one show me how can i achive this? I mean how can i pass the month and year selected to my `allreport-summary.php` page. It would be better if you guys can show me examples of codes on how can i implement this. Any help will be appreciated. Thank you so much. cheers!
<div class="row">
<div class="col-4 my-auto">
<input type="month" id="month" class="form-control" value="<?php echo date('Y-m'); ?>">
</div>
<div class="col-4 my-auto">
<select class="form-control" id="seller">
<option value="">Select All</option>
<?php
$sql = "SELECT * FROM sellers ORDER BY seller_registered";
$query = $conn->query($sql);
while ($row = $query->fetch_assoc()) {
?>
<option value="<?php echo $row['id'];?>"><?php echo $row['seller_fullname'];?></option>
<?php } ?>
</select>
</div>
<div class="col-4">
<button type="button" class="btn btn-info" onclick="loadreports();">
<i class="nc-icon nc-zoom-split"></i>
</button>
<a href="allreport-summary.php?month=<?php echo date('Y-m');?>">
<button type="button" class="btn btn-info" style="height: 40px;">
<i class="fa fa-file-excel-o"></i> Export All Report
</button>
</a>
</div>
I am looking to add Spanish to a website and would like the users to be able to click a button to switch between english and Spanish. Is this something that php would be good for or should I look into another language? Would there be a benefit to doing this on the client side versus the server, hence the use of javascript versus php? I would appreciate any help in this area; samples, websites, and such. I am looking to learn, and not for someone to do all the work for me. Thank you in advance for your help. Whats going on PHPfreaks? So this is what I've been trying to do for the whole weekend and just can't figure it out. I want to let users create new pages on my site like wiki style but dont want a wiki or drupal or joomla or any of that. I know its possible with: $text = $_POST['text']; $file = fopen($text . ".php","x"); fwrite($file,"Welcome to your new page!"); but I'm not sure how to integrate it. For further clarification here's an example: You come to the site and there is a list of previously made user pages all with their own user generated name. What I want to have is a create new page button that opens a new page allows the user to upload images then submit it to the database and upon refresh of the page their page is now in the list. The create new page resets and is available for another user and on and on. Any help will be appreciated. I need to get this done it's driving me crazy. |
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